A student reacted 0.600 g of lead (II) nitrate with 0.850 g of potassium iodide

Answer:

30.031 g/mol

Explanation:

..................

The molar mass of CH₂O is 30.

Molar mass can be defined as 'mass per mole.' In other words, molar mass is the sum of the mass of all the atoms found in one mole's worth of a substance. It is expressed in units of grams per mole.

The definition applies to pure substance.

The molar mass allows for converting between the mass of a substance and its amount for bulk quantities.

It is calculated as the sum of standard atomic weights of all atoms that form one entity of the substance.

Given,

The molecular formula = CH₂O

Atomic mass of C = 12

Atomic mass of H = 1

Atomic mass of O = 16

Molar mass = Sum of atomic masses of all the atoms

                       = 12 + (2 × 1) + 16

                       = 12 + 2 + 16

                       = 30

Therefore, The molar mass of CH₂O is 30.

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Answer:

1 cal = 0.004187 kJ

1,500,000 cal = 6280.5 kJ

Answer: 581 Sn and 13 Sn

Explanation:

581 Sn and 13 Sn are both Sn which are the same element with different masses. Isotopes are same element with different masses and the elements can have different masses because of different number of neurons

Answer:

Its Polar bby

Explanation:

Answer:

polar

Explanation:

Mass of Helium = 4

Helium = 55 liters

How many moles = ?

By the equation(AT S.T.P) of,

Moles = \(\frac{Given\ Volume}{22.4\ dm^3}\)

Substitute the values,

Moles = \(\frac{55}{22.4}\)

Simplify the fraction,

Moles = 2.5 grams/moles

Answer:

Humans use Oxygen or O2 to begin the process of cellular respiration, and then when this process is finished it gives of carbon dioxide or Co2

Explanation:

Answer:

oxygen is used by human in the process of cellular respiration

Explanation:

because cells uses oxygen to break down sugar

Answer:

The removal of this ion from water by the calcifiers will definitely decrease the pH of water.

What is the bicarbonate ion?

The bicarbonate ion is the ion that is designated as HCO3-. We must notice that this ion is present in abundant amounts in the sea. This amount definitely make the sea slightly alkaline.

Now we must note that the removal of this ion from water by the calcifiers that require it to make their shell will definitely decrease the pH of water.

Explanation:

The removal of this ion from water by the calcifiers will definitely decrease the pH of water.

The bicarbonate ion is the ion that is designated as \(HCO^{3-}.\) We must notice that this ion is present in abundant amounts in the sea. This amount definitely makes the sea slightly alkaline.

Now we must note that the removal of this ion from water by the calcifiers that require it to make their shell will definitely decrease the pH of water.

Hence, the removal of this ion from water by the calcifiers will definitely decrease the pH of water.

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Answer:

SAMPLE A - pure substance.

SAMPLE B - homogeneous mixture.

SAMPLE C - heterogeneous mixture.

Explanation:

Answer:

pure substance.

homogeneous mixture.

heterogeneous mixture.

Explanation:

20 mL of 0.170 M NaOH solution is required to neutralize 20 mL of 0.170 M HCl solution.

To determine the volume of 0.170 M NaOH solution required to neutralize 20 mL of a 0.170 M HCl solution, we can use the equation:

moles of acid = moles of base

First, let's calculate the number of moles of HCl in 20 mL of the solution:

moles of HCl = (0.170 mol/L) x (20 mL / 1000 mL/L) = 0.0034 mol

Since the neutralization reaction between HCl and NaOH has a 1:1 stoichiometry, we know that 0.0034 mol of NaOH will be required to completely neutralize the HCl.

Next, we can use the concentration of the NaOH solution to determine the volume required:

moles of NaOH = 0.0034 mol

Molarity of NaOH = 0.170 M

Volume of NaOH = moles of NaOH / Molarity of NaOH = 0.0034 mol / 0.170 mol/L = 0.02 L or 20 mL

Therefore, 20 mL of 0.170 M NaOH solution is required to neutralize 20 mL of 0.170 M HCl solution.

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Answer:

Differences in melting points between graphite and butter is how their atoms are fixed structurally. Graphite consists of carbon atoms that have covalent bonding with a compact hexagonal arrangement that gives a lot of stability to the compound and makes its melting point elevated to approximately 3500oC.

The allotropes of carbon are diamond and graphite. The allotropes can have same or different physical or chemical properties. Therefore,  differences in melting points between graphite and butter is due difference in structure.

Allotropy is a property by which an element exist in more than one form. The different forms of element are called allotropes.

The features of graphite are :

1.Graphite form strong covalent bonds.

2. Graphite has delocalized electrons but they don't have metallic bonding.

3. There are total four electrons per carbon but only three electrons are available for covalent bond. One electron per carbon is responsible for delocalization.

