A string exerts a force of 20 N on a box at an angle of 38° from the horizontal. What is the horizontal
component of the force on the box?

A. the Moon broke from a rapidly spinning Earth is the most widely accepted theory of the Moon's origin, known as the Giant Impact Hypothesis or Theia Impact.

According to this theory, a Mars-sized object called Theia collided with the early Earth, and the debris ejected from the impact eventually coalesced to form the Moon.

This theory explains many of the Moon's characteristics, such as its size, composition, and the fact that it orbits the Earth in the same plane as the Earth's equator.

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Answer:

D is the answer wave behavior

Interference, refraction, diffraction, and dispersion are all aspects of wave behavior. (D).  That is, particles don't do these things.

Answer:

the instrument that gives this precision is the micrometer screw

Explanation:

The high precision measurements of small parts are the general vernier and the micrometer screw.

In these two instruments the same principle is used: there is a fixed rule and a mobile one that increases precision.

Let's analyze the absolute error or precision of each instrument

* For the vernier, the precision of the fixed rule is 1 mm and there are 20 divisions (the most common); therefore the precision of the instrument is

            Δx = 1 mm / 20

            Δx = 0.05 mm

* For the micrometer screw, the precision of the fida rule is 0.5 mm and the number of divisions is 50, therefore the precision of the screw is

            Δx = 0.5mm / 50

            Δx = 0.01 mm

consequently the instrument that gives this precision is the micrometer screw

a) y(t) = te⁻³ᵗ is a possible position function.

b) General equation: y(t) = C₁e^(-2t) + C₂e^(-3t) + t(e^(-3t))(At + B).

c) Exact motion equation: y(t) = (23/5)e^(-2t) - (8/5)e^(-3t) + t(e^(-3t))(At + B), with initial conditions y(0) = 3 and v(0) = -7.

a) To show that y(t) = te⁻³ᵗ is a possible position function, we substitute it into the differential equation:

y(t) = te⁻³ᵗ

y'(t) = e⁻³ᵗ - 3te⁻³ᵗ

y''(t) = -6e⁻³ᵗ + 9te⁻³ᵗ

Substituting these expressions into the differential equation, we have:

-6e⁻³ᵗ + 9te⁻³ᵗ + 7(e⁻³ᵗ - 3te⁻³ᵗ) + 6(te⁻³ᵗ) = -6te⁻³ᵗ - e³ᵗ

Simplifying this equation, we find that both sides are equal, thus confirming that y(t) = te⁻³ᵗ is a possible position function.

b) The general equation for all possible position functions can be written as:

y(t) = C₁e^(-2t) + C₂e^(-3t) + t(e^(-3t))(At + B)

c) Given the initial conditions y(0) = 3 and y'(0) = v(0) = -7, we substitute these values into the general equation and solve for the constants:

3 = C₁ + C₂

-7 = -2C₁ - 3C₂

Solving these equations, we find C₁ = 23/5 and C₂ = -8/5.

The exact motion equation for the weight is:

y(t) = (23/5)e⁻²ᵗ - (8/5)e⁻³ᵗ + t(e⁻³ᵗ)(At + B)

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Suppose a weight of 1 kg is attached to an oscillating spring with friction constant b = 7 and stiffness constant k = 6. Suppose the external forces on the weight are: Fₑₓₜ(t) = - 6te⁻³ᵗ - e³ᵗ

y" + 7y' + 6y = - 6te⁻³ᵗ - e³ᵗ

a) Show y(t) = te⁻³ᵗ is a possible position function for this weight.

b) Find a general equation for all possible position functions.

c) Find the exact motion equation for this weight if its initial position is y(0) = 3, and its initial velocity is v(0) = y'(0) = -7.

Answer:

0.0001 m

Explanation:

Given

M=1000 KG

PE=1 J

G=9.8 m/s

H=?

Formula

PE = MGH

H= PE/MG

H=1/1000x9.8

H= 1/9800

or 0.00010204

Answer:

The magnitude of swing's tension is 0.71 N.

Explanation:

Given;

mass of the ball, m = 18 g = 0.018 kg

angular speed of the ball, ω = 1 rev/s

radius of the motion, r = 1 m

Angular speed in rad/s is calculated as follows;

\(\omega = \frac{2\pi \ rad}{rev} \times \frac{1 \ rev}{s} \\\\\omega = 2 \pi \ rad/s\)

Linear speed of the ball, v;

v = ωr

v = 2π x 1

v = 2π  m/s

The magnitude of swing's tension is calculated as the centripetal force keeping the ball in circular motion.

