When a fluid flows through a cylindrical pipe and the radius of the pipe is increased by a factor of 2 while the volumetric current remains the same, the speed of the fluid decreases by a factor of 2. The correct option is (b).
Here's a step-by-step explanation:
1. The volumetric flow rate (Q) can be calculated using the formula: Q = A * v, where A is the cross-sectional area of the pipe, and v is the speed of the fluid.
2. The cross-sectional area of a cylindrical pipe can be calculated using the formula: A = π * r², where r is the radius of the pipe.
3. If the radius of the pipe is increased by a factor of 2, the new radius is 2r, and the new cross-sectional area (A') can be calculated as: A' = π * (2r)² = 4 * π * r².
4. As the volumetric current remains the same, Q = A * v = A' * v', where v' is the new speed of the fluid.
5. Substituting the values of A and A' in the equation: π * r² * v = 4 * π * r² * v'.
6. Cancelling out the common terms, we get: v = 2 * v'.
7. Therefore, the new speed of the fluid (v') is half of the original speed, indicating that the speed decreases by a factor of 2.
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If a bicyclist travels at 15 km/hr, how long will it take her to travel 30 km?
Answer:
The answer is 2 hoursExplanation:
To find how long it took we use the formula
\(t = \frac{d}{v} \\ \)
d is the distance
v is the velocity
From the question we have
\(t = \frac{30}{15} \\ \)
We have the final answer as
2 hoursHope this helps you
For transmissivity (T) = 2500 m2/day, storativity (S) = 1.0 x 10-3, and a pumping rate
(Q) = 500 m3/day, calculate drawdowns in a confined aquifer (isotropic, homogeneous, transient
condition) at observation wells located (i) 10 m and (ii) 50 m at t = 150
Answer:
The drawdown in a confined aquifer under transient conditions can be estimated using the Theis solution for the non-equilibrium radial flow of water. This solution is given by:
s = Q / (4πT) * W(u),
where s is the drawdown, Q is the pumping rate, T is the transmissivity, and W(u) is the well function (also called the Theis function) which depends on the variable u, where:
u = r²S / (4Tt),
where r is the distance from the pumping well and t is the time since pumping began.
Given T = 2500 m²/day, S = 1.0 x 10-3, and Q = 500 m³/day, we can calculate the drawdown at 10 m (r1 = 10 m) and 50 m (r2 = 50 m) for t = 150 days.
For (i) r1 = 10 m:
u1 = r1²S / (4Tt) = (10 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.000667
s1 = Q / (4πT) * W(u1) = 500 m³/day / (4π * 2500 m²/day) * W(0.000667).
For (ii) r2 = 50 m:
u2 = r2²S / (4Tt) = (50 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.01667
s2 = Q / (4πT) * W(u2) = 500 m³/day / (4π * 2500 m²/day) * W(0.01667).
Explanation:
Unfortunately, the well function W(u) cannot be evaluated directly without more specialized knowledge or tools. The well function is related to the exponential integral function, which requires numerical computation. You would typically use a table of values, a calculator with this function, or a computer program to evaluate it. After obtaining W(u), multiply it by the remaining fraction to find the drawdowns.
A rock is thrown horizontally off a cliff with an initial velocity of 15 m/s. How high was the cliff if the rock lands 22 m from the base of the cliff?
Answer:
22 m
Explanation:
Answer:
cliff height = 10.55 m
Explanation:
Remarks
This is one of those questions that defies belief. The final vertical velocity is the same as if you just dropped the rock, which is amazing.Another amazing fact is that the horizontal speed has no acceleration. And amazing fact number three is the the vertical initial speed is 0.And finally, the time taken to go horizontally = time to go vertically.Solution
Time
So the time taken is d = r * t
Remember, this formula can only be used when there is no acceleration.
d = 22 meters
r = 15 m/s
t = ?
t = d / r
t = 22 / 15
t = 1.467
Height of the Cliff
vi = 0 (vertially)
a = 9.8 m/s^2
t = 1.467 seconds The time horizontally and vertically is the same.
d = ?
