A small-motorized cart can go from a standing start to 42 m/s in 7 seconds. What is the acceleration rate of the cart?
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Related Questions
FASTTT I BEG U An astronaut weighs 900 N on earth. On the moon he weighs 150 N. Calculate the moons’ gravitational strength. (Take g = 10 N/kg).
Answers
mass of an object is always constant
weight is a force, \(W=mg\) where $g$ is acceleration due to gravity.
Weight on earth is , $900=m\cdot 10 \implies m=90$ kg
weight on moon is $150=90\times g_{\text{moon}} \implies g=\frac{5}{3}$
Determine la inercia rotacional de una varilla de 4 m de largo y 2 Kg de mesa si su eje de rotación esta situado a la mitad de la varilla.
Answers
Answer:
I = 2.667 kg m²
Explanation:
The moment of inertia of a body can be calculated by the expression
I = ∫ L² dm
For high symmetry bodies the expressions of the moment of inertia are tabulated, for a rod with its axis of rotation at its midpoint it is
I = \(\frac{1}{12}\) m L²
let's calculate
I = \(\frac{1}{12}\) 2 4²
I = 2.667 kg m²
A toy car starts from rest and accelerates at a uniform rate of 4.0 ms^-2 for 3.0 seconds. It then maintains a uniform speed for 12.0 seconds. Finally it takes 6.0 seconds to decelerate uniformly to rest. Find the total distance travelled and the average speed of the entire trip.
Answers
The total-distance travelled by toy-car is 198 meter, and average-speed of toy-car for entire trip is 9.43 ms⁻¹.
We break down the car's motion into three parts: the acceleration phase, the constant velocity phase, and the deceleration phase.
We use kinematic equations of motion to find distance traveled and average speed in each phase.
⇒ Acceleration phase:
The initial velocity (u) is = 0, the acceleration (a) is = 4.0 ms⁻², and time (t) is = 3.0 seconds. We use equation : s = ut + 1/2 at²,
s = 0 × (3.0) + 1/2 (4.0)(3.0)²,
s = 18.0 meters
So, The distance traveled during the acceleration phase is 18.0 meters.
⇒ Constant velocity phase:
The car maintains a constant velocity for 12.0 seconds, so we can use the equation : s = v × t,
where v is = constant velocity. Since, velocity is constant, we use final velocity (v) from acceleration phase:
v = u + at
v = 0 + (4.0)(3.0)
v = 12.0 ms⁻¹,
So, s = (12.0 ms⁻¹)(12.0 s)
s = 144.0 meters
The distance traveled during the constant velocity phase is 144.0 meters.
⇒ Deceleration phase:
The final velocity (v) is = 0, acceleration (a) is unknown, and time (t) is = 6.0 seconds. We can use the equation : v = u + at,
0 = 12.0 + a(6.0),
a = -2.0 ms⁻²,
The negative acceleration indicates that car is decelerating or slowing down. We use the same kinematic equation as before to find distance traveled : s = ut + 1/2 at²,
s = 12.0(6.0) + 1/2 (-2.0)(6.0)²,
s = 72.0 - 36.0
s = 36.0 meters
So, distance traveled during deceleration phase is 36.0 meters.
⇒ Total distance traveled can be found by adding the distances traveled in each phase:
total distance = 18.0 + 144.0 + 36.0
total distance = 198.0 meters
So, The total distance traveled is 198.0 meters.
⇒ Average speed:
We find the average speed of entire trip by dividing the total distance traveled by the total time taken:
total time = 3.0 + 12.0 + 6.0
total time = 21.0 seconds,
So, average speed = 198/21,
average speed = 9.43 ms⁻¹,
Therefore, the average-speed of entire-trip is 9.43 ms⁻¹.
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derive an expression from the energy stored E, in a stretched wire of original length L cross sectional area A, e, tension e,and young modulus Y of the material of the wire
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The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A
How to explain the expressionThe work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).
The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:
T = Y * (ΔL / L)
where Y is the Young's modulus of the material of the wire.
