A block is acted on by two forces as shown in the diagram below.If the magnitudes of the forces are F1 = 53.5 N and F2 = 26.0 N, what are the magnitude (in m/s2) and direction of the acceleration of the block? Let m = 8.00 kg and = 41.0°.magnitude m/s2direction

Answer:

dynamic equilibrium

Explanation:

Substances transition between the reactants and products at equal rates, meaning there is no net change. Reactants and products are formed at such a rate that the concentration of neither changes.

a) The final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\) and 293 K, respectively, while  b) the final pressure and temperature for the adiabatic compression are\(5.58*10^5 Pa\) and 515 K, respectively.

a. Isothermal compression:

For an isothermal process, the temperature remains constant. Therefore, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.

Since the process is isothermal, we can write:

\(P_1V_1 = P_2V_2\)

where P1 and V1 are the initial pressure and volume, and\(P_2\)and\(V_2\)are the final pressure and volume.

We are given that the volume is compressed to 1/3 of its original volume, so\(V_2 = (1/3)V_1\). Substituting this into the equation above gives:

\(P_2 = (V_1/V_2)P_1 = 3P_1\) = \(4.5*10^5 Pa\)

To find the final temperature, we can use the ideal gas law again:

PV = nRT

Rearranging, we get:

T = PV/(nR)

Substituting the values we know, we get:

T = (\(1.5*10^5\)Pa)(V1)/(nR)

Since the process is isothermal, the temperature remains constant, so the final temperature is the same as the initial temperature:

T2 = T1 = 293 K

b. Adiabatic compression:

For an adiabatic process, there is no heat transfer between the gas and its surroundings. Therefore, we can use the adiabatic equation:

PV^γ = constant

where γ = Cp/Cv is the ratio of specific heats.

Since the process is adiabatic and reversible, we can write:

\(P_1V_1\)^γ = \(P_2V_2\)^γ

We are given that the volume is compressed to 1/3 of its original volume, so V2 = (1/3)V1. Substituting this into the equation above gives:

\(P_2 = P_1(V_1/V_2)\)^γ = \(P_1\)\((3)^{(1.4)\) = \(5.58*10^5 Pa\)

To find the final temperature, we can use the adiabatic equation again:

\(T_2 = T_1(P_2/P_1)\)^((γ-1)/γ) = T1(5.58/1.5)^(0.4) = 515 K

Therefore, the final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\)and 293 K, respectively, while the final pressure and temperature for the adiabatic compression are \(5.58*10^5\) Pa and 515 K, respectively.

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Answer:

1) the required horizontal force F is 1095.6 N

2) W = 0 J { work done by rope will be 0 since tension perpendicular }

3) work is done by the worker is 1029.4 J

Explanation:

Given that;

mass of bag m = 125 kg

length of rope \(l\) = 3.3 m

displacement of bag d = 2.2 m

1) What horizontal force is necessary to hold the bag in the new position?

from the figure below; ( triangle )

SOH CAH TOA

sin = opp / hyp

sin\(\theta\) = d / \(l\)

sin\(\theta\) = 2.2/ 3.3

sin\(\theta\) = 0.6666

\(\theta\) = sin⁻¹ ( 0.6666 )

\(\theta\)  = 41.81°

Now, tension in the string is resolved into components as illustrated in the image below;

Tsin\(\theta\) = F  

Tcos\(\theta\) = mg

so

Tsin\(\theta\) / Tcos\(\theta\) = F / mg

sin\(\theta\) / cos\(\theta\) = F / mg

we know that; tangent = sine/cosine

so

tan\(\theta\) = F / mg

F = mg tan\(\theta\)

we substitute

Horizontal force F = (125kg)( 9.8 m/s²) tan( 41.81° )

F = 1225 × 0.8944

F = 1095.6 N

Therefore, the required horizontal force F is 1095.6 N

2)  As the bag is moved to this position, how much work is done by the rope?