Formula
d = vi*t + 1/2 a t^2
Solution
d = 0 + 1/2 * 9.8 * 1.467^2
d = 10.55 meters.
eyeglass lenses can be coated on the inner surfaces to reduce the reflection of stray light to the eye. if the lenses are medium flint glass of refractive index 1.62 and the coat- ing is fluorite of refractive index 1.432, (at) what minimum thickness of film is needed on the lenses to cancel light of wavelength 550 nm reflected toward the eye at normal incidence? (b) will any other wave- lengths of visible light be cancelled or enhanced in the reflected light?
The minimum thickness of the film needed to cancel light of wavelength 550 nm reflected toward the eye at normal incidence is zero. No other wavelengths of visible light will be cancelled or enhanced in the reflected light.
To determine the minimum thickness of the film needed to cancel light of wavelength 550 nm reflected toward the eye at normal incidence, we can use the concept of interference in thin films.
For constructive interference to occur and cancel the reflected light, the phase difference between the light waves reflected from the top and bottom surfaces of the film should be an integer multiple of the wavelength.
The condition for constructive interference in a thin film is given by:
2nt = mλ
Where:
n = refractive index of the film
t = thickness of the film
m = integer representing the order of the interference (m = 0 for the first minimum)
λ = wavelength of the incident light
In this case, the incident light is traveling from the medium flint glass (refractive index 1.62) to the fluorite coating (refractive index 1.432).
For the first minimum (m = 0), the phase difference should be zero. Thus, the thickness of the film (t) should satisfy:
2nt = 0
Since the refractive index of the film is less than the refractive index of the medium flint glass, we can assume the film is thinner than a wavelength of light. Therefore, we can disregard the higher-order interference effects.
Now we can solve for the minimum thickness of the film (t) using the equation:
2nt = 0
t = 0 / (2n)
t = 0
The minimum thickness of the film needed to cancel light of wavelength 550 nm reflected toward the eye at normal incidence is zero.
(b) Since the minimum thickness of the film is zero, no other wavelengths of visible light will be cancelled or enhanced in the reflected light.
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how to make 3d soft body objects interact pressing against the surface of each other increase friction
The way to make 3d soft body objects interact pressing against the surface of each other increase friction is given below
How do you bring about the friction?The way to make 3d soft body objects interact pressing against the surface of each other increase friction is by:
In your 3D modeling or animation software, select the objects that you want to be soft bodies.In the properties or settings for the objects, enable the "soft body" option. This will allow the objects to deform and interact with each other in a more realistic way.In the soft body settings, increase the friction coefficient between the objects. This will make it so that the objects resist sliding against each other more when they press against each other.You can also adjust the stiffness of the objects to control how much they deform when they press against each other. Increasing the stiffness will make the objects less deformable, while decreasing the stiffness will make them more deformable.Finally, you can use the simulation settings to control how the objects interact with each other and with the environment. For example, you can increase the strength of the gravity force to make the objects more prone to pressing against each other, or you can add forces such as wind or explosions to make the objects interact in more dynamic ways. These steps should help you create more realistic and interactive soft body objects in your 3D models or animations.Learn more about friction from
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land controlled by the lord of the manor is called
Answer: The whole of it was owned originally by the lord of the manor. He lived in the big house called the manor house. Attached to it were many acres of grassland and woodlands called the park. These were the "demesne lands" which were for the personal use of the lord of the manor.
The lord of the manor previously owned the entire property. He resided in the substantial home known as the manor house.
Thus, The park, which covered many acres of grassland and trees, was connected to it. These "demesne lands" belonged to the lord of the manor and were used exclusively for his exclusive purposes.
The word "manor" is derived from the Old French word "manoir," which means "dwelling place," but a manor isn't just any old house.
The homes and grounds of the nobility were referred to as manors back when people still had titles of nobility. expressing to someone that his home is a manor is the equivalent of expressing that it is so lavish and beautiful that it could have belonged to a lord.
Thus, The lord of the manor previously owned the entire property. He resided in the substantial home known as the manor house.
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A ball is projected at an angle of elevation of 60 ° with an initial velocity of 120m/s.calculate
1) The time taken to get to the maximum height
ii) the time of flight
Explanation:
It is given that,
The angle of projection is 60 degrees
Initial velocity of the ball is 120 m/s
We need to find the time taken to get to the maximum height and the time of flight.
Time taken to reach the maximum height is given by :
\(T=\dfrac{u^2\sin^2\theta}{2g}\)
g is acceleration due to gravity
\(T=\dfrac{(120)^2\times \sin^2(60)}{2\times 10}\\\\T=540\ s\)
(ii) Time of flight,
\(t=\dfrac{2u\sin\theta}{g}\)
So,
\(t=\dfrac{2\times 120\times \sin(60)}{10}\\\\t=20.78\ s\)
Hence, this is the required solution.
When an object moves, stops moving, changes speed, or changes direction, how do scientists describe that condition? Question 10 options: A balanced set of forces Unbalanced forces Frictional forces Stability factors.
The force applied in one direction is higher than the force applied in the opposing direction, resulting in imbalanced forces. Unbalanced force is that force shows the condition when an object moves, changes speed or changes direction.
What is an unbalanced force?The force applied in one direction is higher than the force applied in the opposing direction, resulting in imbalanced forces.
There is a shift in speed and/or direction when unbalanced forces occur on an item. You can affect the motion of an object by exerting an imbalanced force.
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the air leaves the balloon in one direction; the car moves in the opposite direction. This balloon car illustrates for action, there is an equal and opposite reaction or?
Answer:
Newtons 3rd law
Explanation:
according to our textbook, roughly what percent of the mass and energy contents of the universe is made up of dark matter plus dark energy?
It turns out that dark energy makes up about 68% of the universe.About 27% of matter is dark matter.Less than 5% of the universe is made up of everything else, including everything that has ever been observed by all of our sensors and all regular matter.
How much dark matter makes up the entire universe? It turns out that dark energy makes up about 68% of the universe.About 27% of matter is dark matter.Less than 5% of the universe is made up of everything else, including everything that has ever been observed by all of our sensors and all regular matter.Dark matter, which makes up about 27% of the cosmos, appears to outnumber visible matter by a factor of nearly six to one.A sobering fact is this:Only 5% of the universe is made up of the known matter, which is what gives rise to all of the stars and galaxies.According to the most recent calculations, the universe is composed of 73% dark energy, 23% dark matter, and 4% normal baryonic matter.To learn more about dark energy refer
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William took a 7 hour bicycle trip. In all, he traveled 112 miles. What was his average rate of speed in miles per hour?
Answer:
16 miles
Explanation:
112 miles/ 7 hours= 16 miles per hour
The distance between Carol's house and her uncle's house is 24 km. What is her speed in kilometers per hour in order to get to her uncles house in 40 minutes by motorcycle.
Carol's speed in kilometers per hour in order to get to her uncles house in 40 minutes by motorcycle is 36km/hr.
How to calculate average speed?The average speed of a moving body can be calculated by dividing the distance moved by the time taken.
According to this question, the distance between Carol's house and her uncle's house is 24 km. The speed it will take her to get to her uncle's house in 40 minutes by motorcycle is as follows:
Average speed = 24km ÷ 40/60 hour
Average speed = 36km/hr
Therefore, Carol's speed in kilometers per hour in order to get to her uncles house in 40 minutes by motorcycle is 36km/hr.
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A 23-N force is applied to a 7-kg object to move it with a constant velocity of 6.1 m/s across a level surface. The coefficient of friction between the object and the surface is approximately ____. Round your answer to the hundredths place.(Use the approximation g ≈ 10 m/s2.)
Given:
The applied force is F = 23 N
The mass of the object is m = 7 kg
The object moves with a constant velocity of v = 6.1 m/s
The acceleration due to gravity is g = 10 m/s^2
Required: The coefficient of friction between the object and the surface.
Explanation:
The object moves at a constant velocity, so the acceleration will be zero.
