(a) The kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.
(b) The work done in firing the projectile is 2,500 J.
Kinetic energy of the projectile at maximum height
The kinetic energy of the projectile when it reaches the highest point in its trajectory is calculated as follows;
K.E = ¹/₂mv₀ₓ²
where;
m is mass of the projectilev₀ₓ is the initial horizontal component of the velocity at maximum heightNote: At maximum height the final vertical velocity is zero and the final horizontal velocity is equal to the initial horizontal velocity.
K.E = (0.5)(2)(30²)
K.E = 900 J
Work done in firing the projectileBased on the principle of conservation of energy, the work done in firing the projectile is equal to the initial kinetic energy of the projectile.
W = K.E(i) = ¹/₂mv²
where;
v is the resultant velocityv = √(30² + 40²)
v = 50 m/s
W = (0.5)(2)(50²)
W = 2,500 J
Thus, the kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.
The work done in firing the projectile is 2,500 J.
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State the hamilton's equation of
motion and derive each of them
Hamilton's equations of motion are a set of equations that describe the dynamics of a classical mechanical system in terms of a generalized coordinate and its conjugate momentum.
How to explain the equationThe equations are derived from the Hamiltonian formalism. Hamilton's equations can be derived from the Hamilton's principle, which is a variational principle that states that the action of a dynamical system is stationary.
To derive these equations, we start with the Hamiltonian function H(p, q) and use the principle of least action. The action S is defined as the integral of the Lagrangian L(q, q', t) over time:
S = ∫[L(q, q', t)] dt
To find dp/dt, we differentiate the Lagrangian with respect to q:
∂L/∂q = ∂(p * q' - H)/∂q
= -∂H/∂q
Using the chain rule, we find:
dL/dt = (∂L/∂q) * dq/dt + (∂L/∂q') * dq'/dt
= -∂H/∂q * dq/dt + p * d(q')/dt
= -∂H/∂q * dq/dt + p * d^2q/dt^2
= -∂H/∂q * dq/dt + dp/dt
Since the Lagrangian is equal to p * dq' - H, we can write:
dL/dt = -∂H/∂q * dq/dt + dp/dt
From the principle of least action, we know that the action S is stationary, so dL/dt = 0. Thus, we have:
-∂H/∂q * dq/dt + dp/dt = 0
Rearranging the equation, we obtain the first equation of motion:
dp/dt = -∂H/∂q
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Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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WILL GIVE BRAINLIEST
Answer:
2.5N
Explanation:
Given :
Mass = 0.5kg
Acceleration = 5 m/s²
For the glass to accelerate, a force, F = ma must act on it in the right direction :
F = ma
F = 0.5kg * 5m/s
F = 2.5 kgm/s
F = 2.5 N
The net force required such that the glass accelerates 5m/s² to the right is 2.5N
A 64-kg skater initially at rest throws a 4.0-kg medicine ball horizontally to the left. Suppose the ball is accelerated through a distance of 1.0 mm before leaving the skater's hand at a speed of 7.0 m/s. Assume the skater and the ball to be point-like and the surface to be frictionless and ignore air resistance. Use a vertical y-axis with the positive direction pointing up and a horizontal x-axis with the positive direction pointing to the right.
Required:
a. Determine the acceleration of the ball during the throw.
b. Determine the acceleration of the skater during the throw.
Answer:
yeah
Explanation:
Solved: Problem 2.41 A 64-kg Skater Initially At Rest Thro ...www.chegg.com › ... › physics questions and answers
Suppose The Ball Is Accelerated Through A Distance Of 1.0 M Before Leaving The Skater's Hand At A Speed Of 7.0 M/s . Assume The Skater And The Ball To Be Point-like, The Surface To Be Frictionless, And Ignore Air Resistance. Use A ... A 64-kg skater initially at rest throws a 5.0-kg medicine ball horizontally to the left
1. Calculate the increase in length of an iron wire that is 30m long at 20°c when it is warmed to 45°c (take airon 1.1x10³J/k)
2. If 2200 Joule of heat is added to a 190 g object its temperature increases by 12°c.W hat is
a. specific heat capacity
b. heat capacity of the object
The increase in length of the iron wire when warmed from 20°C to 45°C is approximately 8.25 millimeters. The specific heat capacity of the object is approximately 9.62 J/kg°C. The heat capacity of the object is approximately 1.83 J/°C.