Tension in the rope and displacement of mass are perpendicular,

so, work done will be;

W = Tdcos90°

W = Td × 0

W = 0 J { work done by rope will be 0 since tension perpendicular }

3) As the bag is moved to this position, how much work is done by the worker

from the diagram in the image below;

SOH CAH TOA

cos = adj / hyp

cos\(\theta\)  = (\(l\) - h) / \(l\)

we substitute

cos\(\theta\)  = (\(l\) - h) / \(l\)  = 1 - h/\(l\)

cos\(\theta\) = 1 - h/\(l\)

h/\(l\) = 1 - cos\(\theta\)

h = \(l\)( 1 - cos\(\theta\) )

now, work done by the worker against gravity will be;

W = mgh = mf\(l\)( 1 - cos\(\theta\) )

W = mf\(l\)( 1 - cos\(\theta\) )

we substitute

W = (125 kg)((9.8 m/s²)(3.3 m)( 1 - cos41.81° )

W = 4042.5 × ( 1 - 0.745359 )

W = 4042.5 × 0.254641

W = 1029.4 J

Therefore,  work is done by the worker is 1029.4 J

Explanation:

a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed

Time needed = t = 20.83 s

Given

car speed = 85 km/h

truck speed = 73 km/h

Required

the time it takes for the car to reach the truck

Solution

When the car reaches the truck, the distance between them will be the same

x car - 250 m = x truck

General formula for distance (d) :

d = v.t

So the equation becomes :

85t-250 = 73t

12t=250

t = 20.83 s

Answer:

5.4×10⁶J

Explanation:

1 cal = 4.184 J

1.3×10⁶ cal × (4.184 J/cal) = 5.4×10⁶J

Answer:

The kinetic theory of matter can be used to explain how solids, liquids and gases are interchangeable as a result of increase or decrease in heat energy. When an object is heated the motion of the particles increases as the particles become more energetic

Assuming constant acceleration, if v is the final velocity of the ball, then

v ² - (16 m/s)² = 2 (-2 m/s²) (4 m)

v ² = 240 m²/s²

v ≈ 15.5 m/s

The amount of the work done will be 100 J. Work done is denoted by W.

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive and negative.it depends on the direction of the body displaced. if the body is displaced in the same direction of the force it will be positive.

The given data in the problem is;

F is the force applied = 20 N

d is the displacement = 5.0 m

The work done is found as;

W = F × d

W =  20 N × 5

W= 100 J

Hence, the amount of work done will be 100 J.

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Answer:

lifts the basket, 40J

Explanation:

The average speed of the baseball is  option  a. 40 m/s .

To calculate the average speed of the baseball, we use the formula:

Average Speed = Distance / Time

Given:

Distance = 18.4 m

Time = 0.46 s

Plugging in the values, we have:

Average Speed = 18.4 m / 0.46 s = 40 m/s

Therefore, the average speed of the baseball is 40 m/s.

Option a, 40 m/s, is the correct answer. This means that the baseball traveled an average distance of 40 meters per second from the pitcher's mound to home plate.

Average speed is a scalar quantity that represents the total distance traveled divided by the total time taken. It gives us an idea of how fast an object is moving on average over a given distance.

In this case, the baseball covered a distance of 18.4 meters in a time of 0.46 seconds. Dividing the distance by the time gives us the average speed of 40 m/s.

It's important to note that average speed is a measure of the overall rate of motion and does not provide information about the direction of motion. Therefore, negative values such as option b (-40 m/s) or extremely small values such as option c (0.03 m/s) are not appropriate in this context.

Option d (8.5 m/s) is also incorrect as it does not match the calculated average speed of 40 m/s.

Therefore, the correct answer is option a, 40 m/s, as it accurately represents the average speed of the baseball.

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Answer:

none no work cuz no motion

Explanation:

GOOD LUCK

There are 36 ounces of yellow paint.

