b. In order to determine the speed of the coin, use the following formula:
\(v=\omega r=\frac{2\pi}{T}\cdot r\)where,
T: period = 1.80s
r: distance of the coin to the center of the record = 10.3 cm, 17.8 cm
Replace the previous values of the parameters into the formula for v and simplify:
c. The acceleration of the coin is given by:
\(a=\frac{v^2}{r}\)Then, by replacing the values of v and r, you obtain:
d. In this case, the force is about the centripetal force, which is given by:
\(F=ma\)By using the previous results, you obtain:
A baton twirler throws a spinning baton directly upward. As it goes up and returns to the twirler’s hand, the baton turns through four revolutions. Ignoring air resistance and assuming that the average angular speed of the baton is 1.90 rev/s, determine the height to which the center of the baton travels above the point of release.
the answer is in the photo.
HELPPPP LATE HOMEWORK DUE TODAY
If F₁ has a greater magnitude than F₂, the box will accelerate backward because the net force is in the backward direction (1st option)
How do i know which direction the box will move to?To obtain the direction in which the box will move, we shall determine the net force acting on the box. This is illustrated below:
Assumption:
Magnitude of force 1 (F₁) = 40 NMagnitude of force 2 (F₂) = 25 NNet force (F) =?Net force = Magnitude of force 1 (F₁) - Magnitude of force 2 (F₂)
Net force = F₁ - F₂
Net force = 40 - 25
Net force = 15 N backward
From the above illustration, we can see that the net force is 15 N backward.
Thus, we can conclude from the box will accelerate backward (1st option)
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Find distance between two object of radius 6 cm and 2 cm
The distance between two objects of radius 6 cm and 2 cm is zero
To find the distance between two objects with radii of 6 cm and 2 cm, we need to consider the center-to-center distance between the objects and subtract the sum of their radii.
Let's denote the radii of the objects as r1 = 6 cm and r2 = 2 cm.
The distance between the centers of the objects can be represented as d = r1 + r2. Adding the radii ensures that we account for the space occupied by both objects.
Substituting the values, we have d = 6 cm + 2 cm = 8 cm.
Now, to find the actual distance between the objects, we subtract the sum of their radii from the center-to-center distance:
Distance = d - (r1 + r2) = 8 cm - (6 cm + 2 cm) = 8 cm - 8 cm = 0 cm.
The resulting distance is 0 cm, indicating that the objects are in direct contact with each other. This means that their surfaces are touching. When the distance between two objects is zero, it implies that they are overlapping or in physical contact. In this case, since the distance is equal to 0 cm, the two objects are touching each other, with their surfaces coming into contact.
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what is the average gravitational force of attraction between the earth and the sun? the earth averages a distance of about 150 million km. the earth has a mass of 5.97x10^24 kg, and the sun has a mass of about 2x10^30 kg.
Answer:
B
Explanation:
Hhhhh
two wharves A and B are directly opposite each other on a 40m wide river which flows in the direction shown. a boat leaves A and heads at constant speed at right angles to the flow of the river. it lands at point C, with the trip taking 20 seconds.
find;
a) the displacement from C to A
b) the speed of the boat as seen by people standing at A.
c) the speed of the water in the river
d) the speed of the boat as seen by a fish drifting with the river.
e) Draw a vector diagram and u
se it to find the direction the boat should head ( at the same constant speed as before) if it is to travel directly from A to B.
Answer:
a)40 meters
b)2 m/s
c)2 m/s
d)0 m/s
e)45 degrees northeast
Explanation:
a) The displacement from C to A is the distance directly across the river, which is 40 meters.
b) The speed of the boat as seen by people standing at A is the magnitude of the boat's velocity vector, which is equal to the displacement divided by the time taken:
Speed = displacement / time = 40 m / 20 s = 2 m/s.
c) Let v be the speed of the water in the river. The boat is moving at right angles to the flow of the river, so the water exerts a perpendicular force on the boat. The time taken for the boat to travel from A to C is 20 seconds, during which time the boat will have been carried downstream by the river by a distance equal to v times the time taken.
Distance carried downstream = v × time = v × 20 m.
Since the boat landed at C, which is directly across the river from A, the distance it traveled horizontally is 40 meters. Therefore:
40 m = (boat speed) × (time taken) = (boat speed) × 20 s.
Hence, the speed of the boat is:
Boat speed = 40 m / 20 s = 2 m/s.
