Answer:
\(\frac{a+4\sqrt{ay}+4y }{a-4y}\)
given:
\(\frac{\sqrt{a}+2\sqrt{y}}{\sqrt{a}-2\sqrt{y} }\)
solve for:
Rationalized denominator
Step-by-step explanation:
1. Rationalize the denominator
\(\frac{\sqrt{a}+2\sqrt{y}}{\sqrt{a}-2\sqrt{y} } * \frac{2\sqrt{y} }{2\sqrt{y} }\)
2. Simplify
\(\frac{2\sqrt{y}(\sqrt{a}+2\sqrt{y} ) }{2\sqrt{y}(\sqrt{a}-2\sqrt{y}) }\)
\(\frac{a+4\sqrt{ay}+4y }{a-4y}\)
Answer:
\(\frac{a+4\sqrt{ay}+y }{a-4y }\)
Step-by-step explanation:
As far as I understand, it looks like this: \(\frac{\sqrt{a}+2\sqrt{y} }{\sqrt{a}-2\sqrt{y} }\)
We know that:
\((a - b)*(a + b) = a^{2} -b^{2}\) we can always multiply by 1\(\frac{\sqrt{a}+2\sqrt{y} }{\sqrt{a} +2\sqrt{y} }=1\) \((a+b)^2=a^2+2ab+b^2\)Therefore,
\(\frac{\sqrt{a}+2\sqrt{y} }{\sqrt{a}-2\sqrt{y} } *1 =\frac{\sqrt{a}+2\sqrt{y} }{\sqrt{a}-2\sqrt{y} } *\frac{\sqrt{a} +2\sqrt{y} }{\sqrt{a}+2\sqrt{y} } =\frac{(\sqrt{a}+2\sqrt{y})^2 }{(\sqrt{a})^2-(2\sqrt{y})^2 } =\frac{a+4\sqrt{ay}+y }{a-4y }\)
a certain phone call costs 75 cents for the first three minutes plus 15 cents for each additional minute.if the call lasted x minutes and x is an integer greater than 3, which of the following expresses the cost of the call in dollars?
The equation that represents the cost of the call in dollars is option d. 0.75 + 0.15(x - 3).
What is linear equation?A linear equation has the formula y = mx + b, where x and y are variables, m is the angle of the line's slope, and b denotes the y-intercept (the location where the line crosses the y-axis). On a graph, this equation represents a straight line.
The y-intercept of a linear equation, which is determined by the value of b, is first plotted on a graph. The slope is then used to determine further points along the line. How much y changes for each unit of x is indicated by the slope. For instance, if the slope is 2, then y grows by 2 for every unit increase in x.
Given that, a certain phone call costs 75 cents for the first three minutes plus 15 cents for each additional minute.
Let us suppose number of minutes = x.
Then,
Cost = 0.75 + 0.15(x - 3)
hence, the equation that represents the cost of the call in dollars is option d. 0.75 + 0.15(x - 3).
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The complete question is:
An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had in the previous year. The results are shown below. Under Age of 18 Over Age of 18 n1 = 500 n2 = 600 Number of accidents = 180 Number of accidents = 150 ​ We are interested in determining if the accident proportions differ between the two age groups. ​ Refer to Exhibit 11-7 and let p u represent the proportion under and p o the proportion over the age of 18. The null hypothesis is a. p u - p o = 0 b. p u - p o ≠0 c. p u - p o ≥ 0 d. p u - p o ≤ 0
The 95% confidence interval for the difference between the two proportions is (0.056, 0.164)
Here, we are given that from the sample information for people under 18-
n₁ = 500
x₁ = 180
⇒ p₁ = 180/ 500
p₁ = 0.36
then,
q₁ = 1 - p₁
q₁ = 0.64
Similarly, from the sample information for people over 18, we have-
n₂ = 600
x₂ = 150
⇒ p₂ = 150 / 600
p₂ = 0,25
then,
q₂ = 1 - p₂
q₂ = 1 - 0.25
q₂ = 0,75
Now, we conduct a hypothesis test as follows-
Null hypothesis (H₀) ⇒ p₁ = p₂
Alternative Hypothesis (Hₐ) ⇒ p₁ ≠ p₂
Confidence interval = 95 %
⇒ significance level (α) = 5 %
α = 0.05
and α/ 2 = 0.025
⇒ z at 95% significance level = 1.96 (from z tables)
Now, we calculate z statistic-
z(s) = (p₁ - p₂) / EED
EED = √[(p₁*q₁)n₁ + (p₂*q₂)/n₂]
EED = √[( 0.36*0.64)/500 + (0.25*0.75)/600]
EED = √[0.00046 + 0.0003125]
EED = 0.028
and (p₁ - p₂) = 0.36 - 0.25
= 0.11
Therefore,
z(s) = 0.11 / 0.028
z(s) = 3.93
we can see that z(s) > 1.96
⇒ z(s) is in the rejection region for H₀
Thus, we reject H₀. We can´t support the idea of equals means
Now, CI at 95 % = (p₁ - p₂) ± z(c) * EED
CI = (0.11 ± 1.96 * 0.028)
CI = (0.11 ± 0.054)
CI = (0.056, 0.164)
Thus, the 95% confidence interval for the difference between the two proportions is (0.056, 0.164)
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Your question was incomplete. Check for missing content below-
Q1. Let P, represent the proportion under and p, the proportion over the age of 18. The null hypothesis is:_____.
