A 19.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.8-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.22 s .

Required:
What is the average induced emf in the loop?

Answer:

yes

Explanation:

Bouncing is a way to increase impulse. Because an object that bounces changes directions the force of impulse must be absorbed then generated by the target object. (Impulse is nearly doubled.)

Answer:

the heat emitted by potatoes is much less than the heat emitted by turkey

Explanation:

The heat transfer is given by

        Q = m \(c_{e}\) ΔT

where m is the mass of the body, c_e is the specific heat and ΔT is the change in temperature of the body

in this case they ask us to appear the heat emitted by the potatoes and the turkey.

From the tables found the specious colors of both

potato     c_e = 0.82 Kcal / kg ºC

turkey      c_e = 0.72 Kcal / kg ºC

Since the two bodies have the same initial temperature and we assume that they reach the same final (ambient) temperature, the ratio of the heat emitted is

          Q₁ / Q₂ =  \(\frac{ m_1 \ c_{e1} }{m_2 \ c_{e2} }\)

where we use the rise 1 for the potatoes and the su index 2 for the turkey

the mass of the potatoes can be estimated at approximately m = 1 ka

we substitute

          Q₁ / Q₂ =  \(\frac{1 \ 0.82}{ 20 0.72}\)

           Q₁ /Q₂ = 0.0569

           Q₁ = 0.0569 Q₂

therefore the heat emitted by potatoes is much less than the heat emitted by turkey

"A Night at the Museum" is a story about a guard at the Museum of Natural History named Larry Daley who discovers that the museum exhibits come to life after hours due to a curse. Through Larry's experiences in the museum, the story illustrates a few specific progressions:First, the story highlights Larry's personal growth.

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Answer:

the conclusion is that the plant that had been given fertilizer B grew more than the plant with fertilizer A and the plant without fertilizer. so in conclusion fertilizer B is better for growing plants fastly.

the problem is that you noticed your tomatoes were not growing properly.

Hope this helps!❤

The initial temperature of the forging is approximately 1,090.42°C.

To determine the initial temperature of the forging, we can use the principle of conservation of energy. The heat lost by the forging is equal to the heat gained by the oil during the quenching process.

The heat lost by the forging can be calculated using the formula:

Q_lost = m_forging * c_forging * (T_forging_initial - T_equilibrium)

where:

- Q_lost is the heat lost by the forging

- m_forging is the mass of the forging (90.8 kg)

- c_forging is the specific heat capacity of the forging (434 J/(kg C°))

- T_forging_initial is the initial temperature of the forging (unknown)

- T_equilibrium is the final temperature of the oil and forging at thermal equilibrium (58.9°C)

The heat gained by the oil can be calculated using the formula:

Q_gained = m_oil * c_oil * (T_equilibrium - T_oil_initial)

where:

- Q_gained is the heat gained by the oil

- m_oil is the mass of the oil (689 kg)

- c_oil is the specific heat capacity of the oil (2680 J/(kg C°))

- T_oil_initial is the initial temperature of the oil (38.3°C)

Since the heat lost by the forging is equal to the heat gained by the oil, we can set up the following equation:

m_forging * c_forging * (T_forging_initial - T_equilibrium) = m_oil * c_oil * (T_equilibrium - T_oil_initial)

Plugging in the given values, we can solve for T_forging_initial:

90.8 kg * 434 J/(kg C°) * (T_forging_initial - 58.9°C) = 689 kg * 2680 J/(kg C°) * (58.9°C - 38.3°C)

Simplifying the equation:

90.8 * 434 * (T_forging_initial - 58.9) = 689 * 2680 * (58.9 - 38.3)

Solving for T_forging_initial:

T_forging_initial - 58.9 = (689 * 2680 * (58.9 - 38.3)) / (90.8 * 434)

T_forging_initial = 58.9 + (689 * 2680 * (58.9 - 38.3)) / (90.8 * 434)

Calculating the value:

T_forging_initial ≈ 1,090.42°C

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Answer:

lets go brandon!

Explanation:

Answer:

a) DOWN direction,  b)  directed INTO THE SCREEN, c)    F = 0

Explanation:

The direction of the force is

for electric force

           F = q E

where we assume a positive test charge, for which the force has the direction of the electric field.