So, we have two equations:
Distance carried downstream = v × 20 m
Boat speed = 2 m/s
From the first equation, we get:
v × 20 m = 40 m
Therefore, the speed of the water in the river is:
v = 40 m / 20 m = 2 m/s.
d) The speed of the boat as seen by a fish drifting with the river is the difference between the speed of the boat and the speed of the water in the river:
Boat speed - Water speed = 2 m/s - 2 m/s = 0 m/s.
So, the speed of the boat as seen by a fish drifting with the river is zero.
e) The boat should head in a direction that makes its velocity vector point directly from A to B. Since A and B are directly opposite each other, this means the velocity vector should be perpendicular to the line connecting A and B.
We know the boat's velocity vector has a magnitude of 2 m/s and is at right angles to the velocity vector of the water in the river, which has a magnitude of 2 m/s. So, we can draw a vector diagram with the velocity vector of the boat pointing straight up and the velocity vector of the water pointing straight to the right. The vector connecting the tail of the water velocity vector to the head of the boat velocity vector will then point directly from A to B.
The angle between the boat's velocity vector and the line connecting A and B can be found using trigonometry. Let θ be this angle. Then:
tan(θ) = (boat speed) / (water speed) = 2 m/s / 2 m/s = 1.
Taking the inverse tangent of both sides gives:
θ = tan^(-1)(1) = 45°.
So, the boat should head in a direction 45 degrees to the right of straight up, or northeast.
choose inertial frames. check all that apply. choose inertial frames.check all that apply. a carousel rotates at a constant speed. a vertically tossed ball is at the highest point of its trajectory. a plane moves at a constant speed of 254 m/s . at the instant the traffic light turns green, a bus starts from rest
The highest point in a ball's trajectory is when it is thrown vertically. The average speed of a plane is 254 m/s/s. A carousel rotates continuously.
What is the unit for speed?seconds per metre Miles per hour (mph), kilometres per hour (km/h), and metres per second (m/s) are the three most popular speed units (mph). The distance an object covers in a given amount of time is its speed. Speed equals distance x time is the speed equation.
Who defined speed?Galileo Galilei, an Italian physicist, is typically attributed with being the first to quantify speed by taking into account the distance travelled and the time required. Galileo defined speed as the amount of distance travelled in a given amount of time.
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How much POWER is used in 30 seconds when you complete 150 Joules of work?
Answer:
Power of 5 watts is used
Explanation:
Mechanical Work and Power
Mechanical work is the amount of energy transferred by a force.
Being F the force vector and s the displacement vector, the work is calculated as:
\(W=\vec F\cdot \vec s\)
If both the force and displacement are parallel, then we can use the equivalent scalar formula:
W=F.s
Power is the amount of energy converted per unit of time. The SI unit of power is the watt, equal to one joule per second.
The power can be calculated as:
\(\displaystyle P=\frac {W}{t}\)
Where W is the work and t is the time.
It's required to calculate the power used in t=30 seconds when W=150 Joules of work are completed. Substitute in the formula:
\(\displaystyle P=\frac {150}{30}\)
P = 5 Watt
Power of 5 watts is used
The components of a 15 meters per second velocity at an angle of 60 degrees above the horizontal are?
Answer:
x-component of velocity: 7.5 m/s
y-component of velocity: 13 m/s
Explanation:
This problem is pure trigonometry. Assuming you know trig, there are only a couple of steps to solving this problem. First, split the velocity into components; recall that any vector not directed along an axis has x and y components. Then, remember that sinΘ = opposite/hypotenuse. Applying this to your scenario, you get sin60° = vy/15. Multiplying this out gives you vy=15sin60. Put this into a calculator (make sure it's set to degree mode because the angle in this problem is in degrees) and you should get 12.99, which you can round up to 13 m/s. This is the velocity in the y-direction.
The procedure to find the x-velocity is very similar, but instead of using sine, we will use the cosine of theta. Recall that cosΘ=adjacent/hypotenuse. Once again plugging this scenario's numbers into that, you end up with cos60 = vₓ/15. Multiplying this out gives you vₓ = 15cos60. Once again, plug this into your calculator. 7.5 m/s should be your answer. This is the velocity in the x-direction.
