a digital output voltmeter has an input range of 0 to 30 v and displays three significant figures xx.x. the manufacturer claims an accuracy of of full scale. with a voltage reading of 5 v, what are the percent uncertainties of the reading due to accuracy and resolution

Answer:

  0 ft

Explanation:

The equation of the plane can be found from the cross product AC×BC. That vector is ...

  N = (2, 11, -6) × (-3, -6, 4) = (8, 10, 21)

Then the equation of the plane is ...

  8x +10y +21z = 14 . . . . . 14 = N·A

Point P satisfies this equation, so is on the plane. The distance is 0 feet.

  8(9) +10(11) -8(21) = 72 +110 -168 = 14

Answer:

its c

Explanation:

Answer:

a) the safety factor according to the maximum normal-stress theory; n = 3

b) the safety factor according to the maximum-shear-stress theory; n = 1.714

c) the safety factor according to the maximum distortion-energy theory is; n = 1.97278

Explanation:

Given the data in the question;

a) What is the safety factor according to the maximum normal-stress theory;

According to the maximum normal-stress theory

n = S\(_y\) / σ\(_{max\)

since σ₁ = 20 ksi is greater than σ₂ = -15 ksi

σ\(_{max\) = 20 ksi and yield strengths in tension and compression S\(_y\) = 60 ksi

we substitute

n = 60 ksi / 20 ksi

n = 3

Therefore, the safety factor according to the maximum normal-stress theory; n = 3

b) What is the safety factor according to the maximum-shear-stress theory.

According to maximum-shear-stress theory;

τ\(_{max\) = [(σ₁ - σ₂) / 2]

= S\(_y\) / 2n

n = S\(_y\) / 2[(σ₁ - σ₂) / 2]

n = S\(_y\) / (σ₁ - σ₂)

we substitute

n = 60 ksi  / (20 ksi - (-15 ksi))

n = 60 ksi  / (20 ksi +15 ksi)

n = 60 ksi  / 35 ksi

n = 1.714

Therefore, the safety factor according to the maximum-shear-stress theory; n = 1.714

c) the safety factor according to the maximum distortion-energy theory?

By distortion energy theory

σ₁² + σ₂² - σ₁σ₂ = (S\(_y\)/n)²

we substitute

(20)² + (-15)² - ( 20 × -15 ) = ( 60 / n )²

400 + 225 + 300 = 3600 / n²

925 =  3600 / n²

n² = 3600 / 925

n = √( 3600 / 925 )

n = 1.97278

Therefore, the safety factor according to the maximum distortion-energy theory is; n = 1.97278

The minimum allowable bar diameter to ensure that fatigue failure will not occur is 23.4mm

Given

Fatigue limit series for this 1045 steel in 310 MPa

Factor of safety = f = 2

The maximum allowable stress is

σ = 310/2 = 155Mpa = 155 × \(10^{6}\) N/m²

Given cyclic load amplitude is 66700N

σ = Cyclic load/area

155 × \(10^{6}\) N/m² =  66700 / πd²/4

d = 0.023m = 23.4mm

A recurrent or cyclic stress causes cracks to grow and spread, which is known as a fatigue failure. Cyclical loads that are far below those that would cause material yielding are what lead to the majority of fatigue failures. The failure happens as a result of the load's cyclical nature, which causes minute material faults (flaws) to enlarge and eventually form a macroscopic crack (initiation phase). Once it reaches a threshold size, the crack may spread and cause the component to collapse structurally or along its pressure boundary.

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The easiest way for the hotel to control for potential bias in their statistics would be to survey visitors at various periods throughout the year.

The hotel can make sure that the data in its survey of visitors is representative of those who stay there during various seasons, for various periods of time, and through various booking channels by conducting surveys of guests at random times throughout the year.

By solely surveying specific visitor subsets, any potential bias that might result will be reduced.

The most popular kind of guest satisfaction survey is the post-stay survey, which is given to guests after they have left the property and asks them about various elements of their stay.

Therefore, The easiest way for the hotel to control for potential bias in their statistics would be to survey visitors at various periods throughout the year.

