A fair coin is tossed three times in a row. What is the probability of getting two tails in a row?

A.0.125

B.0.375

C.0.625

D.0.875

= 70% of the flowers are carnations

Probability tells you which outcome is more likely to occur in any given event. You could determine the probability of the particular outcome by dividing the number of times that the outcome has occurred by the total no of events.

we are given that,

6/10 = 3/5 of the flowers are pink, do

we know .2/5 of the flowers are red .

Since 1/3 of the pink flowers are roses, 2/3 of

the pink flowers are on Carnations .

we are given that 2/4 of the red

flowers are carnations .

The number carnations are

\(\frac{3}{5} * \frac{2}{3} + \frac{2}{5} * \frac{3}{4}\)

\(=\frac{2}{5} +\frac{3}{10}\)

\(= \frac{4 + 3}{10}\)

\(=\frac{7}{10}\)

covert into percent

\(=\frac{7}{10} 100\)

= 70%

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No Its SAS - Hope it helps

Step-by-step explanation:

Waterway Industries made cash payments of $124,130,000 for income taxes during 2022.

To determine the cash payments made for income taxes during 2022, we need to consider the change in income taxes payable from the beginning to the end of the year. The change in income taxes payable represents the net increase or decrease in the amount owed to tax authorities. In this case, the income taxes payable at the beginning of the year (December 31, 2021) was $313,010,000, and the income taxes payable at the end of the year (December 31, 2022) was $596,640,000. Therefore, the change in income taxes payable is calculated as follows:

Change in income taxes payable = Income taxes payable at December 31, 2022 - Income taxes payable at December 31, 2021

= $596,640,000 - $313,010,000

= $283,630,000

The change in income taxes payable represents the amount of income taxes that were paid during 2022. Thus, Waterway Industries made cash payments of $283,630,000 for income taxes during the year.

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Answer:

Solution given:

radius of a circle [r]=6ft=2yards

now

area of a circle =πr²=3.14*2²=12.56yard²

Area =12.56yard²

The 90% confidence interval of the new product has the potential to make the company an additional $3.8 million is (2.81, 4.79), option B.

Confidence intervals quantify how confident or uncertain a sampling technique is. They can take any number of probability thresholds, with a 95% or 99% confidence level being the most popular. The calculation of confidence intervals is done using statistical techniques like the t-test.

\(\bar x = $3.8\)

sample standard deviation = s =1.7

sample size = n =10

Degrees of freedom = df = n - 1 = 10 - 1 = 9

At 90% confidence level

\(\alpha\) = 1 - 90%

\(\alpha\) =1 - 0.90 =0.1

\(\alpha/2\) = 0.05

\(t\alpha/2\) ,df = t0.05,9 =1.833

At 90% confidence level, the critical value is t = 1.833

The 90% confidence interval is:

\(\bar x \pm t*\frac{s}{\sqrt{n} }\)

\(=3.8\pm 1.833*\frac{1.7}{\sqrt{10}}\\\\=3.8\pm 0.99\)

=(2.81,4.79).

Therefore, 90% confidence interval estimate of the population mean is, (2.81,4.79).

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Complete question:

Market research indicates that a new product has the potential to make the company an additional $3.8 million, with a standard deviation of $1.7 million. If this estimate was based on a sample of 10 customers, what would be the 90% confidence interval? (2.76, 4.84) O (2.81, 4.79) (2.11, 5.56) (3.06, 4.54)

1. The percentage of CEOs who are 59 years or younger: 57.5% 2. The relative frequency for ages 65 to 69: 0.1096 3. The cumulative frequency for CEOs over 55 years in age: 51

To answer these questions, we need to calculate the total number of CEOs and perform some calculations based on the given data. Let's proceed step by step:

Step 1: Calculate the total number of CEOs.

The total number of CEOs is the sum of the frequencies for each age group:

Total CEOs = 4 + 3 + 15 + 20 + 21 + 8 + 2 = 73

Step 2: Calculate the percentage of CEOs who are 59 years or younger.

To determine the percentage, we need to find the cumulative frequency up to the age group of 59 years and divide it by the total number of CEOs:

Cumulative frequency for CEOs 59 years or younger = Frequency for age 40-44 + Frequency for age 45-49 + Frequency for age 50-54 + Frequency for age 55-59

= 4 + 3 + 15 + 20 = 42

Percentage of CEOs 59 years or younger = (Cumulative frequency for CEOs 59 years or younger / Total CEOs) * 100

= (42 / 73) * 100

≈ 57.53%

Rounded to the nearest tenth, the percentage of CEOs who are 59 years or younger is 57.5%.

Step 3: Calculate the relative frequency for ages 65 to 69.

To find the relative frequency, we need to divide the frequency for ages 65 to 69 by the total number of CEOs:

Relative frequency for ages 65 to 69 = Frequency for age 65-69 / Total CEOs

= 8 / 73

≈ 0.1096

Rounded to four decimal places, the relative frequency for ages 65 to 69 is approximately 0.1096.

Step 4: Calculate the cumulative frequency for CEOs over 55 years in age.

The cumulative frequency for CEOs over 55 years in age is the sum of the frequencies for the age groups 55-59, 60-64, 65-69, and 70-74:

Cumulative frequency for CEOs over 55 years = Frequency for age 55-59 + Frequency for age 60-64 + Frequency for age 65-69 + Frequency for age 70-74

= 20 + 21 + 8 + 2

= 51

The cumulative frequency for CEOs over 55 years in age is 51.

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The complete question is:

Forbes magazine published data on the best small firms in 2012. These were firms which had been publicly traded for at least a year, have a stock price of at least $5 per share, and have reported annual revenue between $5 million and $1 billion. The table below shows the ages of the chief executive officers for the first 73 ranked firms

Age:

40-44

45-49

50-54

55-59

60-64

65-69

70-74

Frequency:

4

3

15

20

21

8

2

1. What percentage of CEOs are 59 years or younger? Round your answer to the nearest tenth.

2. What is the relative frequency of ages 65 to 69? Round your answer to 4 decimal places.

3. What is the cumulative frequency for CEOs over 55 years in age? Round to a whole number. Do not include any decimals.

Answer:

155 = 2^7 + 3^3

Step-by-step explanation:

3 cubed = 27

2 to the 7th power = 128

27 plus 128 = 155

have a shiny day.

Answer:

1.2x + 3

Step-by-step explanation:

It has to have +3 because 0 alresdy starts at 3 than use any point (I choose (5,9)) and find how much changed. The point moved 6 up and 5 to the right so divide 6/5 and get 1.2. Then test it with other points. (2,5.4) is a great example because it shows that whatever the equation is it is not 1.5 or anything above.

Answer:

\(p = \frac{214}{400} = .535 = 53.5\%\)

The angle between two vectors a = 5i + j and b = 2i - 4j is approximately 52.125°.

The angle between two vectors can be calculated using the following formula: cosθ = (a · b) / (||a|| ||b||)

where θ is the angle between the vectors, a · b is the dot product of the vectors, and ||a|| and ||b|| are the magnitudes of the vectors.

In this case, the dot product of the vectors is 13, the magnitudes of the vectors are √29 and √20, and θ is the angle between the vectors. So, we can calculate the angle as follows:

cos θ = (13) / (√29 * √20) = 0.943

The inverse cosine of 0.943 is approximately 52.125°. Therefore, the angle between the two vectors is approximately 52.125°.

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Required sum of interior angles of the kite is 360°.

What is kite?

A quadrilateral with two pairs of adjacent sides which are congruent is called kite. Total number of sides are four.

Let the kite has vertices A, B, C,D and the lengths of its diagonals are d_1 and d_2.

The interior angles of a kite can be found using the following formulas:

\(∠A = ∠C = \frac{(180° - ∠B - ∠D)}{ 2} \\ ∠B = ∠D = \frac{(360° - (∠A + ∠C)) }{2}\)

We know sum of interior angles = (n-2) × 180°

Where n is number of sides.

Here number of sides are 4.

So, sum of interior angles of kite = (4-2)×180° = 2×180° = 360°

Therefore required sum of interior angles is 360°.

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Correct question is " What is the sum of interior angles of a kites for A,B,C,D ?"

The experimental probability of rolling a 1 or a 2 is 0.2.

Hence, Option A is correct.

We know that,

The experimental probability of an event is defined as the number of times the event occurred divided by the total number of trials.

In this case,

The event is rolling a 1 or a 3,

Which occurred ⇒  3 + 1

                           = 4 times.

Given that there are total number of trials = 20.

Therefore,

The experimental probability of rolling a 1 or a 3 = 4/20,

                                                                                = 1/5

                                                                                 = 0.2

Hence, the required probability is 0.2.

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The complete question is:

Sarah is playing a game in which she rolls a number cube 20 times. The results are recorded in the chart below. What is the experimental probability of rolling a 1 or a 3?

Number on cube:1,2,3,4,5,6

Number of times event occurs:3,6,1,5,3,2

A.0.2

B.0.3

C.0.6

D.0.83

Answer:

Original Cost: $76

Fee: 7.5%

Take 7.5% of 76 (76 times .075)  and add the result to the original amount $76

So, 76 times .075= 5.7

5.7+76= 81.7

Step-by-step explanation:

A triangle and a quadrilateral are special cases of a polygon.

A polygon is a two-dimensional geometric shape that is formed by connecting a finite number of line segments called sides. It is a closed figure with straight sides.

A triangle is a polygon with three sides, while a quadrilateral is a polygon with four sides.

In general, a polygon can have any number of sides greater than or equal to three. Triangles and quadrilaterals are specific examples of polygons with a fixed number of sides.

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To graph and find the intersection points of the functions f(x) = \(x^3\) - 5x + 10 and g(x) = 4sin(3x) + 6, we can use the Python libraries matplotlib and scipy.

Here's an example code that accomplishes this:

import numpy as np

import matplotlib.pyplot as plt

from scipy.optimize import brentq

# Define the functions

def f(x):

   return x**3 - 5*x + 10

def g(x):

   return 4*np.sin(3*x) + 6

# Define the range of x values

x_vals = np.linspace(-5, 5, 1000)

# Plot the functions

plt.plot(x_vals, f(x_vals), label='f(x)')

plt.plot(x_vals, g(x_vals), label='g(x)')

# Find and plot the intersection points

intersection_points = []

for x0 in np.linspace(-5, 5, 10):

   intersection = brentq(lambda x: f(x) - g(x), x0, x0 + 1)

   intersection_points.append((intersection, f(intersection)))

   plt.plot(intersection, f(intersection), 'r*', markersize=10)

# Set plot attributes

plt.axhline(0, color='black', linewidth=0.5)

plt.axvline(0, color='black', linewidth=0.5)

plt.xlabel('x')

plt.ylabel('y')

plt.legend()

# Show the plot

plt.show()

# Print the intersection points

for point in intersection_points:

   print(f"Intersection point: x = {point[0]}, y = {point[1]}")

This code imports the necessary libraries, defines the functions f(x) and g(x), generates a range of x values, plots the functions, uses the brentq function from scipy to find the intersection points, plots the intersection points as red stars, and finally displays the plot. The intersection points are also printed to the console.

Make sure you have the required libraries installed (matplotlib and scipy) before running the code

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The z value is calculated by using the equation  (x- μ)/ σ/ √n. Here the true value lies between the confidence interval. So null hypothesis is accepted.

The data which is given are, mean of the sample (x) = 100.6 psi

Standard deviation, σ = 2 psi

Number of specimens tested, n = 9

Let us consider the mean breaking point of yarn of the population = μ

Since it is said that the mean breaking point should at least be 100,

Null hypothesis, H₀ , μ ≥ 100

Alternate hypothesis, H₁  μ < 100

a. Z value = (x- μ)/ σ/ √n =  \(\frac{100.6-100}{\frac{2}{\sqrt{9}} }\) = 0.89

So P ( z ≥ 0.89) = 0.1711

If significance level,α is greater than P(z ≥ 0.89), we cannot reject the null hypothesis.

b. If significance level is 0.05

Critical value for the breaking point , (x-μ)/σ/√n = 1.64

        \(\frac{x- 100}{\frac{2}{\sqrt{9} } }\)    = 1.64

x = 101.093

Z value =   \(\frac{101.09-102}{\frac{2}{\sqrt{9} } }\)  =  -1.378

P(z< -1.378) = 0.0885

Probability of committing type 2 error = 8.85%

c. Required confidence interval level =  \(x-z_{0.05}(\frac{2}{\sqrt{n} })\)  = \(102-1.64(\frac{2}{\sqrt{9} } )\) = 102 - (1.64× 0.67) = 100.9

d. If true value lies between the two confidence interval, null hypothesis is accepted. Here 100.9 < 102 < α

So null hypothesis is accepted.

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The complete question is

The mean breaking strength of yarn used in manufacturing drapery material is required to be at least 100 psi. Past experience has indicated that the standard deviation of breaking strength is 2 psi. A random sample of nine specimens is tested, and the average breaking strength is found to be 100.6 psi.

a) Should the fiber be judged acceptable? Use the P-value approach.

b) What is the probability of not rejecting the null hypothesis at

α=0.05

if the fiber has a true mean breaking strength of 102 psi?

c) Find a 95% one-sided lower CI on the true mean breaking strength.

d) Use the CI found in part (d) to test the hypothesis.

Answer:

a = 23

b = 10

Step-by-step explanation:

The general formula is

y = 3x +  5

Just to check, let x = 2

y = 3*2 + 5

y = 6 + 5

y = 11

And a confirmation check

x = 3

y = 3*3 + 5

y = 9 + 5

y = 14

So for a

x = 6

y = 6*3 + 5

y = 18 + 5

y = 23

For b, you know y

35 = 3x + 5

- 5           -5              Subtract

30 = 3x                       Divide by 3

30/3 = 3x/3

x = 10

The values of the variables a and b are:

a = 23

b = 10

Answer:

Given that,

Height of dougal is 1.84 meters and height of seb is 1.7 meters. We need to find the height of dougal as a fraction of the height of seb.

Let x is height of dougal as a fraction of the height of seb. So,

If we divide 1.7 on both sides of above equation, then,

On removing decimal, we get,

Hence, this is the required solution.

Step-by-step explanation:

Hi,, i saw this answer here in brainly because i had this one too so i hope this one helps

The correct option is B) 5 minutes.

The width of each class /(class width) is 5 minutes.

The term "class interval" refers to the numerical width of a class in such a frequency distribution.

Some key features regarding the class width/class interval are-

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The complete question is -

The following are the duration in minutes of a sample of long-distance phone calls made within the continental United States reported by one long-distance carrier.

RelativeTime (in Minutes)/

Frequency

0 but less than 5/0.37

5 but less than 10/0.22

10 but less than 15/0.15

15 but less than 20/0.10

20 but less than 25/0.07

25 but less than 30/0.07

30 or more/0.02

What is the width of each class?

A) 1 minute

B) 5 minutes

c) 2%

d) 100%

For the given lottery daily game, total number of choices player have to pick for three numbers from 0 to 9 where order does not matter is equal to 120.

As given in the question,

Total number have to pick by a player in a lottery daily game is equal to 3

Numbers  from which player have to pick the three numbers is 0 to 9

Total numbers from which player have to pick the three numbers = 10

Given condition : Order of the number does not matter

Total number of choices to pick three numbers from 0 to 9

= ¹⁰C₃

= ( 10! ) / ( 10 - 3 )! (3!)

= 10! / 7! 3!

= ( 10 × 9 × 8 × 7! ) / ( 7!) ( 3 × 2 × 1 )

= 10 × 3 × 4

=120 choices

Therefore, for the given lottery daily game, total number of choices player have to pick for three numbers from 0 to 9 where order does not matter is equal to 120.

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Answer:

6

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

In the image, there is only one section that is above 2 1/4 and below 2 3/4, which  is 2 1/2. there are 6 crosses on 2 1/2, indicating 6 students

Answer: x = 5.625

Step-by-step explanation:  The triangles are similar; the side lengths of the large triangle are proportional to the lengths of the small triangle. The corresponding parts are proportional.

Use proportion. The total length of side FV is 16.

6:16 = x:15 . or 6/16=x/15

cross multiply 15 × 6 = 90, then divide 90/16

90/16 = x

5.625 = x

Answer:

Katie,

Once the skydiver reaches terminal velocity, then he will be falling with constant speed. The distance he falls in time t will then be d = (160 ft/s)·t. And his altitude above the ground (height h) will be his altitude when the parachute opened minus the distance he has fallen so we can write:

h = (3200 ft) - (160 ft/s)·t

As a point of interest, the time it will take him to fall all the way to the ground is t = (3200 ft)/(160 ft/s) = 20 s

Answer:

h(t) = -16t^2 + 200

Step-by-step explanation:

Answer:

h = (p/0.7 - b) ÷ r

Step-by-step explanation:

Anastasia uses the equation p = 0.7(rh + b) to estimate the amount of take-home pay, p, for h hours worked at a rate of r dollars per hour and any bonus received, b. What is an equivalent equation solved for h?

Given:

p = 0.7(rh + b)

Divide both sides by 0.7

p / 0.7 = rh + b

p/0.7 - b = rh

p/0.7 - b ÷ r = h

h = (p/0.7 - b) ÷ r

The soft drink vendor's maximum profit per day is $5250, and he must sell 1500 cans of soda pop to reach the maximum profit.

To find the maximum profit per day for the soft drink vendor, we need to use the formula P(x) = 0.001x^2 + 3x + 1800, where x is the number of cans of soda pop sold in one day.

To find the maximum profit, we need to find the vertex of the parabola represented by the profit function. The x-coordinate of the vertex is given by -b/2a, where a = 0.001 and b = 3. Plugging in these values, we get x = -3/(2*0.001) = -1500.

Since the soft drink vendor cannot sell a negative number of cans, we know that the maximum profit occurs at the closest whole number to x = -1500, which is x = 1500.

To find the maximum profit per day, we can plug in x = 1500 into the profit function:

P(1500) = 0.001(1500)^2 + 3(1500) + 1800 = $5250

Therefore, the soft drink vendor's maximum profit per day is $5250, and he must sell 1500 cans of soda pop to reach the maximum profit.

To find the maximum profit per day and the number of cans needed to reach that profit, we'll first need to find the critical point of the given quadratic profit function, P(x) = -0.001x^2 + 3x - 1800.

Step 1: Find the derivative of P(x) with respect to x. This will give us the rate of change of profit as the number of cans sold changes.

P'(x) = -0.002x + 3

Step 2: Set the derivative equal to zero and solve for x. This will give us the critical point where the maximum profit occurs.

-0.002x + 3 = 0

x = 1500 cans

Step 3: Substitute the critical point (x = 1500) back into the profit function P(x) to find the maximum profit.

P(1500) = -0.001(1500)^2 + 3(1500) - 1800

P(1500) = $600

So, the maximum profit per day is $600, and the soft drink vendor must sell 1500 cans to reach the maximum profit.

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The maximum profit per day is $4800, and the vendor must sell 1500 cans of soda pop to reach this maximum profit.

The profit function for the soft drink vendor is given by:

P(x) = \(0.001x^2 + 3x + 1800\)

To find the maximum profit, we need to find the vertex of the parabola represented by this function. The x-coordinate of the vertex can be found using the formula:

x = -b / (2a)

where a = 0.001 and b = 3. Substituting these values, we get:

x = -3 / (2 * 0.001) = -1500

Since the value of x cannot be negative in this context, we know that the maximum profit occurs at x = 1500. To find the maximum profit, we substitute this value of x into the profit function:

P(1500) =\(0.001(1500)^2 + 3(1500) + 1800 = $4800\)

Therefore, the maximum profit per day is $4800, and the vendor must sell 1500 cans of soda pop to reach this maximum profit.

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The average speed for the downhill section must be 20 km/hour

Let's call the average speed for the uphill section "u" and the average speed for the downhill section "d". The total average speed for the 20 km section must be 20 km/hour, so we can set up an equation:

\((10 km / u) + (10 km / d) = 20 km / 20 km/hour\)

We know that the average speed for the uphill section is 12 km/hour, so we can substitute this value into the equation:

\((10 km / 12 km/hour) + (10 km / d) = 20 km / 20 km/hour\)

Simplifying the equation:

\(5/6 + 10/d = 1\)

\(5/6 = 1 - 10/d\)

\(d = 20 km/hour\)

So the average speed for the downhill section must be 20 km/hour in order for the average speed for the entire trip to be 20 km/hour.

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Answer:

The third one.. :)

Step-by-step explanation:

Can I have brainliest, please? hee hee

The attached graph represents the graph of the function f(x) = |x - 3| + 2

The equation of the function is given as:

f(x) = |x - 3| + 2

The above equation is an absolute value function, and it has the following parameter:

Vertex = (3,2)

Next, we plot the graph of the function (see attachment)

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