The equation of motion can be written as
\(\begin{gathered} F-f\text{ = ma} \\ F-f\text{ =m}\times0 \\ F-f=0 \\ F=f \end{gathered}\)So, the applied force will be equal to the frictional force.
The coefficient of friction can be calculated as
\(\begin{gathered} F\text{ = }\mu mg \\ \mu=\frac{F}{mg} \end{gathered}\)On substituting the values, the coefficient of friction will be
\(\begin{gathered} \mu=\frac{23}{7\times10} \\ =\text{ 0.33} \end{gathered}\)Thus, the coefficient of friction is 0.33
Final Answer: The coefficient of friction between the object and the surface is 0.33.
Can a compass provide the evidence we need
Answer:
answer
Explanation:
A compass is a device that indicates direction. It is one of the most important instruments for navigation. This compass was used by Robert Peary to reach the North Pole, allegedly the first person to do so. A compass is a device that indicates direction
Which element most likely interacts with water the same way lithium interacts with water?
Answer:
Is there a multiple choice or select all that apply? I would say Potassium (K) or Sodium (Na)
Explanation:
what is the derived relationship between molar mass and delta t
The relationship between molar mass and delta t (Δt) is derived from the colligative properties of solutions. Colligative properties are those properties that depend on the number of solute particles in a given volume of solution, regardless of the type of solute particles.
One of the colligative properties is the freezing point depression, which is the difference between the freezing point of a pure solvent and the freezing point of a solution containing a solute. The freezing point depression is directly proportional to the molality (moles of solute per kilogram of solvent) of the solution, and inversely proportional to the molar mass of the solute. This can be mathematically expressed as Δt = Kf * m * (1/M), where Δt is the freezing point depression, Kf is the freezing point depression constant, m is the molality of the solution, and M is the molar mass of the solute. Therefore, as the molar mass of the solute increases, the freezing point depression decreases, and vice versa. This relationship can be useful in determining the molar mass of an unknown solute in a solution.
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a store owner plans to hang a sign weighing 750 n so that cable a, attached to the store, makes a 30.0 degree angle to the vertical side of the building. cable b is horizontal and attached to an adjoining building. what is the tension in cable b?
A remains constant, the tension in cable B can be calculated using the formula T = W/sin(θ), where T is the tension, W is the weight of the sign, and θ is the angle formed by cable A. the tension in cable B is 750N/sin(30°) = 1333.38N.
what is cable ?
Cable is a type of wiring system used to transmit electrical signals. It consists of insulated conductors, usually copper, twisted together in a pattern that reduces interference from external sources. Cables are often used to connect components within a system, such as computers, televisions, and audio systems.
They can also be used to connect systems to each other, such as connecting a laptop to a router or connecting a router to a modem. Cables can be used to carry data as well as power. Depending on the type of cable, it can support various types of data transfer speeds and resolutions. For example, HDMI cables are used to transmit audio and video signals in high-definition.
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is
A 0.155 kg arrow is shot upward
at 31.4 m/s. What is its kinetic
energy (KE) when it is 30.0 m
above the ground?
Kinetic energy = 29.912 J
Further explanationGiven
mass = 0.155 kg
vo=initial velocity = 31.4 m/s
h/d=30 m
Required
KE=kinetic energy
Solution
vt²=vo²-2ad⇒vt=final velocity
vt²=31.4²-2.10.30⇒g=10 m/s²
vt²=985.96-600
vt²=385.96 m/s
Kinetic energy (KE)
\(\tt KE=\dfrac{1}{2}mv^2\\\\KE=\dfrac{1}{2}\times 0.155.\times 385.96\\\\KE=29.912~J\)
Answer:
The answer is 30.8 (J)
Explanation:
You're welcome
Jack and jill travel up a hill at a speed of 2 mi/h. they travel back down the hill at a speed of 4 mi/h. what is their average speed for the entire trip? express your answer as a mixed number.
Jack and jill travel up a hill at a speed of 2 mi/h. They travel back down the hill at a speed of 4 mi/h. Their average speed for the entire trip is 8/3 mi/h
The average speed is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity
Let x be the distance of hill from one side.
