a concave mirror forms a real image twice as large as the object. the object is then moved such that the new real image produced is three times the size of the object. if the image was moved 70.9 cm from its initial position, ...a) ... how far was the object moved? (if it was moved closer to the mirror, the result will be negative. if it was moved farther away from the mirror, the result will be positive).

The power required to move the automobile to the top of the hill is 130,666.67 watts or 175.41 horsepower.

The power required to move an object can be calculated using the formula: power = work / time.

First, let's calculate the work done in lifting the automobile to the top of the hill. The work done against gravity is given by the formula: work = force × distance.

The force required to lift the automobile is equal to its weight. The weight of an object is given by the formula: weight = mass × acceleration due to gravity.

Substituting the given values, we have: weight = 2,000 kg × 9.8 m/s^2 (acceleration due to gravity) = 19,600 N.

The distance the automobile is lifted is 100 meters.

Therefore, the work done against gravity is: work = 19,600 N × 100 m = 1,960,000 J (joules).

The time taken to reach the top of the hill is given as 15.0 seconds.

Now, we can calculate the power using the formula: power = work / time.

power = 1,960,000 J / 15.0 s = 130,666.67 W (watts).

To convert watts to horsepower, divide the power in watts by 746 (1 horsepower = 746 watts).

power in horsepower = 130,666.67 W / 746 = 175.41 hp (horsepower).

Rounding to two decimal places, the power required to move the automobile to the top of the hill is approximately 130,666.67 watts or 175.41 horsepower.

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The  to problem of calculating the power required to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15.0 seconds is given

Given, Mass of the automobile, m = 2000 knight of the hill, h = 100 time, t = 15.0 the gravitational potential energy of the automobile when at the bottom of the hill is equal to the work done in lifting it up the hill

.W = mgh= (2000 kg) (9.81 m/s²)

(100 m)= 1,962,000 J

Power is defined as the rate at which work is done, or the work per unit time. Therefore,

Power = Work / Time= 1,962,000 J / 15.0 s

= 130,800 WIn horsepower, Power = (130,800 W) / (746 W/hp)

= 175.3 hp

Therefore, the required power to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15.0 seconds is 130,800 W or 175.3 hp.

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The mathematical representation of a sine wave with a peak amplitude of 5 and a frequency of 500 Hz is y(t) = 5sin(2π500t). The corresponding period for a frequency of 18 Hz is 0.0556 seconds (s). The corresponding period for a frequency of 20 MHz is 0.00000005 seconds (s).

(a) The mathematical representation of a sine wave with a peak amplitude of 5 and a frequency of 500 Hz is:

y(t) = 5sin(2π500t)

(b) To calculate the corresponding period for a frequency of 18 Hz:

Period (T) = 1 / Frequency

T = 1 / 18 Hz = 0.0556 seconds (s)

Converting to milliseconds: T = 0.0556 s * 1000 ms/s = 55.6 milliseconds (ms)

Converting to microseconds: T = 0.0556 s * 1000000 μs/s = 55600 microseconds (μs)

(c) To calculate the corresponding period for a frequency of 20 MHz:

Period (T) = 1 / Frequency

T = 1 / 20,000,000 Hz = 0.00000005 seconds (s)

Converting to milliseconds: T = 0.00000005 s * 1000 ms/s = 0.00005 milliseconds (ms)

Converting to microseconds: T = 0.00000005 s * 1000000 μs/s = 0.05 microseconds (μs)

(d) To calculate the corresponding period for a frequency of 4 kHz:

Period (T) = 1 / Frequency

T = 1 / 4,000 Hz = 0.00025 seconds (s)

Converting to milliseconds: T = 0.00025 s * 1000 ms/s = 0.25 milliseconds (ms)

Converting to microseconds: T = 0.00025 s * 1000000 μs/s = 250 microseconds (μs)

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The electric field at x=2m is 800V/m since the derivative of 200x² with respect to x is 400x, and when x=2m, Ex=400*2=800V/m.

The electric field along the x-axis can be found by taking the derivative of the electric potential function with respect to x.

Therefore, Ex at x=0m would be 0 since the derivative of any constant term (in this case, the constant term is 0) is 0. Ex at x=2m would be 800V/m since the derivative of 200x² with respect to x is 400x and when x=2m, Ex=400*2=800V/m.

The electric potential is a measure of the electric potential energy per unit charge at a given point in space. It is a scalar quantity and is related to the electric field, a vector quantity, by a gradient relationship.

The electric field is the negative gradient of the electric potential, which means that the electric field is the rate at which the potential changes per unit distance in a particular direction.

In this case, the electric potential along the x-axis is given as V=200x², and the electric field can be found by taking the derivative of this function with respect to x. The electric field at x=0m is zero since the derivative of any constant term is zero.

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Answer: B

Explanation:

It is given that the first collision is elastic so we can conserve momentum as well as the kinetic energy of the system.

The value of the coefficient of restitution is equal to one for an elastic collision. An elastic collision is also called a perfectly Elastic collision.

A perfectly inelastic collision is one in which there is the loss of kinetic energy and some of the kinetic energy is converted into another form of energy, for example, internal energy.

although momentum is conserved in Inelastic collision kinetic energy is not conserved.

Answer:

1 Unit Electricity is the amount of electrical energy consumed by a load of 1 kW power rating in 1 hour..

Explanation:

The specific heat of pure water is 4.184 J/g °C. A 10.00-gram sample of pure water goes from 22.00°C to 32.00°C. The specific heat of pure water is 4.184 J/g °C. A 10.00-gram sample of pure water goes from 22.00°C to 32.00°C. sample gain  418.4 J. Therefore correct option is B.

To calculate the amount of heat gained by the sample of water, we can use the formula:

q = m × c × ΔT

where q is the amount of heat gained, m is the mass of the sample (in grams), c is the specific heat of water (in J/g °C), and ΔT is the change in temperature (in °C).

Plugging in the values given in the question, we get:

q = 10.00 g × 4.184 J/g °C × (32.00°C - 22.00°C)
q = 10.00 g × 4.184 J/g °C × 10.00°C
q = 418.4 J

Therefore, the answer is B. 418.4 J.

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Answer:

Velocity as a Vector Quantity

=Because the person always returns to the original position, the motion would never result in a change in position. Since velocity is defined as the rate at which the position changes, this motion results in zero velocity. ... As such, velocity is direction aware.

Explanation:

please mark me brainliest please.

the value of ax, given the data from the question is 4.55 m/s²

From the question given above, the following data were obtained:

s = ½at²

s = ½ × ax × 2²

s = 2ax

v = at

v = ax × 2

v = 2ax

Remaining distance = velocity × remaining time

Remaining time = 12 - 2 = 10

Remaining distance = 2ax × 10

Remaining distance = 20ax

Total distance = Distance for first 2 s + Remainng distance

100 = 2ax + 20ax

100 = 22ax

Divide both sides by 22

ax = 100 / 22

ax = 4.55 m/s²

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Answer:

15 kg ball

Explanation:

Answer:

When insulating materials rub against each other, they may become electrically charged . The material that gains electrons becomes negatively charged The material that loses electrons is left with a positive charge

Explanation:

The diffusion coefficient of electrons is 4.28 x 10⁻¹⁰ \(m^2/s.\)

To calculate the diffusion coefficient of electrons, we can use the Einstein relation:

D = kT/u

where D is the diffusion coefficient, k is Boltzmann's constant (1.38 x 10⁻²³ J/K), T is the temperature in Kelvin, and u is the electron mobility.

Plugging in the values given in the problem:

u = 970 \(cm^2/Vs\) (note that the units need to be converted to \(cm^2/Vs\))

T = 300 K

k = 1.38 x 10⁻²³ J/K

Converting the units of electron mobility from \(cm^2/Vs\) to \(m^2/s\) gives:

u = 9.7 x 10⁻³  \(m^2/s\)

Now we can calculate the diffusion coefficient:

D = kT/u

D = (1.38 x 10⁻²³ J/K) x (300 K) / (9.7 x 10⁻³ \(m^2/s\))

D = 4.28 x 10⁻¹⁰ \(m^2/s\)

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Answer:

2.2 m/s

Explanation:

r = 0.1 m

ω₀ = 0 rad/s

α = 4.4 rad/s²

t = 5 s

ω = αt + ω₀

ω = (4.4 rad/s²) (5 s) + 0 rad/s

ω = 22 rad/s

v = ωr

v = (22 rad/s) (0.1 m)

v = 2.2 m/s

The linear velocity is 2.2 m/s

Given:

r = 0.1 m

ω₀ = 0 rad/s

α = 4.4 rad/s²

t = 5 s

So from the equation for angular acceleration we will get,

ω = αt + ω₀

ω = (4.4 rad/s²) (5 s) + 0 rad/s

ω = 22 rad/s

Angular velocity ω is analogous to linear velocity v

The relation between velocity and angular acceleration is given which is:

v = ωr

v = (22 rad/s) (0.1 m)

v = 2.2 m/s

Therefore, linear velocity of  the point on its rim after 5s is​ 2.2 m/s.

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As the rollercoaster moves from point A to point B, the correct answer is option c: The kinetic energy increases and the potential energy decreases.

At point A, the rollercoaster is at its highest position, which corresponds to the maximum potential energy and minimum kinetic energy. As the rollercoaster moves downwards towards point B, it gains speed and its height decreases.

This results in a decrease in potential energy since the height is decreasing. At the same time, the rollercoaster's speed increases, leading to an increase in kinetic energy.

The conservation of energy principle states that the total mechanical energy (the sum of potential energy and kinetic energy) of a system remains constant in the absence of external forces.

In this case, as the rollercoaster moves from point A to point B, the decrease in potential energy is equal to the increase in kinetic energy, keeping the total mechanical energy constant.

Therefore, the correct answer is option c: The kinetic energy increases and the potential energy decreases.

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Answer:

The force of gravitational attraction is 8.454 x 10⁻⁸ N.

Explanation:

Given;

mass of the boy, m₁ = 78 kg

mass of the girl, m₂ = 65 kg

distance between the boy and the girl, r = 2 meters

The force of gravitational attraction is given as;

\(F = \frac{Gm_1m_2}{r^2}\)

where;

G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

r is the distance between two masses, m₁ and m₂

\(F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67 \times 10^{-11})(78 \times 65)}{2^2}\\\\F = 8.454 \times 10^{-8} \ N\)

Therefore, the force of gravitational attraction is 8.454 x 10⁻⁸ N.

Answer:(d) mass

Explanation: The kilogram is the standard mass unit that is used almost globally and is the SI unit of mass. The kilogram weighs 9.8 Newtons under normal conditions on the surface of the Earth, and Newton is the corresponding SI unit of force and weight.

The energy of the scattered photon increases as the scattering angle in the Compton effect increases. The correct option is A.

The Compton effect refers to the scattering of photons by charged particles, typically electrons. When a photon interacts with an electron, it can transfer some of its energy and momentum to the electron. As a result, the photon changes its direction and its energy.

In the Compton effect, the change in the energy of the scattered photon depends on the scattering angle, which is the angle between the initial and final directions of the photon. According to the Compton formula, the change in energy (ΔE) of the scattered photon is given by:

ΔE = E' - E = \(\frac{{h}}{{m_e c}}(1 - \cos \theta)\),

where E' is the energy of the scattered photon, E is the initial energy of the photon, h is the Planck's constant, me is the mass of the electron, c is the speed of light, and θ is the scattering angle.

From the Compton formula, it can be observed that as the scattering angle increases (θ increases), the term (1 - cosθ) becomes larger, resulting in a larger change in energy (ΔE). Therefore, the energy of the scattered photon increases as the scattering angle increases in the Compton effect. Option A is the correct answer.

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The mercury content, CFLs (compact fluorescent lamps) contain a small amount of mercury, typically about 4-5 milligrams per bulb. The mercury is essential for the functioning of the bulb because it helps to create the ultraviolet light that activates the phosphors, which in turn produce visible light.

The mercury is tightly bound within the CFL and is not released unless the bulb is broken. In fact, a study by the US Department of Energy found that CFLs emit less mercury overall compared to incandescent bulbs, taking into account the amount of electricity needed to power them. On the other hand, incandescent bulbs do not contain any mercury, but the production and consumption of electricity needed to power them can result in mercury emissions. Coal-fired power plants are the largest source of mercury emissions in the United States, and when incandescent bulbs are used, more electricity is needed to produce the same amount of light as a CFL. Additionally, proper disposal of CFLs can further reduce the risk of mercury pollution. It's important to note that newer LED (light-emitting diode) bulbs have even lower mercury content and are even more energy-efficient than CFLs, making them a great choice for environmentally conscious consumers.

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Answer:

Nucleus :)

Explanation:

An electron will only react with a proton in the nucleus via electron capture if there are too many protons in the nucleus.

I also learned this in freshman year in high school for biology.

Answer:

Nucleus

Explanation:

The Heisenberg Uncertainty Principle explains why electrons do not fall into the nucleus of an atom. The principle specially states that the product of the uncertainty of position and the uncertainty of momentum is greater than or equal to Planck's reduced constant divided by two.

Answer:

Foil insulation can prevent radiant heat loss all year round. In summer, it can prevent heat from entering by reflecting sunlight. In winter, it can reflect heat back inside a room, keeping it warmer.

Answer:

C

Explanation:

Answer:

A isolate the DNA From a sample of cells

Answer:

true

Explanation:

Just searched it

Telescopes designed to study the earliest stages in galactic lives should be optimized for observations in infrared light (Option C).

Telescopes designed to study the earliest stages of galactic formation need to observe light that can penetrate the dust clouds that often obscure these early events. Infrared light is well suited for this purpose because it has longer wavelengths than visible light and can penetrate dust clouds more easily. Infrared telescopes can detect the heat radiation given off by the dust, which is a signature of the formation of stars and planets.

Additionally, infrared light can reveal the presence of cold gas, which is necessary for the formation of stars. By using telescopes optimized for observations in infrared light, astronomers can gain important insights into the early stages of galactic lives.

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Answer:

Which best describes what happens if two waves meet and build on each other?

destructive interference

reflection

absorption

Explanation:

When two waves meet in phase they will overlap together and form a constructive interference. The resultant amplitude of the waves will be greater than that of individual waves.

A wave of greater, lower, or the same amplitude is created when two waves merge through interference by combining their displacements at all points in space and time.

The interaction of waves that are coherent or correlated with one another, either because they originate from the same source or because their frequencies are similar or almost identical, leads to both constructive and destructive interference.

All sorts of waves, including light, radio, acoustic, surface water waves, gravity waves, and matter waves, can exhibit interference effects. In constructive interference, the waves are in single phase forms a resultant wave with higher amplitude.

When waves from out of phase meets, the resultant wave will have an amplitude less than the individual amplitudes. Here, the waves are meet in phase and build on each is constructive interference.

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Explanation:

a) Velocity and acceleration of a car are parallel when the car is moving along a straight line in the same direction. For example, when a car is gaining speed as it moves forward in a straight line, both velocity and acceleration are directed in the same direction.

b) Velocity and acceleration of a car are anti-parallel when the car is moving along a straight line in the opposite direction. For example, when a car slows down while moving in a straight line, its acceleration is directed opposite to the direction of its velocity, or the other way around.

Answer:

a)

There is only one case where velocity and acceleration are parallel only when they are moving in the same direction.

b)

There are 3 cases where velocity and acceleration are antiparallel.

(i) When both are moving in different direction

   It means :

(ii) When the object is slowing down, where velocity and acceleration are in the opposite direction.

(iii) In case of motion reversal.

Explanation:

Answer:

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The arrow pointing downwards ↓ represents emission of energy from higher excited state to lower excited state whereas the arrow pointing upwards ↑ represents the absorption of energy from lower excited state to higher excited state.

In a process known as absorption, an atom takes on energy from its surroundings to move from its ground state to its excited state. After taking in the energy, the electron ascends to a higher energy level.

Conservation of momentum can be applied here because the electron only takes in energy when it is exactly in line with its energy gap. Because photons and electrons have wavelengths that are nearly identical, you can say that electrons absorb energy.

When electrons regain their energy levels, they emit. When electrons absorb energy, they move to higher energy levels. By revealing the number of energy levels and the space between them, light absorption and emission reveal details about an atom's atomic structure.

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Answer:

The student would definitely weigh lower than 71 kg when the student rolls down the incline on their skateboard. This is because as he goes down, there will be air pushing against him, and though it isn't enough to fully lift him, the air pressure is enough to decrease the student's original weight. It mainly depends on how steep the incline is; if the incline is just enough to get him going, then the bar will show just a bit less than 71 kg after a while. However, if the student goes down a much steeper incline, say something like just a bit further out than a wall at 90 degrees, then the student will most probably have a much less weight than 71 kg.

Kinda long, but hope it helps.

Answer:

Below

Explanation:

Find acceleration first

vf = vo + at     (starts from rest so vo = 0)

8 = 0 + at    

8 = at

d = vo t + 1/2 a t^2     (substitute 8 in for 'at')

200 = 0 t  + 1/2 (8) t

200 / 4 = t = 50 seconds for front of train to pass her at 8 m/s

  acceleration = change in velocity / change in time = 8 / 50 = .16 m/s^2

Back of train has to travel 120 meters at initial v = 8 m/s  and accelerating  at .16 m/s^2   :

  d = vo t + 1/2 a t^2

 120 = 8 t + 1/2 ( .16 ) t^2

           .16t^2 + 8t - 120 = 0      Quadratic Formula shows t = 13.25 s

vf = vo  + a t

vf = 8 m/s  + .16 m/s^2 ( 13.25 s) = 10.1 m/s