4. Graphite forms a giant structures.

Graphite consists of carbon atoms that have covalent bonding with a compact hexagonal arrangement that gives a lot of stability to the compound and makes its melting point elevated.

Therefore, differences in melting points between graphite and butter is due difference in structure.

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Answer: "Minerals the necessity of human use are extracted from ores."

Explanation:

An ore can be defined as a natural sediment or rock which comprises of one or more kinds of necessary minerals. The minerals typically comprises of either metals or non-metals. The ores are extracted from the deep earth layers by the mining process. The ores are refined and treated by smelting. In this process the heat is applied to the ores to extract the metals. The metals are of great economic importance without conducting mining and extraction processes no one can get metals. Metals are used for making cans, metal wires, gadgets and others.

''Minerals are extracted from ores which can be used by human."

Ore is a natural rock or sediment which is deposit in Earth's crust that consist of one or more valuable minerals. The most valuable ore deposits contain metals that is important to industry and trade like copper, gold, aluminium and iron etc. These minerals can be extracted from the soil by using different types of methods and machineries.

These minerals can be used in making various products as well as sold directly to other countries at high price which contributes in the economy of the country so we can conclude that minerals are very important for the economy of a country.

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Answer:

143.991

Explanation:

47.997 * 3 = 143.991

For an electron in 4s orbital, the principal quantum number is 4, Azimuthal quantum number is 0, magnetic quantum number is 0 and spin quantum number is -1/2 or + 1/2.

There are four quantum numbers are used to describe completely the movement and trajectories of each electron within an atom. In atoms, there are a total of four quantum numbers. Principal quantum number n, designates the principal electron shell. The magnetic quantum number ml determines the number of orbitals and their orientation within a subshell. Electron spin quantum number designates the direction of the electron spin and may have a spin of +1/2. The orbital angular momentum quantum number determines the shape of an orbital, and therefore the angular distribution. The number of angular nodes is equal to the value of the angular momentum quantum number l.

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The number of mole present in 87 grams of potassium bromide, KBr is 0.731 mole

We'll begin our calculation by obtaining the molar mass of potassium bromide, KBr. Details below:

Molar mass of potassium bromide, KBr = K + Br

Molar mass of potassium bromide, KBr = 39 + 80

Molar mass of potassium bromide, KBr = 119 g/ mol

Finally, we shall determine the number of mole present. Details below:

Mole = mass / molar mass

Mole of potassium bromide, KBr = 87/ 119

Mole of potassium bromide, KBr = 0.731 mole

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Complete question:

How many moles are in 87g of potassium bromide?

Answer:

The stars arent moving, we are.

Explanation:

The rotational movement of the Earth is what makes the star appear as if moving from the east to the west in the sky, as the planet rotates with an axis pointed towards the direction of our/the North Star.

The theoretical yield of MgO from the given reactants is 1.25 g.

What do you mean by theoretical yield?

The theoretical yield is the maximum amount of a product that can be produced from a given amount of reactants according to the stoichiometric equation. It is calculated using the balanced equation for the reaction. The theoretical yield is an ideal value and does not take into account any losses due to side reactions, incomplete conversion of reactants, or any other physical or chemical losses.

1. Calculate the molar mass of the reactants:

Molar mass of Mg = 24.30 g/mol

Molar mass of O2 = 32.00 g/mol

2. Calculate the moles of reactants used:

Moles of Mg = 0.429 g/24.30 g/mol = 0.0176 mol

Moles of O2 = 0.429 g/32.00 g/mol = 0.0134 mol

3. Calculate the moles of product formed:

Moles of MgO = 0.0176 mol + 0.0134 mol = 0.0310 mol

4. Calculate the theoretical yield of product:

Theoretical yield of MgO = 0.0310 mol x 40.30 g/mol = 1.25 g

The theoretical yield of MgO is 1.25 g.

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When 2 liters of nitrogen gas reacts with 6 liters of hydrogen gas at constant temperature and pressure, 3.99 liters of ammonia gas will be produced.

The balanced chemical equation is:

N₂ + 3H₂ ⇒ 2NH₃

According to the balanced equation, it shows that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.

Since the molar ratio is fixed, use the principles of stoichiometry to determine the volume of ammonia gas produced.

Moles of nitrogen gas (N2) = 2 liters / 22.4 liters/mole

= 0.089 moles

Moles of hydrogen gas (H2) = 6 liters / 22.4 liters/mole

= 0.268 moles

According to the balanced equation, the stoichiometric ratio of N₂ to H₂ is 1:3. Since we have 0.089 moles of N₂, it means we need 3 times that amount of H₂, which is 0.089 moles × 3 = 0.267 moles. Since we have 0.268 moles of H₂, it is in excess.

Now, let's calculate the moles of ammonia gas produced using the limiting reactant, which is N₂:

Moles of ammonia gas = (0.089 moles of N) × (2 moles of NH₃ / 1 mole of N2) = 0.178 moles

Volume of ammonia gas  = (0.178 moles) × (22.4 liters/mole)

= 3.99 liters

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Mass of sample = 270.4g

To find the mass of a chemical compound, you need to know the chemical formula of the compound, the number of moles and the atomic masses of its constituent elements.

The formula for sodium hydroxide is NaOH, and its molar mass is 23.00 g/mol for Na + 16.00 g/mol for O + 1.01 g/mol for H = 40.01 g/mol.

To calculate the mass of the 6.761-mol sample, we can use the formula:

mass = moles x molar mass

mass = 6.761 mol x 40.01 g/mol

mass = 270.44 g

Therefore, the answer is option B) 270.4 g.

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To determine the percent silver (Ag) by mass in the lead metal, we can use electrochemical measurements based on the standard reduction potentials of the species involved.

The reaction occurring at the silver electrode is as follows:

Ag+ (aq) + e- → Ag (s)

The standard reduction potential for this reaction is 0.799 V vs. the standard hydrogen electrode (SHE).

Given that the potential difference between the Ag electrode and SHE was found to be 0.498 V, we can calculate the actual reduction potential for the Ag+ to Ag reaction:

Ecell = EAg - ESHE

0.498 V = EAg - 0.000 V

EAg = 0.498 V

Since the standard reduction potential for Ag+ to Ag is 0.799 V, the difference between the actual reduction potential and the standard reduction potential is:

ΔE = EAg - E°Ag

ΔE = 0.498 V - 0.799 V

ΔE = -0.301 V

Now, we can use the Nernst equation to relate the potential difference to the concentration of Ag+ ions:

E = E° - (0.0592 V/n) log([Ag+])

Where:

E is the measured potential difference (0.498 V)

E° is the standard reduction potential (0.799 V)

n is the number of electrons transferred in the reaction (1 for Ag+ to Ag)

[Ag+] is the concentration of Ag+ ions (unknown)

Substituting the values into the equation:

0.498 V = 0.799 V - (0.0592 V/1) log([Ag+])

0.301 V = 0.0592 V log([Ag+])

Now, we need to determine the number of moles of Ag+ ions present in the solution. We know that the volume of the solution is 500.0 mL (0.5000 L), and the concentration of Ag+ ions is [Ag+]. So:

moles of Ag+ = [Ag+] * volume (in L)

moles of Ag+ = 10^5.084 * 0.5000 L

Finally, to calculate the percent silver (Ag) by mass in the lead metal, we divide the moles of Ag+ by the initial mass of the lead sample (1.080 g) and multiply by 100:

percent Ag = (moles of Ag+ / initial mass of lead) * 100

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This scientific project aims to analyze and implement strategies to rejuvenate a dying lawn, ensuring its vitality and health.

If you notice that a lawn looks unhealthy and the grass is dying, you can undertake a scientific project to save it by following these steps:

Step 1: Identify the problemThe first step is to identify the problem. Observe the lawn and try to determine what is causing the grass to die. Common causes include poor soil quality, lack of water, too much sun or shade, pests, or disease.

Step 2: ResearchOnce you have identified the problem, conduct research to find out more about it. Look for information about how to treat the specific problem that is causing the grass to die. You can consult gardening books or online resources.

Step 3: Develop a hypothesisBased on your research, develop a hypothesis about what is causing the problem. For example, if you think the soil quality is poor, your hypothesis might be that adding fertilizer will improve the health of the grass.

Step 4: Design an experimentDesign an experiment to test your hypothesis. For example, if your hypothesis is that adding fertilizer will improve the health of the grass, you could divide the lawn into two sections. Apply fertilizer to one section and not the other. Record your observations over time to see if the grass in the fertilized section is healthier.

Step 5: Conduct the experiment , Carry out your experiment, making sure to record your observations.

Step 6: Analyze the data Analyze your data and determine whether your hypothesis was correct. If the grass in the fertilized section is healthier than the grass in the section without fertilizer, your hypothesis was correct.

Step 7: Draw a conclusion Based on your analysis, draw a conclusion about what is causing the problem and how it can be fixed. For example, if your experiment showed that adding fertilizer improved the health of the grass, you could conclude that the soil quality is poor and that fertilizing the lawn will help to improve it.

Step 8: Take action Based on your conclusion, take action to fix the problem. In this case, you would apply fertilizer to the entire lawn to improve its health.

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The reaction has not yet started, and the time required for 16.8% of the reactant to remain cannot be calculated using the given rate constant.

Given,The rate constant for this first-order reaction is 0.0830 s−1 at 400 ∘C.A⟶products After how many seconds will 16.8% of the reactant remain-The time taken for a first-order reaction to reach a particular percentage of completion can be calculated using the following formula:t = (ln(A/A₀))/kwhere A₀ is the initial concentration of the reactant, A is the concentration of the reactant at a given time, k is the rate constant, and t is the time elapsed since the reaction began.In this question, we are given the rate constant, k = 0.0830 s−1 at 400 ∘C, and we want to find out the time required for 16.8% of the reactant to remain.Let's assume that the initial concentration of the reactant is 100 units (we can assume any value as it does not affect the percentage of completion).Therefore, the concentration of the reactant remaining after 16.8% of completion would be: A = 16.8 units.Substituting these values in the above formula, we get:t = (ln(16.8/100))/0.0830t = (−1.7918)/0.0830t = −21.58 sThis time value is negative, which means that the reaction has not even started yet. Therefore, we need to check the given percentage of completion.

If it is less than 50%, we can assume that the reaction has not yet started. In this case, the percentage of completion is 16.8%, which is less than 50%.

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Answer:

Bromine atom would have smallest radius.

Explanation:

As we know that on ascending down the group the size of atom increases as a new shell is added on ascending by one step... so Iodine has a greater size than Bromine.

As bromine is a halogen atom, so it's ionisation enthalpy is the most in it's period.. so it cannot loose an electron to form a Br+ cation.. so it forms a Br- anion.. by accepting a. electron, so as 1 electron is added to the shell.. the electrons have increased than the no. of protons, so the size would increase as the protons now have to hold more electrons than before, so attraction would decrease. A second reason can also be mentioned as when an electron is added to an atom, it experiences some repulsion from other electrons in same energy shell, so the size would increase. Screening effect of the mid shell electrons also contribute in increasing the size of atom. So Bromine ion would have a greater size than Bromine atom.

By the same analogy the iodine ion would also have grater size than the iodine atom, it also becomes greater in size than the bromine atom..

THUS THE BROMINE ATOM HAS THE LEAST RANKING WHEN ARRANGED IN DECREASING SIZE OF GIVEN SPECIES!!!

Answer:

The troposphere is the lowest layer of Earth's atmosphere, and is also where nearly all weather conditions take place. It contains 75% of the atmosphere's mass and 99% of the total mass of water.

Explanation:

Answer:

A. The largest value is 7 and the smallest value is 1. Find the difference. 7 - 1 = 6.

Explanation:

A. Neutral salts.  (7, 2), B. Acidic salts.  (4, 6), C. Basic salts. (1, 3, 5)

We must understand where the ions originate. Since they can produce hydrolysis in water if they originate from a weak acid or base, the medium is given OH and H+.

1. Li+ + F + LiF

F + H2O -> HF + OH

The hydrolysis can be produced by F, which produces OH. The elemental salt.

2. SrBr2 Sr2+ 2Br

Both are weak and incapable of hydrolyzing. The salt is impartial.

3. NH4+ + NH4CN

Given their strength, both ions can produce the hydrolysis. The problem is that although cyanide produces hydroxides, ammonium produces protons. We must contrast the Ka and Kb to assess how the salt is doing.

Ka = 5.7 1010 NH4+ + H2O NH3 + H3O+

HCN + OH + Kb = 1.61 105 from CN + H2O.

Since Kb exceeds Ka, pH is basic.

Ka > Kb would result in an acidic pH.

4. NH4Br = NH4+ Br

Br doesn't hydrolate. Since the ammonium cation combines with water to release protons into the medium, the salt will be acidic.

Ka = NH3 + H3O + NH4+ + H2O

5. K+ + CN + KCN

Hydrolization of K+ is not possible. The salt will be basic because the cyanide anion reacts in water to produce hydroxides for the medium.

OH + OH Kb = HCN + OH Kb CN + H2O

NH4ClO4 = NH4+ + ClO4

Perchloric acid is the source of ClO4 (a strong acid). No hydrolysis occurs.

Ka = NH3 + H3O + NH4+ + H2O

The medium receives H+ from ammonium, making the acidic salts.

7. LiNO3 Li+ + NO3

Hydrolysis cannot be produced by both ions. They are the result of a strong base and a strong acid, so

Identify the following salts as neutral, acidic, or basic. Drag each item to the appropriate bin.

1. LiF

2. SrBr2

3. NH4CN

4. NH4Br

5. KCN

6. NH4ClO4

7. LiNO3

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The industrial methods of preparing alcohol that is more economical is fermentation.

Fermentation is defined as the industrial method by which starch is converted to ethyl alcohol by using some specific enzymes and microorganisms known as yeast

It is an economical method because the raw material which is starch is readily available.

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