⇒ Distance for round trip = 2x
Let t1 and t2 be the time taken by them when going and returning back respectively.
Total time taken for round trip = t1+ t2
we have,
speed = distance/ time
⇒time = distance/speed
so, t1 = x/2
t2= x/4
Average speed for round trip = total distance/ total time
\(average speed = \frac{2x}{ \frac{x}{2} + \frac{x}{4} } \)
= 8/3 mi/h
therefore, Their average speed for the entire trip is 8/3 mi/h.
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in the qualifying round of the 50-yd freestyle in the sectional swimming championship, susan got an early lead by finishing the first 25.00 yd in 10.01 seconds. susan finished the return leg (25.00 yd distance) in 10.22 seconds. determine susan's average velocity for the entire race.
Susan's average velocity for the entire race was 2.47 yards per second.
To find Susan's average velocity for the entire race, we need to know the total distance and the total time taken. The total distance is 50 yards, and the total time taken is the sum of the time taken for each leg of the race:
Total time = 10.01 s + 10.22 s = 20.23 s
To find the average velocity, we divide the total distance by the total time:
Average velocity = total distance / total time
Average velocity = 50 yd / 20.23 s
Average velocity = 2.47 yd/s
Note that we could also convert this to other units of velocity, such as meters per second or miles per hour, if desired.
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10
A5 kilogram gun fires a 0.02 bullet with a velocity of 380 m/s. What is the recoil velocity of the gun?
A) - 1900 m/s
B - 1.5 m/s
C -7.6 m/s
D - 0.1 m/s
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1. A charged particle moves from one point to another. What is the connection between the change in potential energy of the particle and the change in electric potential? A. The change in electric potential equals the change in potential energy. B. The change in electric potential is twice the change in potential energy. C. The change in electric potential is the change in potential energy times the charge D. The change in electric potential is the change in potential energy divided by the charge.
The connection between the change in potential energy of the particle and the change in electric potential is defined as "the change in electric potential is the change in potential energy divided by the charge". So, the correct answer is D.
The electric potential at a point in an electric field is defined as the electric potential energy per unit charge at that point. Therefore, the change in electric potential between two points is equal to the change in electric potential energy divided by the charge of the particle that is moving between those points.
As the charged particle moves from one point to another, its potential energy changes due to the work done by the electric field on the particle. The change in potential energy of the particle is equal to the work done by the electric field on the particle. Therefore, the change in potential energy divided by the charge of the particle is equal to the change in electric potential.
In summary, the change in electric potential between two points is equal to the change in potential energy divided by the charge of the particle that is moving between those points. Therefore, the correct answer is D - "The change in electric potential is the change in potential energy divided by the charge".
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which layer in a zigbee device is responsible for detecting the presence of an rf signal in the currently selected channel?
In a Zigbee device, the layer responsible for detecting the presence of an RF (Radio Frequency) signal in the currently selected channel is the Physical Layer (PHY).
The PHY layer in Zigbee is responsible for managing the transmission and reception of RF signals. It handles functions such as channel selection, modulation, demodulation, and signal detection. When a Zigbee device is operating in a specific channel, the PHY layer continuously monitors that channel for incoming RF signals. It performs energy detection, which involves measuring the power level of the received signal. By analyzing the received signal strength, the PHY layer can detect the presence of an RF signal in the selected channel.
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A ball is kicked at an angel of 37° to a goalkeeper who is 24m away. What was the initial velocity of the ball?
The initial velocity of the ball when it was projected is 15.64 m/s.
The given parameters:
Angle of the projection, θ = 37⁰The range of the projectile, R = 24 mThe initial velocity of the ball is calculated by applying formula for range of projectile as follows;
\(R = \frac{u^2 sin(2\theta)}{g} \\\\u^2 = \frac{Rg}{sin(2\theta)} \\\\u = \sqrt{\frac{Rg}{sin(2\theta)} } \\\\u =\sqrt{\frac{24 \times 9.8}{sin(2\times 37)} } \\\\u = 15.64 \ m/s\)
Thus, the initial velocity of the ball when it was projected is 15.64 m/s.
