a. the integral becomes A = ∫[1 to 2] (2 - 4/x) dx
b. the integral becomes: A = ∫[2 to 4] (1 - 4/y) dy
a. To calculate the area of the region between the curves xy = 4, x = 1, and y = 2 by integrating with respect to x, we need to find the limits of integration and set up the integral.
First, let's analyze the curves. The equation xy = 4 represents a hyperbola, x = 1 is a vertical line, and y = 2 is a horizontal line.
To find the limits of integration, we need to determine the x-values at which the curves intersect.
For xy = 4, we can solve for y in terms of x: y = 4/x.
To find the x-values at the intersections, we set y = 2 and solve for x:
2 = 4/x
x = 4/2
x = 2
Therefore, the limits of integration for x are from x = 1 to x = 2.
Now, we can set up the integral to calculate the area:
A = ∫[1 to 2] (upper curve - lower curve) dx
The upper curve is y = 2, and the lower curve is y = 4/x. So the integral becomes:
A = ∫[1 to 2] (2 - 4/x) dx
b. To calculate the area of the region between the curves xy = 4, x = 1, and y = 2 by integrating with respect to y, we again need to find the limits of integration and set up the integral.
This time, let's solve the equation xy = 4 for x in terms of y: x = 4/y.
To find the y-values at the intersections, we set x = 1 and solve for y:
1 = 4/y
y = 4
Therefore, the limits of integration for y are from y = 2 to y = 4.
Now, we can set up the integral to calculate the area:
A = ∫[2 to 4] (right curve - left curve) dy
The right curve is x = 1, and the left curve is x = 4/y. So the integral becomes:
A = ∫[2 to 4] (1 - 4/y) dy
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suppose average pizza delivery times are normally distributed with an unknown population mean and a population standard deviation of 6 minutes. a random sample of 28 pizza delivery restaurants is taken and has a sample mean delivery time of 36 minutes. what is the correct interpretation of the confidence interval? select the correct answer below: we can estimate with 95% confidence that the sample mean pizza delivery time is between 33.78 and 38.22 minutes. we can estimate that 95% of the time that a pizza is ordered, the pizza delivery time is between 33.78 and 38.22 minutes. we can estimate with 95% confidence that the true population mean pizza delivery time is between 33.78 and 38.22 minutes. we can estimate that 95% of the pizza delivery restaurants have a mean pizza delivery time between 33.78 and 38.22 minutes.
The correct interpretation of the confidence interval is: "We can estimate with 95% confidence that the true population mean pizza delivery time is between 33.78 and 38.22 minutes."
The confidence interval represents a range of values within which the
population mean delivery time is likely to fall, based on the sample data.
It does not provide information about the delivery times of individual pizzas
or restaurants.
The confidence level refers to the percentage of times that the true
population mean would be expected to fall within the interval if the same
sampling procedure were repeated many times.
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select the correct answer from the drop-down menu Given: W(-1,1),X(3,4),Y(6,0) and Z(2,3) are the vertices of quadrilateral WXYZ Prove: WXYZ is a square using the distance formula I found ________
The quadrilateral WXYZ is not a square using the distance formula
Proving WXYZ is a square using the distance formulaFrom the question, we have the following parameters that can be used in our computation:
W(-1,1),X(3,4),Y(6,0) and Z(2,3)
The lengths of the sides can be calculated using the following distance formula
Length = √[Change in x² + Change in y²]
Using the above as a guide, we have the following:
WX = √[(-1 - 3)² + (1 - 4)²] = 5
XY = √[(3 - 6)² + (4 - 0)²] = 5
YZ = √[(6 - 2)² + (0 - 3)²] = 5
ZW = √[(2 + 1)² + (3 - 1)²] = 13
The sides that are congruent are WX, XY and YZ
This means that WXYZ is not a square
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2.01 as a mixed number
Answer:
2 1/100
Step-by-step explanation:
First you put the 2 in Then you get the 1/100 and put it next to the 2
Write 6.51 x 10^-8 in Standard Form
Please help :) also this is the same thing question as last time but I forgot to put the little arrow
Answer:
\(651*10^{-8\)
Step-by-step explanation:
Sure hope this helps you
Question content area top
Part 1
Write an equivalent expression without parentheses. Then simplify the result.
m−(8−3m)
using exponents, On simplifying the equation, we get =4m+8.