Both blue and yellow paint reflect intermediate wavelengths. Therefore, if you mix blue and yellow paint the mixture will appear green. I have found that blues and greens produce predominantly cyan or turquoise tones but mixing colors is never the right thing to do with darker or lighter grays.

Mixing blue and green makes him a tertiary color on the color wheel, teal. Blue-green is similar to turquoise or the color of the sea. This is one of the most common and popular tertiary colors. For a light aqua color mix cobalt blue with white. The primary colors are red blue and yellow. Primary colors cannot be mixed with other colors. They are the source of all other colors.

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The energy present in pond water and kerosene are potential energy and chemical energy respectively.

Energy is a quantifiable quantity in physics that can be transferred from an item to do work. Thus, we might characterise energy as the capacity to engage in any kind of physical action. So, to put it simply, we can define energy as: Energy is the capacity to carry out work.

Energy "can neither be created nor destroyed but can only be changed from one form to another," according to the rules of conservation of energy. The SI unit for energy is called a joule.

In pond, water is stored during rain and stored potential energy whereas in kerosene, carbon molecules have chemical energy and when it burns, chemical energy revels as thermal energy.

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There are multiple questions in your prompt, so let's break them down one by one.

How much gravitational potential energy does the goat gain?

The gravitational potential energy gained by the goat can be calculated using the formula:

GPE = mgh

where m is the mass of the goat, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the cliff.

Substituting the given values, we get:

GPE = 50 kg x 9.8 m/s^2 x 450 m

GPE = 220500 J

Therefore, the goat gains 220500 J of gravitational potential energy.

How much gravitational potential energy does Evan gain?

The gravitational potential energy gained by Evan can be calculated using the same formula as above:

GPE = mgh

where m is the mass of Evan (including his parachute gear), g is the acceleration due to gravity, and h is the height of the jump.

Substituting the given values, we get:

GPE = 90 kg x 9.8 m/s^2 x 2.0 m

GPE = 1764 J

Therefore, Evan gains 1764 J of gravitational potential energy.

How much kinetic energy does the goat have just before it hits the ground?

The conservation of energy principle tells us that the total energy of the system (in this case, the goat) remains constant. So, the kinetic energy gained by the goat just before it hits the ground is equal to the gravitational potential energy it had at the top of the cliff. Therefore, the kinetic energy of the goat just before it hits the ground is:

KE = GPE = 220500 J

Note that we have assumed that there is no loss of energy due to air resistance or other factors during the goat's fall.

How much GPE does Evan gain given: h = 2.0 m

We have already calculated the gravitational potential energy gained by Evan earlier. Using the same formula, we get:

GPE = mgh

GPE = 90 kg x 9.8 m/s^2 x 2.0 m

GPE = 1764 J

What is the kinetic energy of the aircraft at a height of 5000.00 m?

We cannot calculate the kinetic energy of the aircraft with the given information. The kinetic energy of an object depends on its mass and velocity, but we only have information about its height. If we assume that the aircraft is stationary at a height of 5000.00 m, then its kinetic energy would be zero.

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The stopping distances are found to be 218.13 m and 149 m, respectively, for

a = -2.6 m/s²

b = -5.5 m/s² with time 0.3 s.

Newton's equations of motion link an object's motion to the forces acting on it. According to the first law, an object won't change its motion until a force is applied to it. The second law states that an object's force can be determined by multiplying its mass by its acceleration. The third law states that when two things come into contact, they put equal and opposing pressures on one another.

Initial speed = U = 94Km/hr

=> 26.11m/s

a1 = -2.6m/s²

a2 = -5.5 m/s²

Final velocity = V = 0

t= 0.3sec

A) the stopping distance with a1 = -2.6m/s²:

V² = U² +2as

=> 0 = 26.11² + 2 x -2.6 x s

S=> 131.1 m

the stopping distance  

=> 26.11/0.3 + 131.1

=> 218.13m

B) the stopping distance with a2 = -5.5 m/s²:

V² = U² +2as

=> 0 = 26.11² + 2 x -5.5 x s

S=> 61.97 m

the stopping distance  

=> 26.11/0.3 + 61.97

=> 149m

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Answer:

An electron configuration is used to name the sublevels in which electrons are found within an atom

Explanation:

An electron configuration is used to name the sublevels in which electrons are found within an atom for example for the atom carbon has 6electrons so its configuration is 1s²2s²2p²

With the 1s 2s and 2p showing the various energy sublevels

Concerning the concepts and fundamentals of the atomic model, an electron configuration is used to name the sublevels in which electrons are found within an atom. Hence, option (C) is correct.

The arrangement of electrons in specific energy levels around the atomic nucleus of an atom is known as the electron configuration of an atom.

As per the atomic shell model, "The electrons occupy the various energy levels from the first shell nearest to the nucleus, upto the farthest shell from the nucleus.

Consequently, an electron configuration is used to name the sublevels in which electrons are found within an atom. For example for the atom carbon has 6 electrons so its configuration is 1s²2s²2p². With the 1s 2s and 2p showing the various energy sublevels.

Thus, we can conclude that an electron configuration is used to name the sublevels in which electrons are found within an atom.

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Answer:

Et = 30018 [W]

Explanation:

To solve this problem we must use the definition of potential energy, which is expressed by the following equation:

\(E_{p} =m*g*h\)

where:

Ep = potencial energy [W]

g = gravity acceleration [m/s^2]

h = elevation = 120 [m]

m = mass flow = [1800/min]

But in order to get watts into potential energy, we must convert the mass flow from kilograms per minute to kilograms per second.

\(1800[\frac{kg}{min} ]*\frac{1}{60}\frac{min}{s}=30[\frac{kg}{s} ]\)

Ep = 30*9.81*120

Ep = 35316 [W]

If we use  85% of the potential  energy will have:

Et = 35316*0.85

Et = 30018 [W]

Sand and salt and water will be separated by decanting. The student's best option for separating the mixture is to leave the sand in the original container.

The salt will be left behind as a solid even if you boil or evaporate the water. Distillation is an option if you wish to collect the water. Salt has a far greater boiling point than water, which explains why this is effective.

Filtration. Filtration is among the most straightforward techniques for separating mixtures. Filtration is simple if one component is a liquid and the other is a solid. In this case, the mixture can simply be poured through filter paper.

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We are given the following quantity:

Let's remember that in scientific notation the term "Micro" refers to ten to the minus 6, therefore, this is equivalent to:

We can convert this into standard notation by multiplying by the ten to the minus six:

Therefore, the charge is 0.00016 Coulomb.

Answer:

these are in the hooks the balloons repel each other if the hooks are isolated.

Explanation:

In electrostatics, charges of the same sign repel and of a different sign attract each other.

With this explanation we analyze the situation presented, they indicate that the balloons have a negative taste, so when these are in the hooks the balloons repel each other if the hooks are isolated.

If the hooks are connected to Earth, the poop of the balloons is neutralized, so there is neither attraction nor repulsion.

Answer:

Here you go : )

Explanation:

The distance an object moves if 25J of work is done with 3.0N of force is 8.33 m.

For a given amount of force, F, and a given distance, d, the formula for calculating work done is as follows:

Work done = Force x distance

So, the distance would be,

Work done / force = 25/3 = 8.33 m.

Work is the energy exerted by an object when it applies a force to move another object over some distance.

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The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people

We'll begin by converting 175 cm to m. This can be obtained as illustrated below:

100 cm = 1 m

Therefore,

175 cm = (175 cm × 1 m) / 100 cm

175 cm = 1.75 m

Thus, 175 cm is equivalent to 1.75 m

The number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:

Number of people needed = Height of tower / height of a person

Number of people needed = 553 / 1.75

Number of people needed = 316 people

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Answer:

Higher denisty

Explanation:

High pressure=high denisty

The energy efficiency of the car is approximately 16.7%.