ΔL = L × α × ΔT
Where:
ΔL is the change in length
L is the original length of the wire
α is the coefficient of linear expansion for iron
ΔT is the change in temperature
The coefficient of linear expansion for iron is typically 1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\).
Given:
L = 30 m (original length of the wire)
α = 1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\) (coefficient of linear expansion)
ΔT = 45°C - 20°C = 25°C (change in temperature)
ΔL = 30 m × (1.1 x \(10^(^-^5^)\) °\(C^(^-^1^)\)) × 25°C
= 30 m × 1.1 x\(10^(^-^5^)\) × 25
= 8.25 x \(10^(^-^3^)\) m
2) Q = mcΔT
Where:
Q is the heat energy transferred
m is the mass of the object
c is the specific heat capacity
ΔT is the change in temperature
Given:
Q = 2200 J (heat energy transferred)
m = 190 g (mass of the object)
ΔT = 12°C (change in temperature)
a. Specific heat capacity (c):
one need to rearrange the formula to solve for c:
c = Q / (m × ΔT)
Substituting the given values:
c = 2200 J / (190 g × 12°C)
First, need to convert the mass to kilograms:
m = 190 g = 190 g / 1000 = 0.19 kg
Now can calculate the specific heat capacity:
c = 2200 J / (0.19 kg × 12°C)
= 9.62 J/(kg°C)
b. Heat capacity (C):
The heat capacity is the amount of heat energy required to raise the temperature of the object by 1 degree Celsius.
C = mc
Substituting the given values:
C = 0.19 kg × 9.62 J/(kg°C)
= 1.83 J/°C
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4. What is stellar parallax?
Answer:
I don't k own what it is dad fjf f fjff
Answer:
Explanation:
Stellar parallax is the apparent shift of position of any nearby star against the background of distant objects
Answer this question. URGENT!!
Answer:
D)80/10 × 5 × 10^-4 N m^-2
Explanation:
this is the answer that was on my assignment
A ball has a mass of 140 g what is the force needed to accelerate the mall at 25 m/s squared
Answer:
\(\boxed {\boxed {\sf 3.5 \ Newtons}}\)
Explanation:
Force is the product of mass (in kilograms) and acceleration (in meters per square second).
\(F=ma\)
The mass of the ball is 140 grams and the acceleration is 25 m/s². Convert grams to kilograms.
1 kg=1000 g\(140 \ g *\frac{1 \ kg}{1000 \ g}=\frac{140}{1000} \ kg =0.14 \ kg\)Substitute the values into the formula.
\(F= 0.14 \ kg * 25 \ m/s^2\)
Multiply.
\(F= 3.5 \ kg*m/s^2\)
1 kilogram meter per square second is equal to 1 NewtonOur answer equals 3.5 Newtons\(F= 3.5 \ N\)
3.5 Newtons of force are required.
The two masses (mA
= 6.50 kg is hanging and mB
= 3.30 kg is on the floor) in the Atwood's machine shown in the figure below are released from rest, with mA
at a height of 0.865 m above the floor. When mA
hits the ground its speed is 1.89 m/s. The pulley is not massless and can be considered a solid disk with a moment of inertia of (1/2)mpr2
.
What is the total mechanical energy of the two blocks prior to being released from rest?
(Figure 1)
What is the total mechanical energy of the two blocks when mA
hits the ground?
Part C
What is the rotational kinetic energy of the pulley just before mA
hits the ground?
Part D
What is the mass of the pulley?
A)The total mechanical energy of the two blocks prior to being released from rest can be found by adding the gravitational potential energy of mA and the pulley to zero.
B).The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J,where mp is the mass of the pulley.The total mechanical energy of the two blocks prior to being released from rest is54.33 J + 0 J = 54.33 J
C) The rotational kinetic energy of the pulley just before mA hits the ground is(0.178 mp) J.
