A softball is thrown perfectly vertically (straight-up) at 18 m/s.

a) How high will it go?

b) Find the total time the ball is in the air.

Answers

Answer 1

Answer:

a) y = 16.51 [m]

b) t = 1.83 [s]

Explanation:

To solve this problem we must use two kinematics equations, the first to determine the height to which the ball reaches, and the second equation to determine how long it lasts in the air.

\(v_{f} ^{2}= v_{i} ^{2} - (2*g*t)\\\)

where:

Vf = final velocity = 0

Vi = initial velocity = 18 [m/s]

g = gravity acceleration = 9.81[m/s^2]

t = time [s]

Note: the negative sign of the Equation indicates that the acceleration of gravity acts in the opposite direction to the movement of the ball.  The final velocity is zero, since the ball reaches its maximum altitude when the velocity is zero.

Now replacing:

0 = (18)^2 - (2*9.81*y)

y = 16.51 [m]

b)

\(v_{f} = v_{i} - (g*t)\)

0 = 18 - (9.81*t)

t = 1.83 [s]


Related Questions

What is the change in internal energy if 30 J of heat are released from a
system and the system does 50 J of work on its surroundings?
Use AU = Q-W.
A. 80 J
B. -80 J
C. 20 J
D. -20 J

Answers

I think it would be B- -80 J

Answer:

Explanation:

Given:

Q =  30J   (The system did not prepare energy, but allocated)

W =  + 50 J  (System operation)

__________________

ΔU - ? (Change in internal energy)

ΔU = Q - W =  30 - (50)  = - 20J

4. A lens has a focal length of 2m. A pencil is placed 3m from the lens.
a. Where will the image of the pencil be formed? (show all work) (3 marks)
I
b. Is the image inverted or upright? How do you know? (1 mark)

Answers

(a) The distance of the image of the pencil from the lens is determined as 6 m.

(b) The image formed is upright, because it is magnified.

Image distance

The distance of the image formed is determined by applying lens formula as shown below;

1/f = 1/v + 1/u

1/v = 1/f - 1/u

1/v = 1/2 - 1/3

1/v = (3 - 2)/6

1/v = 1/6

v = 6 m

Magnification of the image

M = v/u

M = 6/3

M = 2

A convex lens forms an upright and magnified image.

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output work is less than input work why?

Answers

Answer:

In general, the concept of output work being less than input work does not align with the laws of physics, specifically the principle of conservation of energy. According to this principle, energy cannot be created or destroyed, but it can be transformed from one form to another. Therefore, the total amount of energy in a closed system remains constant.

When considering work, which is the transfer of energy through the application of force over a distance, the input work and output work should theoretically be equal if no energy is lost to other forms, such as heat or friction. However, in real-world scenarios, various factors can result in a decrease in output work compared to input work. Some possible reasons for this disparity include:

Inefficiencies: Real systems are not perfectly efficient, and energy losses can occur due to factors like friction, heat dissipation, electrical resistance, or mechanical limitations. These losses reduce the amount of useful work obtained from the input energy.

Energy conversion: If the input work is in one form of energy (such as electrical or chemical), and the output work is in a different form (such as mechanical), energy losses can occur during the conversion process. The efficiency of the conversion process determines the amount of output work obtained.

External forces: External factors, such as resistance or opposing forces, can require additional work to overcome, resulting in a decrease in net output work compared to the input work.

It's important to note that while output work can be less than input work in certain situations due to these factors, the total amount of energy remains conserved. Energy that is not converted into useful work is typically dissipated as waste heat or other forms of energy loss.

Answer:

The output work is always less than the input work because of friction.

Explanation:

Friction is a force that opposes the relative motion of two surfaces in contact. When a machine is used, frictional forces are created between the moving parts of the machine and the surfaces they rub against.

These frictional forces require some of the input work to be used to overcome them, which reduces the amount of work that is available to do the desired task.

A doppler effect occurs when a source of sound moves:_____.
a. towards you.
b. either towards you or away from you.
c. in a circle around you.
d. away from you.

Answers

Answer:

(b) is correct

object moving towards you - higher frequency heard

object moving away from you - lower frequency heard

ILL GIVE BRAINLIST FOR SHOWING WORK!!

ILL GIVE BRAINLIST FOR SHOWING WORK!!

Answers

The description of the motion and the gravitational potential energy of the particles are as follows;

26. (2) Energy

27. (4) Work

28. (3) Energy kg·m²/s²

29. (2) Joule

30. (4) a 6.0-kg mass 5.0 m above the floor

31. (3) Gravitational potential energy remain the same and speed decreases

32. (2) B

33. About 9.81 Joules

34. Option (1)

35. (4) The gain is the same along all paths

36. (2) Speed decreases and the gravitational potential energy increases

What is the gravitational potential energy?

Gravitational potential energy is the energy a body posses due to its relative posirtion.

26. A scalar quantity is a quantity that has only magnitude but no direction.

The quantity that has only magnitude is energy.

The correct option is (2) Energy

27. Energy is the ability to do work, therefore, work has the same unit as energy. The correct option is therefore;

(4) Work

28. Energy = Force × Distance

Force = Mass × Acceleration

The unit of force is therefore; kg·m/s²

The unit of energy is therefore; m × kg·m/s² = kg·m²/s²

The correct option is; (3) Energy; kg·m²/s²

29. Gravitational potential energy, is a form of energy due to elevation, therefore, the unit is the Joule

The correct option is; (2) Joule

30. Gravitational potential energy can be found using the formula;

P.E. = m·g·h

Where;

m = The mass

g = The acceleration due to gravity

h = The height

The greatest gravitational potential is therefore;

6.0 kg × 9.81 m/s² × 5.0 m

The correct option is therefore;

(4) a 6.0-kg mass 5.0 m above the floor

31. The rough horizontal surface decreases the speed. The elevation of the horizontal surface is constant, therefore, the gravitational potential energy remains the same.

The correct option is therefore;

(3) Gravitational potential energy remains the same and speed decreases

32. The gravitational potential energy of the cart is least at the lowest point.

The correct option is; (2) B

33. The gravitational energy with respect to Earth is found as follows;

5.00 kg × 2.00 m × 9.81 ² = 98.1 Joules

34. The equation for the gravitational potential energy is; P.E. = m·g·h

Therefore, P.E. is directly proportional to the distance above the Earth and graph is a straight line passing through the origin

Option (1) is correct

35. The change in elevation is the same for all 5. The correct option therefore is option (4)

(4) The gain is the same along all paths.

36. The speed of the ball decreases when it is thrown upwards, while the gravitational potential energy increases as the height increases, therefore;

(2) Speed decreases and the gravitational potemntial energy increases

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what is the gravitational potential energy of a 150kg object suspended 5m above the earths surface?

Answers

the gravital energy is produce my magnet

why is physics to study the heat absorbed by the ocean​

Answers

Answer:

Heat is a source of energy

Explanation:

Just took the test

fm transmitter is producing 50 watts into a 50 antenna at a carrier frequency of 525.425 mhz. the deviation ( ) of the transmitter is 1.25 khz; in this service a maximum of 2.5 khz is allowed

Answers

The FM transmitter is producing 50 watts into a 50-ohm antenna at a carrier frequency of 525.425 MHz with a deviation of 1.25 kHz.

In FM (Frequency Modulation) transmission, the power output, antenna impedance, carrier frequency, and deviation are important parameters to consider. Here's a breakdown of the given information:

Power Output: The FM transmitter is producing 50 watts of power. This refers to the amount of power delivered to the antenna.

Antenna Impedance: The antenna connected to the transmitter has an impedance of 50 ohms. This impedance should match the transmitter's output impedance to ensure efficient power transfer.

Carrier Frequency: The carrier frequency is given as 525.425 MHz. This frequency represents the center frequency around which the FM signal varies.

Deviation: The deviation of the transmitter is specified as 1.25 kHz. Deviation refers to the maximum frequency difference between the carrier frequency and the highest or lowest frequency of the modulated signal.

From the provided information, we can conclude that the FM transmitter is operating within the specified limits for this service. The maximum allowable deviation in this service is 2.5 kHz, and the transmitter's deviation is only 1.25 kHz, which means it complies with the regulatory requirements. Additionally, the power output and antenna impedance are also within the acceptable range for the given application.

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Electricity flows from
positive to positive
negative to positive
negative to negative
positive to negative

Answers

Answer:

is it from positive to negative am I right tell me if I am wrong

Answer:

positive to negative

The flow of electric current is similar to the flow of water which is from higher level to lower level.

The electric current flow from higher potential region(positive* low concentration of electron) to lower potential region(negative*high concentration of electron)

Complete the following Water enters a 200L tank at a rate of 32g/s and is withdrawn at a rate of 10g/s. The tank is initially half full. Write a mass balance for this process and solve the balance equation to determine how long it will take the tank to drain completely in minutes. The density of water conversion is 1000g/1L an Engineering Connect

Answers

It will take the time  to drain completely in minutes when The density of water conversion is 1000g/1L is 75.76 minutes.

To write a mass balance for this process, we need to consider the inflow of water into the tank and the outflow of water from the tank. The mass balance equation for this process can be written as follows:

dM/dt = Q_in - Q_out

where dM/dt is the rate of change of the mass of water in the tank over time, Q_in is the inflow of water into the tank, and Q_out is the outflow of water from the tank.

In this case, the inflow of water into the tank is 32 g/s, and the outflow of water from the tank is 10 g/s. The initial mass of water in the tank is 200L * 1000 g/L = 200,000 g, and the tank is half full, so the initial mass of water in the tank is 200,000 g/2 = 100,000 g.

Substituting these values into the mass balance equation, we get:

dM/dt = 32 g/s - 10 g/s = 22 g/s

To determine how long it will take the tank to drain completely, we can solve the mass balance equation for t. The mass of water in the tank at any time t is given by:

M(t) = M(0) + dM/dt * t

where M(0) is the initial mass of water in the tank and t is the time in seconds.

Substituting the values for M(0) and dM/dt, we get:

M(t) = 100,000 g + 22 g/s * t

To drain the tank completely, the mass of water in the tank must be zero, so we can set M(t) = 0 and solve for t:

0 = 100,000 g + 22 g/s * t

t = -100,000 g / 22 g/s

t = -4545.45 s

Since there are 60 seconds in a minute, the time it will take the tank to drain completely in minutes is t/60 = -4545.45 s / 60 s/min = 75.76 minutes.

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Consider the system shown in the figure. The rope and pulley have negligible mass, and the pulley is frictionless. The coefficient of kinetic friction between the 8.00-kg block and the tabletop is m_k=.25 . The blocks are released from rest.Use energy methods to calculate the speed of the 6.00-kg block after it has descended 1.50 m. How do i calculate work on the 8kg block.

Answers

Plugging in the given values and solving for the final velocity of the 6kg block will give you the speed of the 6.00-kg block after it has descended 1.50 m. In this case, the normal force is the weight of the 8kg block, and the displacement is the distance that the 8kg block moves.

Energy Method Block Speed

To calculate the speed of the 6.00-kg block after it has descended 1.50 m, you can use the conservation of mechanical energy. The initial mechanical energy of the system is the potential energy of the 6.00-kg block (mgh) and the potential energy of the 8.00-kg block (mgh). As the blocks move, some of this energy is converted into kinetic energy, and some is lost to friction. The equation for the conservation of mechanical energy is:

E_initial = E_final + W_friction

Where E_initial is the initial mechanical energy of the system, E_final is the final mechanical energy of the system, and W_friction is the work done by friction.

The final mechanical energy of the system is the kinetic energy of the 6.00-kg block (1/2 mv²) and the potential energy of the 8.00-kg block (mgh).

To calculate the work done by friction, you can use the equation:

W_friction = force x distance x cos(theta)

Where force is the force of friction, distance is the distance over which the force of friction acts, and theta is the angle between the force of friction and the displacement. The force of friction is the coefficient of kinetic friction times the normal force.

In this case, the normal force is the weight of the 8kg block, and the displacement is the distance that the 8kg block moves.

W_friction = m_kF_nd

Where m_k = 0.25 is the coefficient of kinetic friction, F_n = 8*9.8 N is the normal force, and d = 1.5m is the distance that the 8kg block moves.

Plugging in the given values and solving for the final velocity of the 6kg block will give you the speed of the 6.00-kg block after it has descended 1.50 m.

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explain how to identify the points under compression and tension ​

 explain how to identify the points under compression and tension

Answers

Answer:

Pls make me brainliest

Explanation:

the compression force is the force generated from compressing an object or substance. When shearing forces are aligned into each other, they are called compression forces.

The compression force is used to power everything from compression brakes to hand tools. The compressive strength of materials and structures is an important engineering consideration.

The compression force can be visualized by placing an object on a spring. When the spring is compressed and then released, the object is ejected into the air.

This is a result of the compression force that is generated from compressing the spring.

This system has a constant velocity, and there is an equilibrium because the tension in the cable, which is pulling up the object, is equal to the weight force, i.e., mg. Where M is a mass, and g is the acceleration caused by gravity, which is pulling down the object.

The Formula of Tension.

T = Mg

Tension word becomes from a Latin word meaning “to stretch.” Testing part of the force, Like one type of pull force. All physical objects that are in contact may exert forces on each other.

This contact forces different names based on these types of objects in contact. Where one of the objects exerting the force happens to be a rope, string, chain, or cable we call the force tensions

When charging a secondary cell, energy is stored within a dielectric material using an electric field. True or False

Answers

It is a false statement that; "when charging a secondary cell, energy is stored within a dielectric material using an electric field"

What is a secondary cell?

The term secondary cell refers to a cell that can be recharged when it is used up. A typical example of a secondary cell is a lithium ion battery.

We know that most of the secondary cell are charged using a chemical that is inside the battery. As such, it is a false statement that; "when charging a secondary cell, energy is stored within a dielectric material using an electric field"

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Explain how temperature differences at different depths of the ocean provide a possible energy source

Answers

Ocean thermal energy conversion (OTEC) is a technology that uses the temperature differences between warm surface water and cold deep water in the ocean to generate electricity. The temperature difference can be significant, up to 20 degrees Celsius or more in some places, and this temperature gradient can be harnessed to drive a power-generating turbine.

The basic principle of OTEC involves the use of a heat engine, which works by exploiting the difference in temperature between two reservoirs of water. In the case of OTEC, one reservoir is warm surface water, and the other is cold deep water. The heat engine uses this temperature difference to generate mechanical energy, which can then be converted into electricity.

There are two main types of OTEC systems: closed-cycle and open-cycle. In a closed-cycle system, a working fluid with a low boiling point, such as ammonia, is vaporized by the warm surface water and then condensed by the cold deep water. The resulting pressure difference drives a turbine, which generates electricity. In an open-cycle system, warm surface water is used to evaporate a working fluid, which then expands through a turbine, generating electricity. The vapor is then condensed using cold deep water and returned to the ocean.

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can someone explain and solve in detail? I really don't get it.

A baseball player hits a 0.155-kilogram fastball traveling at 44.0 m/s into center field at a speed of 500 m/s. If the impact lasts for 0.00450 second, with what force does he hit the baseball? (Hint: Momentum is a vector)​

Answers

Answer:

15706.666

Explanation:

F = 0.155(500-(+44))/0.00450

A 300 g wooden block on a smooth, level surface is firmly attached to a very light horizontal spring with a spring constant of 200 N/m.
The spring-block system is initially stretched a distance “d” beyond the spring's equilibrium position and is released from rest. As the block moves to the right, its speed is 50.0 cm/s when the spring-block system is 4.00 cm from the equilibrium position.
Find d, the initial displacement of the spring-block system (in cm).

A 300 g wooden block on a smooth, level surface is firmly attached to a very light horizontal spring

Answers

the solution for the oscillatory movement allows to find the result for the amplitude of the initial displacement is:

The range of motion is: A = 4.44 cm

Oscillatory movement.

The oscillatory periodic motion of a system occurs when there is a recovered force, in the special case that this force is proportional to the displacement is called simple harmonic motion, which is described by the expression.

            x = A cos (wt + Ф)

            w² = k/m

where x is the displacement, A the amplitude, w the angular velocity, t the time, k the spring constant, m the mass, and Ф a phase constant determined by the initial conditions.

Let's find the angular velocity/

            w= \(\sqrt{ \frac{200}{0.300} }\)

            w = 25.8 rad/s

Let's look for the constant Ф, as the system is released from rest its initial velocity is zero, for zero time. The definition of speed is:

             v= \(\frac{dx}{dt}\)

             v= - A w sin (wt +Ф)

             

             0 = -A w sin Ф

            Ф= 0

They indicate that at a given instant of the time the velocity is v= 50.0 cm/s and it is in a position x= 4.00 cm, let us write the equations for this time

Position.

               4.00 = A cos 25.8t

Speed.

              50.0 = - At 25.8 sin 25.8t

To solve the system, ;et's square and add.

              Cos² 25.8t = \(\frac{16}{A^2}\)

              sin² 25.8t = \(\frac{3.756}{A^2 }\)

              1 = \(\frac{1}{A^2} \ (16 + 3.756)\)

               A = \(\sqrt{19.756}\)

               A= 4.44 cm

In conclusion using the solution for the oscillatory movement we can find the result for the amplitude of the initial displacement is:

The range of motion is: A = 444 cm

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HELP PLEASE !!!!!!! If a ball is accelerating down through the air with no horizontal motion, what must be true about the net forces acting on the ball? The gravitational force is greater than the drag. The net force on the ball is zero. The drag is greater than the gravitational force. The net force on the ball is directed upward.
physics

Answers

Answer:

A. The gravitational force is greater than the drag.

Explanation:

Remember that the second Newton's law says that:

F = m*A

Force equals mass times acceleration.

With this we will see that the correct option is:

"The gravitational force is greater than the drag."

We know that the ball is accelerating downwards, and there is no horizontal motion. Because the acceleration is downwards, we know that the net force must be downwards (for the second law).

Now, what must be true about the net forces acting on the ball? let's analyze each statement:

1) "The gravitational force is greater than the drag."

The gravitational force is what causes the objects to fall down to the ground, so if the ball is falling, this will always be true.

2) " The net force on the ball is zero."

We know that the ball is accelerating, thus the net force can not be zero, this is false.

3) "The drag is greater than the gravitational force. "

This is the opposite to the first option, this is false.

4) "The net force on the ball is directed upward."

The acceleration and the net force have the same direction, if the ball is accelerating downwards, then the net force is directed downwards. This is false.

Then the only true statement is the first one:

"The gravitational force is greater than the drag."

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The _____is a measure of the number of waves that pass a point in a given amount of time

Answers

The answer is frequency
Answer: wave frequency

Scott was watching the electrician install a new light fixture. Scott noticed that when he was finished, he carefully wrapped some wires with plastic caps and black plastic tape. Select the best explanation of why the electrician would wrap electrical wires with plastic products.

Answers

Answer: The electrician wrapped the wires with plastic caps because plastic is an insulator.

Explanation: Metals are excellent conductors of electricity, largely because electrons in the metal are only loosely bound by their respective atoms and thus will readily flow under the influence of an external electric field. Plastics are very different. All the electrons in plastics are tightly bound by their respective molecules and it would take a lot of energy to remove them. Consequently, most plastics are insulators that do not conduct electric current (or do so only poorly).

find the angle between the vectors. u = (2, 3, 0), v = (3, −2, 1)

Answers

Therefore, the angle between vectors `u` and `v` is 90°.

To find the angle between two vectors, we can use the formula:

`cos(θ) = (u . v) / (||u|| ||v||)`

Where u and v are vectors, `.` is the dot product of vectors and || || is the magnitude of a vector.θ is the angle between the two vectors.

In this problem, we need to find the angle between vectors `u` and `v`.

We have the following vector

s:u = (2, 3, 0) and v = (3, −2, 1)

Let's find the dot product of vectors `u` and `v`.u .

v = 2 × 3 + 3 × (−2) + 0 × 1

= 6 − 6 + 0

= 0

Let's now find the magnitudes of vectors `u` and `v`.||u|| = √(2² + 3² + 0²) = √(13) and

||v|| = √(3² + (−2)² + 1²)

= √(14)

Now, we can use the formula to find the angle between vectors `u` and `v`.cos(θ) = (u . v) / (||u|| ||v||)cos(θ)

= 0 / (√(13) × √(14))cos(θ)

= 0θ

= cos⁻¹(0)θ

= 90°

The angle between the vectors u = (2, 3, 0) and v = (3, −2, 1) is 90 degrees.

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Two solid spheres, both of radius 5cm, carry identical total charges of 2μC. Sphere A is a good conductor.Sphere B is an insulator, and its charge is distributed uniformly throughout its volume.
How do the magnitudes of the electric fields they separately create at radius 4 cm compare?

Answers

The magnitudes of the electric fields they are separately create at the radius 4 cm is the correct option is C. EA = EB > 0.

Two solid spheres, both of the radius 5cm, they carry the identical total charges of the 2μC. Sphere A is the good conductor. Sphere B is an insulator, and the charge are distributed uniformly throughout the volume. Both the spheres are produce the identical fields at the outer locations, the like particles will do at the cores, because of the spherically symmetric charge distributions.

The magnitudes of the electric fields they are separately create at the radius 4 cm is EA = EB > 0.

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Describe the three methods of thermal energy transfer and provide a sketch that depicts each:
Conduction:
Convection:
Radiation:

Answers

Answer:

a)the process by which heat or electricity is directly transmitted through the material of a substance when there is a difference of temperature

b)the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat

c)radiation is the emission or transmission of energy in the form of waves or particles through space or through a material medium.

20 BRAILY POINTS Which of the following actions will keep the gravitational force between two objects unchanged? Decreasing the mass of the objects Increasing the temperature of the objects Increasing the distance between the objects Decreasing the distance between the objects

Answers

Answer:

Explanation:

See attachment.

Decreasing the mass of the objects   No.  Force will change.

Increasing the temperature of the objects Yes,  No change in force (at most a very small change if the heat causes excessive expansion, reducing the distance, although 1/2 will be further apart)

Increasing the distance between the objects No.  Force will change.

Decreasing the distance between the objects  No.  Force will change.

20 BRAILY POINTS Which of the following actions will keep the gravitational force between two objects

help meh pls- i lazy

help meh pls- i lazy
help meh pls- i lazy
help meh pls- i lazy
help meh pls- i lazy

Answers

Answer:

the first question is B, if not then its C

Explanation:

sorry if I am wrong

A tightrope walker is walking between two buildings holding a pole with length L=14.0 m, and mass mp=17.5 kg. The daredevil grips the pole with each hand a distance d=0.595 m from the center of the pole. A bird of mass mb=560 g lands on the very end of the left‑hand side of the pole. Assuming the daredevil applies upward forces with the left and right hands in a direction perpendicular to the pole, what magnitude of force Fleft and Fright must the left and right hand exert to counteract the torque of the bird?

Answers

Answer:

F = 32.28 N

Explanation:

For this exercise we must use the rotational equilibrium relation

          Σ τ = 0

In the initial configuration it is in equilibrium, for which all the torque and forces are compensated. By the time the payment lands on the bar, we assume that the counter-clockwise turns are positive.

          W_bird  L / 2 - F_left 0.595 - F_right 0.595 = 0

we assume that the magnitude of the forces applied by the hands is the same

          F_left = F_right = F

          W_bird L / 2 - 2 F 0.595 = 0

          F = \(\frac{m_{bird} \ g L} { 4 \ 0.595}\)

   

we calculate

         F = 0.560 9.8 14.0 /2.38

         F = 32.28 N

Please help I'm so lost.
Erbium-165 has a half-life of 10.4 hours. If you start with 1,000 grams of erbium-165, how much time will it take to have 125 grams of erbium-165 left in the sample?

A. 41.6 hours
B. 31.2 hours
C. 10.4 hours
D. 20.8 hours

Answers

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

option D is the correct answer.

What is half life?

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is calculated as follows;

1,000 ---------- 0 time

500 ----------- 10.4 hours

125 ------------- 20.8 hours

Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

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a heavy fireworks petard explodes with high energy at the peak of its parabolic trajectory. what will the trajectory of its center of mass be after the explosion? neglect air resistance.

Answers

The trajectory of the center of mass of the heavy fireworks petard will continue along the original parabolic path after the explosion. This is because the center of mass follows a path that is independent of the internal forces acting within the object.

When the petard explodes, the internal forces acting within the object will cause it to break apart into many smaller pieces. However, the center of mass will continue along the original path of the object, following a parabolic trajectory. This is because the motion of the center of mass is only influenced by external forces acting on the object, such as gravity.

Therefore, neglecting air resistance, the trajectory of the center of mass of the petard after the explosion will be the same as its trajectory before the explosion.

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A 1500 kg car is moving at 15m/s what is the impulse experienced by the car

*Pls put the formula of how you did it too*

Answers

Answer:

22500 Ns

Explanation:

Given,

Mass ( m ) = 1500 kg

Velocity ( v ) = 15 m/s

Formula : -

Impulse = mv

Impulse

= 1500 x 15

= 22500 Ns

Therefore,

22500 Ns is the impulse experienced by the car.

Note : -

Ns is the unit of impulse.

Impulse= mass x velocity so answer is 22500

Convert 93.6 miles per hour. Convert this to kilometers per hour.

Answers

Answer:

150.6 km

Explanation:

One mile is about 1.61 km so multiply 93.6 by 1.6 which gives you above 150.6

A ray of light hits a plane mirror 35 degrees from the normal. What is the angle of reflection?

Answers

ANSWER

\(\begin{equation*} 35\degree \end{equation*}\)

EXPLANATION

We want to find the angle of reflection of the ray of light.

According to the law of reflection, the angle of reflection must be equal to the angle of incidence of a ray of light:

\(\theta_r=\theta_i\)

Therefore, the angle of reflection of the ray of light is:

\(\theta_r=\theta_i=35\degree\)

That is the answer.

It would be 35 hope this helps you sorry I gave you just the answer I’m in a rush
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