The PEMDAS order of operations must be followed when you want to simplify a mathematical equation without using parenthesis (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction). There are no parenthesis in the expression, so you may start looking for exponents. If it does, first make that simpler.
What is the main objective of simplification?Work simplification is to develop better work processes that boost output while cutting waste and costs.
What does simplifying mean in algebra?Simplifying an expression is the same as solving a mathematical issue. When you simplify an equation, you essentially try to write it as simply as you can. There shouldn't be any more multiplication, dividing, adding, or deleting to be done when the process is finished.
Given equation,
m-(8-3m)
=m-8+3m
=4m+8
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SUPER URGENT!!!
Joel sells ice cream cones at the county fair. He has to rent the equipment for $36 and spend $0.52 on ingredients for each cone. What is the minimum number of ice cream cones Joel must sell at $1.40 each in order to make a profit?
Please explain ALL OF THE STEPS, or your answer is useless. Thanks!!
Denote by x the number of cones sold or produced.
Denote by C(x) the total cost.
Denote by R(x) the revenue made.
Denote by P(x) the net profit accumulated.
\(C_{T}(x)=C_{fixed}+C_{variable} \: \\ C_{T}(x)=36+0.52x\)
\(R_{T}(x)=selling \: price \: x \\ R_{T}(x)=1.4x\)
\(P(x)=R_{T}(x)-C_{T}(x) \\ P(x)=1.4x-(36 + 0.52x) \\ P(x)=1.4x - 36 - 0.52x \\ P(x)=0.88x - 36\)
If there exists profit, then P(x) has to be positive.
\(P(x) > 0 \\ 0.88x - 36 > 0 \\ 0.88x > 36 \\ x > \frac{36}{0.88} \\ x > 40.90909 \\ x = 41\)
Could some one help me please
Answer:
12
Step-by-step explanation:
Write an equation in standard form for the line that passes through the given points.
(5,-2) and (5,3)
The equation of the line in standard form is
(Type your answer in standard form.)
x=5 is the required equation of straight line
What is slope of line ?The steepness of a line is determined by its slope. The slope is m in the equation for a line that is typically used, y = mx + b. The term "rise over run" is also frequently used to describe it and describes how much the y-value changes as the x-value does.
According to the given value;
slope of line is Y₂-Y₁/X₂-X₁
hence slope for given line will be
3-(-2)/5-5 =5/0 = ∞
slope is infinity means straight line is vertical in nature and vertical lines are of the form x=a where a is some constant
now we can observe that 5 is constant in both the given points so x=5 is the required line which passes through (-2,-6),(-2,5)
Hence,x=5 is the required equation of straight line .
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Write the formula of the sinusoidal function (CORRECT ANSWER WILL BE MARKED BRAINLIEST)
Answer:
The equation of a basic sine function is f(x)=sinx. In this case b, the frequency, is equal to 1 which means one cycle occurs in 2π. If b=12, the period is 2π12 which means the period is 4π and the graph is stretched.
Step-by-step explanation:
Why I’m i here?
Can I please get help
Step-by-step explanation:
y+64=180
y=180-64=116°.
y=4x-28 (vertically opposite angle)
116=4x-28
116+28=4x
144=4x
x=36°.
hope this helps you.
That’s the pictureeeeeeee
Answer:
Selections are shown in the image
Step-by-step explanation:
Relations and Functions
A function is a relation between an input and an output set of values with the condition that every element in the domain relates only with one element in the range.
From the options presented below, we'll mark as functions only those who don't have relations between one element in the input set with more than one element in the output set.
In the first relation, every input element is related to only one output element. The same occurs in the second relation.
Note that in the third relation, the input element -5 is related to 4 and also to -4. Element -3 is also related to two different elements. This is not a function.
The fourth relation has the input element 1 related to two different output elements in the pairs (1,0) and (1,2). Thus, this is not a function either.
The fifth relation is a function. No input element is related to more than one output element.
Summarizing the options to select are shown below.
