A 100kg couch is being pushed with 196N of force. As it slides along the ground it experiences a coefficient of friction of 0.1. What is the net force in this situation?

A 300N
B 202N
C 398N
D 98N

An insulating vessel contains 80 g of a block of ice at -12 °C. If 450 g of water at 60 °C is added to the ice in the vessel, Energy required for complete melting = \(80 g X (3.33 X 10^3 J/kg)\).

To determine whether the ice will soften absolutely and calculate the final temperature of the system, we need to do not forget the strength transferred among the ice and water at some stage in the procedure.

(i) To decide if the ice will melt completely, we need to examine the energy won by using the ice to the electricity required for complete melting.

Energy received by way of the ice = mass of ice × particular heat capacity of ice × alternate in temperature

Energy won by using the ice = eighty g × 2100 J/(kg·°C) × (final temperature - (-12°C))

Energy required for complete melting = mass of ice × latent warmth of fusion of ice

Energy required for whole melting = 80 g × (3.33 × 10^3 J/kg)

If the strength received via the ice is extra than or same to the electricity required for entire melting, the ice will soften completely.

(ii) To calculate the very last temperature of the gadget, we want to keep in mind the power transferred between the ice and water.

Energy won by the water = mass of water × unique heat ability of water × trade in temperature

Energy received by using the water = 450 g × 4200 J/(kg·°C) × (final temperature - 60°C)

Since electricity is conserved inside the machine, the power gained by means of the ice and water need to be identical:

Energy gained through the ice = Energy won by the water

Using the equations above, we will installation the following equation:

80 g × 2100 J/(kg·°C) × (very last temperature - (-12°C)) = 450 g × 4200 J/(kg·°C) × (very last temperature - 60°C)

Thus, this the final temperature of the system.

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The relative velocity of the car 2 with respect to car 1 is 70 m/s west. So, the correct option is C.

Velocity of the car 1 with respect to the ground, v₁ = 45 m/s west

Velocity of the car 2 with respect to the ground, v₂ = 25 m/s east

Let the direction towards the east be positive and the opposite direction towards the west be negative.

The expression for the relative velocity of the car 2 with respect to car 1 is given by,

v₂₁ = v₂ - v₁

v₂₁ = 25 - (-45)

Therefore, the relative velocity,

v₂₁ = 70 m/s west

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Attaching the image file here.

Answer:

Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air? Neither, the speed of sound is constant in air.

Answer:

20

Explanation:

R= resistance  P = resistivity  

L = length  A = area

0.8 = 1cm/A

R = J l/A       => 0.8* 50*A/A

                   => 0.8 * 25

                   => 20

Answer:

Resistance is directly proportional to length, inversely proportional to cross-sectional area. Pay attention in class, and observe that even easy multiple choice questions can have only wrong answers if the setter makes a mistake.

The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.

The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.

Calculation:-

A. angular velocity ω = v/r

                                     = 30 /8

                                      = 3.75 m/s

B. Centripetal force = mv²/r

                             = 2×30²/8

                              = 225 N

There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.

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Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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The concept of right triangles is applied in different areas in real life. The areas include survey, carpentry, calculations involving ladder heights, etc. The are used by applying the pythagorean theorem which is expressed as

hypotenuse^2 = opposite side^2 + adjacent side^2

where hypotenuse is the longest side of the triangle and the opposite and adjacent sides are the legs of the triangle.

An example is the position of a ladder leaning on a wall. The angle that the ladder would make with the ground, the required length of the ladder and the distance from the wall can be calculated.

If we want to calculate the length of a ladder required to reach a certain height on a buliding, the length of the reuired ladder would be the hypotenuse of the right triangle formed. the height to be accessed would be the opposite side of the triangle. The distance between the foot of the ladder and the building would be the adjacent side of the triangle.

Answer:

There no image

Explanation:

Answer:

V2 = 37.5 L

Explanation:

Given the following data;

Initial volume, V1 = 25 L

Initial temperature, T1 = 20°C

Final temperature,T2 = 30°C

To find the final volume V2, we would use Charles' law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

\( \frac {V}{T} = K\)

\( \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}} \)

Making V2 as the subject formula, we have;

\( V_{2}= \frac{V_{1}}{T_{1}} * T_{2}\)

\( V_{2}= \frac{25}{20} * 30 \)

\( V_{2}= 1.25 * 30 \)

V2 = 37.5 L

Answer:

(a)  24.56 N

(b) 142.28 N

Explanation:

(a)

The designation assigned to something like the net force pointed toward the middle including its circular route seems to be the centripetal force. The net stress only at lowest point constitutes of the strain throughout the arm projecting upward towards the middle as well as the weight pointed downwards either backwards from the center.

The centripetal function is generated from either scenario by Equation:

⇒  \(Fc = \frac{mv^2}{r}\)

On putting the values, we get

⇒       \(=\frac{12\times 1.33^2}{0.864}\)

⇒       \(=24.56 \ N\)

(b)

Use T to denote whatever arm stress we can get at the bottom including its circle:

⇒  \(Fc = T - mg =\frac{ mv^2}{r}\)

⇒  \(T = mg + Fc\)

⇒      \(=12\times 9.81+24.56\)

⇒      \(=142.28 \ N\)

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

This observation that electromagnetic radiation behaves like particles is known as the photoelectric effect.