The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:

The useful work output can be calculated as the kinetic energy of the car using the equation:

where m is the mass of the car and v is its velocity.

Substituting the given values:

The total energy input is the energy released by burning 0.1 L of gasoline, which is:

Substituting these values into the equation for efficiency:

Therefore, the energy efficiency of the car is approximately 16.7%.

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Answer:

\(0.000835\ \text{m}\)

Explanation:

d = Distance between plates = 2 mm

V = Potential difference = 500 V

v = Velocity of proton = \(2\times 10^5\ \text{m/s}\)

a = Acceleration

m = Mass of proton = \(1.67\times 10^{-27}\ \text{kg}\)

Electric field is given by

\(E=\dfrac{V}{d}\\\Rightarrow E=\dfrac{500}{2\times 10^{-3}}\\\Rightarrow E=250000\ \text{V/m}\)

Force balance is given by

\(ma=qE\\\Rightarrow a=\dfrac{qE}{m}\\\Rightarrow a=\dfrac{1.6\times 10^{-19}\times 250000}{1.67\times 10^{-27}}\\\Rightarrow a=2.395\times 10^{13}\ \text{m/s}^2\)

We have the relation

\(v^2=u^2+2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{(2\times 10^5)^2-0}{2\times 2.395\times 10^{13}}\\\Rightarrow s=0.000835\ \text{m}\)

The farthest distance from the negative plate that the proton reaches is \(0.000835\ \text{m}\).

The farthest distance from the negative plate that the proton reaches will be s=0.000835 m

The electric field is defined as the force across the charged particles which attract or repel the other charged particles.

Now it is given in the question that

d = Distance between plates = 2 mm

V = Potential difference = 500 V

v = Velocity of proton =   \(2\times 10^5\ \dfrac{m}{s}\)

a = Acceleration

m = Mass of proton = \(1.67\times10^{-27} kg\)

The Electric field will be calculated as

\(E=\dfrac{V}{d}\)

\(E=\dfrac{500}{2\times10^{-3}} =250000\ \frac{V}{m}\)

Force balance is given by

\(ma=qe\)

\(a=\dfrac{qE}{m}\)

\(a=\dfrac{1.6\times10^{-19}\times250000}{1.67\times10^{-27}}\)

\(a=2.395\times 10^{13}\frac{m}{s^2}\)

Now from equation of motion

\(v^2=u^2+2as\)

\(s=\dfrac{v^2-u^2}{2a}\)

\(s=\dfrac{(2\times10^5)^2-0}{2\times 2.395\times 10^{13}}\)

\(s=0.000875 m\)

Thus the farthest distance from the negative plate that the proton reaches will be s=0.000835 m

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Answer:

Explanation:

Given:

Q = 90 J

W = 60 J

________

ΔU - ?

1 law of thermodynamics:

Q = ΔU + W

Change in internal energy:

ΔU = Q - W = 90 - 30 = 60 J

the initial velocity of the bike rider is 10.35 m/s.

The required percentage is 24% and the number of ways to get the microstates is 2.98*10²⁹.

The number of microstates for 49 heads, 51 tails, 50 heads and 50 tails and 51 heads and 49 tails are tabulated below:

The total number of microstates is,

Total(micro) = 9.9*10²⁸ + 1*10²⁹ + 9.9*10²⁸

Total = 3 * 10²⁹

The total number of microstates is 3 * 10²⁹.

The number of microstates in the whole range (100 heads and 0 tails to 0 head and 100 tails) when tossing 100 coins is 1.27 * 10³⁰.

The percentage required is =

= (total number of microstates / total no. of possible ways)*100

= (2.98*10²⁹/1.27*10³⁰)*100

= 24%

Therefore, the required percentage is 24% and the number of ways to get the microstates is 2.98*10²⁹.

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