D) The mass of the pulley ismp = (1/2)mpr²/R² =(1/2)(0.020 kg)(0.100 m)²/(0.200 m)² = 0.001 kg = 1 g.r = (1/2)R.
The Atwood's machine shown in Figure 1 consists of two masses mA = 6.50 kg and mB = 3.30 kg. The height of mA above the floor is 0.865 m. When mA hits the floor, its velocity is 1.89 m/s. The pulley has a moment of inertia (1/2)mpr². We have to find the total mechanical energy of the two blocks before they are released, the total mechanical energy when mA hits the ground, the rotational kinetic energy of the pulley just before mA hits the ground, and the mass of the pulley. Let's solve these one by one. Part A The total mechanical energy of the two blocks prior to being released from rest can be found by adding the gravitational potential energy of mA and the pulley to zero.
The equation for gravitational potential energy is mgh. The gravitational potential energy of mA and mB is mAg(h-hB)where h is the height of mA above the floor and hB is the height of mB above the floor. Since the pulley is at the same height as mB, its gravitational potential energy ismBg(h-hB).The gravitational potential energy of mA is6.50 kg × 9.81 m/s² × 0.865 m = 54.33 J.The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J,where mp is the mass of the pulley.The total mechanical energy of the two blocks prior to being released from rest is54.33 J + 0 J = 54.33 J.Part BThe total mechanical energy of the two blocks when mA hits the ground can be found by adding the kinetic energy of mA, the kinetic energy of mB, and the rotational kinetic energy of the pulley to the gravitational potential energy of mB and the pulley. The equation for kinetic energy is (1/2)mv². The kinetic energy of mA is(1/2) × 6.50 kg × (1.89 m/s)² = 11.54 J.The kinetic energy of mB is(1/2) × 3.30 kg × 0 m/s² = 0 J, since it is at rest.The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J.The rotational kinetic energy of the pulley is(1/2) × (1/2)mp × R² × ω²,where R is the radius of the pulley and ω is its angular velocity just before mA hits the ground. We can use the fact that the linear speed of the rope is the same on both sides of the pulley to find ω. The equation for linear speed is v = Rω. When mA hits the ground, its speed is 1.89 m/s. The speed of mB is zero. Since the rope is inextensible, the speed of the rope is also 1.89 m/s.
Therefore, the speed of the pulley is also 1.89 m/s. We can find the angular velocity of the pulley by dividing the linear velocity by the radius.ω = v/R = 1.89 m/s ÷ (0.200 m/2) = 18.9 rad/s.The rotational kinetic energy of the pulley is(1/2) × (1/2)mp × R² × ω² =(1/4)mpR²ω² =(1/4)mp(0.200 m)²(18.9 rad/s)² =(0.178 mp) J.The total mechanical energy of the two blocks when mA hits the ground is11.54 J + 0 J + 0 J + (0.178 mp) J = 11.72 J + (0.178 mp) J.Part CThe rotational kinetic energy of the pulley just before mA hits the ground is(0.178 mp) J.Part DWe can find the mass of the pulley by using the moment of inertia of a disk and the mass of the pulley. The moment of inertia of a disk is (1/2)mr². Therefore,(1/2)mpR² = (1/2)mpr²,where R is the radius of the pulley and r is the radius of gyration of the pulley. The radius of gyration of a disk is (1/2)R.
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The spacecraft was moved closer to the launcher by the same amount Wednesday as it was on Tuesday, and yet its speed went up much more. Claim 3 suggests that the magnetic force was much stronger on Wednesday than on Tuesday.
Consider the two subclaims for Claim 3 and answer the question below.
Claim 3.A: The magnetic force was much stronger on Wednesday because the magnet was stronger.
Claim 3.B: The magnetic force was much stronger on Wednesday because the magnetic force is stronger closer to the magnets.
Which claim do you think is more convincing, and why?
Answer:
The magnetic force was much stronger on Wednesday because the magnetic force is stronger closer to the magnets.
Explanation:
The magnetic force was much stronger on Wednesday than on Tuesday because the magnetic force is stronger closer to the magnets. Therefore claim 3B is more convincing.