For a magnetic field

in this case the direction of the force is given by the right hand rule.

For a positive test charge, the thumb points in the direction of velocity, the other fingers extended in the direction of the magnetic field, and the palm gives the direction of force for a positive charge.

           F = q v x B

Let us apply these considerations to our case.

a) negative charge moving to the left

in a magnetic field points away from the screen

In this case the thumb goes to the left, the fingers extended outwards and the palm points upwards, but since the charge is negative the force has a DOWN direction.

b) negative charge moves to the left

in electric field it points off the screen.

The outside is in the direction of the electric field and since the charge is negative, the force is directed INTO THE SCREEN

c) positive charge moves down

in magnetic field points up

in this case the velocity and the field have the same direction so the vector product of them is zero

       F = q v  B sin 0

       F = 0

Answer:

42.36 m/ s^2

Explanation:

First implement the formula f=m*a. f=33Nmass=0.78kg.where acceleration comes 42.36 m/ s^ 2

Elizabeth accelerates the soccer ball with an acceleration of 42.3 m/s² from rest in the process.

Acceleration of an object can be defined as the rate of change of velocity of an object with respect to time. The acceleration of an object is a vector quantity with both magnitude and direction. Acceleration is also defined as the second derivative of position w.r.t. time and the first derivative of velocity of an object w.r.t. time.

According to Newton's second law of motion, the force is equal to the product of the mass and acceleration of an object.

F = ma

And, a = F/m

Therefore, the acceleration of a body is inversely proportional to the mass of the body.

Given, the force with which, Elizabeth kicks a soccer ball

F = 33.0 N

The mass of the soccer ball = 0.78 Kg

The acceleration of the soccer ball = 33/0.78 = 42.3 m/s²

Therefore, the acceleration of the soccer ball when it gets kicked is 42.3m/s².

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There will be no change in the ration of Q/V. Therefore the correct answer is (a).

The ratio of charge Q to voltage V across a capacitor is given by:

Q/V = C

Where C is the capacitance of the capacitor.

If the capacitance is doubled, the new capacitance C' becomes 2C. Substituting into the equation, we get:

Q/V = C

Q/V = 2C/2 = C'

So the ratio of Q to V remains the same, and there is no change in the ratio Q/V when the capacitance is doubled.

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Answer:

13.04

Explanation:

credit to the comment above

A lens with f= 20.0 cm creates a virtual image at -37.5 cm, then the object distance is approximately 0.0767 cm.

To determine the object distance in this scenario, we can use the lens formula:

\(\rm \frac{1}{f} =\frac{1}{v} -\frac{1}{u}\)

Here, we have:

f = 20.0 cm (positive for a converging lens)

v = -37.5 cm (negative because it is a virtual image formed in front of the lens)

Substituting the values into the lens formula:

1÷20.0 = 1 ÷ (-37.5) - 1 ÷ u

Simplifying the equation:

1 ÷ 20.0 + 1÷ 37.5 = 1 ÷ u

Multiplying through by the common denominator:

(37.5 + 20.0) ÷ (20.0 * 37.5) = 1 ÷ u

57.5 ÷ 750 = 1 ÷ u

Dividing both sides by 57.5:

1 ÷ u = 750 ÷ 57.5

u = 57.5 ÷ 750

u ≈ 0.0767 cm

Thus, the object distance is approximately 0.0767 cm.

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Answer:

allows for efficient transport of materials

Explanation:

Living cells relatively have a small size, so small that a microscope is needed to see their structure. However, this small size is for their benefitting as it increases their surface area to volume ratio (SA:V).

A large surface area to volume ratio (SA:V) enables easy movement of molecules to and fro the cell membrane via the process of DIFFUSION. Therefore, having a small size allows for efficient transport of materials needed in the cell.

Answer: 6

If the mass of this object were tripled (with no change in its net force) =>Its acceleration will decrease by 3 times

=> the new acceleration would be: 18/3 = 6(m/s²)

Explanation:

1 km = 1000 m

1 hr = 3600 s

So, 18 km/hr = (18 * 1000) / (3600) m/s = 5 m/s

And 2 m/s^2 = 2 m/s^2

Now, we can use the formula for final velocity (v) when an object starts with an initial velocity (u) and accelerates at a constant rate (a) for a given time (t):

v = u + at

Plugging in the values, we get:

v = 5 + (2 * 5) m/s v = 15 m/s

To convert this back to km/hr, we use the inverse conversions: v = (15 * 3600) / (1000) km/hr v = 54 km/hr

Therefore, the car’s velocity in km/hr after 5 seconds is 54 km/hr.

Answer:

31.84

Explanation:

To find the magnitude of the sum of the three vectors, first, we need to add the vectors component-wise. Then, we can find the magnitude of the resulting vector.

Add the vectors component-wise:

Vector A + Vector B + Vector C = [13+13+0, 8+0+1, 0+8+8] = [26, 9, 16]

Find the magnitude of the resulting vector:

The magnitude of a vector [x, y, z] is given by the formula:

magnitude = sqrt(x^2 + y^2 + z^2)

Plugging in the values from the resulting vector:

magnitude = sqrt(26^2 + 9^2 + 16^2)

magnitude = sqrt(676 + 81 + 256)

magnitude = sqrt(1013)

magnitude ≈ 31.84

The magnitude of the sum of the three vectors is approximately 31.84.

Hope this helps!

Answer:

The correct difference between chronic and acute stress is:

Acute stress is short-term, while chronic stress endures over time.

Explanation:

Acute stress refers to the immediate and temporary response of the body to a specific stressful event or situation. It is often characterized by a rapid increase in heart rate, heightened alertness, and the release of stress hormones like adrenaline. Acute stress is a normal and natural response to perceived threats or challenges, and once the stressor is removed or resolved, the body returns to its normal state.

On the other hand, chronic stress is long-term and persists over an extended period. It is typically caused by ongoing or recurring stressors, such as work pressures, financial difficulties, relationship problems, or chronic health conditions. Chronic stress can have a cumulative and prolonged impact on physical and mental well-being. It may lead to a range of health issues, including cardiovascular problems, weakened immune system, digestive disorders, anxiety, depression, and burnout.

Chronic stress is considered detrimental to overall health, while acute stress, when experienced in moderation, can actually be beneficial as it can enhance performance and help individuals deal with immediate challenges. It is important to manage chronic stress effectively through stress-reducing techniques, self-care practices, and seeking support when needed to prevent its negative consequences on health and well-being.

The frequency of oscillation of the swing is 0.25 Hz.

The time period of oscillation of the swing is 4 s.

The length of the vine of the swing is 3.97 m.

The restoring force acting on Mohammed is 692.9 N.

Mass of Mohammed, m = 50 kg

Angle made by the vine with the vertical, θ = 45°

Number of complete swings made by Mohammed, n = 30

Time taken for this swing, t = 2 minutes = 120 seconds

a) The frequency of the swing is defined as the number of complete oscillations in one second.

So, the frequency of oscillation of the swing is,

f = n/t

f = 30/120

f = 0.25 Hz

b) The time period of oscillation of the swing is,

T = 1/f

T = 1/0.25

T = 4 s

c) The expression for the time period is given by,

T = 2π√(l/g)

T² = 4π² x (l/g)

l/g = T²/4π²

Therefore, the length of the vine of the swing is,

l = T²g/4π²

l = 4² x 9.8/4 x (3.14)²

l = 3.97 m

d) The restoring force acting on Mohammed,

F = mg sinθ

F = 50 x 9.8 x sin 45°

F = 490 x 1/√2 = 490/1.414

F = 692.9 N

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The values that could be the resultant magnitude of the two forces are 12 N and 7 N.

option C and E are the correct answers.

The resultant of two forces can be obtained by applying Parallelogram law of vector addition.

R² = F₁² + F₂²  -  2(F₁F₂) x cosθ

where;

When the angle between the two forces is 0⁰, the resultant force is calculated as;

R² = 5² + 9²  -  2(5 x 9) x cos0

R² = 16

R = √16

R = 4 N

When the angle between the two forces is 90⁰, the resultant force is calculated as;

R² = 5² + 9²  -  2(5 x 9) x cos(90)

R² = 106

R = √106

R = 10.29 N

When the angle between the two forces is 180⁰, the resultant force is calculated as;

R² = 5² + 9²  -  2(5 x 9) x cos(180)

R² = 196

R = √ 196

R = 14 N

Thus, the resultant force is between 4 N and 14 N. The resultant force must fall within this range, any value outside this range cannot be the resultant magnitude.

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1.The Sun is located at one of the foci of the planets' elliptical orbits.

2.The path of the planets around the Sun is elliptical in shape. are the correct statement.

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Answer:

They are trying to jump-start a car using a kite and lightning connected to the battery. This will not work because there is no positive or negative charged side to the circuit.

Explanation:

45º angle will result in the trebuchet’s furthest thrown projectile.

It is acceptable to infer from the results shown in the demonstration on Interactive Physics that as the weight of a counterweight on a trebuchet rises, so too should the projectile's range. Except for the fact that the distance did not rise linearly but rather more quadratically, the results support the theory. The results showed that the distance rose as the weight of the trebuchet's counterweight was increased in steps of 5 kilograms, starting at 20 kilograms and ending at 200 kilograms.

Each time, the projectiles were launched from the trebuchet at a 45-degree angle, and their distances typically followed the equation -8.1551E-4x2 +.304388x + 8.12756 (where x is the mass of the counterweight). The graph was thought to be more quadratic than linear because gravity has more time to work against the projectile and pull it down to the earth the longer it is in the air. Therefore, as additional mass is applied and the projectile is in the air for a longer period of time, the projectile distances would not grow as quickly. These findings back up Newton's Third Law of Motion as well as earlier, historical investigations.

Thus, Thomas should launch the trebuchet at a 45º angle to get the farthest thrown projectile.

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At height h, on the left side of a loop, a stone is let free from its resting position. h = v^2/(2 x g) + r must the stone be at in order to stay on the track at the top of the loop.

For a stone to not fall off the track at the top of a loop, it must be traveling fast enough to follow the track's curvature. This means that the stone must have a certain minimum speed at the top of the loop in order to complete it from resting position. The minimum speed required for the stone to complete the loop can be calculated using the equation v = sqrt(gr), where v is the minimum speed, g is the acceleration due to gravity, and r is the radius of the loop. Therefore, the minimum height h for which the stone will not fall off the track at the top of the loop can be calculated using the equation h = v^2/(2*g) + r, where h is the minimum height, v is the minimum speed, g is the acceleration due to gravity, and r is the radius of the loop.

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The range of capacitance values that are needed so the antenna can pick up all the radio waves broadcasted by FM stations is from 5.45 x 10⁻¹² H to 3.62 x 10⁻¹² H.

The frequency at which the antenna can pick the radio waves broadcasted is known as resonance frequency.

At resonance frequency, the capacitive reactance is equal to inductive reactance.

Xc = Xl

\(\frac{1}{2\pi fC} = 2\pi fL\\\\4\pi^2 f^2 LC = 1\\\\C = \frac{1}{4\pi^2 f^2L}\)

where;

When the frequency is 88 MHz, the capacitance is;

\(C = \frac{1}{4\pi^2 \times (88 \times 10^6)^2 \times (6\times 10^{-7})} \\\\C = 5.45 \times 10^{-12} \ H\\\\\)

When the frequency is108 MHz, the capacitance is;

\(C = \frac{1}{4\pi^2 \times (108 \times 10^6)^2 \times (6\times 10^{-7})} \\\\C = 3.62\times 10^{-12} \ H\\\\\)

Thus, the range of capacitance values that are needed so the antenna can pick up all the radio waves broadcasted by FM stations is from 5.45 x 10⁻¹² H to 3.62 x 10⁻¹² H.

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The answer by onyebuchinnaji is correct, except for the fact that the final answer is in Farad (F), not H.

Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers

At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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In 1998, David "Cannonball" Smith set the distance record for being shot from a cannon (56.64 m).  we can use the kinematic equations to analyze David "Cannonball" Smith's motion during the launch and deceleration.While he was being stopped by the catching net, his speed decreased from 80 km/h to zero with an average acceleration of 180 m/s2. The speed is s ≈ -1.369 m.

1. **Initial Launch:**

  Initial velocity (u) = 0 (starting from rest)

  Final velocity (v) = 80 km/h = 22.22 m/s (converted from km/h to m/s)

  Time (t) = 0.40 s

  Acceleration (a) = (v - u) / t = (22.22 m/s - 0 m/s) / 0.40 s = 55.55 m/s²

2. **Using Distance Equation for Launch:**

  Using the equation: **s = ut + 0.5at²**

  Distance (s) = 56.64 m (distance record)

  Initial velocity (u) = 0 m/s

  Time (t) = 0.40 s

  Acceleration (a) = 55.55 m/s²

  Solving for distance:

  56.64 m = (0) + 0.5 * 55.55 m/s² * (0.40 s)²

  56.64 m = 0.5 * 55.55 m/s² * 0.16 s²

  56.64 m = 4.444 m

  This calculation seems to suggest that there might be a discrepancy in the data provided, as the calculated distance for the launch is significantly different from the stated distance record of 56.64 m. Please double-check the given values or provide additional information if necessary.

3. **Deceleration (Stopping by Catching Net):**

  Initial velocity (u) = 22.22 m/s (from previous launch)

  Final velocity (v) = 0 m/s (coming to a stop)

  Average acceleration (a) = 180 m/s²

  Using the equation: **v² = u² + 2as**

  Solving for distance (s):

  0² = (22.22 m/s)² + 2 * 180 m/s² * s

  0 = 492.84 m²/s² + 360s

  s = -492.84 m²/s² / (360 m/s²)

  s ≈ -1.369 m

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The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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Answer:

Explanation:

- The friction acts leftwards to balance the tension that must be pulling up and to the right.

- The force of gravity is straight down.

- The normal force is perpendicular to the contact surface.

The force of gravity is straight down.

What is force of gravity?

On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them.

Gravity is measured by the acceleration that it gives to freely falling objects.

According to the question,

A block of cheese is pulled on by a string and remains at rest until we will not apply an external force.

It also posses force of gravity.

The friction acts leftwards to balance the tension that must be pulling     up and to the right.

The force of gravity is straight down.

The normal force is perpendicular to the contact surface.

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Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.

The correct answer is option D.

The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :

Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).

When Mark climbs the stairs with the cello, he is doing work against the force of gravity.

The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.

Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.

Therefore, mark's work decreases.

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The weight of the Mars Rover Curiosity on Earth and on Mars is 8820 N and 3330 N respectively.

The weight of an object is given by the product of its mass and the gravitational field strength at its location.

On Earth:

On Mars:

Therefore, the weight of the Mars Rover Curiosity on Earth and on Mars are 8820 N and 3330 N respectively.

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A cylinder with a movable piston contains 3 moles of hydrogen at standard temperature and pressure. The walls of the cylinder are made of a heat insulator, and the piston is insulated by having a pile of sand on it. By what factor does the pressure of the gas increase if the gas is compressed to half its original volume?

Solution :

The cylinder is completely insulated from its surroundings. As a result, no heat is exchanged between the system (cylinder) and its surroundings. Thus, the process is adiabatic.

Initial pressure inside the cylinder =P1

Final pressure inside the cylinder =P2

Initial volume inside the cylinder =V1

Final volume inside the cylinder =V2

Ratio of specific heats, γ=CVCP=1.4

For an adiabatic process, we have:

P1V1γ=P2V2γ

The final volume is compressed to half of its initial volume.

∴V2=V1/2

P1V1γ=P2(V1/2)γ

P2/P1=V1γ/(V1/2)γ

=21.4=2.639

Hence, the pressure increases by a factor of 2.639.

Answer:

The cylinder is fully isolated from the rest of the environment.

There is no heat exchange between the system (cylinder) and its surroundings as a result of the design. As a result, the process is called adiabatic.

P1 represents the initial pressure inside the cylinder.

P2 is the final pressure within the cylinder.

V1 is the volume of the cylinder at its beginning.

The final volume of the cylinder is equal to V2.

The specific heat ratio, = Cp / Cv = 1.4,

We have the following for an adiabatic process:

P1V1γ = P2V2γ

After compression, the final volume is reduced to half of its original size.

Hence,

V2 = V1 / 2

P1V1γ = P2(V1 / 2)γ

P2 / P1 = V1γ / (V1 / 2)γ

= 21.4

We get,

= 2.639

Therefore, the pressure increases by a factor of 2.639

Explanation:

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