By the way, a quick way to find the components of a vector, whether it's velocity, force, or whatever else, is to use these functions. Generally, if the vector points somewhere that's not along an axis, you can use this rule. The x-component of the vector is equal to hypotenuse*cosΘ and the y-component of the vector is equal to hypotenuse*sinΘ.
Ay which labeled points would the skateboarder have most kinetic energy?
Answer: wheres the picture and it could be where they move the fastest
Explanation:
a 2,400 kg car drives north towad a 60kg shopping cartthat has a velocity of zero the two objects collide giving the car a final velocity 4.33m/s north and the shopping cart 8.88m/s north what is the in itial velocity of the car
Answer:
4.552m/s
Explanation:
\(V=\frac{m_{1}v_{1}+m_{2}v_{2}}{m_{1} } =\frac{2400*4.33+60*8.88}{2400}=4.552m/s\)
In rectilinear motion, motion depends on a?
Answer:
The object moving in a straight path is called linear or rectilinear motion.
An object is said to be in rectilinear motion if it changes its position,along a straight line path.
Explanation:
example: A car moving in a straight road.
A jet moving straight in air
How to find the angle in a projectile motion when displacement and heigh are the same
projectile's vertical speed v yv y v, start , y, drops prior to reaching its maximum height since its acceleration is in the opposite direction. Since the object's height is rising, the initial direction of the velocity is upward
.
At the projectile's highest point, vertical velocity zeroes out. After reaching the highest point, the vertical speed increases due of the same-direction acceleration. As the object's height lowers, the vertical velocity has a downward direction.
In projectile The beginning vertical velocity determines the maximum height. Increasing the launch angle raises the maximum height because steeper launch angles have a larger vertical velocity component.
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What does the symbol "kg" represent in the metric system?
O 1,000 grams
100 liters
10 meters
O 1 degree Celsius
Answer:
its A 1000 grams
Explanation:
its kg that is the biggest
Answer:
its a 1,000
Explanation:
I HOPE THIS HELPED!
The engine of a car is usually no more than 20% efficient. In other words, for every 100 J of energy produced by the engine, 20 J are
converted into kinetic energy of the car and 80 J are lost to heat.
Assuming 20% efficiency, the amount of energy needed to move a car 1 km with an average force of 2000 N is
The amount of energy needed to move the car is 4×10⁵ J
Determination of the energy produced.Force (F) = 2000 NDistance (d) = 1 Km = 1000 mEnergy (E) =?E = Fd
E = 2000 × 1000
E = 2×10⁶ J
Determination of the actual energy needed to move the car to 1 KmFrom the question given above,
For 100 J of energy produced by the engine, 20 J is needed.
Therefore,
For 2×10⁶ J of energy produced = (2×10⁶ × 20) / 100 = 4×10⁵ J is needed.
Thus, 4×10⁵ J of energy is needed to move the car.
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What best describes the relationship between sleep and memory? The quantity of sleep impacts memory, while the quality of sleep does not. The quantity of sleep does not impact memory, while the quality of sleep does. The quantity and quality of sleep have no impact on memory. The quantity and quality of sleep both impact memory.
Answer:
The quantity and quality of sleep both impact memory.
Explanation:
What is the magnitude of the total force exerted by these two charges on a negative point charge q3
= -5.95 nC
that is placed at the origin?
The force exerted between the charges q1 and q3 is -5.25 × 10⁻⁶ N and that between q2 and q3 is -2.93 × 10⁻⁶ N. Hence the net force is - 8.18 × 10⁻⁶ N .
What is Coulomb's law ?According to Coulomb's law of force, the electrostatic force between two charges separated by a distance of r is given as follows:
Fc = Ke q1 q2 /r²
where Ke = 8.9 × 10⁹ Nm²/C²
Given the charge of q1 = 3.97 × 10⁻⁹ C
charge of q3 = -5.95 × 10⁻⁹ C
distance r = 0.200 m
then Fc = 8.9 × 10⁹ Nm²/C² ( 3.97 × 10⁻⁹ C) (-5.95 × 10⁻⁹ C)/(0.200 m)² = -5.25 × 10⁻⁶ N
Similarly, the force on q3 by the charge q2 is calculated as follows:
distance to q2 = 0.30 m
charge of q2 = 4.99 × 10⁻⁹ C.