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Answer:

In most cases, it will never get that far - the shop will cave and agree to properly diagnose your problem and correctly fix it. Usually, the mechanic that failed to do their job correctly will be back-flagged for the labor and in some cases they'll even be charged for the parts as well

Explanation:

To solve this problem, we can use the following formula:

t = (m * c * ΔT) / P

where t is the time taken to warm the plasma to 90°, m is the mass of the plasma, c is the specific heat capacity of the plasma, ΔT is the change in temperature (90° - 40° = 50°), and P is the power of the oven.

We can assume that the mass and specific heat capacity of the plasma are constant.

If the oven is set at 100°, we have:

t = (m * c * ΔT) / P

t = (m * c * 50) / (100 - 40) (since P = 100 - 40 = 60)

t = (m * c * 50) / 60

t = (5m * c) / 6

If the oven is set at 140°, we have:

t = (m * c * ΔT) / P

t = (m * c * 50) / (140 - 40) (since P = 140 - 40 = 100)

t = (m * c * 50) / 100

t = (m * c) / 2

If the oven is set at 80°, we have:

t = (m * c * ΔT) / P

t = (m * c * 50) / (80 - 40) (since P = 80 - 40 = 40)

t = (m * c * 50) / 40

t = (5m * c) / 8

Therefore, it will take 5/6 times as long (or approximately 42.5 minutes) if the oven is set at 100°, half as long (or 22.5 minutes) if the oven is set at 140°, and 5/8 times as long (or approximately 28.1 minutes) if the oven is set at 80°, compared to the original time of 45 minutes when the plasma was placed in an oven at 120°.

Answer:

"7.654 mm" is the correct solution.

Explanation:

According to the question,

Now,

As we know,

The Elongation,

⇒ \(E=\frac{\sigma}{e}\)

       \(=\frac{\frac{P}{A} }{\frac{\delta}{L} }\)

or,

⇒ \(\delta=\frac{PL}{AE}\)

By substituting the values, we get

 \(0.5=\frac{6660\times 380}{(\frac{\pi}{4}D^2)(110\times 10^3)}\)

then,

⇒ \(D^2=58.587\)

     \(D=\sqrt{58.587}\)

         \(=7.654 \ mm\)

Here's a function called Close Enough which takes a const reference to a vector of strings and an int. This function is used to check if there are two adjacent strings in a list that are very similar to each other by determining the number of characters that can be different between any two strings next to each other.

The function starts by iterating through the vector of strings from the first to the second to last string. For each string, it then counts the number of differences between it and the next string by comparing the characters at each position.

If the number of differences is less than or equal to the given integer n, the function returns the index of the current string. If there is no such index, the function returns -1.

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Answer:

they were updated rather than being created

Answer:

Invention is about creating something new, while innovation introduces the concept of “use” of an idea or method.

Complete Question

Air at 40C flows over a 2 m long flat plate with a free stream velocity of 7m/s. Assume the width of the plate (into the paper) is 0.5 m. If the plate is at a co temperature of 100C,find:

The total heat transfer rate from the plate to the air

Answer:

\(q=1.7845\)

Explanation:

From the question we are told that:

Air Temperature \(T_1=40c\)

Length \(l=2m\)

Velocity \(v=7m/s\)

Width \(w=0.5\)

Constant temperature \(T_t= 100C\)

Generally the equation for Total heat Transfer is mathematically given by

 \(q=hA(T_s-T_\infty)\)

Where

h=Convective heat transfer coefficient

 \(h=29.9075w/m^2k\)

Therefore

 \(q=h(L*B)(T_s-T_\infty)\)

 \(q=29.9075*(2*0.5)(100+273-(40+273))\)

 \(q=1794.45w\)

 \(q=1.7845\)

It is essential to inspect the fuel nozzle and clean it when there are stains around it. This will ensure that it is functioning correctly, and the fuel system is working efficiently, preventing further damage to the vehicle's engine. Option (A) is correct.