Now, let's calculate the work done to stretch the wire:
dW = T * dL
Integrating this expression from L to L + ΔL:
W = ∫ T * dL = ∫ Y * (ΔL / L) * dL
W = Y * ΔL * ∫ (dL / L)
W = Y * ΔL * ln(L) + C
Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.
Finally, the expression for the energy stored in the wire (E) is:
E = W = Y * ΔL * ln(L)
or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:
E = Y * e * ln(L) * A
Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:
E = Y * e * ln(L) * A
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what types of electromagnetic radiation does the sun emit?
Answers
Answer:
https://gml.noaa.gov/education/info_activities/pdfs/LA_radiation.pdf
Explanation:
How long will it take an object traveling at 7 m/s to reach a distance of 26 meters
Answers
Answer:
3 hours 71 minutes
Explanation:
As because Speed= distance/time taken
so time taken= 3.71
the proportion of incoming radiation that is reflected by a surface is called
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The proportion of incoming radiation that is reflected by a surface is called albedo. Albedo is a measure of how much of the incoming solar radiation is reflected by a surface.
It is expressed as a percentage, with 0% being no reflection and 100% being a complete reflection.
The albedo of a surface depends on its composition and structure. For example, snow has a high albedo (about 90%), while water has a low albedo (about 5%). The albedo of the Earth's surface is about 30%.
Albedo plays an important role in the Earth's climate. The amount of solar radiation that is reflected back to space by the Earth's surface determines how much of the Earth's energy budget is absorbed by the Earth. A higher albedo means that more solar radiation is reflected back to space, which leads to a cooler Earth. A lower albedo means that more solar radiation is absorbed by the Earth, which leads to a warmer Earth.
The Earth's albedo has changed over time due to a variety of factors, including changes in the Earth's vegetation and ice cover. These changes in albedo have played a role in the Earth's climate history.
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Which of the following statements about conductors under electrostatic conditions is true?
A. Positive work is required to move a positive charge over the surface of a conductor.
B. Charge that is placed on the surface of a conductor always spreads evenly over the surface.
C. The electric potential inside a conductor is always zero.
D. The electric field at the surface of a conductor is tangent to the surface.
E. The surface of a conductor is always an equipotential surface.
Answers
Out of the given statements about conductors under electrostatic conditions, option C is true. The electric potential inside a conductor is always zero. This is because in electrostatic conditions, charges on a conductor are in static equilibrium and there is no electric field inside the conductor.
Any excess charge on the conductor resides on its surface, and the electric field inside the conductor is zero. Due to this, the electric potential inside a conductor is constant and equal to zero.
Option A is false as positive work is not required to move a positive charge over the surface of a conductor. This is because the charge on a conductor is free to move, and the electric field inside a conductor is zero.
Option B is false as the charge that is placed on the surface of a conductor may not always spread evenly over the surface. This is because the shape and geometry of the conductor can affect the distribution of charges on its surface.
Option D is false as the electric field at the surface of a conductor is always perpendicular to the surface. This is because if the field were tangent to the surface, there would be a component of the field along the surface, which would cause charges to move along the surface, resulting in a non-static equilibrium.
Option E is false as the surface of a conductor is not always an equipotential surface. This is because the distribution of charges on a conductor's surface can be uneven, leading to variations in the electric potential on its surface.
Hence, Option C is correct.
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Which element is represented by the atomic model below
A. Calcium
B. Neon
C. Oxygen
D. Helium
Answers
Answer:
b
Explanation:
because f its electronic configuration 2:8 indicating that it has 8 electrons in its outer most energy level
For the following questions, please provide a complete step by step solution. You do notneed interaction, but you are required force diagrams.
Answers
Tennsion 1= horizontal = 484.94 N
Tension 2 = slanted string = 560 N
Explanation
Step 1
Free body diagram
Newton's first law says that if the net force on an object is zero, like in this case the mass is in rest,then that object will have zero acceleration
so
Step 1
set the equations:
a) for x-axis
\(\begin{gathered} \sum ^{}_{}F_x=0 \\ so \\ T_{2x}-T_1=0 \\ T_2\cos 30-T_1=0\rightarrow equation(1) \end{gathered}\)b) for y -axis
\(\begin{gathered} \sum ^{}_{}F_y=0 \\ so \\ T_{2y}-w=0 \\ T_2\sin 30-280N=0\rightarrow equation(2) \end{gathered}\)Step 2
Solve the equations
\(\begin{gathered} T_2\cos 30-T_1=0\rightarrow equation(1) \\ T_2\sin 30-280N=0\rightarrow equation(2) \end{gathered}\)a) solve for T2in equation (2)
\(\begin{gathered} T_2\sin 30-280N=0\rightarrow equation(2 \\ \text{add 280 N in both sides} \\ T_2\sin 30-280N+280N=0+280\text{ N} \\ T_2\sin 30=280\text{ N} \\ \text{divide both sides by sin 30} \\ \frac{T_2\sin30}{\sin30}=\frac{280\text{ N}}{\sin30} \\ T_2=560\text{ N} \end{gathered}\)b) replace the T2 value in equation (1) to find T1
\(\begin{gathered} T_2\cos 30-T_1=0\rightarrow equation(1) \\ 560\cos 30-T_1=0\rightarrow equation(1) \\ 484.97-T_1=0 \\ 484.97=T_1 \end{gathered}\)therefore
Tennsion 1= horizontal = 484.94 N
Tension 2 = slanted string = 560 N
I hope this helps you
Which of the following describes the correct order of energy conversions necessary to form electricity from solar panels?
Solar Heat Kinetic → Electric
Solar- Kinetic Heat → Electric
Solar 1 Heat → Electric
O Solar ->Electric
Answers
Answer:
hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9
A high jumper reaches a height of 2.1 m. If they have a mass of 65 kg, what is the gravitational potential energy at the highest point in the jump?
Answers
Answer:
\(\boxed {\boxed {\sf 1337.7 \ Joules}}\)
Explanation:
We are asked to find the gravitational potential energy at the highest point in the jump.
Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. It is calculated using the following formula:
\(GPE= m \times g \times h\)
The mass of the jumper is 65 kilograms and they reach a height of 2.1 meters. Assuming this situation is occurring on Earth, the acceleration due to gravity is 9.8 meters per second squared.
m= 65 kg g= 9.8 m/s² h= 2.1 mSubstitute the values into the formula.
\(GPE = 65 \ kg \times 9.8 \ m/s^2 \times 2.1 \ m\)
Multiply the numbers together.
\(GPE=637 kg*m^2/s^2 \times 2.1 \ m\)
\(GPE=1337.7 \ kg*m^2/s^2\)
Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer of 1337.7 kg*m²/s² is equal to 1337.7 J.
\(GPE= 1337.7 \ J\)
The gravitational potential energy at the highest point in the jump is 1337.7 Joules.
The following circuit contains three capacitors C₁ = 16 µF, C₂ 6μF, and C3 = 10µF connected to a battery with an unknown emf &. The charge on capacitor C₁is Q₁ = 12 uc. 1. What is the equivalent capacitance Ceq of the circuit? H₁₂ A. 75 x 10-6 F B. 8. 0 x 10-6 F C. 10. 0 x 10-6 F D. 12. 0 x 10-6 F E 2. How much energy is stored on capacitor C₁? A. 49 x 10-6 J C. 25 x 10-5) B. 3. 0 x 10-6/ C₂ tha C₂
Answers
The equivalent capacitance Ceq of the circuit is 75 x 10⁻⁶ F, and the energy stored on capacitor C₁ is 49 x 10⁻⁶ J.
equivalent capacitance Ceq of a circuit with three capacitors in parallel can be found by adding the individual capacitances. In this case, C₁ = 16 µF, C₂ = 6 µ
F, and C₃ = 10 µ
F. So, Ceq = C₁ + C₂ + C₃
= 16 µ
F + 6 µ
F + 10 µ
F = 32 µF. Therefore, the answer to the first question is A. 75 x 10⁻⁶ F.
The energy stored on a capacitor can be calculated using the formula
E = 1/2 ×C ×V²
where E is the energy, C is the capacitance, and V is the voltage across the capacitor. Since the charge Q₁ on capacitor C₁ is given as 12 µC and the capacitance C₁ is 16 µF, we can calculate the voltage V₁ across capacitor C₁ using the formula Q = C ×V.
Thus, V₁ = Q₁ / C₁
= 12 µC / 16 µ
F = 0.75 V.
Now, we can calculate the energy stored on capacitor C₁ using the formula E₁ = 1/2 ×C₁ ×V₁²
= 1/2 ×16 µF ×(0.75 V)²
= 9 µJ.
Therefore, the answer to the second question is A. 49 x 10⁻⁶ J.
In conclusion, the equivalent capacitance Ceq of the circuit is 75 x 10⁻⁶ F, and the energy stored on capacitor C₁ is 49 x 10⁻⁶ J.
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An astronaut on the ISS is doing an experiment with two puffy Cheetos inside a carefully sealed container. A charge of 1.2 E−5 C is place on the first Cheeto. The second one receives a charge of 2.5 E−6 C. The force acting on the first Cheeto is 5.73 E−1 N. What is the distance between the Cheetos if k = 8.99 E9 N*m2/C2?70 cm60 cm40 cm49 cm
Answers
ANSWER:
1st option: 70 cm
STEP-BY-STEP EXPLANATION:
Given:
Force (F) = 5.73 E−1 N^
Electrical charge 1 (q1) = 1.2 E−5 C
Electrical charge 2 (q2) = 2.5 E−6 C
k = 8.99 E9 N*m2/C2
We can calculate the distance between both charges with the help of Coulumb's law, just like this:
\(F=k\cdot\frac{q_1\cdot q_1}{d^2}\)We substitute and solve for the distance, just like this:
\(\begin{gathered} 5.73\cdot\: 10^{-1}=\frac{8.99\cdot10^9\cdot\:1.2\cdot\:10^{-5}\cdot2.5\cdot10^{-6}}{d^2} \\ d^2=\frac{8.99\cdot10^9\cdot1.2\cdot10^{-5}\cdot2.5\cdot10^{-6}}{5.73\cdot10^{-1}} \\ d=\sqrt[]{0.47} \\ d=0.69\text{ m}\cong0.70\text{ m}=70cm \end{gathered}\)The distance is 70 centimeters
physics behind cricket bat
Answers
Cricket bat uses one common law of physics
The law of conservation of linear momentumWhen a ball hits the bat with some velocity ,the cricket bat should hit with some more velocity to get greater impact velocity to move the ball somewhere .
marta flies past you at 75% of the speed of light, traveling in a spaceship that would measure 50 meters from end to end if it were at rest in your reference frame. if you measure the length of her spaceship as it goes by, how long will it be from end to end? b. the star sirius is located 8.6 light-years from earth (in our earth-based reference frame). suppose you travel from earth to sirius at 92% of the speed of light. during your trip, how far would you measure the distance from earth to sirius to be?
Answers
The length of Marta's spaceship as it goes by will be 33 meters from end to end using Lorentz Contraction formula and the distance from Earth to Sirius as measured during the trip would be 22.6 light-years by using relativistic formula for length contraction.
What is Lorentz Contraction formula and relativistic formula for length contraction ?The Lorentz Contraction formula states that the length of an object as measured in a reference frame moving at velocity v with respect to an observer is given by.
\(L=L_{0}\sqrt{1-\frac{v^{2} }{c^{2} } } }\)where \(L_{0}\) is the length of the object at rest in the observer's reference frame, v is the velocity of the object relative to the observer, and c is the speed of light.To find the length of Marta's spaceship as it goes by, we need to use the Lorentz Contraction formula
The relativistic formula for length contraction states that, the length of an object as measured in a reference frame moving at velocity v with respect to an observer is given by.
\(L=\frac{L_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }\)
To find the distance from Earth to Sirius as measured during the trip, we need to use the relativistic formula for length contraction.
CalaculationFor a part
In this case, it is given that \(L_{0}\) = 50 m, v = 0.75c, and c = 3×\(10^{8}\)m/s. Plugging in the values, we get.
\(L = 50 m * \sqrt{(1 - (0.75^2))}\)
\(L = 50 m * \sqrt{(1 - 0.5625)}\)
\(L = 50 m * \sqrt{(0.4375)}\)
\(L = 33 m\)
So, the length of Marta's spaceship as it goes by will be 33 meters from end to end.
For b part
In this case, \(L_{0}\) = 8.6 light-years, v = 0.92c, and c = 3 x 10^8 m/s. Plugging in the values, we get.
\(L= \frac{ 8.6}{\sqrt{(1 - (0.92^2))} }\)
\(L= \frac{ 8.6}{\sqrt{(1 - 0.8544)} }\)
\(L= \frac{ 8.6}{\sqrt{(0.1456)} }\)
\(L= 22.6\)
So, the distance from Earth to Sirius as measured during the trip would be 22.6 light-years.
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you have an 85 m cable run to a poe camera. why do you prefer to use cat 6a as opposed to cat6 cable? because cat 6 cable is not really meant to support poe cameras. because the attenuation caused by the longer distance will cause signal loss not only for the camera video, but also for the dc power. you should not be using either. you should be using cat 5e cable instead. because cat 6 cable is meant to support 100 mb, whereas cat 6a is meant to support 1000 mb.
Answers
The correct answer is: "Because the attenuation caused by the longer distance will cause signal loss not only for the camera video but also for the DC power."
When using Power over Ethernet (PoE) for devices like cameras, it's crucial to consider the distance and the potential signal loss that may occur. Attenuation refers to the decrease in signal strength as it travels through the cable. Over longer cable runs, attenuation becomes a significant factor that can affect both the video signal and the power delivered to the PoE device.
Cat 6a cable is preferred over Cat 6 in this scenario because it has better performance characteristics and reduced attenuation over longer distances. Cat 6a cable is designed to support 10 Gigabit Ethernet (10GBASE-T) at distances up to 100 meters. It provides improved transmission performance, including reduced crosstalk and higher bandwidth.
On the other hand, Cat 6 cable is typically designed for 1 Gigabit Ethernet (1000BASE-T) at shorter distances. While it may work for some PoE applications, the attenuation caused by the longer cable run can lead to signal loss, affecting both the camera video and the DC power transmitted through the cable.
Cat 5e cable is also a suitable option for PoE applications, as it can support both data and power transmission over shorter distances. However, for longer cable runs, Cat 6a is preferred due to its superior performance and reduced signal loss.
In summary, when dealing with an 85-meter cable run to a PoE camera, Cat 6a is the preferred choice over Cat 6 due to its better attenuation characteristics, ensuring reliable transmission of both video and power signals.
Hence, the correct answer is: "Because the attenuation caused by the longer distance will cause signal loss not only for the camera video but also for the DC power."
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A baby carriage is sitting at the top of a hill that is 35 m high. The
carriage with the baby has a mass of 1.5 Kg. What is the potential
energy?
Answers
Gravity=9.8
M=1.5 G=9.8 H=35
so multiply all
=514.5 potential energy
Answer:
\(\boxed {\boxed {\sf E_p= 515.025 \ J}}\)
Explanation:
Potential energy is found using this formula:
\(E_p= mgh\)
The mass of the baby in the carriage is 1.5 kilograms and the height is 35 meters. Assuming this is on Earth, the gravitational acceleration is 9.81 meters per square second.
\(m=1.5 \ kg \\g= 9.81 \ m/s^2\\h= 35 \ m\)
Substitute the values into the formula.
\(E_p= (1.5 \ kg )( 9.81 \ m/s^2)(35 \ m )\)
Multiply the first numbers together.
\(E_p= 14.715 \ kg*m/s^2 (35 \ m )\)
Multiply again.
\(E_p= 515.025 \ kg*m^2/s^2\)
1 kilogram square meter per square second is equal to 1 Joule.Our answer of 515.025 kg*m²/s² is equal to 515.025 J\(E_p= 515.025 \ J\)
The potential energy is 515.025 Joules.
If 10.0 J of work are required to transfer 2.00 coulombs of
charge from point X to point Y in an electric field, what is the
difference in potential between these two points?
Answers
Answer: 5V
Explanation: because 2 goes into 10, five times. Also I know it’s correct cuz I got it right in my quiz
The difference in potential between these two points is 5 V.
Electric potential between the two points
The electric potential between two points is the work done in taking a unit postive charge from one point to another.
The difference in potential between these two points is calculated as follows;
W = qV
V = W/q
V = 10/2
V = 5 V
Thus, the difference in potential between these two points is 5 V.
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Light that has a wavelength of 668 nm passes through a slit 6.73 106 m wide and falls on a screen that is 1.85 m away. What is the distance on the screen from the center of the central bright fringe to the third dark fringe on either side
Answers
The distance from the center of the central bright fringe to the third dark fringe on either side is approximately: 4.838 mm.
To find the distance from the center of the central bright fringe to the third dark fringe on either side, we can use the formula for the angular position of a dark fringe in a single-slit diffraction pattern. The formula is:
θ = (2n + 1) * (λ / (2 * a))
where θ is the angular position of the dark fringe, n is the fringe number (in this case, 3), λ is the wavelength of the light (668 nm or 668 x 10^-9 m), and a is the width of the slit (6.73 x 10^-6 m).
Plugging in the values, we get:
θ = (2 * 3 + 1) * (668 x 10^-9 / (2 * 6.73 x 10^-6))
θ ≈ 0.002617 radians
Now we need to find the linear distance on the screen (y) using the formula:
y = L * tan(θ)
where L is the distance between the slit and the screen (1.85 m). Calculating the distance, we get:
y = 1.85 * tan(0.002617)
y ≈ 0.004838 m or 4.838 mm
So, the distance from the center of the central bright fringe to the third dark fringe on either side is approximately 4.838 mm.
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Complete question:
Light that has a wavelength of 668 nm passes through a slit 6.73x10^-6 m wide and falls on a screen that is 1.85 m away. What is the distance on the screen from the center of the central bright fringe to the third dark fringe on either side?
Which of the following is true about the magnetic field diagram below.Its shows3 Arrows on top pointing to BA B3 Arrows on bottom pointing to BA A is the south pole and B is the north poleB A is the north pole and B is the south poleC A and B are repelling each other******D A and B have no effect on each other
Answers
The correct statement about the magnetic field diagram is C) A and B are repelling each other.
In the given diagram, there are three arrows on top pointing to B and three arrows on the bottom pointing to B. This indicates that the magnetic field lines are moving from A (south pole) to B (north pole). According to the properties of magnets, opposite magnetic poles attract each other, while like magnetic poles repel each other.
Therefore, in this scenario, A (south pole) and B (north pole) are repelling each other, as indicated by the direction of the arrows in the diagram. The magnetic field lines from both poles are pointing away from each other, demonstrating the repulsive interaction between the two poles.
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PLEASE HELP SOMEONE. I'LL GIVE BRAINLIEST.
Use the correct key term to complete each of the following sentences.
1. Amplitude measures the _________ of a wave.
2. When frequency increases, the length of the wavelength ___________. .
3. A wave’s energy is ___________ related to its frequency.
4. The top of a wave is call the _________. .
5. The number of waves that pass a given point per unit of time is the __________. .
6. The _________ refers to the distance between two adjacent crests of a wave.
Answers
Answer: Key Terms - Amplitude, Wavelength, Frequency, Ionizing radiation, Nonionizing radiation, Radio waves, Microwaves, Infrared lights, Visible light waves, Ultraviolet radiation, X-rays, Gamma rays, Speed of light
Work out the wavelength in Meters with a frequnecy of 300 MHz and speed of 3 × 10^8 m/s.
Answers
Answer:
1 m
Explanation:
The following data were obtained from the question:
Frequency (f) = 300 MHz
Velocity (v) = 3×10⁸ m/s
Wavelength (λ) =?
Next, we shall convert 300 MHz to Hz. This can be obtained as follow:
1 MHz = 10⁶ Hz
Therefore,
300 MHz = 300 MHz × 10⁶ Hz / 1 MHz
300 MHz = 3×10⁸ Hz
Thus, 300 MHz is equivalent to 3×10⁸ Hz.
Finally, we shall determine the wavelength of the as follow:
Frequency (f) = 3×10⁸ MHz
Velocity (v) = 3×10⁸ m/s
Wavelength (λ) =?
v = λf
3×10⁸ = λ × 3×10⁸
Divide both side by 3×10⁸
λ = 3×10⁸ / 3×10⁸
λ = 1 m
Therefore, the wavelength is 1 m
how much work is done to lift a 200n box a distance of 2 meters? a. 200 j b. 600 j c. cannot be determined. d. 400 j
Answers
Option (d). Work done to lift a 200 n box a distance of 2 meters is 400 j
Mass of the box, m = 200 N
Distance traveled by the box, d = 2 m
The formula to calculate work done, W = F × d
where,F = Force applied, d = Distance traveled. In this case, we are lifting a box, which means we need to apply force to overcome the weight of the box. The force applied in this case is the weight of the box, which is given by
F = m × g
where,m = Mass of the box, g = Acceleration due to gravity = 9.8 m/s². Substituting the given values,
F = 200 N (weight of the box)
Now, substituting the values of F and d in the formula to calculate work done,
W = F × d
W = 200 N × 2 m
W = 400 J.
Therefore, the work done to lift a 200 N box a distance of 2 m is 400 J, which is option (d). Hence, the correct answer is option (d) 400 J.
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What level of certainty do you have that the sun will rise tomorrow
Answers
my certainty is 99.999999% because the earth has been around for about 4 quadrillion years or more and the sun has risen on almost every single one of them, so the odds of the sun not coming up are very very low.
Answer:
100%
Explanation:
A student leaves their history classroom and walks 20 meters north to a drinking fountain. Then the student turns and walks 50 meters south to their art classroom. What is the magnitude of the total distance traveled by the student?
a. 20 m
b. 30 m
c. 50 m
d. 70 m
Answers
Answer:
D
Explanation: Given that a student leaves their history classroom and walks 20 meters north to a drinking fountain. Then the student turns and walks 50 meters south to their art classroom.
The distance is a scalar quantity.
The distance = 50 + 20
distance = 70 metres
Therefore, the magnitude of the total distance traveled by the student is 70 metres. Which is option D
A car travels 500 km from home at 35 m/s, then travels back at 43 m/s. Find its average speed.
Answers
The average speed of the car is 35.6m/s
What is average speed?The average speed is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity. It is represented by the magnitude and does not have direction. It is measured in meter per second
Therefore average speed = total distance / total time taken
The total distance here is 500+ 500= 1000km = 1×10⁶m
the time taken for the first journey = 500×1000/35= 14285.71 seconds
the time taken for traveling back = 500000/43= 11627.91 seconds
total time taken = 14285.71 + 11627.91 = 25913.62seconds
therefore average speed = 1000000/25913.62
= 35.6m/s
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How does an atom change if all of its electrons are removed?
Answers
Answer: If all the electrons of an atom are removed, it will change to become a positively charged ion called a cation.
Explanation:
Answer:
The atom becomes positively charged.
Explanation:
A karate expert executes a swift blow and splits a cement block with her hand. The force is high since the
momentum is decreased
momentum is increased
mass of the block is so high
time of impact is so low
Answers
Answer:
has f uped hands
Explanation:
A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
Answers
The final speed of the combined masses is 0.186m/s
According to the law of collision, the sum of the momentum of the bodies before the collision is equal to the momentum after the collision.
Mathematically;
m1u1 - m2u2 = (m1+m1)v
v is the final speed of the combined masses.Substituting the given parameters;
0.24(0.6) - 0.26(0.2) = (0.24+0.26)v
0.144 - 0.052 = 0.5v
0.092 = 0.5v
v = 0.092/0.5
v = 0.184m/s
Hence the final speed of the combined masses is 0.186m/s
Learn more on collision here: https://brainly.com/question/7538238