A cylindrical piece of iron pipe is shown below. The wall of the pipe is 0. 75 inch thick, and the pipe is open at both ends:


16wder


What is the approximate inside volume of the pipe? (6 points)


O 113 cubic inches


O 452 cubic inches


O 410 cubic inches


O 254 cubic inches

Answer:

260 cities

Step-by-step explanation:

Multiple 5 and 52

James would visit 260 cities in one year.

Multiplication is a mathematical arithmetic operation. It is also a process of adding the same types of expression for some number of times.

Example - 2 × 3 means 2 is added three times, or 3 is added 2 times.

Given:

1 year = 52 weeks

James visits 5 cities per week.

To find the number of cities in e one year:

Multiply by 52

52 x 5

= 260 cities.

Therefore, he would visit 260 cities.

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Answer:

-11/9 is the slope

Step-by-step explanation:

Use the formula and u will find this is the answer, hope this helped!

Y2 - Y1 / X2 - X1

(-9 - 2) / (6 - (-3))

<!> Brainliest is appreciated!

Answer:

-11/9

Step-by-step explanation:

In order to find the slope from 2 points, use the following formula: \(m=\frac{y_{2} - y_{1} }{x_{2}-x_{1} }\)

Plug in each of the numbers into their corresponding areas. Basically, we are subtracting the y values together and dividing it with the difference of the x values:

\(\frac{-9-2}{6-(-3)}\)

The negatives cancel out and become postive, so the denominator will then read to be 6+3:

\(\frac{-9-2}{6+3}\)

\(-\frac{11}{9}\)

The two equations that represent circles with a diameter of 12 units and a center that lies on the y-axis are:

(x - 4)² + y² = 36

(x + 6)² + y² = 144

(x - 4)² + y² = 36:

This equation represents a circle with center (4, 0) since the x-coordinate of the center is 4, indicating it lies on the y-axis. The radius of this circle is √36 = 6 units. Therefore, it satisfies the given conditions.

(x + 6)² + y² = 144:

This equation represents a circle with center (-6, 0) since the x-coordinate of the center is -6, indicating it lies on the y-axis. The radius of this circle is √144 = 12 units. Hence, it also satisfies the given conditions.

x² + (y - 3)² = 36:

This equation represents a circle with center (0, 3) since the y-coordinate of the center is 3, indicating it does not lie on the y-axis. Therefore, it does not meet the given conditions.

x² + (y + 8)² = 36:

This equation represents a circle with center (0, -8) since the y-coordinate of the center is -8, indicating it does not lie on the y-axis. Thus, it does not fulfill the given conditions.

x² + (y - 5)² = 6:

This equation represents a circle with center (0, 5) since the y-coordinate of the center is 5, indicating it does not lie on the y-axis. Hence, it does not meet the given conditions.

Based on this analysis, the equations that represent circles with a diameter of 12 units and a center that lies on the y-axis are options 1 and 2:

(x - 4)² + y² = 36

(x + 6)² + y² = 144.

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Answer:

C

Step-by-step explanation:

All points between and including two endpoints.

I am so sorry if this is incorrect!!!!!!!!!!!!!!!!!!!

Answer:

B.) the set of all points that are a fixed distance from a given point

Step-by-step explanation:

Search the definition up, it'll give you the same answer.

You're welcome

>:D

Answer:

1016.015625 is the correct answer

Step-by-step explanation:

31.875 to the second power is the same as 31.875 squared.

Equation - 31.875 x 31.875

Solve and your answer should be 1016.015625

Answer:

D. 0 < x < 20

Explanation:

Domain is in the x axis, Range lies in the y axis.

Here it is seen that function's domain lies between 0 to 20.

Here, as the circle's are open. Domain: 0 < x < 20

Additionally,

Answer:

15 Students are in the data pool.

Step-by-step explanation:

So the marks above a number are each a student so we can just add them up. 3, for one, 2 for two, 5 for three, 3 for four, and 2 for five. Then we just add that together, 3+2+5+3+2=15. 15 students are included in the data pool.

Answer:

Step-by-step explanation:

B. Because adding 2 moves you to the left when inside the parentheses.

The interval in which the height is increasing is from t = 0 to t = 17.08 seconds

Since the path of a basketball after being thrown can be modeled by the following function, where x is the horizontal distance (in feet) from where the ball was thrown and y is the corresponding height (in feet).

y = −0.03x² + 1.025x + 4

The interval in which the height is increasing is when the derivative with respect to x, dy/dx ≥ 0

So, dy/dx ≥ 0

⇒ d(−0.03x² + 1.025x + 4)/dx ≥ 0

⇒ -0.06x + 1.025 ≥ 0

⇒ -0.06x ≥ -1.025

Dividing through by -0.06,

⇒ x ≤ -1.025/-0.06

⇒ x ≤ 17.08

Since the minimum value of x is 0 and x  ≤ 17.08, this implies that the maximum value of x = 17.08.

So, the interval in which the height is increasing is from t = 0 to t = 17.08 seconds

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(0.042 / 1.01) + 49.6e^(-t / 100) (in ounces)

The given equation can be solved with the help of the concept of differential equations.

Step 1: To find the rate of change of salt in the tank, we should start with finding the rate of change of salt concentration. The rate of change of salt concentration can be found using the given equation as follows:(dS / dt) = 1.4(1.5sin(t)) - (C(t) / V(t))(dS / dt) = 1.4(1.5sin(t)) - (S(t) / V(t)) x (2 / V(t))(dS / dt) = 1.4(1.5sin(t)) - (S(t) / V(t)) x (2 / 100)

Step 2: To find the rate of change of volume, we can use the fact that the volume remains constant. Hence,(dV / dt) = 0

Step 3: Now, we can use the relation between the amount of salt and the concentration of salt.(dS / dt) = (C(t) / V(t))(dV / dt) + (2 / 100) x 1.4(1.5sin(t))(dS / dt) = 0 + 0.042sin(t) - (S(t) / 100)(dS / dt) + (S(t) / 100) x (2 / 100)The resulting equation is given by:(dS / dt) = 0.042sin(t) - (S(t) / 100) + (S(t) / 5000)

Step 4: The above equation is a linear first-order differential equation. We can solve this using the integrating factor method. Let the integrating factor be e^(t / 100).Multiplying both sides of the equation with the integrating factor and simplifying, we get(e^(t / 100))(dS / dt) + (1 / 100)e^(t / 100)S(t) = 0.042e^(t / 100)The left-hand side of the equation can be written in the form(d / dt)(e^(t / 100)S(t)) = 0.042e^(t / 100) Therefore, e^(t / 100)S(t) = (0.042 / 1.01)e^(t / 100) + c where c is the constant of integration. At t = 0, the amount of salt is 50 ounces.Therefore,50 = (0.042 / 1.01) + c(c = 50 - 0.042 / 1.01 = 49.6)Therefore, e^(t / 100)S(t) = (0.042 / 1.01)e^(t / 100) + 49.6S(t) = (0.042 / 1.01) + 49.6e^(-t / 100)The long-time behavior of the solution is given bye^(-t / 100)S(t) -> 0as t -> infinity. Therefore, the solution approaches a limit, and there are no oscillations. The amount of salt in the tank at any time t is given by S(t) = (0.042 / 1.01) + 49.6e^(-t / 100) (in ounces)

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Overall, the testing facility concluded that the brush tee would be a better option for golfers looking to improve their drives.

An independent golf equipment testing facility compared the difference in the performance of golf balls hit off a brush tee to those hit off a 4 yards more tee. A'Air Force One DFX driver was used to hit the balls, with an average swing speed of 100 miles per hour. The testing facility wanted to determine which tee would perform better and whether it would be beneficial to golfers to switch to a different tee.

The two different types of tees were the brush tee and the 4 Yards More tee. The brush tee is designed with bristles that allow the ball to be suspended in the air, minimizing contact between the tee and the ball. This design is meant to reduce spin and allow for longer and straighter drives. On the other hand, the 4 Yards More tee is designed to be more durable than traditional wooden tees, and its design is meant to create less friction between the tee and the ball, allowing for longer drives.

The testing results showed that the brush tee was able to create longer and straighter drives than the 4 Yards More tee. This is likely due to the brush tee's design, which allows for less contact with the ball, minimizing spin and creating longer and straighter drives.

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The amount of money Company A charge more for x miles,  35 - 0.05x dollars

In mathematics, subtraction is an operation which means taking away a few portions of the group or few things from a whole part.

For example, if we take 4 pencils out of 10 then remaining pencils are 6

so this process is called subtraction.

Let's call the number of miles the family wants to travel "x".

The cost for Company A is $30.50 plus 8 cents per mile, so the total cost for Company A is,

30.50 + 0.08x.

The cost for Company B is $65.50 plus 13 cents per mile, so the total cost for Company B is,

65.50 + 0.13x.

To find out how much more Company A charges, we can subtract the cost for Company B from the cost for Company A:

= (30.50 + 0.08x) - (65.50 + 0.13x)

= 35 - 0.05x

So, Company A charges 35 - 0.05x dollars more than Company B for x miles.

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A normal distribution can be described completely by its mean and standard deviation. These two parameters provide essential information about the central tendency and spread of the data in a normal distribution.

The mean represents the average or central value around which the data is symmetrically distributed, while the standard deviation measures the dispersion or variability of the data points from the mean.The normal distribution, also known as the Gaussian distribution or bell curve, is a continuous probability distribution that is widely used in statistics and various fields of study. It is characterized by its symmetric shape, where the data clusters around the mean and tapers off towards the tails. The mean (average) determines the center of the distribution, while the standard deviation quantifies the spread of the data.

By knowing the mean and standard deviation of a normal distribution, one can determine the probabilities of different events or outcomes using the cumulative probability function. The mean and standard deviation provide a comprehensive description of the distribution's shape, location, and dispersion, making them crucial parameters for understanding and analyzing data that follows a normal distribution. Therefore, the correct answer is "Mean and standard deviation."

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Answer:

1.22

Step-by-step explanation:

divide 8.54 by 7 to get one serving

Information is needed to evaluate the project's financial viability, considering factors such as the initial investment, expected cash flows, cost of capital, and project duration.

To calculate the year 1 operating cash flows (OCF), we need to subtract the year 1 costs from the year 1 revenues:

OCF = Year 1 Revenues - Year 1 Costs

OCF = $192,000 - $125,000

OCF = $67,000

To find the depreciation expense in year 3, we need to determine the depreciation method. The provided information is incomplete regarding the depreciation method, so we cannot calculate the depreciation expense in year 3 without knowing the specific method.

The change in Net Working Capital (NWC) in year 2 can be determined by multiplying the Net Working Capital percentage (given as a percentage of t+1 revenues) by the year 1 revenues and subtracting the result from the year 2 revenues:

Change in NWC = (Year 2 Revenues - Net Working Capital percentage * Year 1 Revenues) - Year 1 Revenues

Without the specific Net Working Capital percentage or Year 2 Revenues values, we cannot calculate the exact change in NWC in year 2.

The net cash flow from salvage (ATSV) is calculated by multiplying the Salvage Value percentage by the Initial Cost:

ATSV = Salvage Value percentage * Initial Cost

ATSV = 28% * $390,000

ATSV = $109,200

To calculate the project's NPV, we need the cash flows for each year, the cost of capital, and the project duration. Unfortunately, the information provided does not include the cash flows for each year, so we cannot calculate the project's NPV.

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The complete question is:

Below are your numerical inputs for the problem: 4 & Initial Cost (\$) & 390000 5 & Year 1 Revenues (\$) & 192000 6 & Year 1 Costs (\$) & 125000  7 & Inflation & 2.75% 8 & Project Duration (years) & 6 9 & Depreciation Method & 10 & Tax Rate & 11 & Net Working Capital (\% oft+1 Revenues) & MACRS 12 & Salvage Value (\$) & 28.00% 13 & Cost of Capital & 15.00% & 245000 How much are the year 1 operating cash flows (OCF)? How much is the depreciation expense in year 3 ? What is the change in Net Working Capital (NWC) in year 2? What is the net cash flow from salvage (aka, the after-tax salvage value, or ATSV)? What is the project's NPV? Would you recommend purchasing the ranch? Briefly explain.

Let's define the functions given below:f(x) = (x + 1)²g(x) = x - 2Now we have to find fofog and gogof for the domain (-1, 2, 4] to Z.fofog

First, we will find g(x), then f(x), and then substitute the value of g(x) in place of x in f(x).This can be written as follows:f(g(x)) = f(x - 2) = [(x - 2) + 1]^2 = (x - 1)^2

Now, we have to substitute the domain (-1, 2, 4] one by one:(-1 - 2 - 4]For x = -1, f(g(-1)) = (-1 - 1)^2 = 4For x = 2, f(g(2)) = (2 - 1)^2 = 1For x = 4, f(g(4)) = (4 - 1)^2 = 9Therefore, fofog for the domain (-1, 2, 4] to Z is given by {(x, fofog(x)) : x ∈ (-1, 2, 4], fofog(x) ∈ {4, 1, 9}}gogof

For this, we will find f(x), then g(x), and then substitute the value of f(x) in place of x in g(x).This can be written as follows:g(f(x)) = g((x + 1)²) = (x + 1)² - 2

Now, we have to substitute the domain (-1, 2, 4] one by one:(-1 - 2 - 4]For x = -1, g(f(-1)) = (-1 + 1)^2 - 2 = -2For x = 2, g(f(2)) = (2 + 1)^2 - 2 = 9For x = 4, g(f(4)) = (4 + 1)^2 - 2 = 22

Therefore, gogof for the domain (-1, 2, 4] to Z is given by {(x, gogof(x)) : x ∈ (-1, 2, 4], gogof(x) ∈ {-2, 9, 22}}.Thus, the composite functions fofog and gogof have been calculated with the domain (-1, 2, 4] to Z.

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The graph of the function f(x) = ex - 2x has a horizontal tangent line at x = 0.693.

To find the values of x for which the graph of the function f(x) = ex - 2x has a horizontal tangent line, we need to determine when the derivative of the function is equal to zero. A horizontal tangent line occurs when the slope of the function is zero, which corresponds to the critical points of the function.

To find the critical points, we differentiate f(x) with respect to x. The derivative of ex is ex, and the derivative of -2x is -2. Setting the derivative equal to zero, we have ex - 2 = 0.

Adding 2 to both sides, we get ex = 2. Taking the natural logarithm of both sides, we have ln(ex) = ln(2), which simplifies to x = ln(2).

Therefore, the graph of f(x) = ex - 2x has a horizontal tangent line at x = ln(2) or approximately x = 0.693. At this point, the slope of the function is zero, indicating a horizontal tangent line.

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The matrix A:  [[0, 2], [2, 1]] has two eigen value i.e. λ1 = (1 + sqrt(17))/2,

λ2 = (1 - sqrt(17))/2 and their eigen values are [2/(1 + sqrt(17)), 1] , [2/(1 - sqrt(17)), -1] respectively and similarly the eigen value of the matrix

A^-1 is λ1 = (1 + sqrt(3))/2 ,  λ2 = (1 - sqrt(3))/2 and their eigen vector is

[2/(1 + sqrt(17)), 1] and [2/(1 - sqrt(17)), -1] respectively and the trace of the matrix  A and A-1 is 1 and 1/2 respectively.

To compute the eigenvalues and eigenvectors of matrix A, we need to solve the characteristic equation det(A - λI) = 0, where I is the 2x2 identity matrix.

STEP 1:-This gives us:

det(A - λI) = (0 - λ)(1 - λ) - 4 = λ^2 - λ - 4 = 0

Using the quadratic formula, we can solve for the eigenvalues:

λ1 = (1 + sqrt(17))/2

λ2 = (1 - sqrt(17))/2

STEP 2 :-To find the eigenvectors, we can solve the system of equations (A - λI)x = 0 for each eigenvalue. This gives us:

For λ1:

-λ1x1 + 2x2 = 0

2x1 - (λ1 - 1)x2 = 0

Solving this system, we get the eigenvector [2/(1 + sqrt(17)), 1].

For λ2:

-λ2x1 + 2x2 = 0

2x1 - (λ2 - 1)x2 = 0

Solving this system, we get the eigenvector [2/(1 - sqrt(17)), -1].

STEP 3:-

To compute the eigenvalues and eigenvectors of matrix A^-1, we need to solve the characteristic equation det(A^-1 - λI) = 0. We can simplify this expression using the fact that det(A^-1) = 1/det(A), which gives us:

det(A^-1 - λI) = (1/2 - λ)(-λ) - (1/2)(1) = -λ^2 + (1/2)λ - (1/2) = 0

Using the quadratic formula, we can solve for the eigenvalues:

λ1 = (1 + sqrt(3))/2

λ2 = (1 - sqrt(3))/2

We can see that A^-1 has the same eigenvectors as A, since the equation (A - λI)x = 0 is equivalent to A^-1(Ax - λx) = 0. Therefore, the eigenvectors of A^-1 are [2/(1 + sqrt(17)), 1] and [2/(1 - sqrt(17)), -1].

We can also check that the trace of A is equal to the sum of its eigenvalues, and the trace of A^-1 is equal to the sum of its eigenvalues. We have:

trace(A) = 0 + 1 = 1

trace(A^-1) = 1/2 + 0 = 1/2

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Answer:

1

_

25

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Hope this helps :3

Answer:

39.8°

Step-by-step explanation:

tan∅= opp/adj

tan∅=5m/6m

tan∅=0.8333

arc tan 0.8333=∅

39.8°=∅

The measurement scale used in the given example is an ordinal scale.

An ordinal scale is a type of measurement scale used to categorize or rank objects or events based on their relative size, order, or position. In the given example, the soccer players are classified into three categories - superior, above average, and average based on their athletic ability, which is a relative measure of their ability compared to other players. The categories are not based on any numerical value or fixed criteria, but rather on a subjective assessment of their ability. Therefore, the data is on an ordinal scale.

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An estimate for the total volume of food and water you've ingested in the last day is 3000-5000 milliliters. On average, the heart pumps about 5 liters of blood per minute. 10-20% or more error I'm expecting. Calculating heart blood volume compared to food and drink consumption is crucial for understanding circulation and liver function.

D.1 Estimating the amount of food and water consumed in a day can be difficult without specific measurements, but a rough estimate can be made based on typical intake amounts. On average, a person may consume 2-3 liters of water and 1000-2000 calories per day, resulting in an estimated total volume of 3000-5000 milliliters.

D.2 The amount of blood pumped by the heart varies from person to person and depends on factors such as heart rate and overall health. On average, the heart pumps about 5 liters of blood per minute, which is much larger than the estimated volume of food and water intake.

D.3 Estimating food and water intake and blood flow is prone to error due to variability and uncertainties in personal measurements. Individuals' habits, health, and physical activity levels can affect these estimates, potentially resulting in a significant error of 10-20% or more.

D.4 The calculation of the heart's blood volume compared to food and drink consumption is crucial for understanding the circulation system and liver role.

The liver processes nutrients, detoxifies, and produces blood components, while the heart is responsible for circulating blood throughout the body. The vast difference in volume between the two is emphasized, emphasizing the heart's crucial role in maintaining circulation.

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Answer:

the solution is 4sqrt(2)

1. The current total bid for Empire Design is $16.2 million.

2. The current total bid for Build-Em-Up Co. is $14.4 million.

We can determine the total bids by using multiplication and addition mathematical operations.

For each vendor, the total bids comprise the total cost based on distance and the total cost based on the number of beams.

The products are added to get the total bids (costs for each bidder).

Distance = 30 km

Number of Beams = 120

$300,000 x 30 =    $9,000,000              

$60,000 x 120 =     $7,200,000

Total bid costs =   $16,200,000

$320,000  x 30 =    $9,600,000

$40,000  x 120 =     $4,800,000

Total bid costs =    $14,400,000

Thus, if the two bidders share equal construction quality, the builder may decide to choose Build-Em-Up Co. whose total bid costs are less costly than Empires.

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A builder wants to build a bridge cross-section with the following particulars:

Distance = 30 km

Number of Beams = 120

Empire Design              Build-Em-Up Co.

$300,000 x d               $320,000 x d

$60,000 per beam      $40,000 per beam

What is the current total bid from each bidder?

Answer:

28 notes (or bills)

Step-by-step explanation:

28.56 to be exact

The left Riemann sum is the Riemann sum where the sample points are the left endpoint of each interval, while the right Riemann sum is the Riemann sum where the sample points are the right endpoint of each interval.So, we have;f(x) = 9 - x on [3, 8]; n = 5

We want to calculate the left and right Riemann sums for f on the given interval and for the given value of n = 5. We are given that f(x) = 9 - x on the interval [3, 8].

Therefore, we can divide the interval [3, 8] into n = 5 subintervals of equal width by using the formula for the width of the subinterval:Δx = (b - a)/n

where a = 3 (the left endpoint of the interval),

b = 8 (the right endpoint of the interval), and

n = 5 (the number of subintervals).

Thus, the width of each subinterval is given by:Δx = (8 - 3)/5 = 1.

The five subintervals are:[3, 4], [4, 5], [5, 6], [6, 7], [7, 8].The left endpoint of each subinterval is used as the sample point for the left Riemann sum, while the right endpoint of each subinterval is used as the sample point for the right Riemann sum.

1. Left Riemann sum

The left Riemann sum for f on [3, 8] with n = 5 is given by:L = f(3)Δx + f(4)Δx + f(5)Δx + f(6)Δx + f(7)Δx

.Substituting the values of Δx and f(x) in the above equation, we get:L = (9 - 3)(1) + (9 - 4)(1) + (9 - 5)(1) + (9 - 6)(1) + (9 - 7)(1)

= 6 + 5 + 4 + 3 + 2= 20.

2. Right Riemann sum

The right Riemann sum for f on [3, 8] with n = 5 is given by:R = f(4)Δx + f(5)Δx + f(6)Δx + f(7)Δx + f(8)Δx.

Substituting the values of Δx and f(x) in the above equation, we get:

R = (9 - 4)(1) + (9 - 5)(1) + (9 - 6)(1) + (9 - 7)(1) + (9 - 8)(1)

= 5 + 4 + 3 + 2 + 1

= 15.

Therefore, the left Riemann sum for f on [3, 8] with n = 5 is 20, while the right Riemann sum for f on [3, 8] with n = 5 is 15.

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Step-by-step explanation:

a ). red cards = 26

then probability is = no. of outcomes / total no. of outcome

p ( red card ) = 26 / 1040

p ( red card ) = 1 / 40

b ) kings = 4

p ( kings ) = 4 / 1040

p ( kings ) = 1 / 260

c ) queen of hearts = 1

p ( queen of heart ) = 1 / 1040

Answer:To divide 15a^6b^4 by 5a^2b, we can divide the coefficients and then divide the variables using the quotient rule of exponents, which states that when dividing two exponential terms with the same base, you can subtract the exponents.

So we have:

(15a^6b^4) / (5a^2b) = (15/5) * (a^6/a^2) * (b^4/b)

= 3a^(6-2)b^(4-1)

= 3a^4b^3

Therefore, the simplified result of dividing 15a^6b^4 by 5a^2b is 3a^4b^3

Step-by-step explanation:

The solution to the division is 3a⁴b³.

Given that we need to divide the expression (15a⁶b⁴) by (5a²b),

To divide the expression (15a⁶b⁴) by (5a²b), you need to apply the rules of division with variables and exponents.

Here's how you can simplify the expression:

When dividing with the same base, you subtract the exponents. In this case, the base is "a" and the exponents are 6 and 2.

Subtracting the exponents gives us a⁶ - a² = a⁶⁻² = a⁴.

Similarly, for the variable "b," the exponents are 4 and 1.

Subtracting the exponents gives us b⁴ - b¹ = b⁴⁻¹ = b³.

Now, let's simplify the coefficients. The coefficient 15 divided by 5 is 3.

Putting it all together, the expression (15a⁶b⁴) / (5a²b) simplifies to:

3a⁴b³

Hence the solution to the division is 3a⁴b³.

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The volume of the solid generated by revolving the region between y=2sin(x) and the x-axis for 6 ≤ x ≤ 5π/6 about the y-axis is 2π (6sin(6) - 5√3) cubic units.

To find the volume of the solid generated by revolving the region between y=2sin(x) and the x-axis for 6 ≤ x ≤ 5π/6 about the y-axis, we use the method of cylindrical shells.

The formula for the volume of the solid generated by revolving the region between y=f(x) and the x-axis for a ≤ x ≤ b about the y-axis is given by:

V = 2π ∫[a,b] x f(x) dx

In this case, f(x) = 2sin(x) and the interval is 6 ≤ x ≤ 5π/6, so we have:

V = 2π ∫[6,5π/6] x (2sin(x)) dx

Using integration by parts, we obtain:

V = -2π [x cos(x)]6^5π/6 + 2π ∫[6,5π/6] cos(x) dx

V = 2π [x sin(x)]6^5π/6 - 2π sin(5π/6) + 2π sin(6)

Simplifying the expression, we get:

V = 2π (6sin(6) - 5√3)

Therefore, the volume of the solid generated by revolving the region between y=2sin(x) and the x-axis for 6 ≤ x ≤ 5π/6 about the y-axis is 2π (6sin(6) - 5√3) cubic units.

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