The number 24 has eight factors in total.What are they
Answer:
The factors are 1,2,3,4,6,8, 12 and 24
Answer:
The factors of 24 are:
a. 1
b. 2
c. 3
d. 4
e. 6
f. 8
g. 12
h. 24
Step-by-step explanation:
A factor is a number that when added or multiplied to another number gives a \(GIVEN RESULT.\)
Maximize la función Z 2x + 3y sujeto a las condiciones x 24 y 25 (3x + 2y = 52
To solve this problem, we can use the method of Lagrange multipliers. This method allows us to find the maximum or minimum of a function subject to constraints.
In this case, the function we want to maximize is Z = 2x + 3y and the constraints are x = 24, y = 25, and 3x + 2y = 52.We begin by setting up the Lagrangian function, which is given by:L(x, y, λ) = Z - λ(3x + 2y - 52)where λ is the Lagrange multiplier. We then take the partial derivatives of the Lagrangian with respect to x, y, and λ and set them equal to zero.∂L/∂x = 2 - 3λ = 0∂L/∂y = 3 - 2λ = 0∂L/∂λ = 3x + 2y - 52 = 0Solving for λ, we get λ = 2/3 and λ = 3/2. However, only one of these values satisfies all three equations. Substituting λ = 2/3 into the first two equations gives x = 20 and y = 22. Substituting these values into the third equation confirms that they satisfy all three equations. Therefore, the maximum value of Z subject to the given constraints is Z = 2x + 3y = 2(20) + 3(22) = 84.
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The maximum value of Z = 2x + 3y, subject to the conditions x ≤ 24, y ≤ 25, and 3x + 2y = 52, is 96.
To maximize the function Z = 2x + 3y, subject to the conditions x ≤ 24, y ≤ 25, and 3x + 2y = 52, we will use the method of linear programming.
Let us first graph the equation 3x + 2y = 52.
The intercepts of the equation 3x + 2y = 52 are (0, 26) and (17.33, 0).
Since the feasible region is restricted by x ≤ 24 and y ≤ 25, we get the following graph.
We observe that the feasible region is bounded and consists of four vertices:
A(0, 26), B(8, 20), C(16, 13), and D(24, 0).
Next, we construct a table of values of Z = 2x + 3y for the vertices A, B, C, and D.
We observe that the maximum value of Z is 96, which occurs at the vertex B(8, 20).
Therefore, the maximum value of Z = 2x + 3y, subject to the conditions x ≤ 24, y ≤ 25, and 3x + 2y = 52, is 96.
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please help me for my homework
Answer:
49/100
Step-by-step explanation:
Answer:
Decimal Fraction Percentage
0.49 49/100 49%
PLEASE HELP!! BRAINLY ONLY ANSWER IF YOU KNOW CORRECT ANSWER THANKKYOUU <3
(!!) DO NOT REPOST OTHER UNRELATED QUESTIONS' ANSWERS PLEASE
Create an ER diagram using Chens notation with these facts:
- Each sport has different events, each event is only for one
sport.
- Events c
The ER diagram in Chen's notation for the given facts would include two entities: "Sport" and "Event." The relationship between the entities would be represented as a one-to-many relationship, where each sport can have multiple events, but each event is associated with only one sport.
In Chen's notation, entities are represented as rectangles, and relationships are represented as diamonds connected to the entities with lines. Based on the given facts, we would have two entities: "Sport" and "Event."
The "Sport" entity would have an attribute representing the name of the sport. The "Event" entity would have attributes such as the name of the event, date, location, and any other relevant information.
To represent the relationship between the entities, we would draw a line connecting the "Sport" entity to the "Event" entity with a diamond at the "Event" end. This indicates a one-to-many relationship, where each sport can have multiple events. The relationship line would have a crow's foot notation on the "Event" end, indicating that each event is associated with only one sport.
Overall, the ER diagram in Chen's notation would visually depict the relationship between sports and events, illustrating that each sport can have multiple events, but each event is specific to only one sport.
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sing income and working hour data, you get a regression mode with intercept -242.3, and slope 31.45. determine the predicted income if 22 hours were worked on an assembly job.
The predicted income for working 22 hours on an assembly job is $450.6 which is determined using the given regression model with intercept and slope values.
The intercept (-242.3) represents the predicted income when the number of working hours is zero, and the slope (31.45) represents the increase in income for each additional hour worked. To find the predicted income for 22 hours of work, we substitute 22 for the number of working hours in the regression model and solve for the predicted income.
Therefore, the predicted income for working 22 hours on an assembly job can be calculated as follows:
Predicted income = Intercept + (Slope x Number of working hours)
Predicted income = -242.3 + (31.45 x 22)
Predicted income = -242.3 + 692.9
Predicted income = 450.6
Thus, the predicted income for working 22 hours on an assembly job is $450.6.
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What is the missing reason in the two-column proof?
answer #4, choices provided
Answer:
AAS
Step-by-step explanation:
Since you already have 2 angles and one side proved, you would use the AAS (Angle Angle Side) Postulate.
In a group of bird-watchers, 4 out of every 5 people have seen a bald eagle. What percent of the bird-watchers have not seen a bald eagle
Answer:
20%
Step-by-step explanation:
4/5=.80
1-.80=.20
.20=20%
good afternoon just need a little help with this problem
Let 'h' represent the number of hours that Charles will work. Since he wants to work for at least six hours, then we have the following inequality:
\(6\le h\)but he also must work fewer than 16 hours this week, then the next inequality is:
\(h\le16\)then, combining the inequalities, we have:
\(6\le h\le16\)Consider the equation =2/3log10()−10.7 relating the moment magnitude of an earthquake and the energy (in ergs) released by it. If increases by 6, by what factor does the energy increase?
Answer:
The energy, 'E', increases by a factor of 1000,000,000
Step-by-step explanation:
The given equation relating moment magnitude of an earthquake and the energy (in ergs) released by it obtained from a similar question online is presented as follows; \(M_W = \dfrac{2}{3} \times log_{10} (E) - 10.7\)
Where;
\(M_W\) = The moment magnitude
E = The energy
If \(M_W\) is increased by 6, we have;
Δ\(M_W\) = 6
\(\Delta M_W = M_{W2} - M_{W1} = 6\)
From which we get;
\(\Delta M_W = M_{W2} - M_{W1} = 6 = \dfrac{2}{3} \times log_{10} (E_2) - 10.7 - \left(\dfrac{2}{3} \times log_{10} (E_1) - 10.7 \right)\)
\(6 = \dfrac{2}{3} \times log_{10} (E_1) - 10.7 - \left(\dfrac{2}{3} \times log_{10} (E_2) - 10.7 \right) = \left(\dfrac{2}{3} \right ) \times \left ( log_{10} (E_2) - log_{10} (E_1) \right)\)
\(6 = \left(\dfrac{2}{3} \right ) \times \left ( log_{10} (E_2) - log_{10} (E_1) \right) = \left(\dfrac{2}{3} \right ) \times log_{10} \left( \dfrac{E_2}{E_1} \right)\)
\(6 = \left(\dfrac{2}{3} \right ) \times log_{10} \left( \dfrac{E_2}{E_1} \right)\)
\(log_{10} \left( \dfrac{E_2}{E_1} \right) = 6 \times \left(\dfrac{3}{2} \right ) = 9\)
Therefore;
\(\dfrac{E_2}{E_1} = 10^9\)
E₂ = E₁ × 10⁹ = 1000,000,000 × E₁
Therefore, when the moment magnitude, \(M_W\), increases by 6, the energy increases by a factor of 1000,000,000
What is the value of y so that the equation is true?
y^2 = −49
a.7
b.-7
c.All real numbers.
d.No real numbers will make the equation true.
Answer:
D
Step-by-step explanation:
it cant be A or B becuase +7 × +7 = +49, -7 × -7 = +49. not all numbers will be squared and = -49
so it must be D
Answer:
d
Step-by-step explanation:
y² = - 49 ( take the square root of both sides )
y = ± \(\sqrt{-49}\)
The \(\sqrt{-49}\) is complex, then
no real values will make the equation true
You are looking for a new cell phone plan. The first company, Cellular-Tastic (f), charges a
monthly fee of $35 and $0.11 per minute of use. Dirt-Cheap Cell (g) charges a monthly fee
of $55 and $0.01 per minute of use.
1. How many minutes would you need to use for the cell phones to cost the same
amount?
Answer:
200 minutes
Step-by-step explanation:
Given that:
Cellular - Tastic (f) :
Monthly fee = $35
Per minute fee = $0.11
Dirt cheap call (g) :
Monthly fee = $55
Per minute fee = $0.01
How many minutes would you need to use for the cell phones to cost the same
amount?
Let number of minutes for cost to be equal = x
35 + 0.11x = 55 + 0.01x
Collect like terms
0.11x - 0.01x = 55 - 35
0.1x = 20
x = 20/0.1
x = 200
Hence, for cost to be the Same, 200 minutes must be used
The area of a rectangular park is 3/5 sq. mile
The length of the park is 7/8 mile.What is the width of the
park?
Answer:24/35
Answer:
3/5=7/8x
=24/35
(you literly put the answer why are u asking this???)
Hope This Helps!!!
What is v in this equation Tan (18)= 7/v.
v is approximately 21.56 in this equation Tan(18) = 7/v.
To solve for v in the equation
Tan(18) = 7/v, we need to isolate v on one side of the equation. We can do this by cross-multiplying, which gives us v * Tan(18) = 7.
To solve for v,
we can divide both sides of the equation by Tan(18): v = 7/Tan(18). Using a calculator, we can find the value of Tan(18) to be approximately 0.3249.
Plugging this value into the equation, we get v = 7/0.3249, which simplifies to v = 21.56 (rounded to two decimal places).
Therefore, v is approximately 21.56 in this equation Tan(18) = 7/v.
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Either Table A or Table B shows a proportional relationship.
Table A
x −2 −1 0 1
y 2 3 0 5
Table B
x −1 0 1 2
y −3 0 3 6
Plot the points from the table that shows a proportional relationship.
Answer:
the answer is table B
Step-by-step explanation:
Answer:
Table B shows a proportional relationship
Explanation:
In a proportional relationship two quantities vary directly with each other.
So,
y ∝ x
y = kx
Where, k is the constant of variation.
The ordered pairs of table A are (-2,2), (-1,3), (0,0) and (1,5).
From these ordered pairs we can conclude that the value of y-coordinate is not changing according to the x-coordinate because the values of x increased by 1 for each ordered pair but the value of y is not increasing in the same proportion..
The ordered pairs of table B are (-1,-3), (0,0), (1,3) and (2,6). The value of y increasing at a constant rate 3 and the value of y-coordinate is 3 times of x-coordinate.
Choose any two ordered pairs of table B. Let the two points are (0,0) and (1,3).
The proportional relationship is defined as
y = 3x
Therefore, 3 is the constant of variation and rate of change.
So, Table B shows a proportional relationship.
20 help pls ness help ASAP no links plssssssssss
Which of these functions could have the graph shown below?
it's the first one it's the f (x) =40x
NEED HELP IMMEDIATELY!
Simplify 10√2y + 5√2y + 3√2y.
A. 18√6y
B. 18√2y
C. 12√2y
D. 18√6y^3
(ANSWER IS NOT A)
18 root
2
Step-by-step explanation:
In this question imagine there is no y
It will be 10 root2 +5 root2 +3 root 2 it will be 18 root 2
The TL of 10 mm thick sheet of plywood at 1000 Hz is 34 dB. Based on the Mass Law, what is the expected TL:
a. At 63 Hz?
b. At 31 Hz for a 20 mm thick sheet?
The expected TL at 63 Hz is 28 dB and the expected TL at 31 Hz for a 20 mm thick sheet of plywood is 34 dB
a. The expected TL at 63 Hz can be calculated using the Mass Law formula TL = 20 log (Mf/Mi), where Mi and Mf are the initial and final masses, respectively.
Assuming the density of the plywood remains constant, the mass is proportional to the thickness,
so Mi/Mf = 10/20 = 0.5.
Substituting this into the formula, we get TL = 20 log 0.5 = -6 dB. Therefore, the expected TL at 63 Hz is 34 - 6 = 28 dB.
b. Using the same formula, we can find the expected TL at 31 Hz for a 20 mm thick sheet of plywood. Since the thickness has doubled, the mass has also doubled, so Mi/Mf = 1.
Substituting this into the formula, we get
TL = 20 log 1 = 0 dB.
Therefore, the expected TL at 31 Hz for a 20 mm thick sheet of plywood is 34 dB (the same as the TL for the 10 mm thick sheet at 1000 Hz).
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