What is magnetic force?Magnetic force can be described as a consequence of electromagnetic force which is caused due to the motion of charges. A moving charge surrounds itself with a magnetic field and the force that arises due to interacting magnetic fields.
The magnetic force between two moving charges is the effect exerted upon either charge by a magnetic field generated by the other. The magnetic force depends on the charge, the motion of each of the objects, and the separation between them.
The magnitude of the force is determined by the cross product of velocity and the magnetic field is equal to q.[v × B]. The resultant force can be described as perpendicular to the direction of the velocity and the magnetic field.
Therefore, the magnetic force was much stronger closer to the magnets.
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what is kinematics ;-;
explain.
Answer:
the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.
Explanation:
explain how wind erosion changes land forms
Answer:
the wind carries abrasive materials
Explanation:
such as sand and salt over time theses small particles slowly strip way at the land form sculpting it by eroding the softer layers first
Protons have
_electric charge. Electrons have
_electric charge. Neutrons have
electric charge. Most atoms are electrically
because the number of protons
equals the number of electrons. Atoms with an electric charge become charged by gaining or losing
When this charge becomes built up on an object, we call that build up
Answer:
Protons have positive charge
Electrons have negative charge
Neutrons have no charge
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Calculate the linear acceleration (in m/s2) of a car, the 0.340 m radius tires of which have an angular acceleration of 15.0 rad/s2. Assume no slippage.
Answer:
Linear acceleration = \(5.1\ m/s^2\)
Explanation:
Given that,
Radius, r = 0.340 m
Angular acceleration of the tire, \(\alpha =15\ rad/s^2\)
We need to find the linear acceleration of the car.
We know that the relation between the linear and angular acceleration is given by :
\(a=\alpha r\)
a is linear acceleration.
Now putting all the values, we get :
\(a=15\times 0.34\\\\a=5.1\ m/s^2\)
So, the linear acceleration of the car is \(5.1\ m/s^2\).
Three different scientific institutions provide data about how much the annual global temperature has deviated from the norm in the years 1880 to 2014. The nort is
based on the temperatures of a base period, from 1951 to 1980
Institution A's data show that the annual global temperature deviated from the norm by 0.75°C in 2010
Institution B's data show that the annual global temperature deviated from the norm by 0.72°C in 2010
Institution C's data show that the annual global temperature deviated from the norm by 0.77°C in 2010.
Which are accurate statements about this data? Select the two correct answers
(1 point)
Based on the findings above, the accurate statements are:
B. The institutions have not yet gathered enough data for scientists to draw a conclusion about whether the annual global temperature is gradually increasing.C. The data gathered by each institution is very similar to the data gathered by the other institutions.What are the accurate statements?The information that all three institutions gathered is quite similar with their results showing a range of annual temperature deviation of 0.05°C in 2010.
However, this data is not enough to say that temperatures are rising gradually because there is no information on temperatures from the previous years.
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1. What does the term monecious mean?
Answer:
Monecious is a plant or invertebrate animal having both the male and female reproductive organs in the same individual; hermaphrodite.
A 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 7.0 N for a distance of 2.0 m. How much farther would the force have to act for the block to have 57 J of kinetic energy?
The distance the block will move to have a kinetic energy of 57 J is 8.14 meters.
What is work?The work is defined as the amount of energy. The work in physics is the product of the force and the displacement.
Given that a 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 7.0 N for a distance of 2.0 m. The total kinetic energy possessed by the block is 57 J.
The distance will be calculated as:-
W = F x D
W = 7 x 2
W = 14 J
The distance is,
W₁ / W₁ = D₂ / D₁
14 / 57 = 2 / D₂
D₂ = ( 57 x 2 ) / 14
D₂ = 8.14 meters
Therefore, the distance the block will move to have a kinetic energy of 57 J is 8.14 meters.
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Why is water often called the "universal solvent"? A. A large amount of energy is needed to raise its temperature. B. It remains a liquid over a wide range of temperatures. C. Many different substances can dissolve in it. D. Strong forces of cohesion allow it to form drops.
Answer:
C
Explanation:
The image shows a diagram explaining a concept.