Then Fc = 8.9 × 10⁹ Nm²/C² (4.99 × 10⁻⁹ C ) (-5.95× 10⁻⁹ C)/(0.30 m)² = - -2.93 × 10⁻⁶ N
The net electric force acting on A = 3.9 × 10⁻⁵ N - (-1.9 × 10⁻⁵ N) = 5.8 × 10⁻⁵ N.
Therefore, the net electric force acting on q3 is 8.18 × 10⁻⁶ N.
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Your question is incomplete. But your complete question probably was:
Two point charges are placed on the x-axis as follows: charge 3.97 nC is located at 0.200 m (q1) and charge 4.99 nC (q3) is at -0.304 m .What is the magnitude of the total force exerted by these two charges on a negative point charge q3
= -5.95 nc that is placed at the origin?
Frequency= Wavelength = 502 km Speed= 100 m/s
Answer:
Explanation:
Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.
A 3 Kg exercise ball is held 2m above the ground. What is the gravitational potential energy?
Answer:
58.8
Explanation:
we should apply formula
m*g*h
3*9.81*2
How do you find the range of a data set?
Answer: You take the biggest number and subtract it from the smallest number.
Explanation: Hope this helps.
Answer:
Subtract the minimum data value from the maximum data value to find the data range.
Explanation:
\(Hope\) \(this\) \(helps!\)
A car has a weight of 8000 N. The car is supported by four tyres.
The weight on each tyre is equal.
The area of one tyre in contact with the ground is 150 cm².
Calculate the pressure that one tyre exerts on the ground.
Show your working and give your answer in N/cm².
Answer: A
Explanation:
what would the net force be on the box in the problems shown below.( both force and direction).
Answer:
4
Explanation:
The net force on the box a will be 20 N to the left and that on box b is 6 N downwards. The net force on box c is 90 N to the left and that on box d is zero.
What is net force?Force is an external agent acting on a body to change its motion or to deform it. The net force acting on a body depends on all the the forces with their magnitudes and directions.
If two same or different forces acts from the same direction they will add up and net force will be their sum. If they acts from the different directions, they will cancel each other in magnitudes.
In box a, the equal forces of 20 N opposes from each direction cancel and the net force will be 20 N to the left. I box b the 15 N cancel each other. Where the 4N and 2 N add up to have net force of 6 N downwards.
In box c, 10 N from opposite direction cancels and the 60 N and 30 N to the left add ups to have the net force of 90 N to the left. On box d, 5 N from opposite directions cancels as 12 N. Hence, net force is zero.
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a defender running away from a goalkeeper at 5m/s is hit in the back by the goal kick. the ball stops dead and the players speed increases to 5.5m/s if the ball had a mass of 500g and the player mass is 70k how fast was the ball moving?
The goal kick strikes a defender racing at 5 m/s away from a goalkeeper in the back. The ball was moving at a speed of 70 m/s if it weighed 500g and the player's mass was 70k.
Why does the goalie in a football game pull his hands back after holding the ball that has been shot towards the goal?The goalkeeper extends the amount of time he has to hold the ball by pulling his hands back. He lessens the force (rate of change of momentum) the football exerts on him by lengthening the time.
Write the formula for momentum and define it.A vector quantity, momentum. A body's momentum is equal to P=m.v if it is travelling at a speed of v while having mass m. P=mv describes the magnitude of the momentum. Because momentum is a function of mass and velocity, its unit is the product of those two quantities.
By using conservation of momentum,
Initial momentum = Final momentum
(5 x 70) + (v x 0.5) = (5.5 x 70) + (0 x 0.5)
350 + 0.5v = 385 + 0
0.5v = 35
v = 70 m/s
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why a moving body stop after some time
Explanation:
Friction acts between two surfaces in contact only and opposes the movement of one body with respect to another. Therefore friction is a force which opposes the relative motion between two bodies. If a body is moving it is slowed down by frictional force applied on it by the surface on which it is moving.
The following are four electrical components.
A. A component which obeys ohm's law
B. Another component which obeys ohm's law
but which has higher resistance than A
A filament lamp
C.
D. A component, other than a filament lamp,
which does not obey ohm's law.
a. For each of these components, sketch current-
voltage characteristics, plotting current on the
vertical axis, and showing both positive and
negative values. Use one set of axes for A and
B, and separate sets of axes for C and for D.
label your graphs clearly.
b.
Explain the shape of the characteristic for C
c. Name the component you have chosen for D.
For the following are four electrical components:
a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.
b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.
c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.
For the following are four electrical components:
a. Sketches of current-voltage characteristics:
For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.
Current (I)
^
| B
| /
| /
| /
| /
| /
| /
| /
| /
| /
|/
+------------------> Voltage (V)
Current (I)
^
| A
| /
| /
| /
| /
| /
| /
| /
| /
| /
|/
+------------------> Voltage (V)
For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.
For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.
b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.
c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.
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The total volume occupied by two internal cable clamps, six 12AWG conductors, and single pole switch is
The total volume occupied by two internal clamps, six 12 AWG conductors and one grounding conductor, and a single-pole switch is 20.25 cu in.
When counting the number of conductors in a box a conductor running through the box is counted as conductor S?
An unbroken conductor, passing through the box without splice or termination, can be counted as one conductor if it is less than two times the minimum length required for the free conductor in 300.14. For example, two conduits are entering opposite sides of a four-inch square metal box that has a depth of 1 1/2 inches.
How many amps can 12 AWG handle?
The twelve-gauge wire is good for 20 amps, 10-gauge wire is good for 30 amps, 8-gauge is good for 40 amps, and 6-gauge is good for 55 amps, and The circuit breaker or fuse is always sized to protect the conductor [wire].
12 AWG =2.25 cu. in. ( 6 x 2.25 = 13.5)
Device( 2 x 12 AWG cu. in.)= ( 2 x 2.25 = 4.5)
Clamp ( 1 x 12 AWG cu. in.)= ( 1 x 2.25 = 2.25)
13.5 + 4.5 + 2.25 = 20.25 cu. in.
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Which correctly describes latent heat?
A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid
Option C. The heat absorbed or lost by a substance while it's changing state correctly describes latent heat
Latent heat is the heat absorbed or lost by a substance while it is changing state.
The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.
For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.
Latent heat is not associated with a temperature change; rather, it's associated with a change of state.
For instance, the temperature of water remains at 100°C while boiling.
When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.
When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.
Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.
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During the 28-day lunar cycle, the positions of the Sun,
Earth, and the Moon change in relation to one another. The
diagram shows how their relative positions change.
Which statement describes the positions of the Moon, the Sun, and Earth
during a new moon?
A. Earth is closer to the Sun than to the Moon.
B. The Moon is between Earth and the Sun.
C. Earth is between the Moon and the Sun.
D. The Sun is between Earth and the Moon.
Answer: B
Explanation: B is the correct statement describing the positions of the Moon, the Sun, and the Earth during a new moon. The Moon is between Earth and the Sun.
During a new moon, the Moon is positioned between the Sun and the Earth, with the illuminated side of the Moon facing away from the Earth. This means that the side of the Moon that faces the Earth is not receiving any sunlight, making it invisible to us from Earth. The new moon is the first phase of the lunar cycle and occurs roughly every 29.5 days.
If used with godly wisdom, the earth has sufficient resources to sustain its human population.
A power plant burns coal at
830 K, and exhausts to air at
288 K. If it runs at the Carnot
efficiency, how much input heat
must be fed into the plant to
produce 230,000 J of work?
(Unit = J)
The efficiency of an engine is defined as ratio of the useful work done to the heat provided or,
in terms of temperature of the source and the sink the efficiency of heat engine is given by \(1-\frac{T_{2} }{T_{1} }\)
Thus, we have two formulae to calculate the efficiency of a heat engine.
η= \(\frac{useful work done}{heat absorbed}\) ....1
η= \(1-\frac{T_2}{T_1}\) ....2 (where \(T_{2}\) and \(T_{1}\) are temperatures of sink and source respectively)
Given quantities are,
\(T_{1}\) = 830K\(T_1\) =288KWork done = 230000JNow, by equating (1) and (2) equation,
⇒ \(1-\frac{T_2}{T_1}\) = \(\frac{Useful work done}{Heat absorbed}\)
Substituting the given values;
⇒ \(1-\frac{288}{830}\) = \(\frac{230000}{heat absorbed}\)
⇒therefore, heat absorbed = 353846.15 J
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the projectile thrown with the same initial velocity , one at an angle theta and the other at an angle 90-theta can both projectiles strike at the same distance from the projection point? can both projectiles be in air for the same time interval?
Answer:
If theta is equal to 90, then both projectiles strike at the same distance from the projection point and projectiles are in air for the same time interval.
Explanation: