Answer:
7.5 m/s^2
Explanation:
v=at
a= v/t
Since you have to v so
(v2- v1) /t
(15-0)/2= - 7.5
When you push a crate across a level floor at constant velocity, friction between the crate and the floor is?
Answer:
The friction between the crate and the floor is the same amount as your pushing force when you push a crate across a level floor at constant velocity.
Explanation:
Remember that the force produced by two surfaces coming into contact and sliding against one another is frictional force. This is expressed by the direct relationship between frictional force and normal force.
f=μN
Where
f = frictional force
µ = coefficient of friction
N = Normal force
By dry friction, two solid surfaces in touch are opposed to one another's relative lateral motion. Dry friction is further separated into kinetic friction between moving surfaces and static friction (sometimes known as "stiction") between non-moving surfaces. Additionally, dry friction is typically caused by the interaction of surface characteristics, particularly rough surfaces.
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A train is moving to the right. The force of air resistance and the surface friction from the tracks totals 259,800 N . In order for the train to keep moving at a constant velocity, how much forward force is the engine providing?
The engine is providing a forward force of 259,800 N to keep the train moving at a constant velocity.
What is forward force?
Forward force is the force applied in the direction of motion, which causes an object to move or maintain a constant velocity.
Constant velocity refers to the motion of an object moving in a straight line at a steady speed, without changing its direction. The velocity of the object is constant when its speed and direction remain unchanged over time, regardless of whether the object is moving or stationary.
Since the train is moving at a constant velocity, the net force acting on the train is zero. Therefore, the forward force provided by the engine must be equal in magnitude and opposite in direction to the force of air resistance and surface friction.
So, the magnitude of the forward force provided by the engine is:
Magnitude of forward force = Magnitude of force of air resistance and surface friction
Magnitude of forward force = 259,800 N
Therefore, the engine is providing a forward force of 259,800 N to keep the train moving at a constant velocity.
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State government approves a series of grants to fund job training. Which of the following is a negative externality? (5 points
Businesses would not necessarily increase hiring rates.
Economic recession would result in a backlog of applicants.
Money for conservation efforts would be eliminated.
The state would have to provide child care for parents in training.
None of the options listed is a negative externality. A negative externality is an unintended consequence of an economic activity that affects a third party who is not directly involved in the activity.
If I were to choose: Businesses would not necessarily increase hiring rates.
This could be considered a negative externality because the grant funding is intended to fund job training in order to increase employment opportunities, but if businesses do not increase their hiring rates despite having a pool of trained workers, then the intended benefit of the grant may not be fully realized. This could result in a loss of resources and a missed opportunity to address unemployment in the community.
an adiabatic compressor compresses air at 150 kpa and 400k to 2 mpa. what is the exit temp of the air if it is an isentropic process
The exit temperature = 5333.33 K
Explanation:The inlet pressure: P₁ = 150 kpa
The inlet temperature T₁ = 400K
The exit pressure, P₂ = 2 MPa = 2000 kPa
The exit tenperature, T₂ = ?
The relationship between temperature and pressure for an isentropic process is shown below
\(\frac{T_2}{T_1}=\frac{P_2}{P_1}\)Substitute the given parameters into the formula and solve for T₂
\(\begin{gathered} \frac{T_2}{400}=\frac{2000}{150} \\ \\ T_2=400(\frac{2000}{150}) \\ \\ T_2=5333.33K \\ \end{gathered}\)The exit temperature = 5333.33 K
Energy. (4 points)
2. When you eat pizza, Chemical Energy is transferred to
O Solar
Electrical
Mechanical
Chemical
When you eat pizza, chemical energy is transferred to mechanical energy.
What is energy?Energy can be defined as the ability to do work. Thus, energy must be possessed or transferred to a physical object (body) before work can be done.
The forms of energy.In Science, there are different forms of energy and these include the following;
Sound energyGravitational energyElectrical energyChemical energyElectromagnetic energyMechanical energyWhen a person eats pizza, the chemical energy contained in this snack is transferred to mechanical energy.
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A film badge worn by a radiologist indicates that she has received an absorbed dose of 2. 5 x 10-6 gy. the mass of the radiologist is 71 kg. how much energy has she absorbed?
Energy absorbed by the radiologist is 1.775*10^-6J.
To find the answer, we have to know about the radiation.
How much energy has she absorbed?We have the expression for dose of absorption as,\(D=\frac{E}{m}\)
where; E is the energy absorbed and m is the mass of the body.
From the above expression, substituting appropriate values given in the question, we get,\(E=D*m=2.5*10^{-6}J/kg*71kg=1.775*10^{-4}J\)
Thus, we can conclude that, the Energy absorbed by the radiologist is 1.775*10^-6J.
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Answer:
Use the table below to answer questions 5-6.
Answer:
its also difficult for me.
The Sun constantly undergoes explosions called solar eruptions. When a solar eruption happens, satellites capture images of bright flashes of light called solar flares. Solar eruptions emit more energy than millions of megaton hydrogen bombs. Space is a vacuum and void of any matter.
The sound of solar eruptions cannot be heard on earth, because they cannot travel through space, as there is no medium.
The colliding, crossing, or reorganisation of magnetic field lines close to sunspots results in solar eruptions, which are rapid explosions of energy.
It is very dense on the Sun's surface. It contains electrically charged gases, which produce magnetic fields with strong magnetic forces in certain regions.
As there is no physical medium in space, where the sound of explosions is meant to travel. However, we are aware that sound cannot travel in a vacuum and needs a medium for propagation.
As a result, we cannot hear the explosions that are taking place in the Sun.
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Your question was incomplete, but most probably your question would be:
The Sun constantly undergoes explosions called solar eruptions. When a solar eruption happens, satellites capture images of bright flashes of light called solar flares. Solar eruptions emit more energy than millions of megaton hydrogen bombs. Space is a vacuum and void of any matter. Write a scientific explanation on why we don't hear solar eruptions on Earth.
A skateboard has a mas of 450g if it travels at 7m/s what is te momentum
Answer:
Momentum (P)= 3.15Kg.m/s
Explanation:
Because momentum by definition is the product of mass and velocity, therefore, it's calculated by the formula;
P=mv,,,
where 'P' Is the momentum
'm' is mass in Kilograms, note that mass should be in Kilograms, therefore the 450grams should be converted to kilograms by dividing it with a 1000, i.e (450g×1kg/1000g)= 0.45kg, and now you can substitute in the formula because you have everything you need to find momentum in the right si units.
so P=mv
P=0.45Kg×7m/s
P=3.15Kg.m/s
marked as brainiest if correct
Answer:
I think the the answer is creating and layout and template style ( C )
Explanation:
I did it before and i was checking my notes and i wrote that down , Hope this Helps :)
what is the angular velocity (in rad/s) of a 62.0 cm diameter tire on an automobile traveling at 90.5 km/h? (enter the magnitude.)
The angular velocity is 55.6rads/s.
What is angular velocity?
The rotation rate of an object, or how quickly it revolves or rotates in relation to another point, is measured vectorially as angular velocity. Angular velocity is simply the rate of rotation or revolving around an axis of an object.
What is magnitude?
Magnitude serves as the common denominator for both vector and scalar quantities. Their definition states that scalar quantities are those that have only magnitude.
Using the second relationship in v = r, vr = v r, and knowing v and r, we can get the angular velocity. To calculate the angular velocity, we will use the formula = vr. = v r.
If an object's radius is r, its linear speed is v, and its angular velocity is measured in radians per second, then v = r.
Substituting the values, in the formula
=62.0cm*90.5
V=55.6
Therefore, the angular velocity is 55.6rads/s.
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Jenny applies a 60 N force to a 20 kg cart , what is the acceleration of the cart if friction can be neglected
Hello!
a = 3 m/s²
Use the equation F = m · a (Newton's Second Law) to solve.
We are given the force and mass, so plug these values into the equation:
60 = 20 · a
60 = 20a
Divide both sides by 20:
60/20 = 20a/20
a = 3 m/s²
33. A zebra is at rest 60 m away from a charging lion
running at 20 m/s. If the zebra accelerates at 4
m/s2, will the lion catch it?
Answer:
the lion will miss the zebra by 3 meters
Explanation
The zebra has gone 23.75m after 5 seconds
and the lion can only go 20 m/s
The lion can not catch zebra.
A diagram is attached below which describe situation of question.
The speed of Zebra is,
\(v=u+at=0+4t=4t\)
Where u is initial speed of zebra.
The speed of lion is 20m/s.
The lead in speed by lion for every second is \((20-4t)\).
\((20-4t)*t=60\\\\20t-4t^{2}=60\\ \\t^{2}-5t+15=0\\ \\t=\frac{5\pm\sqrt{(-35)} }{2}\)
Here time is imaginary.
Therefore, The lion can not catch zebra.
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The Figure 6A-2 Stüve diagram includes lines representing the adiabatic processes of dry (unsaturated) and saturated air. Click on Figure 6A-2 to print or draw on it digitally. Figure 6A-2. Vertical atmospheric (Stüve) chart with adiabats. On the Stüve diagram, the solid, straight green lines from upper left to the lower right represent the dry adiabatic lapse rate: the temperature change of an unsaturated air parcel undergoing vertical motion in the atmosphere. The dashed, curved blue lines from upper left to lower right represent the temperature change of saturated air undergoing vertical motion, the saturated adiabatic lapse rate. Locate an air parcel with a temperature of 17
∘
C and a pressure of 1000mb by placing a dot on the chart on the 1000mb horizontal line where 17
∘
C would occur. 7. If this air rises as unsaturated (dry) air from 1000mb, determine its temperature at 500mb by following the solid, straight green dry adiabatic lapse rate line from the starting point, up to 500mb. At 500mb, the temperature of the unsaturated air parcel is about
∘
C. a. −5 b. −35 c. −45 8. If this air rises as saturated air from 1000mb, determine its temperature at 500mb by following the dashed, curved blue saturated adiabatic lapse rate line passing from the starting point up to 500mb. At 500mb, the saturated air parcel's temperature is approximately
∘
C. a. −15 b. −25 c. −35 9. At 500mb, the temperature of the unsaturated air parcel is the temperature of the saturated air parcel. a. lower than b. the same as c. higher than 10. This comparison demonstrates that rising unsaturated, clear air cools than rising saturated, cloudy air over the same pressure change. a. less b. more
When an air parcel rises from 1000mb to 500mb, unsaturated air cools to around -35°C, while saturated air cools to approximately -25°C.
On the Stüve diagram, the solid, straight green lines represent the dry adiabatic lapse rate, which indicates the temperature change of an unsaturated air parcel undergoing vertical motion in the atmosphere. The dashed, curved blue lines represent the temperature change of saturated air undergoing vertical motion, known as the saturated adiabatic lapse rate.
To determine the temperature of the air parcel at 500mb when it rises as unsaturated air, we follow the solid, straight green dry adiabatic lapse rate line from the starting point (17°C, 1000mb) up to 500mb. Following this line, we find that at 500mb, the temperature of the unsaturated air parcel is approximately -35°C.
On the other hand, if the air parcel rises as saturated air, we follow the dashed, curved blue saturated adiabatic lapse rate line from the starting point (17°C, 1000mb) up to 500mb. By following this line, we determine that at 500mb, the temperature of the saturated air parcel is approximately -25°C.
Comparing the temperatures of the unsaturated and saturated air parcels at 500mb, we find that the temperature of the unsaturated air parcel (-35°C) is lower than the temperature of the saturated air parcel (-25°C). Therefore, at 500mb, the temperature of the unsaturated air parcel is lower than the temperature of the saturated air parcel.
This comparison demonstrates that rising unsaturated, clear air cools more than rising saturated, cloudy air over the same pressure change.
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Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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Alice pulls her wagon with a force of 75N. If the she pulls the wagon for 50 meters, how much work has she done?
Answer: W=75.50J
Explanation:
W=Fd
Sound waves travel through steel railroad rails a distance of 2350 m in 0.383 s. What is the speed of sound in the rails?
(units = m/s)
Answer:
Speed of sound ways in railroad = 6,135.8 m/s
Explanation:
Given:
Distance cover by sound wave = 2,350 meter
Time taken by sound wave to cover distance = 0.383 seconds
Find:
Speed of sound ways in railroad
Computation:
Speed = Distance / Time
Speed of sound ways in railroad = Distance cover by sound wave / Time taken by sound wave to cover distance
Speed of sound ways in railroad = 2,350 / 0.383
Speed of sound ways in railroad = 6,135.77
Speed of sound ways in railroad = 6,135.8 m/s
Consider the motion of a particle of mass m and charge q moving in constant electric and magnetic fields perpendicular to each other. E= (0, 0, E), B= (0, B,0) (a) Write the Schrödinger equation. (Hint: A convenient choice of gauge is A = (Bz,0,0), ø= -Ez) (b) Separate variables and reduce it to a one dimensional problem. (c) Calculate (vr) in any energy eigenstate (this velocity is sometimes called the drift veloc- ity.)
(a) The Schrödinger equation describes the behavior of a particle with mass m and charge q moving in constant electric and magnetic fields perpendicular to each other. By choosing a specific gauge (A = (Bz, 0, 0) and ø = -Ez), the Schrödinger equation can be written in terms of the wavefunction ψ and the electric and magnetic fields.
(b) To simplify the equation, we assume a separable solution of the form ψ(x, y, z, t) = X(x)Y(y)Z(z)T(t) and substitute it into the Schrödinger equation. This leads to separating the equation into individual equations for each variable, allowing us to analyze the behavior of the particle in a one-dimensional context.
(c) To determine the drift velocity (vr) in any energy eigenstate, we solve the one-dimensional Schrödinger equation obtained in part (b) and find the corresponding eigenvalues and eigenfunctions. The drift velocity is calculated by taking the expectation value of the velocity operator, v = (1/m) ∇S, where S is the phase of the wavefunction. The drift velocity provides insight into the average velocity of the particle under the influence of the electric and magnetic fields.
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23. In addition to the fulcrum, every lever uses a____
to move the____
Answer:
i think its a load to move a object,
Explanation:
im taking this to and it isnt in the lesson
a jet fighter pilot wishes to accelerate from rest at 5 g to reach mach-3 (three times the speed of sound) as quickly as possible. experimental tests reveal that he will black out if this acceleration lasts for more than 4.9 s . use 331 m/s for the speed of sound.
The greatest speed pilot can reach with an acceleration of 5g before he blacks out is 240 m/s.
The acceleration due to gravity is g.
g = 9.8 m/s²
The acceleration of the jet is,
\(Acceleration = Mass \times Gravity\)
\(a = m \times g\)
\(a = 5 \times 9.8\)
\(a = 49 \: m/s ^{2} \)
The acceleration of the jet is 49 m/s².
Let the speed of sound be v.
\(v = 331 \: m/s\)
Let the initial velocity of the jet be
\(Let \: the \: initial \: velocity \: of \: the \: jet \: \)
\(be \: v _i.\)
\(v _i = 0\)
The time at which the pilot will black out with 49 m/s² acceleration = 4.9 s
Let the time taken to reach Mach 3 be t.
Then the final velocity will be,
\(v _f = 3 \times v\)
\(v _f = 3 \times 331\)
\(v _f = 993 \: m/s\)
\(v _f = v _i + at\)
\(993 = 0 + (49)t\)
\(t = 20.26 \: s\)
Thus, the time taken to reach Mach 3 is 20.26 s.it is greater than the time interval at which the pilot will black out. So the pilot will black out.
The greatest speed pilot can reach with an acceleration of 5g before he blacks out is,
\(v _f = 0 +( 49 \times 4.9)\)
\(v _f = 240.1 \: m/s\)
Therefore, the greatest speed pilot can reach with an acceleration of 5g before he blacks out is 240 m/s.
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true or false, the gastrocnemius is also known as the calf muscle.
Answer:
It's true
Explanation:
Have a great day:)
A DC motor is powered with Ea = 400V, the armature resistance is Ra = 20, the torque constant of the motor is K+ = 1 Nm/A. What gear ratio G is required to drive this load at its maximum operating speed? Hint: The load torque intercepts the motor torque in two places, only one will be positive, dwop you will again need to solve = 0. dG
A DC motor is powered with Ea = 400V, the armature resistance is Ra = 20, the torque constant of the motor is K+ = 1 Nm/A.
What gear ratio G is required to drive this load at its maximum operating speed?The load torque intercepts the motor torque in two places, only one will be positive, drop you will again need to solve = 0. d the given details are Ea = 400VRa = 20K+ = 1 Nm/A
To find; Gear ratio G required to drive this load at its maximum operating speed.
Formula used: θ=K+ * Ia The motor torque, Tm = K+ * Ia The load torque, TL = J * dw / G The armature current, Ia = (Ea - V) / Ra By equating the motor torque and load torque, we have; K+ * Ia = TL The load torque is positive, so we have;TL = J * dw / G Since the load is operating at maximum speed, d w = 0So, TL = 0 = J * 0 / G
Thus, G is not found in the equation.
So, we can conclude that G does not affect the maximum speed of the motor. The maximum speed is determined by the back EMF, Ea, and the motor constants, K+ and Ra.
So, the gear ratio G is irrelevant in determining the maximum speed of the motor.
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write down the freezing and boiling point of alcohol
Identify the career that matches the description.
Runs the front desk at a hotel or motel: Hotel/Motel Clerk
Oversees other employees at a hotel or motel: Hotel/Motel Supervisor or Manager
Cleans the interior of buildings: Housekeeper/Cleaning Worker
Helps guests at places of lodging with personal services: Concierge
Handles luggage for travelers: Porter/Bellhop
The answers to them are in each line behind the :'s.
Answer: 1.Hotel/Motel Clerk 2.Hotel/Motel Supervisor or Manager 3.Housekeeper/Cleaning Worker 4.Concierge 5.Porter/Bellhop
What is profession?
A successfully professionalized field of employment is referred to as a profession.
It can be characterized as a disciplined team of people, professionals, who uphold ethical standards, present themselves as, and are recognized by the public as possessing, special knowledge and skills in a widely acknowledged body of learning derived from research, education, and training at a high level, and who are prepared to apply this knowledge and exercise these skills in the interest of others.
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Which of the following was not a main idea of Dalton's atomic theory?
1. Compounds contain atoms of more than one element.
2. There are four elements that make up matter: air, water, fire, and earth.
3. All atoms of the same element have the same mass, while atoms of different elements have different masses.
4. All matter is composed of atoms.
Answer:
1 IS CORRECT
Explanation:
The lift sling is used to hoist a container having a mass of 500 kg. Determine the force in each of the cables AB and AC as a function of θ. If the maximum tension allowed in each cable is 5 kN, determine the shortest lengths of cables AB and AC that can be used for the lift. The center of gravity of the container is located at G.
The tension forces in cables AB and AC for lifting a 500 kg container are found as functions of θ, and the shortest lengths of cables satisfying a maximum tension of 5 kN are 4408.5 m and 1886.5 m.
Assuming the container is being lifted vertically, we can draw a free-body diagram of the container and apply Newton's second law to find the tension forces in cables AB and AC.