Which concept does the diagram show?
A. tempature
B. Altitude
C. air density
D. air pressure
Answer:
D.
Explanation
Air pressure.
Answer:air pressure
Explanation:
An ultraviolet wave traveling through a vacuum has wavelength of 4.0 x 10^-7 m. The waves frequency, written in scientific notation to two significant figures, is ? X10^14Hz.
Answer:
λ = c / f or f = c / λ
f = 3.0E8 / 4.0E-7 = .75E15 / sec = 7.5E14 / sec = 7.5 X 10^14 /sec
In a shipping yard, a crane operator attaches a cable to a 1,390 kg shipping container and then uses the crane to lift the container vertically at a constant velocity for a distance of 33 m. Determine the amount of work done (in J) by each of the following.
a) the tension in the cable.
b) the force of gravity.
Answer:
a) A = 449526 J, b) 449526 J
Explanation:
In this exercise they do not ask for the work of different elements.
Note that as the box rises at constant speed, the sum of forces is chorus, therefore
T-W = 0
T = W
T = m g
T = 1,390 9.8
T = 13622 N
Now that we have the strength we can use the definition of work
W = F .d
W = f d cos tea
a) In this case the tension is vertical and the movement is vertical, so the tension and displacement are parallel
A = A x
A = 13622 33
A = 449526 J
b) The work of the force of gravity, as the force acts in the opposite direction, the angle tea = 180
W = T x cos 180
W = - 13622 33
W = - 449526 J
Eugene recorded the sound waves made by his drum on an oscilloscope. He found that if he hit his drum harder, the amplitude of the waves got larger. How did
the sound from his drum change?
O A. The sound became louder in volume.
OB. The sound became softer in volume.
C. The sound became higher in pitch.
D. The sound became lower in pitch.
?
The amplitude of a sound wave refers to the maximum displacement of the particles of the medium through which the sound wave is traveling. In other words, the larger the amplitude, the louder the sound.
Therefore, if Eugene hit his drum harder and the amplitude of the sound waves got larger, the sound would have become louder in volume.
It's important to note that the pitch of a sound is related to the frequency of the sound wave, which is not affected by changes in amplitude.
Therefore, hitting the drum harder would not have changed the pitch of the sound produced.
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What is revolution?
A. The motion of an object along a curved path
B. The spinning of an object on its axis
C. The orbit of a satellite around a central body
D. The motion of two objects around each other
Answer:
A. the motion of an object along a curved path
Two masses are suspended by cord that passes over a pulley with negligible mass. The cord also has negligible mass. One of the masses, m1, has a mass of 7.0 kg and the other mass, m2, has a mass of 3.0 kg. The pulley turns on a shaft through the center of the pulley and supports the pulley and all the masses. The vertical force of the shaft on the pulley that supports the whole system is
Answer: F = 98N
Explanation: The shaft have to sustain the pulley, the cord and the two masses. The pulley and the cord have negligible masses, so, they have negligible weight.
The two masses have two vertical forces acting on them: force of traction because of the cord and force due to gravitational force, also known as weight.
So, the vertical force the shaft has to support is the sum of the weight of each mass:
\(F_{net}=F_{g}_{1}+F_{g}_{2}\)
\(F_{net}=m_{1}.g+m_{2}.g\)
\(F_{net}=g(m_{1}+m_{2})\)
\(F_{net}=9.8(7+3)\)
\(F_{net}=\) 98
The vertical force that supports the whole system is 98 N.
A 5 kW, 230 V motor draws a current of 24 A from the supply. Determine the efficiency of this motor.
The efficiency of motor is 90.58%.To determine the efficiency of the motor, we need to calculate the input power and the output power, and then divide the output power by the input power
The input power can be calculated using the formula:
Input Power = Voltage × Current
Given that the voltage is 230 V and the current is 24 A, we have:
Input Power = 230 V × 24 A
Input Power = 5520 W (or 5.52 kW)
The output power of the motor is given as 5 kW (since it is a 5 kW motor).