\(F_c =T = \frac{mv^2}{r} \\\\T= \frac{0.018 \ \times (2\pi )^2}{1} \\\\T = 0.71 \ N\)

Therefore, the magnitude of swing's tension is 0.71 N.

Answer:

Behavior is determined by the environment. Behavior, no matter how complex, can be reduced to a simple stimulus.

Explanation:

The pilot should immediately reduce the speed to the maximum specified for the category to ensure the safety of the flight. The pilot should also adjust the airplane's altitude and heading to maintain a stable approach path and touchdown point.

The pilot should follow the appropriate procedure as outlined in the airplane's operating manual. If pilot is circling to land in a Category B airplane but is maintaining a speed 5 knots faster than the maximum specified for that category.

The pilot should also adjust the airplane's altitude and heading to maintain a stable approach path and touchdown point. The pilot should communicate with air traffic control and follow their instructions to ensure proper sequencing with other traffic. Additionally, the pilot should remain vigilant and monitor the airplane's systems and

instruments to ensure that the airplane is operating within its limits and that the flight remains safe and under control. Following these procedures will help ensure a safe and successful landing.

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Answer:

☞Inertia of rest

☞Inertia of motion

Inertia of motion☞Inertia of direction

The speed of sound can reach 285 metres per second. option.D

The formula for calculating the speed of sound is:

Frequency x Wavelength = Speed

The frequency of the sound wave in this case is 318 Hz, and the wavelength is 0.896 m. As a result, the speed of sound can be estimated as follows:

318 Hz x 0.896 m = speed

285 m/s is the maximum speed.

The wave's amplitude is not required to compute the speed of sound. The highest displacement of the wave from its equilibrium position is referred to as amplitude, and it has no effect on the wave's speed.

It should be noted that the speed of sound is affected by the qualities of the medium through which it travels.The speed of sound in air at room temperature is roughly 343 m/s, however it varies depending on temperature, pressure, and humidity.

The speed of sound can be substantially faster in other medium, such as water or steel. As a result, the given frequency and wavelength correspond to different sound velocity in different mediums.So Option D is correct.

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Answer:

Coal was one of man's earliest sources of heat and light. The Chinese were known to have used it more than 3,000 years ago. The first recorded discovery of coal in this country was by French explorers on the Illinois River in 1679, and the earliest recorded commercial mining occurred near Richmond, Virginia, in 1748

Explanation:

Answer:

The planets move in perfect circles.

Explanation:

In the 1500s Copernicus reintroduced the heliocentric model and suggested that the planets all orbit around the Sun in perfect circles.

Answer:

Mostly with aid of Kohlberg 's moral growth theory, I clarify this answer, which would also be separated into three stages under which this particular problem is illustrated below.

Explanation:

The daughter's father would think about either the penalty during that point if he commits any wrongdoing or breaches laws to save her daughter. But another way to make that happen for surgery is that a person cares about either the legislation and rules as well as the significance of respecting them throughout the pre-conventional process. He will also attempt to establish its insight into solving these problems.

As per the traditional process of the spiritual psychosocial development of Kohlberg, her father would think of civilization because there are conventions that unless he borrows money of his dad again for the procedure of their daughter, culture would label him greedy or prejudice against him to pay the profits of his father despite his consideration.

As per this argument, he might determine for her child as well as father in his philosophy including perspectives, which means that his father is not in the situation of requesting credit, but because he's in a position to give a recommendation, therefore he certainly gives authorization rescue her grandchildren even though she is small and has several activities to do in hers life. And subsequently, with emerging profits, he will take care of his father as well as daughter, and nowadays focus says their daughter wants treatment to recover.

Answer:

The acceleration of the plane is 35.6 meters per square second.

Explanation:

By Newton's Laws of Motion, we know that force (\(F\)), in newtons, is directly proportional to acceleration (\(a\)), in meters per square second. That is:

\(F \propto a\)

If four engines are running simultaneously and each produce the same force, then we find that acceleration of the plane is:

\(a_{T} = 4\cdot \left(8.9\,\frac{m}{s^{2}} \right)\)

\(a_{T} = 35.6\,\frac{m}{s^{2}}\)

The acceleration of the plane is 35.6 meters per square second.

Answer:

Part A;

The charges are;

Q₁ = 1.32687 μC and Q₂ = 92.67313 μC

Part B

Q₁ = 95.29042 μC, Q₂ = -1.29042 μC

Explanation:

Part A

The total charge on the two nonconducting spheres = 94.0 μC

The force exerted by each on the other when placed 31 cm apart = 11.5 N

Let Q₁ = x represent the charge on one of the spheres and let Q₂ represent the charge on the other sphere

The force, 'F', exerted by a charge is given as follows;

\(F = k \times \dfrac{\left | Q_1 \right | \cdot \left | Q_2 \right | }{d^2}\)

Where;

d = The distance between the spheres = 31 cm = 0.31 m

k = 8.9875 × 10⁹ N·m²/C²

Where F = 11.5 N

Q₁ + Q₂ = 94.0 μC

∴ Q₂ = 94.0 - Q₁ = 94.0 - x

We get;

\(F =11.5 = 8.9875 \times 10^9 \times \dfrac{x\times (94.0-x) \times 10^{-12}}{0.31^2}\)

Therefore;

94·x - x² - 122.965 = 0

x² - 94·x + 122.965

x = (94 ± √((-94)² - 4×1×122.965))/(2 × 1)

Solving gives;

x ≈ 1.32687 × 10⁻⁶ C or x = 92.67313 × 10⁻⁶ C

Therefore, the charges are;

Q₁ = 1.32687 × 10⁻⁶ C and Q₂ = 92.67313 × 10⁻⁶ C

Q₁ = 1.32687 μC and Q₂ = 92.67313 μC

Part B

For attractive force, we have;

Q₁ + Q₂ = 94 × 10⁻⁶...(1)

\(11.5 = 8.9875 \times 10^9 \times \dfrac{-x\times (94.0-x)}{0.31^2} = 8.9875 \times 10^9 \times \dfrac{-Q_1\times Q_2}{0.31^2}\)

-Q₁ × Q₂ = 11.5 × 0.31²/(8.9875 × 10⁹) = 1.2296523 × 10⁻¹⁰...(2)

∴ Q₂ = -1.2296523 × 10⁻¹⁰/(Q₁)

Q₁ + Q₂ = Q₁  - 1.2296523 × 10⁻¹⁰/(Q₁) = 94 × 10⁻⁶

Q₁² - 94 × 10⁻⁶·Q₁ - 1.2296523 × 10⁻¹⁰ = 0

∴ Q₁ = (94 × 10⁻⁶ ± √((-94 × 10⁻⁶)² - 4 × 1 × 1.2296523 × 10⁻¹⁰))/(2×1)

Q₁ = 9.529042 × 10⁵ C or -1.29042 × 10⁻⁶ C

Therefore, Q₁ = 9.529042 × 10⁵ C and Q₂ = -1.29042 × 10⁻⁶ C

Q₁ = 95.29042 μC and Q₂ = -1.29042 μC

If an electron vibrates back and forth in an clean wire with a frequency of 60.0 Hz, then it will make 2.2×10⁵ cycles. in 1.0 h. Hence option D is correct.

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C

Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.

Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform. There are two types of the wave longitudinal wave and transverse wave.

Frequency is nothing but the number of oscillation in a unit time.

Given,

frequency f = 60.0 Hz.

time t = 1.0 h = 60*60 = 3600s

F = number of cycles/time

number of cycles = F×time

The number of cycles in 1 Hr is

60*3600 = 2.2×10⁵ cycles.

Hence option D is correct.

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Answer:

heat and power

Explanation:

is the simultaneous production of electricity and heat both of which are used

The force acting upon the car is 0.691N. Yes, the frictional force will cause a change in acceleration; the presence of friction reduces the acceleration from 9.8 m/s^2 to 8.3 m/s^2.

Newton's second law of motion states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. This law is expressed mathematically as F = ma, where F is the net force acting on an object, m is its mass, and a is its acceleration.

c. The force acting upon the car can be found using Newton's Second Law. In this case, we know the weight of the car is 3.92N, which is equal to its mass times the acceleration due to gravity (9.8 m/s^2). Therefore, the mass of the car is 3.92N / 9.8 m/s^2 = 0.4 kg.

