a generator produces 44 mw m w of power and sends it to town at an rms voltage of 74 kv k v . part a what is the rms current in the transmission lines? express your answer in amperes.

The 0.0104 moles NO2 are reacted.

What is mole?

Chemists use the mole as a crucial unit of measurement. When you have a mole of something, you have 602,214,076,000,000,000,000,000 of that specific thing, just like when you have a dozen eggs, you have twelve eggs. Mole units are used by chemists to measure extremely small objects, such as atoms, molecules, or other particles.

What is concentration?

A solution's concentration is an indicator of how much solute has dissolved in a specific volume of solvent or solution. When there is a significant amount of dissolved solute in a solution, it is said to be "concentrated."

0.00520 moles

N2O5 x 4 moles NO2 / 2 moles

N2O5 = 0.0104 moles NO2 are reacted.

Therefore, the 0.0104 moles NO2 are reacted.

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The resulting equation of motion for the system is given by m × x''(t) + k × x(t) = f(t), which is 2 × x''(t) + 18 * x(t) = 2 * sin(2t).

What is  equation of motion?

The equations of motion are a set of mathematical relationships that describe the motion of objects under the influence of forces. There are different sets of equations of motion, depending on the specific scenario and the type of motion being considered (linear motion, projectile motion, circular motion, etc.). The equations of motion for linear motion, also known as the equations of uniformly accelerated motion.

To find the equation of motion for the system, we start with Newton's second law of motion, which states that the sum of forces acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the object is the 2-kg mass attached to the spring.

The force exerted by the spring is proportional to the displacement of the mass from its equilibrium position, and it can be expressed as F_spring = -k× x(t), where k is the spring constant and x(t) is the displacement of the mass at time t.

In addition to the force exerted by the spring, there is an external force f(t) = 2 ×sin(2t) acting on the mass.

Applying Newton's second law, we have the equation of motion: m ×x''(t) + k ×x(t) = f(t).

Substituting the given values, m = 2 kg and k = 18 N/m, we obtain 2 ×x''(t) + 18 × x(t) = 2 ×sin(2t).

Therefore, the resulting equation of motion for the system is 2 × x''(t) + 18 × x(t) = 2 × sin(2t).

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Answer:

B) below the plane and behind it.

Answer:

The current decreases.

Explanation:

Current and resistance are inversely proportional. The equation connecting current, resistance and voltage is \(V = IR\), where V is voltage, I is current and R is resistance.

Rearranging this equation, you get:

\(I = \frac{V}{R}\)

and

\(R = \frac{V}{I}\)

If the value of voltage in both equations remains constant, and the value of R decreases, the value of I will increase. Conversely, if in the second equation \(R = \frac{V}{I}\) , the value of V remains constant the value of I decreases, then the value of R, resistance will increase.

Thus, it can be seen that the current will decrease as resistance increases and vice versa.

The latitude and longitude coordinates for Location C are given as 50S, 68W. Therefore, the correct answer is 4) Cannot discern from the information provided.

Latitude and longitudinal lines are shown on a globe of Earth as parallel and vertical lines. To determine which distance is farther, we need to compare the distance between Location B and the Equator with the distance between Location C and the Equator.

However, the latitude and longitude coordinates for Location B and the specific direction or coordinates of the Equator are not provided. Without this information, it is not possible to determine which distance is farther between Location B and the Equator or Location C and the Equator.

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Answer:

\(m_B > m_A\)

the mass of body B must be greater than the mass of body A

Explanation:

Newton's second law establishes a linear relationship between the force, the mass of the body and its acceleration

        F = m a

        a = F / m

Let's analyze this expression tells us that the force is of equal magnitude for the two bodies, but body A goes faster than body B, this implies that it has more relationships

         a_A > a_B

         \(\frac{F}{m_A} > \frac{F}{m_B}\)

         \(m_B > m_A\)

Therefore, for this to happen, the mass of body B must be greater than the mass of body A

The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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The force on the clove will have the same magnitude but a negative sign with it that is F = - 14 N

The definition of force is: The pushing or pulling on a massed object changes its velocity. Force is an external agent that has the power to alter a body's resting or moving condition.

It has a size and a movement.

Newton's second law of motion defines the force formula as follows:

A force is equal to an object's mass times its acceleration, or F = m a. You must use SI units when applying this formula: kilograms for mass, meters per second squared for acceleration, and newtons for force.

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Answer:2.7 X 10₁₀W = 27 GW

Explanation:

W=1.4 X 10₁₃ J

ΔT=8.5 mins

P=W/ΔT=

1.4 x 10₁₃J/(8.5 mins)(60s/min)=2.7 x10₁₀W=27GW

The x-coordinate of the center of mass of the uneaten pizza above the x-axis is -1.5 in.

The x-coordinate of the center of mass of the uneaten pizza above the x-axis (second quadrant) can be found by taking the average of the x-coordinates of the points in that quadrant.

To find the x-coordinate of the center of mass, we need to determine the average x-coordinate of the uneaten pizza in the second quadrant.

In the given scenario, the center of mass of the partially eaten pizza is located at Xcm = -1.5 in. This means that the uneaten pizza in the second quadrant is symmetric with respect to the y-axis.

Since the uneaten pizza is symmetrical, the x-coordinate of the center of mass of the uneaten portion above the x-axis will also be -1.5 in. This is because the uneaten portion is evenly distributed in the second quadrant, resulting in an equal distribution of mass on both sides of the y-axis.

Therefore, the x-coordinate of the center of mass of the uneaten pizza above the x-axis is -1.5 in.

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The complete question is:

The location of the center of mass of the partially eaten, 12-inch diameter pizza shown in the figure (Figure 1) is Xcm = - 1.5 in

and Ycm = -1.5 in . Assuming each quadrant of the pizza to be the same, find the center of mass of the uneaten pizza above the x axis (that is, the portion of the pizza in the second quadrant). Find the x-coordinate.

the transverse Wave which is Answer:2

Answer:

1

Explanation:

amplitude is the maximum distance from the rest of the particles. amplitude is thus measured from the rest position to the peak of a crest or of a trough.

as seen below, graph 1 has an amplitude of 1 while both graph 2 and 3 has an amplitude of 2.

Answer: A Hydrothermal vent

Explanation:

Answer:

Thanos went *snap*

Explanation:

In conclusion, to calculate the recommended daily dosage of mercaptopurine for a child weighing 44 lb, we need to convert the weight to kilograms and then multiply it by the recommended initial dose. This results in a dosage of approximately 29.7 mg/day.

The recommended initial dose of mercaptopurine is 1.5 mg/kg/day p.o. To calculate the recommended daily dosage for a child weighing 44 lb, we need to convert the weight from pounds to kilograms.
First, we know that 1 lb is equal to approximately 0.45 kg. So, we can calculate the weight of the child in kilograms by multiplying 44 lb by 0.45 kg/lb.
44 lb * 0.45 kg/lb = 19.8 kg (rounded to one decimal place)
Now that we have the weight in kilograms, we can calculate the recommended daily dosage by multiplying the weight by the recommended initial dose of 1.5 mg/kg/day.
19.8 kg * 1.5 mg/kg/day = 29.7 mg/day (rounded to one decimal place)
Therefore, the recommended daily dosage for a child weighing 44 lb is approximately 29.7 mg/day.
In conclusion, to calculate the recommended daily dosage of mercaptopurine for a child weighing 44 lb, we need to convert the weight to kilograms and then multiply it by the recommended initial dose. This results in a dosage of approximately 29.7 mg/day.

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2. The primary reflection from the sand/mud interface will arrive first at the hydrophone. To determine which event arrives first, we need to calculate the two-way travel times (TWTT) for each event. The TWTT for the primary reflection from the sand/mud interface is:

TWTT = (2 × depth × sin (angle of incidence)) / velocity

TWTT = (2 × 509 × sin (9)) / 1478TWTT = 0.317 s

The TWTT for the double bounce off the seafloor is:TWTT = (2 × depth) / velocityTWTT = (2 × 509) / 1478TWTT = 0.689 s

Therefore, the primary reflection arrives first at the hydrophone. Here is a simple drawing of the two-event seismic trace:

3. To calculate the time it takes for energy to travel directly from the air gun to the first hydrophone, we need to determine the distance between them and divide it by the velocity of sound in seawater. Using the given values, we have:

Distance = depth + (thickness of sand/mud) + (thickness of mudstone)

Distance = 509 + 1003 + 373

Distance = 1885 m

Velocity of sound in seawater = 1478 m/s

Time = Distance / VelocityTime = 1885 / 1478Time = 1.276 s

Therefore, it takes 1.276 seconds for energy to travel directly from the air gun to the first hydrophone.

