Answer:4m
Explanation:
Thats the girls maximum speed
What are some examples of objects or substances that are magnetic?
Answer:
iron,Cobalt and nickel
When a single charge q is placed on one corner of a square, the electric field at the center of the square is F/q. If three other equal charges are placed on the other corners, the electric field at the center of the square due to these four equal charges is
a) F/(2q)
b) F/(4q)
c) 4F/q
d) F/q
e) zero
Please explain how you came to the correct answer.
The answer to the question is option (c) 4F/q.
The electric field due to a single charge q at the center of a square is given by
E = F/qWhere F = 1/4πε₀ * q / r²,
where r is the distance between the charge and the center of the square. The electric field of the single charge q has a magnitude of F/q when it is at the center of the square.
If three other charges, each of the same magnitude, are placed on the other corners of the square, the resultant electric field at the center of the square is the vector sum of the electric fields due to the four charges.Let the distance between the charges and the center of the square be a.
The force due to each charge is given by
F' = 1/4πε₀ * q / a²
The electric field due to each charge at the center of the square is given by
E' = F'/q = 1/4πε₀ * q / a²q.
The electric field at the center of the square due to these four charges is the vector sum of the electric fields due to the four charges. Since the charges are placed at the corners of a square and are equidistant from the center, the angle between any two fields is 90°.
Hence, the resultant electric field is given by
E = 2E' sin 45° + 2E' sin 135°= 2E' /√2 + 2E' /-√2= 4E' /√2= 4 (1/4πε₀ * q / a²q) /√2= 4F /q.
Hence, the option (c) is the correct answer.
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Background information on thermal energy transfer and conservation of energy
Answer:
Generally, when thermal energy is transferred to a material, the motion of its particles speeds up and its temperature increases. There are three methods of thermal energy transfer: conduction, convection, and radiation. ... Convection transfers thermal energy through the movement of fluids or gases in circulation cells.Convection. When a fluid, such as air or a liquid, is heated and then travels away from the source, it carries the thermal energy along. This type of heat transfer is called convection. The fluid above a hot surface expands, becomes less dense, and rises.
Friction opposes the movement of the crate across the warehouse foor Does the frictional force change or stay the same as the crate gets heavier?
Answer:
well, the opposed friction is caused because of the weight of the crate,so if the weight is been added more and becomes heavier the friction between the floor and the crate will increase
Friction is the one that opposes motion. Increase in the weight of the body causes an increase friction offered to the relative motion of the surfaces in contact. It is clear that the frictional force will change.
What are the factors affecting friction?There are several factors that can affect friction either increase or decrease the resistance.
Some of them are:
Texture of the surface.Shape or design of the surface.Type of friction involved.Dry friction, etc.The friction is directly proportional to the weight of the body on a horizontal surface and hence an increase in weight increases friction.
Thus, the frictional force will change as the crate gets heavier.
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Sound will travel slowest through which medium?
How could you cause a chemical change to vinegar?
Answer: Any chemical reaction is an example of a chemical change. Examples include: Combining baking soda and vinegar (which bubbles off carbon dioxide gas)Jan 13, 2020
Explanation:
If the rate at which the oceanic ridge is spreading is 5 cm/yr. How much farther (in kilometers) will continents A and B be from each other in one million years? Hint: Speed = Time Dis tan ce , so Distance = Speed × Time. 1 km=1000 m,1 m=100 cm. Show your work. (2)
In one million years, continents A and B will be 50 kilometers farther apart.
The rate at which the oceanic ridge is spreading is given as 5 cm/yr. To find how much farther continents A and B will be from each other in one million years, we can use the formula Distance = Speed × Time.
First, let's convert the speed from cm/yr to km/yr. Since 1 km = 1000 m and 1 m = 100 cm, we divide the speed by 100,000 to convert cm/yr to km/yr. Therefore, the speed is 5 cm/yr ÷ 100,000 = 0.00005 km/yr.
Next, we multiply the speed by the time (1 million years) to find the distance. Distance = 0.00005 km/yr × 1,000,000 years = 50 km.
Therefore, in one million years, continents A and B will be 50 kilometers farther from each other.
To summarize:
- Convert cm/yr to km/yr by dividing by 100,000.
- Multiply the speed in km/yr by the time (1 million years) to find the distance.
- The continents will be 50 kilometers farther from each other.
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A trapezoid is a 4-sided polygon which has 2
parallel sides.