Q2. The 95% confidence interval for the difference between the two proportions is:____.
2(2x - 4) = 3(x + 4)
Answer:
24
Step-by-step explanation:
i dont know if its correct
Decide which of the two given prices is the better deal and explain why.
You can buy shampoo in a 5-ounce bottle for 3,89$ or in a 14-ounce bottle for 11,99$.
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.The -ounce bottle is the better deal because the cost per ounce is $
nothing per ounce while the -ounce bottle is $
nothing per ounce.
B.The -ounce bottle is the better deal because the cost per ounce is $
nothing per ounce while the -ounce bottle is $
nothing per ounce.
(Round to the nearest cent as needed.)
Answer:
The 14-ounce bottle is the better deal
Step-by-step explanation:
I know this beause inorder to figure out which one is better you have to make them the same price and then see which bottle has more ounces. So I made each price 1$ so there is 1.58-ounces per dollar in the 5-ounce bottle and 1.17 -ounces per dollar in the 14-ounce bottle.
What is 5x + 80 Will?
Which expression is equivalent to 4(y + 2) ? to
Answer:
4y+8
Step-by-step explanation:
Answer:4y+8
Step-by-step explanation:
To find an equivalent expression you can just simplify this expression by multiplying the numbers in the parentheses by 4. 4y+8
A theater sells 74877 tickets. They sell 21243 tickets and then they sell 39643 how much is is combined
Answer:1897
Step-by-step explanation:
add 74,877 to 21,243 then add 39,643 to get 1897
- Using Determinant, Find the value of K below are which the consistent equations for 3x + y + 2 = 0 - 4x + 2Y = K = 0 3X - Y -3K = 0 value are
Using the system of equation and determinant given, the value of k is any real number except -1/3
What is DeterminantThe determinant is a scalar value that can be computed from the elements of a square matrix. It is a useful tool in linear algebra and is used in many applications, including solving systems of linear equations, finding the inverse of a matrix, and calculating the volume of a parallelepiped.
Given the system of equations 3x + y + 2 = 0, -4x + 2y = k and 3x - y - 3k = 0.
We can write these equations in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix and B is the constant matrix.
A = [3 1 2]
[-4 2 k]
[3 -1 -3k]
X = [x]
[y]
[k]
B = [0]
[0]
[0]
To find the value of k for which the system is consistent, we need to find the determinant of the coefficient matrix.
|A| = (3)(2k) - (1)(-4) + (2)(3) = 6k + 2
For the system of equations to be consistent, the determinant of the coefficient matrix should not be equal to zero.
So, |A| = 6k + 2 ≠ 0
Therefore, the value of k can be any real number except -1/3.
So, the value of k can be any real number except -1/3. The system of equations is consistent for all real numbers except -1/3.
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Which two expressions are equivalent?
A. (14 – 8) x and 14 – (8 x)
B. 14 – (8 x) and 14 – (x 8)
C. (8 – 14) x and 14 – 8 x
D. (8 – 14) and (14 – 8)
Answer:
6
Step-by-step explanation:
Answer easy ypu just subtract i am not the best at this so dont take my word for it lol
what is the area of the figure
Answer:
A = 2184 cm²
Step-by-step explanation:
the area (A) of the figure is calculated as
A = \(\frac{1}{2}\) h(b₁ + b₂)
where h is the perpendicular height between the bases b₁ and b₂
here h = 42 , b₁ = 52 , b₂ = 52 , then
A = \(\frac{1}{2}\) × 42 × (52 + 52) = 21 × 104 = 2184 cm²
Answer:
A = 2184 cm2
Step-by-step explanation:
Area of a parallelogram:
\(A = b*h\)
\(b=52,h=42\)
\(A=(42)(52)=2184cm^{2}\)
Hope this helps.
A skyscraper casts a shadow 200 ft long. If the angle of elevation of the Sun is 38 degrees, then the height of the skyscraper is approximately _____.
A. 200 ft
B. 173.34 ft
D. 156.26 ft
The height of the skyscraper is D. 156.26 ft
How to determine the valueTo determine the height of the skyscraper, we need to consider the following trigonometric identities listed thus;
sinecosinetangentcotangentsecantcosecantFrom the information given, we have that;
Angle, θ = 38 degrees
The shadow casted is the adjacent side of the angle and is 200 ft
The height off the skyscraper is the opposite side
Now, using the tangent identity, we have that;
tan θ = opposite/adjacent
tan 38 = h/200
cross multiply the values, we get;
h = 200(0.7812)
Multiply the values
h = 156. 26 ft
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I NEED HELP PLEASE THANKS! :) Find the seventh partial sum of 13, 22, 31, 40, ...
9
67
106
280
Answer:
Step-by-step explanation:
Arithmetic sequence
First term a = 13
Common difference = 2nd term - first term
= 22 - 13
d = 9
\(a_{n}= a + (n-1)d\\\\a_{7}= 13 + 6*9\)
= 13 + 54
= 67
Sum of 7 terms = \(\frac{n}{2}(2a + (n-1)d)\\\\\)
= \(\frac{7}{2}(2*13+6*9)\\\)
=\(\frac{7}{2}(26+54)\\\)
= \(\frac{7}{2}*80\\\)
= 7 *40
= 280
Answer:
280
Step-by-step explanation:
the 7th number is
Jerry drew AJKL and AMNP so that ZK ZN, ZL 2P, JK= 6, and
MN = 18. Are AJKL and AMNP similar? If so, identify the similarity postulate
or theorem that applies.
A. Similar - SAS
B. Similar - AA
C. Similar - SSS
D. Cannot be determined
The two considered triangles JKL and MNP are similar by the AA rule of similarity as the two angles that is ∠K = ∠N and ∠L = ∠P are there.
What are similar triangles?Similar triangles are triangles that have the same shape, but their sizes may vary. All equilateral triangles, squares of any side lengths are examples of similar objects. In other words, if two triangles are similar, then their corresponding angles are congruent and corresponding sides are in equal proportion. We denote the similarity of triangles here by ‘~’ symbol.
It is given that two triangles that are JKL and MNP are considered in which:
∠K = ∠N∠L = ∠PJK = 6MN = 18Now, from ΔJKL and ΔMNP, we have
∠K = ∠N (Given in the question)
∠L = ∠P(Given in the question)
Thus, by AA rule of similarity,
ΔJKL is similar to ΔMNP.
Therefore, the two considered triangles JKL and MNP are similar by the AA rule of similarity as the two angles that is ∠K = ∠N and ∠L = ∠P are there.
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PLEASE HURRY! WILL MARK BRAINLIEST IF CORRECT (Screenshot)
Answer:
The length of XY is 22.5
Step-by-step explanation:
Since you need to hurry I will not write an explanation
Hope this helps! :)
૮ ・ﻌ・ა
Bennett Griffin and Chula Garza organized Cole Valley Book Store as a corporation; each contributed $71,500 cash to start the business and received 5,600 shares of common stock. The store completed its first year of operations on December 31, current year. On that date, the following financial items for the year were determined: December 31, current year, cash on hand and in the bank, $69,250; December 31, current year, amounts due from customers from sales of books, $43,500; unused portion of store and office equipment, $72,500; December 31, current year, amounts owed to publishers for books purchased, $12,400; one-year note payable to a local bank for $3,200. No dividends were declared or paid to the stockholders during the year.
Required:
Complete the following balance sheet as of the end of the current year. Some information has been given below.
What was the amount of net income for the year? (Hint: Use the retained earnings equation [Beginning Retained Earnings + Net Income − Dividends = Ending Retained Earnings] to solve for net income.)
he net income for the year is $16,550.
Calculation of the net income for the year:Retained earnings equation is:Beginning Retained Earnings + Net Income − Dividends = Ending Retained EarningsWhere, Beginning Retained Earnings = $0 (not given)Ending Retained Earnings = $16,550 (calculated from balance sheet)Dividends = $0 (not given)
Therefore,Net Income = Ending Retained Earnings - Beginning Retained Earnings + Dividends= $16,550 - $0 + $0= $16,550 Balance Sheet of Cole Valley Book Store as of December 31, current year:Current assets Cash on hand and in bank = $69,250 Amounts due from customers from sales of books = $43,500 Total current assets = $112,750 Property, plant, and equipment Unused portion of store and office equipment = $72,500
Total assets = $185,250Liabilities Amounts owed to publishers for books purchased = $12,400 One-year note payable to a local bank = $3,200 Total liabilities = $15,600 Stock holders' Equity Common stock, 5,600 shares at $71,500 = $400,400 Retained earnings, beginning = $0Net income = $16,550 Retained earnings, ending = $16,550 Total stockholders' equity = $416,950Total liabilities and stockholders' equity = $185,250 + $15,600 + $416,950= $617,800
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Jocelyn boils 24 eggs. From experience, she knows that the shell of any given during the boiling process. If shells crack independently, what is the probability the boiling process with a cracked shell? Round to 2 decimal places.
Answer:
.62
Step-by-step explanation:
Keep it nice and simple.
Answer:
.62
Step-by-step explanation:
Maya counts 55 passengers on the bus. There were only 50 passengers on the bus. What is Maya's percent error?
Answer:
I don't know.
A student places a block on a table and hangs one mass from the block. The student lets the block go and observes the block move towards the end of the table where the mass was located. The student then places the block on the table and hangs a second, larger mass from the opposite end of the block. The block moves in the opposite direction as the first trial. What does this experiment demonstrate? Use information from the experiment to support your answer.
What the given experiment demonstrates is; The magnitude of acceleration according tp newton's second law of motion
How to identify the magnitude of acceleration?Newton's second law of motion states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.
This law basically establishes a relationship between the net force and the acceleration, which is expressed as;
∑ F = m a
where;
∑F is the sum of the external forces
m the mass of the body
a is the acceleration of the body
The initial situation in the question shows the block and a baking mass. This means that an acceleration is created towards the hanging mass expressed as;
W₁ = M₁ g
F = ma
Thus;
M₁g = m a
a = (M₁g/m)
where;
W₁ is the weight of the body
M₁ is the mass of the body hanging under the acceleration of gravity.
For the second case, there are two masses, with one on each side, and so we have;
∑ F = W₁ - W₂
∑F = (M₁ - M₂) g
Using Newton's second law of motion gives us;
(M₁ - M₂ )g = ma
a = (M₁ - M₂ )mg
Thus, the acceleration depends on the difference of the hanging masses which proves Newton's second law of motion.
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Mike has a right rectangular shipping carton with a volume of 31.605 cubic meters. The height of the shipping carton is 2.1 meters, and the width is 3.5 meters.
What is the length of Mike's shipping carton?
Enter your answer as a decimal in the box.
Please help <3
Answer:
volume
\( = lbh\)
\(31.605 = l \times 3.5 \times 2.1 \\ 31.605 = l \times 7.35\)
divide both side by 7.35
\(l = 4.3\)
Answer:
The Answer is 4.3
Step-by-step explanation:
How i got 4.3 is i multiplied 2.1 and 3.5 and that gave me 7.35
2.1 x 3.5 = 7.35
Then i divided the Volume with 7.35
31.605 ÷ 7.35 = 4.3
So, your answer is 4.3
For each of the 6 coverage areas of a standard homeowners insurance policy, briefly describe what they cover: Dwelling, Other Structures. Personal Property,
Loss of Use, Personal Liability, Medical Payments
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Find the measure of angle AEB
Answer:
∠ AEB = 114°
Step-by-step explanation:
the chord- chord angle AEB is half the sum of the measures of the arcs intercepted by the angle and its vertical angle , that is
∠ AEB = \(\frac{1}{2}\) (AB + CD) = \(\frac{1}{2}\) (140 + 88)° = \(\frac{1}{2}\) × 228° = 114°
2. The half life of uranium-232 is 68.9 years. a) If you have a 100 gram sample, how much would be left after 250 years? b) If you have a 100 gram sample, how long would it take for there to be 12.5 grams remaining?
Step-by-step explanation:
The amount left is:
A = A₀ (½)^(t/T)
where A₀ is the initial amount,
t is the amount of time,
and T is the half life.
a) A = 100 g (½)^(250 yr / 68.9 yr)
A = 8.09 g
b) 12.5 g = 100 g (½)^(t / 68.9 yr)
0.125 = (½)^(t / 68.9 yr)
3 = t / 68.9 yr
t = 206.7 yr
Two sides and an angle SSA of a triangle are given determine whether the given measurements produce one triangle two triangles or no triangle at all solve each triangle that results a=13 b=16.9 A=26 degrees
Given:
a = 13
b = 16.9
A = 26 degrees
Asked: What are the values for angles B and C and side c?
Solution:
To solve this problem, we will be needing the formula for the sine law.
Sine Law Formula:
\(\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}\)Now, we will first solve for the angle B.
\(\begin{gathered} \frac{a}{\sin A}=\frac{b}{\sin B} \\ \frac{13}{\sin 26}=\frac{16.9}{\sin B} \\ 13\sin B=16.9\sin 26 \\ \frac{13\sin B}{13}=\frac{16.9\sin 26}{13} \\ \sin B=\frac{16.9\sin26}{13} \\ B=\sin ^{-1}(\frac{16.9\sin26}{13}) \\ B=34.75203189 \\ B=35\text{ degr}ees \end{gathered}\)Now that we have angle B, we can now find angle C by combining all the angles and equate it to 180 degrees.
\(\begin{gathered} A+B+C=180 \\ 26+35+C=180 \\ 61+C=180 \\ C=180-61 \\ C=119\text{ degr}ees \end{gathered}\)
In order to find side c, we will use again the sine law formula.
\(\begin{gathered} \frac{a}{\sin A}=\frac{c}{\sin C} \\ \frac{13}{\sin 26}=\frac{c}{\sin 119} \\ 13\sin 119=c\sin 26 \\ \frac{13\sin119}{\sin26}=\frac{c\sin 26}{\sin 26} \\ c=\frac{13\sin119}{\sin26} \\ c=25.9370542 \end{gathered}\)ANSWER:
Angle B = 35 degrees
Angle C = 119 degrees
Side c = 25.9
Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this lesson to solve the following exercise.
Find the following sums without using a calculator or a formula. Hint: Apply the procedure used by Gauss. (See the Math Matters on page 31.)
+393 +394 + 395
(a) 1+2+3+4+...+392
(b) 1+2+3+4
x
546 + 547 +548 + 549
(c) 2+4+6+8+...+76 + 78 + 80 +82
(a) The sum of the series 1+2+3+4+...+392 is 77,028.
(b) The sum of the series 1+2+3+4...x is (x/2)(1 + x).
(c) The sum of the series 546 + 547 + 548 + 549 is 2,190.
To solve the exercise using Polya's four-step problem-solving strategy, we will apply the procedures presented in the lesson.
(a) For the series 1+2+3+4+...+392:
Using the arithmetic series formula Sn = (n/2)(a + l), where n is the number of terms, a is the first term, and l is the last term, we can substitute the values: Sn = (392/2)(1 + 392) = 196(393) = 77,028.
(b) For the series 1+2+3+4...x:
To find the sum of this series, we need to know the number of terms (n) based on the value of x. Since the series follows a consecutive pattern, the number of terms will be equal to x itself. Thus, the sum of the series would be Sn = (x/2)(1 + x).
(c) For the series 546 + 547 + 548 + 549:
Using the arithmetic series formula Sn = (n/2)(a + l), we can determine the number of terms (n) by subtracting 546 from 549 and then adding 1: n = 549 - 546 + 1 = 4. Substituting the values into the formula: Sn = (4/2)(546 + 549) = 2(1095) = 2,190.
The final answer for each part is:
(a) The sum of the series 1+2+3+4+...+392 is 77,028.
(b) The sum of the series 1+2+3+4...x is (x/2)(1 + x).
(c) The sum of the series 546 + 547 + 548 + 549 is 2,190.
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As a salesperson at Roaring Waves Beach Supplies, Carissa receives a monthly base pay plus commission on all that she sells. If she sells $500 worth of merchandise one month, she is paid $390. If she sells $1,000 of merchandise in one month, she is paid $480.
Find Carissa's salary when she sells $2,400 worth of merchandise.
Carissa's salary when she sells $2,400 worth of merchandise is $732.
What is Carissa's salary?The first step is to determine the base pay and the commission rate.
In order to determine these values, form a system of equations that represent the information in the question:
a + 500b = 390 equation 1
a + 100b = 480 equation 2
Where:
a = base pay
b -= commission rate
Subtract equation 1 from equation 2:
500b = 90
Divide both sides by 500:
b = 90 / 500
b = 0.18
Substitute for b in equation 1:
a + 500(0.18) = 390
a + 90 = 390
a = 390 - 90
a = 300
Salary = 300 + (0.18 x 2400)
Salary = 300 + 432 = $732
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Conner's car is worth $24,578. Each year the car's value decreases by $1,345. Create an
equation to describe how much money the car will be worth after a set amount of years. Write the
equation for this problem in function notation. Then interpret how much money his car will be
worth after 4 years. Make sure to define your variables and show all of your work.
Answer:
f(x)=24578-1345x
$19198
Step-by-step explanation:
Let's suppose "x" years pass.
\(f(x)=24578-1345x\)
When x=4,
\(f(4)=24578-1345*4\\=24578-5380\\=19198\)
The equation is y = $24,578 - $1,345x and value of car after 4 years is
$19,198.
What is linear equation?First order equations include linear equations. In the coordinate system, the linear equations are defined for lines. A linear equation in one variable is one in which there is a homogeneous variable of degree 1 (i.e., only one variable). Multiple variables may be present in a linear equation. Linear equations in two variables, for example, are used when a linear equation contains two variables.
Given cost of car = $24,578
amount decrease every year = $1,345
let amount after x years be y
where x = time and y = amount
equation is
y = $24,578 - $1,345x
amount after 4 years,
put x = 4
y = $24,578 - $1,345x
y = $24,578 - $1,345(4)
y = $24,578 - $5,380
y = $19,198
Hence equation for amount is y = $24,578 - $1,345x and amount after 4 years is $19,198.
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A castle under siege has enough food for 300 men for 90 days. (Level 6) After 40 days, 150 men have left the castle.
How long would the food last at the same rate of consumption?
Answer:
45 days
Step-by-step explanation:
300 men = 90 days
the percentage of food consumed by one man
= ( 90 / 300 ) * 100
= 30% = 0.3
After 40 days
150 men remain to consume at 30%
determine the number of days the remaining food will last ( x )
= x / 150 = 0.3
therefore ; X = 150 * 0.3 = 45 days
8. The first three terms of a geometric sequence are ( x-6), 3x, and y. If the common ratio is 6, then the value of y is.
Answer:
The value of y is 216
(and the value of x is 12)
Step-by-step explanation:
The general formula for a geometric sequence is,
\(a_n = a_1(r)^{n-1}\)
Where n represents the nth term, a_1 is the first term and r is the common ratio,
we see that,
r = 6,
the first term is,
a_1 = (x-6)
the 2nd term is,
a_2 = 3x,
the 3rd term is,
a_3 = y, finding y,
first we find x, using the above given formula we have,
\(a_2 = a_1(6)^{2-1}\\3x = (x-6)(6^1)\\3x = 6x -36\\36 = 6x - 3x\\36 = 3x\\x=36/3\\x=12\)
x = 12,
Now, for y we can use the relation between a_3 and a_2,
\(a_3 = a_1(6)^{3-1}\\y = (x-6)(6)^2\\y = (12-6)(6^2)\\y = 6(6^2)\\y = 6^3\\y = 216\)
y = 216
what would be your first step in completely factoring 6a^2-15a+6
The completely factoring form of 6a^2 - 15a + 6 is 3(2a - 1)(a - 2).
To completely factor the expression 6a^2 - 15a + 6, the first step is to check if there is a common factor among the coefficients (6, -15, and 6) and the terms (a^2, a, and 1).
In this case, we can see that the common factor among the coefficients is 3, so we can factor out 3:
3(2a^2 - 5a + 2)
Now we need to factor the quadratic expression inside the parentheses further. We are looking for two binomials that, when multiplied, give us 2a^2 - 5a + 2. The factors of 2a^2 are 2a and a, and the factors of 2 are 2 and 1. We need to find two numbers that multiply to give 2 and add up to -5.
The numbers -2 and -1 fit this criteria, so we can rewrite the expression as:
3(2a - 1)(a - 2)
Therefore, the completely factored form of 6a^2 - 15a + 6 is 3(2a - 1)(a - 2).
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6abc2 + 6a2bc
A=1
B=2
C= -3
\(\\ \rm\longmapsto 6abc^2+6a^2bc\)
\(\\ \rm\longmapsto 6(1)(2)(-3)^2+6(1)^2(2)(-3)\)
\(\\ \rm\longmapsto 12(9)+6(-6)\)
\(\\ \rm\longmapsto 108-36\)
\(\\ \rm\longmapsto 72\)