The presence of fuel stains around a fuel nozzle would indicate the clogged fuel nozzle. A fuel nozzle is a component of the fuel system that is responsible for dispensing fuel into the engine of a vehicle. The fuel nozzle is typically located on the fuel line, which runs from the fuel tank to the engine.

It is designed to regulate the flow of fuel into the engine, ensuring that the engine receives the proper amount of fuel to operate efficiently and effectively.
However, when there are stains around the fuel nozzle, it is a sign that there may be a problem with the fuel nozzle. Typically, these stains are caused by a clogged fuel nozzle that is not dispensing fuel properly. This can cause fuel to leak from the nozzle, resulting in stains around the nozzle and other areas of the vehicle.
Clogging of the fuel nozzle can happen due to debris accumulation within the nozzle. Dirt, rust particles, and other contaminants can build up within the fuel nozzle over time, leading to blockages.

Other causes of clogging can be due to the use of contaminated fuel or due to the malfunction of fuel filters that are used in the fuel system.

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Answer:

  5

Explanation:

One pulse is required for each bit to be moved.

5 pulses are required.

The reference OSHA standard requires several important characteristics of a PFAS. The employer must ensure that personal fall arrest systems (PFAs) must:

a. Limit the maximum arresting force on the employee to 1,800 pounds (8 kN). The figure used above must be based on the use of a full body harness.

From the above, we can therefore say that The reference OSHA standard requires several important characteristics of personal fall arrest systems (PFAs) as employers must reduce the maximum arresting force on the employee to 1,800 pounds (8 kN) using full body harness.

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Answer:

In I-Q modulation technique, many symbols or signals with different amplitude and phase are generated. What is the map of all of the symbols called:____.

d. constellation diagram.

Explanation:

A constellation diagram is a representation of all the possible symbols that a system can transmit.  It shows these as a collection of points on the map.  For a signal modulated by a digital modulation scheme, the constellation diagram is used to display both the ideal (reference) signal and the actual measured signal on the same plot.  Modulation simply means the process of converting data into electrical signals so that they are optimized for transmission.

Some of the things that can be done in the above scenario regarding issues with the LAN involving high broadcast frames are:

A network analyzer, also known as a network protocol analyzer or packet analyzer, is a software program, dedicated appliance, or feature set inside a network component that is used to diagnose network performance or to improve security within a corporate network.

A network analyzer is a tool for monitoring and analyzing network traffic in real time. Using a network analyzer, you may locate the source of the broadcast traffic and take appropriate action.

In the preceding example, your network architecture may not be optimum for the amount of switches and devices you have. To lower the amount of broadcast frames, you may need to install extra switches or reorganize your present switches.

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4 netherite scrap and 4 gold

in a crafting table

The stress in a concrete test cylinder can be determined by calculating the compressive force acting on the cylinder and dividing it by the cross-sectional area of the cylinder.

The cross-sectional area of the 6-in.-diameter cylinder can be calculated as follows:

A = π * r^2

where r is the radius of the cylinder, given as r = 6 in. / 2 = 3 in.

A = π * 3^2 = 28.26 in.^2

The compressive force acting on the cylinder can be determined from the given value of 113.1 kips.

The stress in the cylinder can be calculated by dividing the compressive force by the cross-sectional area:

σ = F / A = 113.1 kips / 28.26 in.^2 = 4 ksi

This stress is the average normal stress acting on the cylinder. It represents the force per unit area acting on the cylinder due to the applied compressive load.

In conclusion, the stress in a concrete test cylinder can be determined by calculating the compressive force acting on the cylinder and dividing it by the cross-sectional area of the cylinder. In the case of the 6-in.-diameter cylinder loaded with 113.1 kips, the stress was calculated to be 4 ksi. This stress is the average normal stress acting on the cylinder.

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At amateur operating frequencies, the FTDX10 is designed for 50 Ohm resistive impedance.

Impedance is the sum of resistance and reactance. It was defined as anything that can obstructs the flow of electrons within the electrical circuit. As a result, it influences current generation in the electrical circuit. It could be found in all the possible circuit components and across all possible electrical circuits. Impedance is represented mathematically by the letter Z and has the unit ohm. It's a mix of resistance and reactance.

Z stands for impedance, which is an expression of the resistance to alternating and/or direct electric current that an electronic component, circuit, or system offers. Resistance and reactance are two independent scalar (one-dimensional) phenomena that make up the vector (two-dimensional) quantity known as impedance.

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Answer:

Motorcyclist Fatality and Injury Rates per Vehicle Miles Traveled, 1998-2008. 10. 9. Fatalities in School Transportation Related Crashes,. 1998-2008.

Explanation:

We would need approximately 466.48 linear feet of 2 x 12's for the floor framing

Total Length of Joists = (2 * 20) + (2 * 30) = 100 feet

Spacing in Inches = 16

Linear Feet = (100 / 12) * (16 / 16) = 8.33 feet per joist

Total Linear Feet = Linear Feet per Joist * Total Number of Joists

Therefore, the total linear feet of 2 x 12's needed for this floor would be:

Total Linear Feet = 8.33 * 56 = 466.48 feet

So we would need approximately 466.48 linear feet of 2 x 12's for the floor framing.

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Where the above hydrology engineering flood routing conditions are given, the Muskingum coefficients for reach A-B are:

C1 = 0.606

C2 = 0.182

C3 = 0.212

To calculate the Muskingum coefficients for reach A-B, we need to use the following equations:

Q[n] = K*(P[n] + X*Q[n-1] + (K-X)Q[n-2])/(2K-X)

where Q[n] is the discharge at point B at time n, P[n] is the excess precipitation at time n, and K and X are the Muskingum coefficients.

We can first calculate the total excess precipitation over the two hours in sub-basin 2:

P_total = 0.78 + 1.12 = 1.9 inches

To convert this to a unit hydrograph, we can divide by the total volume of runoff produced by 1 inch of excess precipitation over sub-basin 2. This volume can be calculated as follows:

Volume = (1 hour)(1 acre)(1 inch)/(12 inches/foot)*(4840 square yards/acre) = 3630 cubic feet

Therefore, the unit hydrograph for sub-basin 2 is:

Time [hr] 0 1 2 3 4 5 6 7 8

Q (CFS) 0 36300.2 36300.67 36301 36300.73 36300.4 36300.19 3630*0.08 0

Now we can use the Muskingum method to calculate the discharge at point B. We'll assume that the excess precipitation is uniformly distributed over sub-basins 1, 2, and 3, and that the hydrograph for sub-basins 1 and 3 are triangular with a peak of 500 cfs and a base of 6 hours.

To simplify the calculations, we can first calculate the coefficients C1, C2, and C3 using the following equations:

C1 = (2K-X)/(2K+X)

C2 = (K-X)/(2K+X)

C3 = K/(2K+X)

Using K=2.3 hours and X=0.15, we get:

C1 = 0.606

C2 = 0.182

C3 = 0.212

Now we can calculate the discharge at point A for each hour of the storm:

Time [hr] 0 1 2 3 4 5 6 7 8

P [in] 0 0.95 0.95 0 0 0 0 0 0

Qt [cfs] 0 500/60.78/2+36300.20.95+500/61.12/2 500/60.78/2+36300.670.95+500/61.12/2 0 0 0 0 0 0

Qb [cfs] 0 0 600C1+QtC2 2000*C1+QtC2 3000C1+QtC3 2200C1+QtC2 1200C1+QtC2 700C1+QtC2 300C1+QtC2 100C1

In the second hour, the discharge at point B is given by:

Qb[2] = 600C1 + Qt[2]C2 = 6000.606 + (500/60.78/2+36300.20.95+500/6*1.12/2)*0.182 = 715.7 cfs

Therefore, the Muskingum coefficients for reach A-B are:

C1 = 0.606

C2 = 0.182

C3 = 0.212

Note that the Muskingum method is an approximation and assumes that the inflow hydrograph is continuous and has a smooth transition between time steps. In reality, the hydrograph may be more jagged

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Answer:

1. --a 10

--b 100 in.

2. --a 4

--b 4

3. --a 2

--b 30 rpm

--c 75 ft.·lb.

4. --a Second class lever

--b 50 lbs.

Explanation:

The Actual Mechanical Advantage, AMA, is given as follows;

\(AMA = \dfrac{F_R}{F_E}\)

Where;

\(F_R\) = The resistance force magnitude

\(F_E\) = The effort force magnitude

1. a. We have;

\(F_R\) = 10 lb.

\(F_E\) = 100 lb.

\(AMA = \dfrac{100 \ lb}{10 \ lb} = 10\)

b. \(Mechanical \ advantage, \ M.A. = \dfrac{Distance \ moved \ by \ load}{Distance \ moved \ by \ effort}\)

The diameter of the axle, d = 2 in.

Let 'D' represent the diameter of the wheel, we have;

The distance moved by the axle, c = π·d

The distance moved by the load, C = π·D

\(M.A. = 10 = \dfrac{\pi \cdot D}{\pi \times 2}\)

∴ 2 × 10 = D

D = 20 in.

The required wheel diameter to overcome the resistance force, D = 100 in.

2. --a The mass of the participants, m = 200 lb.

The depth of the ground of the participants = 20 feet

The effort force = 50 lb

Actual Mechanical Advantage, AMA = 200 lb./(50 lb.) = 4

--b. The number of strands of pulley needed ≈ The mechanical advantage = 4

3. The number of gears on Gear A = 10 teeth

The number of gears on Gear B = 8 teeth

The number of gears on Gear C = 20 teeth

-a. Given that the driver gear = Gear A

The output gear = Gear C

\(The \ gear \ ratio = \dfrac{The \ number \ of \ teeth \ on \ the \ driven \ gear}{The \ number \ of \ teeth \ on \ the \ driver \ gear}\)

The driver gear = The input gear

Therefore, we have;

\(The \ gear \ ratio = \dfrac{20 \ teeth}{10 \ teeth} = 2\)

The gear ratio = 2

-b \(The \ gear \ ratio = \dfrac{The \ driver \ gear\ speed}{The \ driven \ gear\ speed}\)

Therefore, we have;

\(The \ gear \ ratio = 2 = \dfrac{60 \ rpm}{Gear\ C \, speed}\)

\(Gear\ C \, speed = \dfrac{60 \ rpm}{2} = 30 \ rpm\)

-c The output (driven) gear torque at Gear C = 150 ft.·lb.

\(The \ gear \ ratio = \dfrac{Driven \ gear \ torque}{Driver \ gear \ torque}\)

Therefore;

\(2 = \dfrac{150 \ ft \cdot lb}{Driver \ gear \ torque}\)

\(Driver \ gear \ torque = \dfrac{150 \ ft \cdot lb}{2} = 75 \ ft \cdot lb\)

The input (driver) torque at Gear A = 75 ft·lb

4. -a Given that the load is between the effort and the fulcrum, we have;

The type of lever is a second class lever

-b The distance between the load and the fulcrum = 4 feet

The distance between the effort and the fulcrum = 8 feet

We have;

100 lbs × 4 ft. = Effort × 8 ft.

∴ Effort = 100 lbs × 4 ft./(8 ft.) = 50 lbs.

The effort = 50 lbs.

Answer:

represnt

Explanation:

The molar volume of acetylene vapor at 247.1 K and 13.5 bar, using the Pitzer correlation for the second virial coefficient, is approximately 72.5 cm3/mol.

Explanation:

The Pitzer correlation can be used to estimate the second virial coefficient of a gas. The equation is given by B = (RTc)/(Pc) * (1 + m(1 - (T/Tc)^(0.5))) where B is the second virial coefficient, R is the ideal gas constant, Tc is the critical temperature, Pc is the critical pressure, T is the temperature, and m is the acentric factor.

Plugging in the given values and solving for B, we get B = -0.009413 m3/mol. Then, using the ideal gas law, V = RT/P, we can calculate the molar volume as V = (RT)/P = (8.314 J/mol-K * 247.1 K) / (13.5 bar * 10^5 Pa/bar) ≈ 0.0725 m3/mol ≈ 72.5 cm3/mol.

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It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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The flight time that can be logged as instrument time when on an instrument flight plan includes the time spent flying solely by reference to instruments in conditions of reduced visibility or when practicing instrument approaches. This allows pilots to accurately track and log their instrument flying experience.

When a pilot is flying on an instrument flight plan, the flight time that can be logged as instrument time primarily consists of two scenarios. First, it includes the time spent flying solely by reference to instruments in conditions of reduced visibility, such as flying in clouds or fog. In these situations, pilots rely on their instruments to maintain control and navigate the aircraft, ensuring safe and precise flight. Logging this time allows pilots to document their experience in instrument flying and track their progress. Secondly, pilots can log instrument time when practicing instrument approaches. This refers to the time spent executing precision approaches, such as instrument landing system (ILS) or non-precision approaches like a localizer approach, while following specific instrument procedures. During these practice sessions, pilots rely heavily on their instruments to maintain accurate positioning and execute the approach accurately. By logging the flight time in these scenarios, pilots can maintain a record of their instrument flight experience, which is essential for currency, proficiency, and meeting regulatory requirements. It allows them to track their progress, demonstrate competency, and ensure they meet the necessary qualifications for instrument flight operations.

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The binary number (1 1000 0110 0011)2 is converted to its hexadecimal equivalent, resulting in (1863)16. Additionally, the sum and product of binary numbers (100 0111) and (111 0111)2 are calculated as (1 0111 0110)2 and (10 0110 0001 111)2, respectively.

Conversion of (1 1000 0110 0011)2 to its hexadecimal expansion.To convert a binary number to a hexadecimal number, the binary number is divided into groups of four starting from the rightmost digit.

If there are not enough digits to fill a group of four digits, zeroes are added to the left of the binary number to fill the group. Once you have divided the binary number into groups of four, you can convert each group of four digits to its hexadecimal equivalent.

The binary number given is:(1 1000 0110 0011)2. Converting the binary number to hexadecimal we have:  (1 1000 0110 0011)2 = (1) 8 6 3. Hence, the hexadecimal equivalent of (1 1000 0110 0011)2 is (1863)16.

Sum and Product of (100 0111) and (111 0111)2We can perform the sum and product of binary numbers (100 0111) and (111 0111)2 as shown below:

Addition of Binary numbers(100 0111)2+ (111 0111)2= (1 0111 0110)2Therefore, (100 0111) + (111 0111)2 = (1 0111 0110)2.Product of Binary numbers(100 0111)2× (111 0111)2= (10 0110 0001 111)2Therefore, (100 0111) × (111 0111)2 = (10 0110 0001 111)2.

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Answer:

building sewer

I hope this helps...

Please mark me Brainliest

The drainage piping between the building foundation and the sewer main or septic tank is known as the sewer lateral or building sewer.

The drainage piping between the building foundation and the sewer main or septic tank is commonly referred to as the "sewer lateral" or "building sewer." This piping system is responsible for carrying wastewater and sewage from individual buildings or structures to the main sewer line or septic tank.

The sewer lateral is typically a buried pipe that connects the building's plumbing system to the larger sewer infrastructure. It is designed to transport wastewater, including water from sinks, toilets, showers, and other sources, away from the building and into the public sewer system or on-site septic system for further treatment or disposal.

In urban areas with centralized sewage systems, the sewer lateral connects the building's plumbing to the municipal sewer main. The sewer main is the primary pipe that carries wastewater from multiple buildings and eventually leads to a wastewater treatment plant.

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Besides hev and ev motor systems themselves what other systems may use high voltage are the air conditioning compressor, auxiliary battery, and water pump.

High voltages are utilized in transmission structures due to the fact a better voltage implies a decrease modern-day for a given energy of transmission. With a decrease modern-day, much less warmth is generated withinside the transmission traces and so much less electricity is wasted. Furthermore, it has superb environmental benefits.

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