Now, we can calculate the efficiency:
Efficiency = (Output Power / Input Power) × 100%
Efficiency = (5 kW / 5.52 kW) × 100%
Efficiency ≈ 90.58%
Therefore, the efficiency of this motor is approximately 90.58%.
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Question 2 of 10
What happens to the resistance of a wire as its length increases?
A. The resistance is not affected by a change in wire length.
B. The resistance decreases.
C. The resistance alternates between high and low values.
D. The resistance increases.
Answer:
D. resistance increases
Explanation:
The relationship between resistance and wire length is directly proportional, meaning the longer the wire the greater the resistance.
Answer: The resistance increases.
Explanation: A wire's resistance is directly proportional to its length. This implies that as a wire's length increases, so does its resistance. The following formula describes this relationship:
R = ρ (L/A)
where L is the wire's length, A is its cross-sectional area, R is the wire's resistance, and ρ is the wire material's resistivity.
This formula shows that the resistance will rise when the wire's length is extended while its cross-sectional area remains the same. On the other hand, if we shorten the wire, the resistance will rise. As a result, choice D is the right response.
two pictures show friends playing with a string telephone. in which picture can they hear each other
Answer:
In picture one because string telephones are best heard when there is more tension on the string
Explanation:
Which of the following is a hypothesis?
A. The thickness of transparent glass affects how much light passes through.
B. Light may pass through a transparent sheet of glass.
C. A transparent sheet of glass has some effect on light.
D. Light will travel slowly through glass.
The hypothesis is, the thickness of transparent glass affects how much light passes through. Option A is correct.
A hypothesis is a proposed explanation or prediction for a phenomenon or observation that is based on limited evidence and subject to testing and validation through further investigation. It is an essential part of the scientific method, which involves developing a research question, making observations, and forming a hypothesis to explain the observed phenomenon.
The hypothesis should be testable, falsifiable, and based on evidence and reasoning. Testing the hypothesis involves designing experiments and collecting data, which can either support or refute the hypothesis. If the hypothesis is supported by the data, it may be further developed into a scientific theory, which is a widely accepted explanation of a natural phenomenon that has been extensively tested and validated. Option A is correct.
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When you drop a 0.37 kg apple, Earth exerts
a force on it that accelerates it at 9.8 m/s² to-
ward the earth's surface. According to New-
ton's third law, the apple must exert an equal
but opposite force on Earth.
If the mass of the earth 5.98 x 10²4 kg, what
is the magnitude of the earth's acceleration
toward the apple?
Answer in units of m/s².
The earth is accelerating toward the apple at a rate of 6.2 × 1025 m/s2.
How is this acceleration determined?The apple weighs m = 0.37 kg.
The apple's speed when it approaches the earth's surface is 9.8 meters per second.
Earth's mass, M, is 5.98 × 1024 kg.
Using Newton's Second Law of Motion, we may now:
The strength of the force exerted by Earth on the apple is,
F = ma
⇒ F = 0.37 × 9.8
⇒ F = 3.626 N
We are informed that the apple must exert an equal but opposite force on Earth in accordance with Newton's third law of motion.
Therefore, the force exerted by the apple on Earth will be of the following magnitude:
F = 3.626 N
Let "A" be the acceleration of the earth relative to the apple in m/s2.
Thus,
The following will be used to determine how quickly the earth is moving toward the apple:
F = MA
⇒ 3.626 = [5.98 × 10²⁴] × A
⇒ A = 3.626 / [5.98 × 10²⁴]
⇒ A = 0.606 × 10⁻²⁴
⇒ A = 6.06 × 10⁻²⁵ m/s²
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A cylinder of metal has the weight of 20 N hanging from a spring scale. Upon being submerged in water, the cylinder now has an apparent weight on the spring scale of 12 N. What is the buoyant force on the piece of metal?
This question involves the concepts of buoyant force and the weight of an object.
The buoyant force on the piece of metal is "8 N".
The apparent weight of the piece of metal is given by the following formula:
Apparent Weight = Actual Weight - Buoyant Force
Buoyant Force = Actual Weight - Apparent Weight
Buoyant Force = 20 N - 12 N
Buoyant Force = 8 N
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The attached picture illustrates the buoyant force.