Write an expression that represents the
perimeter of a trapezoid whose sides have
length a, b, c and d.
Use this expression to find the perimeter of
the trapezoid when a= 12. b
16. c = 16.
and d = 20.
Calculate the initial oil-in-place (N) of a volumetric oil reservoir if:
A=1,600 acres, h=32 ft, Ø = 22%, Si = 20%, B= 1.23 bbISTB
Calculate the initial gas-in-place of a volumetric gas reservoir if:
A=1,320 acres, h=45 ft, Ø = 17.5%, Sw = 23%, By = 0.004276 cuft/SCF
The initial oil-in-place (N) of a volumetric oil reservoir is a critical parameter used to estimate the total amount of oil that can be recovered from the reservoir. It represents the total volume of oil contained within the reservoir at the beginning of its production life.
The initial gas-in-place (G) of a volumetric gas reservoir is a critical parameter used to estimate the total amount of gas that can be recovered from the reservoir. It represents the total volume of gas contained within the reservoir at the beginning of its production life.To calculate the initial oil-in-place and gas-in-place, we need to use certain parameters such as the area of the reservoir, the thickness of the reservoir, the porosity of the reservoir, the initial oil or water saturation, and the formation volume factor. The formulas used to calculate the initial oil-in-place and gas-in-place are different, and the parameters used in each formula are specific to either an oil or gas reservoir.
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1. Which object is farthest from the origin at t=2sec
A.a B. b
C. they are the same location at t=2sec
D. they are the same distance from the origin , but in opposite direction
2. Which object moves with constant non-zero acceleration
A. A C. both a and b
B. B. D. neither A and B
3. Which object is in its initial position at t=2sec?
A. A C. both a and b
B. B D. neither A and B
Help me ppppppppp
Answer:
that one i know only pe not that sorry again
The following problem presents hypothetical values. In the diagram below, the synodic period (one lunar month) is given as 30 days. The measured time from 3rd to 1st Quarter is 14.9 days. Use the given values to find x. Show your work in the space below.
Answer:
x is approximately 95.495
Explanation:
The given information are;
One lunar month = 30 days
The measured time between the first and third quarters = 14.9 days
Therefore, the angle of rotation for 30 days = 360°
The angle of rotation for 14.9 days = 14.9×360/30 = 178.8°
Therefore, whereby 2·θ = 178.8°
θ = 178.8°/2 = 89.4°
Therefore, given that the angle at the tangent from Sun to the Moon = 90°, we have;
The angle between the line from the Sun to the Moon = 90° - 89.4° = 0.6°
From sine rule, we have;
1/(sin 0.6) = x/(sin 90°)
x = (sin 90°)/(sin 0.6°) ≈ 95.495
x = 95.495.
Consider the electronic transition from n = 7 to n = 4 in the hydrogen atom. is light absorbed or emitted? calculate the energy, the frequency and wavelength (nm) of the photon involved.
Energy for this electronic transition is ΔE=0.572eV frequency is ν=1.38×\(10^{14}\) \(s^{-1}\) and wavelength is 2.17×\(10^{-6}\) m
The Bohr Model for the energy of an electron in a hydrogen atom gives us:
E=−\(\frac{13.6}{n^{2} }\) eV
Where n is the principle quantum no
For the transition 7→4 the difference in energy is given by:
ΔE= -\(\frac{13.6}{49}\)+\(\frac{13.6}{16}\) eV
ΔE=0.85-0.277
ΔE=0.572eV
To convert this to Joules we multiply by the electronic charge:
ΔE=0.572×1.6×\(10^{-19}\)=9.16×\(10^{-20}\)J
(b)
To find the frequency of the emitted photon we use the Planck expression:
ΔE=hν
∴ν=ΔE/h=(9.16×\(10^{-20}\))÷(6.626×\(10^{-34}\))\(s^{-1}\)
ν=1.38×\(10^{14}\) \(s^{-1}\)
To find the wavelength
λ=c/ν
(3×\(10^{8}\))/(1.38×\(10^{14}\)) m
=2.17×\(10^{-6}\) m
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which correctly describes how the energy of a wave on the electromagnetic spectrum depends on wavelength and frequency?
Answer:
The answer to this question is given below in this explanation section.
Explanation:
"electromagnetic spectrum depends on wavelength and frequency"
When electromagnetic radiation interacts with single atoms and molecule,its behavior also depends on the amount of energy per quantum(photon)it carries wave number =1/wavelength in cm speed of light=wavelength x frequency energy = Planck's constant x frequency.
Electromagnetic radiation interacts with matter in different parts of the spectrum.
Electromagnetic radiation interacts with matter in different ways in different parts of the spectrum.The types of interaction can be so different that it seems justified to refer to different types of radiation.There is a continuum containing all these different kind of electromagnetic radiation.Thus we refer to spectrum but divide it up based on the different interaction with matter.
Answer:
Energy increases with decreasing wavelength and increasing frequency.
Explanation:
True or false? A well-oiled machine has no friction. Explain your answer.
Answer:
False
Explanation:
A well-oiled machine has oil because there is friction. The oil lessens the friction and also allows the machine to operate and function without wear parts heating up. Oil is a cooling lubricant that decreases friction but does not eliminate it.
Any object free to rotate about a pivot will come to rest with ____________________________.
Any object free to rotate about a pivot will come to rest with its center of mass directly below the pivot, provided there are no external torques acting on it. This is known as the principle of rotational equilibrium. The center of mass is the point at which the object can be balanced on a single point, and if it is directly below the pivot, the object will not rotate further. This principle is commonly used in the design and analysis of objects that pivot, such as seesaws, balance scales, and doors.
Rotational equilibrium means that the object's net torque is zero. This occurs when the sum of the torques acting on the object is balanced and there is no rotational acceleration. In other words, the object is in a balanced state where there is no tendency for it to rotate further.
For an object to come to rest in rotational equilibrium, the torques acting on the object must balance each other out. This can occur when the object's weight or gravitational force acts at the center of mass, or when external forces or torques are applied in a way that cancels out the existing torques.
In summary, when an object free to rotate about a pivot comes to rest, it will come to rest in a state of rotational equilibrium where the net torque acting on the object is zero.
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what is the weight of a 45kg box
____ N
The weight of a \(45 kg\) box is \(441.45 N\).
Weight refers to the measure of the force exerted on an object due to the gravitational pull of the Earth.
Given the mass of the box is \(m=45 kg\).
The weight of an object (\(W\)) can be found by multiplying the mass of the object (\(m\)) by the acceleration due to gravity (\(g\)).
So, \(W=mg\).
It is known that acceleration due to gravity, \(g=9.81 m/s^2\).
Hence, the weight of the box, \(W=(45kg)\times (9.81 m/s^2)\).
\(\Rightarrow W=441.45 (kg\cdot m/s^2)\\\Rightarrow W=441.45 N\)
Therefore, the weight of the box is \(441.45 N\).
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Ball a with diameter d and ball b with diameter 2d are dropped from the same height. When the two balls have the same speed, what is the ratio of the drag force on ball a to the drag force on ball b?.
Ball A with diameter d and ball B with diameter 2d are dropped from the same height. When the two balls have the same speed, the ratio of the drag force on ball A to the drag force on ball B will be F1 : F2 = 1 : 4
what is diameter?
a section of a straight line with all of its ends on the perimeter of a circle; a straight line cutting through the middle of either a figure or body. 2: the diameter's length. size, a noun.
What is an example of diameter?If you look at the cycle wheel, the spikes that run through the center from one end to the other are an illustration of width. This is comparable to a circle's diameter, which is a line segment that extends from one end of the circle to the other end while passing through center.
formula to calculate drag force is = F(d) = 1/2 * C * rho*A *v²
C = drag coefficient
A = area of object
rho = density in which object is moving
v = velocity of object
A = area of the object
F1 ( drag force on ball A ) = 1/2 * C * rho * area of ball A * v²
F2 (drag force on ball A ) = 1/2 * C * rho * area of ball B *v²
since , both the balls have same speed and falling in same environment hence , density and speeds are the same , the only difference is in area of both the balls
F1/F2 = area of ball A / area of ball B = 4 * pi *r1² / 4 * pi *r2²
= r1² / r2²
= (d/2)²/(2d/2)²
= 1/4
F1 : F2 = 1 : 4
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An air conditioner operating at steady state maintains a dwelling at 70oF on a day when the outside temperature is 90oF. If the rate of heat transfer into the dwelling through the walls and roof is 30,000 Btu/h, might a net power input to the air conditioner compressor of 3 hp be sufficient? If yes, determine the coefficient of performance. If no, determine the minimum theoretical power input, in hp.
The power input of 3hP might be sufficient and the coefficient of performance will be "3.93".
According to the question,
In order to maintain the dwelling at 70°F with,
\(Q_{in} = 30000 \ Btu/h\)The COP,
→ \(\beta \leq \ \beta_{max}\)
or,
→ \(\beta \leq \frac{T_c}{T_H-T_c}= \frac{530^{\circ} R}{(550-530)^{\circ}R}\)
\(= 26.5\)
or,
→ \(\frac{Q_{in}}{W_c} \leq 26.5\)
→ \(W_c \geq \frac{3000 \ Btu/h}{26.5}\times \frac{1 \ hP}{2545 \ Btu/h}\)
→ \(W_c \geq 0.445 \ hP\) (minimum required power)
hence,
The corresponding COP will be:
→ \(\beta = \frac{Q_c}{W}\)
\(= \frac{30000}{3\times 2545}\)
\(= 3.93\)
Thus the response above is correct.
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PLEASE HELP - In running a ballistics test at the police department, Officer Rios fires a 6.1g bullet at 350 m/s into a container that stops it in 0.32 min. What average force stops the bullet?
Answer:
–0.11 N.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 6.1 g
Initial velocity (u) = 350 m/s
Time (t) = 0.32 mins
Final velocity (v) = 0 m/s
Force (F) =?
Next, we shall convert 0.32 mins to seconds. This can be obtained as follow:
1 min = 60 s
Therefore,
0.32 mins = 0.32 × 60 = 19.2 s
Next, we shall determine the acceleration of the the bullet. This can be obtained as follow:
Initial velocity (u) = 350 m/s
Time (t) = 19.2 s
Final velocity (v) = 0 m/s
v = u + at
0 = 350 + (a × 19.2)
0 = 350 + 19.2a
Collect like terms
0 – 350 = 19.2a
–350 = 19.2a
Divide both side by 19.2
a = –350 / 19.2
a = –18.23 m/s²
Next, we shall convert 6.1 g to Kg.
1000 g = 1 Kg
Therefore,
6.1 g = 6.1 g × 1 Kg / 1000 g
6.1 g = 0.0061 Kg
Finally, we shall determine the force. This can be obtained as follow:
Mass (m) = 0.0061 Kg
Acceleration (a) = –18.23 m/s²
Force (F) =?
F = ma
F = 0.0061 × –18.23
F = –0.11 N
NOTE: The negative sign indicates that the force is in opposite direction.
Answer:
–0.11 N.
Explanation:
Hope this helps
A circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magnetic field. A field of 1.4 T is directed along the positive z-direction, which is upward. You may want to review (Pages 957-964) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Emf and current induced in a loop Part A If the loop is removed from the field region in a time interval of 2.7 ms ,find the average emf that will be induced in the wire loop during the extraction process. Express your answer using two significant figures. ANSWER:
The average emf induced in the wire loop during the extraction process is 3.8 V.
The average emf induced in the wire loop during the extraction process can be found using Faraday's law of electromagnetic induction. The change in magnetic flux through the loop as it is removed from the field region is given by ΔΦ = BA, where B is the magnetic field and A is the area of the loop.
In this case, ΔΦ = Bπr², where r is the radius of the loop. The time interval for extraction is given as 2.7 ms. Therefore, the average emf induced is given by ε = ΔΦ/Δt = Bπr²/Δt. Substituting the given values, we get ε = (1.4 T)(π)(0.15 m)²/(2.7×10⁻³ s) ≈ 3.8 V.
Hence, the average emf induced in the wire loop during the extraction process is 3.8 V (two significant figures).
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An object traveling at a constant velocity of 15 m/s is experiencing no net
force.
True or
False
A boat moves 3.0 km due north and then moves 1.0 km due south. The time for this trip is half an hour. What is the average velocity of the boat
The average velocity of the boat given the data from the question is 6.32 Km/h
What is velocity?Velocity is defined as the rate of change of displacement with time. Mathematically, it is expressed as
Velocity = displacement / time
How to determine the resultant displacementDisplacement 1 (d₁) = 3 KmDisplacement 2 (d₂) = 1 KmResultant displacement (D) =?
D² = d₁² + d₂²
D² = 3² + 1²
D² = 9 + 1
D² = 10
Take the square root of both sides
D = √10
D = 3.16 Km
How to determine the average velocityResultant displacement = 3.16 KmTime = 1/2 hour = 0.5 hourAverage velocity =?
Average velocity = resultant displacement / time
Average velocity = 3.16 / 0.5
Average velocity = 6.32 Km/h
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What did you include in your response? check all that apply. the law of conservation of momentum is satisfied. the momentum before the collision is 1.5 kg • . the momentum after the collision is 1.5 kg • . the momentum is the same after the collision as it was before the collision.
After a collision, there is no change in the momentum from the initial situation. This statement satisfies the law of conservation of momentum. Hence, Option D is correct.
What is the law of conservation of Momentum?Momentum is the sum of an object's mass and velocity, and it is a property of all moving objects. This can be expressed mathematically as p=MV, where p stands for momentum. The momentum of an object can fluctuate because its velocity can. When describing the momentum of a system of objects, the Law of Conservation of Momentum is helpful. The Law of Conservation of Momentum, in its most basic form, states that the total momentum of an isolated system stays constant.
Hence, the momentum will be the same after the collision as it was before the collision.
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3. A force of 70N is applied to a 10kg box with a friction force of 30N opposing it's motion. The box starts
from rest and reaches a speed of 5m/s. Determine the distance over which the force acts on the box.
The distance over which the force acts on the box, given that 70 N is applied to the 10 Kg box is 3.125 m
How do I determine the distance ?We'll begin by obtaining the acceleration of the box. Details below:
Force applied = 70 NForce of friction = 30 NNet force = Force applied - Force of friction = 70 - 30 = 40 N Mass of box = 10 KgAcceleration (a) =?Net force = mass × acceleration
40 = 10 × acceleration
Divide both sides by 10
Acceleration = 40 / 10
Acceleration = 4 m/s²
Finally, we shall determine the distance. Details below
Initial velocity (u) = 0 m/sFinal velocity (v) = 5 m/s Acceleration(a) = 4 m/s²Distance (s) =?v² = u² + 2as
5² = 0² + (2 × 4 × s)
25 = 0 + 8s
25 = 8s
Divide both side by 8
s = 25 / 8
s = 3.125 m
Thus, we can conclude that the distance covered is 3.125 m
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Please select the word from the list that best fits the definition
Choose the correct process for the description given:
oxygen is given off as a by-product
1) Cellular Respiration
2) Photosynthesis
Answer:
cellular respiration , note how it says oxygen
What happens when similar systems work together?
Answer: skeletal system and nervous systems
Explanation:
Many different body systems work together to perform daily functions in life. The skeletal system and nervous systems work together to produce movement and keep your organs functioning.
What is the elastic potential energy of a rubber band with a spring constant of 25.0 N/m if it is stretched by 10.0 cm from its original length?
Answer: 1,250 joules
Explanation: elastic potential energy is half of the spring constant multipied by extention squared so its 12.5 multiplied by 100 which is 1,250
A broom with a long handle balances at its centre of gravity as shown in the figure. If you cut the broom into two parts through the centre of gravity and then weigh each part, which part will weigh more? a) The part with the broom will weigh more. b) The part without the broom will weigh more c) Both the parts will weigh the same d) It would depend on the weight of the broom
Answer:
c) Both the parts will weigh the same
Explanation:
center of gravity is based on weight so if you cut down the center of gravity you would have 2 equal parts
(might be D if it is cutting against the center of gravity)
Which image shows a situation where conduction occurs?
A box full of pieces of metal.
A woman holds a steaming mug.
A woman holds a frying pan above a stove while stirring.
Answer: A woman holds a steaming mug
Explanation:
Just did it
an ideal spring hangs vertically. when a 475-g object is hung from the bottom end, and lowered gently, the spring stretches 5.11 cm.
when the 475-g object is hung from the bottom end of the ideal spring hanging vertically, the spring stretches by 5.11 cm.
The displacement of the spring when an object is hung from it can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement.Hooke's Law can be expressed as F = kx, where F is the force applied to the spring, k is the spring constant, and x is the displacement.In this case, the object has a mass of 475 g, which can be converted to kilograms by dividing by 1000 (475 g = 0.475 kg).
The weight of the object, which is the force applied to the spring, is given by W = mg, where m is the mass and g is the acceleration due to gravity. Plugging in the values, we have W = 0.475 kg * 9.8 m/s² = 4.655 N.Since the object is hung vertically, the force applied to the spring is equal to the weight of the object, so F = 4.655 N.To find the spring constant k, we divide the force by the displacement: k = F / x = 4.655 N / 0.0511 m = 90.93 N/m.
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