Let T_AB and T_AC be the tensions in cables AB and AC respectively, and let W be the weight of the container. Then we have
T_AC * cos(θ) = T_AB * cos(θ) = W
T_AC * sin(θ) = T_AB * sin(θ)
Dividing the first equation by the second, we get
tan(θ) = T_AC / T_AB
Solving for T_AC and T_AB in terms of θ, we get
T_AC = W / cos(θ)
T_AB = W / (cos(θ) * tan(θ))
Substituting W = 500 kg * 9.81 m/s² = 4905 N, we get:
T_AC = 4905 / cos(θ)
T_AB = 4905 / (cos(θ) * tan(θ))
To find the shortest lengths of cables AB and AC that can be used for the lift, we need to make sure that the tension in each cable does not exceed 5 kN. Since the tensions are functions of θ, we can find the maximum value of θ that satisfies this condition.
For cable AB
T_AB = 4905 / (cos(θ) * tan(θ)) <= 5 kN
cos(θ) * tan(θ) >= 4905 / (5 kN) = 0.981
Using a calculator or a table of trigonometric functions, we can find that the minimum value of cos(θ) * tan(θ) that satisfies this inequality is approximately 0.739. Therefore, we have
cos(θ) * tan(θ) >= 0.739
Solving for θ, we get
θ <= atan(0.739 / cos(θ)) = 51.4°
Similarly, for cable AC
T_AC = 4905 / cos(θ) <= 5 kN
cos(θ) >= 4905 / (5 kN) = 0.981
Solving for θ, we get
θ >= acos(0.981) = 11.2°
Therefore, the shortest lengths of cables AB and AC that can be used for the lift are given by
L_AB = 500 / sin(θ) <= 4408.5 m
L_AC = 500 / sin(θ) >= 1886.5 m
where we have used the maximum and minimum values of θ obtained above. These lengths assume that the cables are perfectly vertical, and in practice there may be some additional length required to account for the angle at which the cables are attached to the container.
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#2. If we have a 9V battery connected to a 100 resistor , what is the current ?
Answer:
90 mAmps
Explanation:
V=IR
V/R = I
9 v / 100 ohm = .09 amps = 90 mAmps
which of the following statements is true? low-velocity injuries produce extensive temporary wound channels. there are four levels of velocity. the higher the velocity of a projectile, the larger the cavity it produces. the velocity of an object is not a critical determination in your assessment.
The statement that is true is: "The higher the velocity of a projectile, the larger the cavity it produces."low-velocity injuries produce extensive temporary wound channels. there are four levels of velocity.
A projectile is an object that is thrown, launched, or shot through the air and travels in a parabolic path under the influence of gravity. It can be a solid, liquid, or gas and can be propelled by various means such as a gun, bow, and arrow, or even by throwing with one's own body. The trajectory of a projectile is determined by its initial velocity, angle of projection, and the force of gravity acting upon it. Understanding the principles of projectile motion is important in a variety of fields, such as engineering, physics, and sports. Projectile motion is also affected by air resistance and other external factors, making it a complex area of study.
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What is the primary type of battery we use today to store energy?
(PLEASE DO NOT GIVE ME ANY LINK, JUST TYPE YOU ANSWER)
Lithium-Ion batteries are commonly used in portable electronics and electric vehicles. These rechargeable batteries have two electrodes: one that's positively charged and contains lithium and another negative one that's typically made of graphite.
Answer:
Lithium-Ion: Li-ion batteries are commonly used in portable electronics and electric vehicles. These rechargeable batteries have two electrodes: one that's positively charged and contains lithium and another negative one that's typically made of graphite.
Explanation:
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Have a great day!
Brainliest?
Which scenario describes a systematic error?
A. A person bumps the table as a volume is measured.
B.A measurement is recorded before a balance comes to rest.
C.A thermometer reads 0.1 degree higher than it should.
D.An incubator unexpectedly loses power for ten minutes during the night.
Answer: C
A Systematic error occurs when there is a problem with the instrument , so the answer should be c .
Explanation:
Answer:
A Systematic Error Occurs When There Is A Problem With The Instrument, so The Answer Is C
Explanation: