A current carrying wire is placed vertically. the magnetic field around the wire is rotating clockwise around the wire. what direction is the current moving?

Answer:

kiloliter and megaliter

Explanation:

kilo is 1000 times bigger and mega is 1e+6 bigger

Answer:

Explanation:

1. If we increase the distance to twice it's original value, the light intensity is reduced by one-fourth, the light intensity would be:

I0/4

2. rms magnetic field is inversely proportional to distance, so the new rms magnetic field would be:

B0/2

3. average energy density is inversely proportional to the square of the distance, so the new average energy density is:

E0/4

Las respuestas a cada inciso son:

a) La resistencia equivalente de la "escalera" de resistores iguales de 125 Ω que se muestra en la figura adjunta es:

\(R_{t} = 341.7 \: \Omega\)

b) La corriente a través de cada uno de los tres resistores de la izquierda si se conecta una batería de 50.0 V entre los puntos A y B es:

a) En la imagen adjuntada correspondiente a la Figura 26-40, podemos observar que las resistencias 1, 2 y 3 están en serie, por lo tanto la ressitencia equivalente entre estas 3 es:

\( R' = R_{1} + R_{2} + R_{3} \)

De aquí en adelante tendremos presente que las todas las resistencias son iguales entre sí y por ende igual a 125 Ω. Las notaciones del 1 al 9 son para poder mostrar la resolución del problema.  

Entonces:

\( R' = 3R \)

Ahora, esta resistencia está en paralelo con la resistencia R₄, por lo tanto la resistencia equivalente entre estas dos es:

\( \frac{1}{R''} = \frac{1}{R'} + \frac{1}{R_{4}} = \frac{1}{3R} + \frac{1}{R} = \frac{4R}{3R^{2}} \)

\( R'' = \frac{3}{4}R \)

Luego, esta resistencia está en serie con las resistencias R₅ y R₆, por lo tanto:

\( R''' = R'' + R_{5} + R_{6} = \frac{3}{4}R + 2R = \frac{11}{4}R \)

Esta resistencia está ahora en paralelo con R₇, entonces:

\( \frac{1}{R''''} = \frac{1}{R'''} + \frac{1}{R_{7}} = \frac{4}{11R} + \frac{1}{R} = \frac{15R}{11R^{2}} \)

\( R'''' = \frac{11}{15}R \)

Finalmente, esta resistencis está en serie con las resistencias R₈ y R₉, por lo tanto la resistencia total es:

\(R_{t} = R'''' + R_{8} + R_{9} = \frac{11}{15}R + 2R = \frac{41}{15}R = \frac{41}{15}*125 \: \Omega = 341.7 \: \Omega\)

b) Para este inciso debemos usar la Ley de Kirchhoff, pues tenemos tres mallas. Supondremos que las corriente de cada malla fluiran en sentido horario, por lo tanto las ecuaciones de para cada malla serán:

Malla 1

Segun la ley de Ohm tenemos:

\(V-i_{1}R-i_{3}R=0\) (1)

Malla 2

\(-i_{2}R-i_{5}R-i_{2}R+i_{3}R=0\) (2)

Malla 3

\(-i_{4}R-i_{4}R-i_{4}R+i_{5}R=0\) (3)

Recordemos tambien que:

\(i_{1}=i_{2}+i_{3}\) (4)

\(i_{2}=i_{4}+i_{5}\) (5)

Lo que debemos hacer ahora es resolver el sistema de ecuaciones y encontrar los valore de las corrientes. Por lo tanto, los valores de las corrientes serán:

\(i_{1}=3/13\: A\)

\(i_{2}=4/65\: A\)

\(i_{3}=11/65\: A\)

\(i_{4}=1/65\: A\)

\(i_{5}=3/65\: A\)

Finalmente:

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Answer:

no idea

Explanation:

follow back if u like your mom after u see this

Answer:

1)5880 J

2)17,820

Explanation:

1) PE=mgh

=6×9.8×100

=5880 J

2)Ke=1/2mv^2

=1/2×110×18^2

=17,820 J

The magnetic field here is perpendicular to the coil's surface from outward to inward because the magnetic field's direction is from south pole to north pole inside the coil.

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the magnetic field and its own velocity acts on a moving charge in a magnetic field.

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Answer:

Newton’s Three Laws of Motion has a great impact.

Explanation:

Newton’s Three Laws of Motion has a great impact on the bowling game for the 2 students. When the student one throw ball to the student 2, the ball decrease its speed due to the gravity and opposing air. If these forces are removed from the system the ball will continue its motion till another force is applied on it. When the force applied to the ball it produces acceleration in the direction to the applied force. If the ball touches the ground it bounce back with equal force which is a reaction of the ground.

Answer:

C

Explanation:

15. 20

x4. x4

60. 80

80km/h

Answer:

80km/h

Explanation:

solution

given

d=20km

t=15min/60min=0.25h

s=?

s=d/t

s=20km/0.25h

s=80km/h

Given,

From the graph, the total displacement of the given object is d=0-7=-7 m

The total time duration, t=12 s

The average velocity is defined as the ratio of the total displacement to the total time duration.

Thus the average velocity of the given object is,

On substituting the known values,

Thus the average velocity of the given object from t=0 s to t=12 s is 0.583 m/s.

The ratio of z to h can be determined by comparing the densities of freshwater and saltwater. The density of a substance is defined as its mass per unit volume.

In this case, the density of freshwater is given as\(1.000 g/cm^3\), while the density of salt water is given as \(1.025 g/cm^3\). To find the ratio of z to h, we need to consider the relationship between density and volume. The density of a substance can be expressed as the ratio of its mass to its volume.

Let's assume z and h represent the volumes of freshwater and saltwater, respectively. Since density is constant for each type of water, we can set up the following equation:

\(1.000 g/cm^3\) (density of freshwater) = \(1.025 g/cm^3\) (density of saltwater)

By canceling out the units, we get:

\(1.000 (g/cm^3) = 1.025 (g/cm^3)\)

Since the densities are equal, we can conclude that the ratio of z to h is 1:1.

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The heat capacity of copper in trial 1 is 1.67 J/(g*K). To determine the heat capacity of copper (Cu) in trial 1, we used the given information in the query.

To determine the heat capacity of copper (Cu) in trial 1, we would need to know the mass of the copper used, the change in temperature of the copper, and the amount of heat added or removed from the copper during the process.

We can use the following formula to calculate the heat capacity of the copper:

where:

q is the amount of heat added or removed (in joules)

m is the mass of the metal (in grams)

ΔT is the change in temperature (in Kelvin)

In trial 1, we heated a 50 gram sample of copper from an initial temperature of 25°C to a final temperature of 85°C, using a heat source that added 5000 joules of heat to the system. We can calculate the heat capacity of copper as follows:

ΔT = T_final - T_initial = (85 + 273) K - (25 + 273) K = 60 K

q = 5000 J

m = 50 g

C = q / (m * ΔT)

= 5000 J / (50 g * 60 K)

= 1.67 J/(g*K)

Therefore, the heat capacity of copper in trial 1 is 1.67 J/(g*K).

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Complete Question:

Showing your calculation determines the heat capacity of the metals for each trial:

a) known metal : cu trial 1: mass 50 grams: initial temperature 25 : final temperature 85 : heat added 5000J.

We want to explain why two different observes may measure different frequencies for the same vibrating object.

We will see that the two correct options are:

Let's assume that the vibrating object is a guitar string. Thus, the string makes a noise, and from that noise, we can estimate the frequency at which the string vibrates.

Now there appears a really cool effect, called the Doppler Effect. It says that the apparent change of frequency is due to the motion of the observer or the source of the frequency (or both).

For example, if you move towards the vibrating string, the perceived frequency will be larger, and you will hear a "higher" sound.

While if you move away from the string, the opposite happens, and you will hear a "lower" sound.

Then the only thing that impacts in how we perceive the frequency is our velocity relative to the source.

So, why do observers A and B measure different frequencies?

The two correct answers are:

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Your Answers for Redshift and Blueshift Quick Check are down here ↓

Which situations might cause two observers (A and B) to measure different frequencies for the same vibrating object? Select the two correct answers. (2 points)

Observer A is stationary and Observer B is moving. * A = yes

Observer A and Observer B are moving at different speeds relative to each other. * B = yes

Observer A and Observer B are stationary but at different distances from the vibrating object. No

Observer A and Observer B are both stationary and at the same distance from the object. No

Why do scientists observe blueshift in certain stars?(1 point)

Light wave frequencies increase as an object moves toward the observer. * A = yes

Stars with lower temperatures emit more light waves at the blue end of the spectrum. No

Light wave frequencies decrease as an object moves toward the observer. No

Stars with higher temperatures emit more light waves at the blue end of the spectrum. No

When will a scientist observe redshift in the spectrum of a distant space object?(1 point)

when the object is stationary. No

when the object is moving toward the scientis. No

when the object is moving away from the scientist * C = yes

when the object is in the same frame of reference as the scientist. No

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The type of objects occur in the halo of our Milky Way galaxy are Globular clusters. Correct option is C.

Globular groups, sub-dwarf stars, and RR Lyrae stars with little metal are all found in the stellar halo of the Milky Way. The majority of the stars in our stellar halo are older (more than 12 billion years old) and less metallic than disc stars, but some halo star groups have metal contents that are comparable to disc stars.

Very few, dispersed stars and globular groups reside in the halo. In spiral galaxies, dark matter also resides in the fringe.

The visible part of what is more generally referred to as the galactic halo is the stellar corona of the Milky Way. Dark matter dominates this galactic halo, and the gravity it produces is the only way to detect its existence. Each galaxy has a unique dark matter ring. And the correct option is C.

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Answer:

Of the inner planets, Mercury and Venus have no natural satellites; Earth has one large natural satellite, known as the Moon; and Mars has two tiny natural satellites, Phobos and Deimos.

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Earth has one large natural satellite, known as the Moon.

In fact, most satellites -- especially the bits of debris -- are too faint to be seen with the unaided eye. But depending on who's counting, several hundred can be spotted with the unaided eye.

Right now, there are nearly 6,000 satellites circling our tiny planet. About 60% of those are defunct satellites—space junk—and roughly 40% are operational. The Union of Concerned Scientists (UCS), determined that 2,666 operational satellites circled the globe in April of 2020.

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Answer:

Yes

Explanation:

When the planet moves farther away, the speed and kinetic energy decrease, and the gravitational potential energy increases.

A. Total momentum in a closed system is conserved

the law of momentum conservation states that The total amount of momentum before the collision is the same as the total momentum after the collision. Regardless of the change of momentum of each object.

Let, time taken is t.

So,

\(s=ut + \dfrac{gt^2}{2}\\\\75 = 0 + \dfrac{10\times t^2}{2}\\\\150=10\times t^2\\\\t = \sqrt{15}\\\\t = 3.873\ s\) ( Here, us is vertical component of initial velocity )

Now, distance covered from the base of the cliff is :

\(D=5\times 3.873\ m\\\\D = 19.365\ m\)

Therefore, time taken and distance covered is 3.873 s and 19.365 m.

Hence, this is the required solution.

Answer:

Explanation:

Overgrazing and woodcutting are responsible for most of the desertification of rangelands, cultivation practices inducing accelerated water and wind erosion are most responsible in the rain-fed croplands, and improper water management leading to salinization is the cause of the deterioration of irrigated lands.

Answer:

0

Explanation:

the forces gets cancelled off. hence when applying F=Ma, F=0 therefore a=o

The acceleration of the cart is 0m/s². Option A is correct.

According to Newton's second law of motion:

\(\sum F=ma\)

m is the mass of the object

a is the acceleration

If a force of 25 newtons east and a force of 25  newtons, then the sum of force is expressed as:

\(\sum F = 25 - 25 =0N\)

Get the acceleration

\(a=\frac{\sum F}{m} \\a=\frac{0}{5} \\a=0m/s^2\)

Hence the acceleration of the cart is 0m/s²

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The net force on an object is zero that is pulled with forces of 80 newtons to the right and 80 newtons to the left.

Net force is equal to sum of all the force acting on a body.

The formula for net force if n force are acting on it:

                       \(F_{net}=F_{1}+ F_{2}+F_{3}.....F_{n}\)

In this case the two forces are equal but opposite in direction.

Putting the values in the formula

\(F_{net} = 80+(-80)\) (since forces are equal but opposite)

\(F_{net}= 0\)

So the net force acting on the object is zero because the forces are equal and opposite.

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The net force on an object that is pulled with forces of 80 newtons to the right and 80 newtons to the left is: 0 newtons

To solve this problem the formula of net force and the procedure that we have to use is:

Fr = ∑F

Where:

Information about the problem:

Applying the resultant force formula we get:

Fr = ∑F

Fr = F1 + F2

Fr = 80 newtons - 80 newtons

Fr= 0 newtons

We can say that the resultant force is the algebraic sum of all the forces acting on a body.

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Explanation:

If the micrometer is still in the working condition, it will be hard for the observer to find its accuracy or precision, which could be matched with the meter stick. Its accuracy can be compromised in comparison with the undamaged micrometer, but it would be more chances of highly precise.

The error which is find in the damaged micrometer would be less than as compared to the width of the hash marks on the stick.

Answer:

The bent micrometer will be more precise but less accurate than the meterstick

Explanation:

Answer: it is A hope that helps

Explanation:

The number of choices you have in this scenario is equal to the number of available quantities for each fruit.

If the number of pears you buy must be equal to the number of bananas you buy, then the choices you have will be limited. Let's say there are n available quantities for each fruit. In this case, you will have n choices because for each possible quantity of pears, there is only one corresponding quantity of bananas that you can buy to maintain the equal count.

For example, if there are 3 available quantities for each fruit (n = 3), your choices could be:

Buy 1 pear and 1 banana

Buy 2 pears and 2 bananas

Buy 3 pears and 3 bananas

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Power describes the rate of the work that is being done. The correct option is A.

Power is defined as the rate at which work is done or the amount of work done per unit time. In other words, power describes how quickly work is being done or how fast energy is being transferred.

The unit of power is the watt (W), which is equal to one joule of work per second.

Power can be calculated by dividing the amount of work done by the time it takes to do that work, or by multiplying the force applied by the distance traveled and dividing by the time it takes to travel that distance.

For example, if a machine does 100 joules of work in 10 seconds, then the power of the machine is 10 watts, calculated as:

Power = Work / Time

Power = 100 J / 10 s

Power = 10 W

Therefore, power describes the rate or speed at which work is being done, and it is measured in watts.

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The angular speed of Io as it orbits Jupiter is approximately: 9.43 x 10⁻⁵ rad/s.

The formula for angular speed w = 2π/T relates the angular displacement per unit time to the time for one complete orbit. To use this formula, we need to convert the time for one orbit from days to seconds by multiplying by 24 (hours per day) and 3600 (seconds per hour), giving:

T = 1.77 x 24 x 3600 seconds = 153216 seconds

The average distance between Jupiter and Io is 4.22 x 10^8 m, which is the radius of the circular orbit that Io follows around Jupiter. Therefore, the circumference of the orbit is 2π times the radius, or:

C = 2π x 4.22 x 10^8 m = 2.66 x 10^9 m

The angular speed w of Io can now be calculated using the formula w = 2π/T, which gives:

w = 2π / (1.77 x 24 x 3600) seconds⁻¹ = 9.43 x 10⁻⁵ rad/s

As a result, Io orbits Jupiter at an angular speed of 9.43 x 10⁻⁵ rad/s.

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Complete question:

Io Completes One Orbit About Jupiter In 1.77 Days And The Average Jupiter-Io Distance Is 4.22 X 100 M. Calculate The Angular Speed W Of Io As It Orbits Jupiter. W = Rad/S

Answer:

here

Explanation:

in torque the length dimension is measured perpendicularly to the direction of the force, and acts as a multiplier of the linear force. Torque is equivalent to force in rotary systems.

Given that a car and a train each make a trip that is 120 km and the average speed of a train is 40 km/h faster than a car. We need to find the average speed of the car.Let the average speed of a car be x km/hour.So the average speed of the train is (x + 40) km/hour. According to the question, time taken by the train is 30 minutes less than the car, so time taken by the car is:

t = d/swhere t = time taken, d = distance covered, and s = speed of the carThe time taken by the train is:t - 0.5h = d/(x + 40)Here, 0.5 hour is equal to 30 minutes.Now, both the car and the train covered the same distance. Hence we have:t = d/xUsing the formulae for t in both equations, we have:d/x - 0.5 = d/(x + 40)Cross-multiplying the above equation, we get:d(x + 40) - 0.5x(x + 40) = dxSimplifying the above expression, we get:x² - 80x - 2400 = 0We can solve the above quadratic equation to get the values of x.

Using the main answer, the average speed of the car is 60 km/h.The explanation to find the average speed of the car:Given, a car and a train each make a trip that is 120 km. Let the average speed of a car be x km/h. Therefore, the average speed of the train is (x + 40) km/hour.The time taken by the train is t - 0.5h = d/(x + 40).Using the formulae for t in both equations, we have:d/x - 0.5 = d/(x + 40)Cross-multiplying the above equation, we get:d(x + 40) - 0.5x(x + 40) = dxSimplifying the above expression, we get:x² - 80x - 2400 = 0We can solve the above quadratic equation to get the values of x.Using the main answer, the average speed of the car is 60 km/h.

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A measure of mass per unit of volume. It is how much material a certain volume contains. ... If the volume of the object stays the same but the mass of the object increases then its density becomes greater.