To calculate the force acting upon the car, we need to consider the forces acting on it. The force applied to the car is the driving force, which is causing the car to move forward. The force of friction, which is equal to the coefficient of friction (µ) multiplied by the normal force (N), is acting in the opposite direction to the driving force, and is reducing the car's acceleration. The normal force is equal to the weight of the car, which is 3.92N.

The force of friction is given as 0.5N, and the coefficient of friction is not given. We can use the equation of motion to calculate the force acting upon the car:

F = ma + µN

F = (0.4 kg)(0.5 m/s^2) + µ(3.92N)

F = 0.2N + µ(3.92N)

To find µ, we can use the fact that the car is just about to move, so the force of friction is equal to the maximum static friction force, which is µsN. Therefore, µsN = 0.5N, and µs = 0.5N / 3.92N = 0.128.

Substituting this value into the equation for force, we get:

F = 0.2N + (0.128)(3.92N) = 0.691N

Therefore, the force acting upon the car is 0.691N.

d. Yes, the frictional force will cause a change in acceleration. This can be calculated mathematically by subtracting the force of friction from the driving force and dividing by the mass of the car:

a = (F - µN) / m

a = (3.92N - 0.5N) / 0.4 kg

a = 8.3 m/s^2

If the car were on a frictionless surface, the acceleration would be equal to the driving force divided by the mass of the car, which would be:

a = F / m

a = 3.92N / 0.4 kg

a = 9.8 m/s^2

Therefore, the presence of friction reduces the acceleration from 9.8 m/s^2 to 8.3 m/s^2.

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Answer:

d. pulling a 10kg box on the floor using a rope

The Lewis structure for the sulfite ion (SO32-) can be completed as follows:

            O

          ╱  ╲

    O = S = O

          ╲  ╱

            O^-

the central sulfur atom (S) is surrounded by three oxygen atoms (O). The sulfur atom has six valence electrons, and each oxygen atom contributes six valence electrons. Adding up the total valence electrons gives us 6 (sulfur) + 3 * 6 (oxygen) + 2 (negative charge) = 26 valence electrons. Starting with the skeleton structure, we distribute the remaining electrons to fulfill the octet rule for each atom. We can place two lone pairs of electrons on each oxygen atom and two lone pairs on the sulfur atom. After distributing all the electrons, we check if each atom has a complete octet.

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Answer:

sodium chloride

Explanation:

Sodium chloride is an ionic compound. The ions of the sodium chloride compound is sodium ion and chloride ion.  The sodium ion is cation while the chloride ion is an anion. Sodium chloride is a very stable compound because of the mutual attraction of oppositely charged ions.

Answer: They are all easy to perform as they are bodyweight exercises.

Explanation:

no difficult exercise so NA. Yes I was plenty of online video to watch to address issues

Answer:

D

Explanation:

The magnitude is 13 m/s

   the direction is east    the   units  are  m/s

Answer:

a = 6.87 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f} =v_{o} +a*t\)

where:

Vf = final velocity = 37 [m/s]

Vo = initial velocity = 15 [m/s]

a = acceleration [m/s²]

t = time = 3.2 [s]

Note: The positive sign in the above equation means that the velocity is increasing, due to the acceleration.

37 = 15 + a*3.2

3.2*a = 37 - 15

a = 6.87 [m/s²]

Answer: 1*10^3 mm^3

That’s it

It is untrue to say that a nucleus's mass is always smaller than the total mass of its nucleons.

The nucleons near the edge of their masses give binding energy to maintain the nucleons inside the nucleus.

The protons and neutrons move in closer together to a distance of 10–14 m during the creation of a nucleus. The mass of the nucleons is sacrificed in order to spend the energy needed for the task.

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the work done to raise a 25kg book to a 1.5 m shelf is 367.5J and the potential energy of the book will be 367.5

Work done by a force is equal to the scalar product of the force applied and displacement. If d displacement happens on applying a force F, then work done, W by the force is

W = F. d

given:

mass, m = 25 kg

height, d = 1.50 m

work has to be done against the weight of the book, F = mg

work done W = F. d

W = mgd

W = (25) ×(9.8)×(1.50)

W = 367.5 J

This work is stored as the potential energy of the book.

Therefore, the work done to raise a 25kg book to a 1.5 m shelf is 367.5J and the potential energy of the book will be 367.5J

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Answer:

In mathematics, an ellipse is a plane curve surrounding two focal points, such that for all points on the curve, the sum of the two distances to the focal points is a constant.

I don’t know how ellipse change tho sorry