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Derive an expression for vo in terms of v1 and v2. Assume that R1 = 9 kΩ, R2 = 40 kΩ, R3 = 18 kΩ, gain = 5, and R4 = (gain-1)*R3 kΩ.
vo = ( ) v1 + ( ) v2
vo = (72/49)v1 + (180/49)v2
This is the final expression for vo in terms of v1 and v2, with all given values plugged in.
To derive an expression for vo in terms of v1 and v2, we can use the voltage divider rule. The voltage at the junction of R2 and R3 is given by v2(R3/(R2+R3)). This voltage is multiplied by the gain of 5, resulting in 5v2(R3/(R2+R3)). This voltage is then divided by R4, which is (5-1)*18 kΩ = 72 kΩ. The resulting voltage is added to v1(R1/(R1+R2)), which is the voltage at the junction of R1 and R2. Therefore, the expression for vo in terms of v1 and v2 is:
vo = (R4/(R1+R2))v1 + (5R3/(R2+R3)R4)v2
Simplifying the expression, we get:
vo = (72/49)v1 + (180/49)v2
This is the final expression for vo in terms of v1 and v2, with all given values plugged in.
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A ball is thrown horizontally at a height of 1.6 metres above the ground, with initialspeed 14 m s^-1a)Find the time of flight of the ball, giving the answer as a fraction.b)Find the range of the ball.
Given:
The initial height of the ball, h=1.6 m
The initial speed of the ball, u=14 m/s
To find:
a) The time of flight of the ball.
b) The range of the ball.
Explanation:
As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.
Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.
The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.
a)
From the equation of motion,
\(h=u_yt+\frac{1}{2}gt^2\)Where g is the acceleration due to gravity and t is the time of flight of the ball.
On substituting the known values,
\(\begin{gathered} 1.6=0+\frac{1}{2}\times9.8\times t^2 \\ \implies t=\sqrt{\frac{2\times1.6}{9.8}} \\ =0.57\text{ s} \end{gathered}\)b)
The range of the ball is given by,
\(R=u_xt\)On substituting the known values,
\(\begin{gathered} R=14\times0.57 \\ =7.98\text{ m} \end{gathered}\)Final answer:
a) The time of flight of the ball is 0.57 s
b) The range of the ball is 7.98 m
Batteries are an example of an ___________________ in an electric circuit .
Answer:
Batteries are an example of an electrochemical device in an electric circuit.
21) Y=2+3 solve for y
Answer:
This must be harder than it appears or I'm missing something, but as far as I know y=5
Explanation:
In Material Science, If The Material Is Linearly Elastic, The Stress And Strain Are Directly Related To The Equation Below: E=Εσ
As long as the applied stress is removed, a material that is linearly elastic experiences stress and strain that are directly proportional within the elastic limit.
In a material that is linearly elastic, the Young's modulus (E), stress, and strain are all related by the equation you supplied, E =. Here is a quick definition of each phrase:
(E) Young's modulus It is a way to gauge how hard or stiff a material is. Within the elastic limit of the material, it indicates the stress to strain ratio. The stiffer the material, the higher the Young's modulus.
Stress (): The force exerted to a material's surface area is called stress. The internal resistance of a material to deformation under an applied force is measured by stress.
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an object 5 cm in size is placed at 30 cm in front of a concave mirror of focal length 45 CM at what distance from the mirror should a screen be placed in order to obtain a shop image find the magnification size and nature of the image
Answer: Given: h₀=5cm
p=30cm
hi
f=45cm
require: q=?
hi=?
formulas:
1/f=1/p+1/q
hi/h₀=q/p
calculations:1/q=1/f-1/p
1/q=1/45-1/30
1/q=0.022=0.033
1/q= = -0.011
q=1/-0.011
q= -90.91cm
hi=p × h₀/q
hi=30ₓ5/-90.91
hi=150/-90.91
hi= -1.65cm
image is virtual , erect and diminished
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