4. The maximum takeoff angle at which seismic energy can reflect from the sand/mud interface is called the critical angle. This angle can be calculated using Snell's law:

n1 × sin (angle of incidence) = n2 × sin (angle of refraction)

where n1 and n2 are the velocities of the two materials and the angle of refraction is 90 degrees (since seismic energy travels along a horizontal path once it reaches the interface).

For the sand/mud interface, the critical angle is:

n1 × sin (critical angle) = n2 × sin (90)n1 / n2 = cos (critical angle)critical angle = cos^-1 (n1 / n2)

Using the given values:

n1 = 2793 m/s (sandstone velocity)n2 = 2240 m/s (mudstone velocity)critical angle = cos^-1 (2793 / 2240)

critical angle = 35.9 degrees

Seismic energy cannot reflect from the sand/mud interface at angles greater than the critical angle. For larger angles, the energy will be transmitted into the mudstone.

5. When seismic energy is transmitted into the mudstone, it travels in all directions away from the source. However, the energy will be attenuated (reduced in amplitude) as it travels through the mudstone due to its relatively low velocity compared to the sandstone and seawater.

As a result, the mudstone acts as a barrier that blocks or reduces the energy that would otherwise be transmitted deeper into the subsurface.

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Answer:

See below.

Explanation:

The difference between these two is that a wave is a disturbance of some quantity in space or intermediate while a particle has a definite mass concentrated on a small area.

The mass of kerosene needed to boil 5 liters of water at 10°C is approximately 28070 kg.

To determine how much kerosene is needed to boil 5 liters of water at 10°C, we must first determine how much heat is needed to bring the water's temperature up to 100°C and then boil it at that degree.

Heating water from 10°C to 100°C:

4.186 J/g°C (or 4.186 kJ/kg°C) is the specific heat capacity of water. As a result, J is the quantity of heat needed to raise the temperature of 5 liters (or 5000 grams) of water from 10°C to 100°C is:

Q1 = m x c x ΔT

= 5000 g x 4.186 J/g°C x (100°C - 10°C)

= 1952200 J

Water vaporizes at a heat of 2260 kJ/kg (or 2.26 × 106 J/kg) at 100 °C when it is heated to boiling. To boil 5 liters (or 5000 grams) of water at 100°C, the following amount of heat is needed:

Q2 = m x L

= 5000 g x 2.26 x 10^6 J/kg

= 1.13 x 10^10 J

To heat and boil the water, the following amount of heat is needed:

Qtot = Q1 + Q2

= 1952200 J + 1.13 x 10^10 J

= 1.149522 x 10^10 J

Where m is kerosene's mass, c is kerosene's specific heat capacity (4.6 kJ/kg°C), and ΔT is the temperature change of the kerosene.

Assuming that the initial temperature of the kerosene is also 10°C, the temperature change of the kerosene is:

ΔT = 100°C - 10°C

     = 90°C

Substituting the values into the equation, we get:

1.149522 x 10^10 J = m x 4.6 kJ/kg°C x 90°C

Solving for m, we get:

m = 28069.6 kg

Hence, 28070 kg of kerosene is required to boil 5 liters of water at 10°C.

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Inelastic collision and a host of other factors causes the loss of energy.

Kinetic energy of an object is the energy that it possesses due to motion.

It can be defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. When it has gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.

In an inelastic collision which is the case of ball X and Y, the kinetic energy of the system is not conserved. The energy that you find lost has been dissipated as other forms of energy. This can be heat, friction, vibrational energy transferred to atoms of the colliding particles, energy lost to deform the atomic structure etc.

In conclusion, the inelastic collision nature of the two balls results in the loss of energy through different forms.

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The momentum flow rate through the pipe carrying liquid ammonia is 1 × \(10^6\) kg·m/s.

The flow rate of momentum (Ṁ) through the pipe can be calculated by multiplying the mass flow rate (ṁ) by the velocity (v). The speed can be determined using the equation v = ṁ / (ρA), where ρ is the density of the liquid ammonia and A is the pipe's cross-sectional area.

Given:

ṁ = 100 kg/s

A = 0.01 m²

Assuming the density (ρ) of liquid ammonia is 700 kg/m³, we can calculate the velocity (v):

v = ṁ / (ρA)

v = 100 kg/s / (700 kg/m³ × 0.01 m²)

v = 10000 m/s

Now, we can calculate the flow rate of momentum (Ṁ):

Ṁ = ṁv

Ṁ = 100 kg/s × 10000 m/s

Ṁ = 1 × \(10^6\) kg·m/s

Therefore, the momentum flow rate through the pipe is 1 × \(10^6\) kg·m/s.

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The sound intensity level (SIL) is a measure of the intensity of sound waves that reach the ear and is measured in decibels (dB).Therefore, the difference in sound intensity levels heard by the father and mother is about 21 db. (74 dB - 53 dB). This means that the father hears a sound that is about 120 times louder than the mother.

The answer the question, we need to know the distance from the baby's mouth to each parent's ear, as well as the intensity of the sound produced by the baby's mouth. Let's assume that the baby's mouth produces a sound of 60 dB at a distance of 30 cm and that the sound intensity decreases as the distance increases according to the inverse square law. Using this law, we can calculate that at a distance of 1.50 m, the sound intensity would be about 33 db. Now, to calculate the difference in sound intensity levels heard by the father and mother, we need to take into account their respective distances from the baby's mouth. Using the inverse square law again, we can calculate that the sound intensity level heard by the father would be about 74 db., while the sound intensity level heard by the mother would be about 53 db. Therefore, the difference in sound intensity levels heard by the father and mother is about 21 db. (74 dB - 53 dB). This means that the father hears a sound that is about 120 times louder than the mother.

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The linear velocity of the hamster's wheel is calculated to be as approximately 3.8 inches/second. The formula for linear velocity is Circumference ÷ time.

A hamster runs in its wheel whose radius is 3 inches. The wheel completes 6.3 revolutions in 5 seconds. We need to calculate the linear velocity of the hamster's wheel. 

The hamster's wheel completes 6.3 revolutions in 5 seconds.

The circumference of the wheel of the hamster can be calculated by using the formula,

C = 2πr, Where r is the radius of the wheel.

Circumference C = 2π × 3

= 6π inch

Linear velocity is given by the formula,

Linear velocity = Circumference ÷ time

= 6π ÷ 5

= 1.2π inch/second

= 3.76991115 inch/second

≈ 3.8 inches/second

Therefore, the linear velocity of the hamster's wheel is approximately 3.8 inches/second.

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Answer: Insulators if i'm correct.

Explanation:

Answer:

164

Explanation:

The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus. The number of neutrons is equal to the difference between the mass number of the atom (M) and the atomic number (Z).

Neutrons: 90

Mass number?

Atomic number of Tungsten: 74

90 + 74 = 164

When two different wires with identical cross-sectional areas carry the same current, the drift velocity will be lower in the better conductor.

To understand this, let's look at the drift velocity equation:
vd = I / (nAe)
In this equation, vd represents the drift velocity,

I is the current,

n is the number density of free electrons,

A is the cross-sectional area, and e is the charge of an electron.
Since the wires have the same cross-sectional areas (A)

and carry the same current (I),

we can focus on the number density of free electrons (n).

A better conductor has a higher number density of free electrons, meaning there are more free electrons available to carry the charge.

This is one of the main factors contributing to the increased conductivity of the better conductor.
Now, let's examine the equation again.

If n is higher in the better conductor, then the value of the fraction I / (nAe) will be smaller.

This means that the drift velocity (vd) will be lower in the better conductor.
In summary, the drift velocity is lower in the better conductor due to its higher number density of free electrons, which allows for more efficient charge transfer without the need for high drift velocities.

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Answer:

75 seconds.

Explanation:

4x = 300

4x/4 = 300/4

x = 75 seconds.

Answer:

Earth's magnetic field serves to deflect most of the solar wind, whose charged particles would otherwise strip away the ozone layer that protects the Earth from harmful ultraviolet radiation.

Answer:

Earth's magnetic field serves to deflect most of the solar wind,

whose charged particles would otherwise strip away the ozone layer that

protects the Earth from harmful ultraviolet radiation.