It provides evidence that electromagnetic radiation exhibits particle-like properties. When EMR with sufficient energy (above a certain threshold) interacts with a metal surface, it can cause the ejection of electrons from the metal.

This behavior indicates that EMR behaves as discrete packets of energy called photons, which transfer their energy to the electrons and cause their release. The photoelectric effect supports the particle nature of EMR and is a fundamental concept in the field of quantum mechanics.

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Answer:

1.84 m

Explanation:

For the small lead ball to be balanced at the tip of the vertical circle just before it is released, the reaction force , N equal the weight of the lead ball W + the centripetal force, F. This normal reaction ,N also equals the tension T in the string.

So, T = mg + mrω² = ma where m = mass of small lead ball, g = acceleration due to gravity = 9.8 m/s², r = length of rope = 1.10 m and ω = angular speed of lead ball = 3 rev/s = 3 × 2π rad/s = 6π rad/s = 18.85 rad/s and a = acceleration of normal force. So,

a = g + rω²

= 9.8 m/s² + 1.10 m × (18.85 rad/s)²

= 9.8 m/s² + 390.85 m/s²

= 400.65 m/s²

Now, using v² = u² + 2a(h₂ - h₁)  where u = initial velocity of ball = rω = 1.10 m × 18.85 rad/s = 20.74 m/s, v = final velocity of ball at maximum height = 0 m/s (since the ball is stationary at maximum height), a = acceleration of small lead ball = -400.65 m/s² (negative since it is in the downward direction of the tension), h₁ = initial position of lead ball above the ground = 1.3 m and h₂ = final position of lead ball above the ground = unknown.

v² = u² + 2a(h₂ - h₁)

So, v² - u² = 2a(h₂ - h₁)

h₂ - h₁ =  (v² - u²)/2a

h₂ =  h₁ + (v² - u²)/2a

substituting the values of the variables into the equation, we have

h₂ =  1.3 m + ((0 m/s)² - (20.74 m/s)²)/2(-400.65 m/s²)

h₂ =  1.3 m + [-430.15 (m/s)²]/-801.3 m/s²

h₂ =  1.3 m + 0.54 m

h₂ =  1.84 m

Answer:

Car A was going at 80 m/s

Explanation:

Let's call "x" the unknown speed of car A. In such case, the speed of car B would be x/2.

We proceed to describe the distance covered by car A (dA) in the 5 seconds it took to collide:  dA = speed * time = x * 5 = 5 x

Now the distance covered by car B (dB) in the same time would be:

dB = speed * time = (x/2) * 5 = 5 x / 2

Now, we know that the distance that separated both cars was 600 meters, so the addition of what car A covered plus what car B covered must equal 600 m, and in equation form:

dA + dB = 600

5 x + 5 x / 2 = 600

combining like terms:

15 x / 2 = 600

multiplying both sides by 2:

15 x = 1200

divide both sides by 15:

x = 80 m/s

This is the speed of car A.

The distance travelled by the muon is 316.8 meter, before it decays.

In radioactivity, mean life refers to the cumulative lifetime of all the nuclei of a specific unstable atomic species. This period of time can be conceptualised as the product of the lifespan of each individual unstable nucleus in a sample divided by the overall number of unstable nuclei present. A specific species of unstable nucleus's half-life is always 1.443 times shorter than its mean life.

The proper mean lifetime of a muon is 2.2 × 10⁻⁶ s.

Speed of the muon is 0.6c.

Hence, the distance travelled by the muon is = 0.6c × 2.2 × 10⁻⁶ s.

= 0.6 × 3 × 10⁸×2.2 × 10⁻⁶  meter

= 396 meter.

In relativistic observation, the distance travelled by the muon is = 396 ×√(1 - (0.6c/c)²) meter

= 316.8 meter

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

Layer C

Explanation:

Hope this helps!

-Liyah<3

1. Completely cutting out food groups, such as grains, fruits, and vegetables, can have negative health implications as each food group provides essential nutrients.

This eating pattern of high meat and protein intake while restricting grains, fruits, and vegetables may not be sustainable over a lifetime, as it lacks balance and variety.

3. Three healthy foods that would be restricted in this diet are grains, fruits, and vegetables. These foods are important as they provide essential nutrients, antioxidants, and dietary fiber, supporting overall health, digestion, and reducing the risk of chronic diseases. Restricting these foods can lead to nutrient deficiencies and negatively impact well-being.

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Explanation:

density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.

The relative density of a substance is defined as the ratio of the density of that substance to the density of water at 4oC. It is also defined as the ratio of the mass of substance to the mass of equal volume of water at 4oC. i.e., R.D. = Mass of the substance / mass of an equal volume of water at 4oC

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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As the substance's thermal energy increases, the kinetic energy of its particles increases, and vice versa.

The kinetic energy of an object increases as its mass or velocity increases. For example, a heavy object moving at a high speed has more kinetic energy than a lighter object moving at a lower speed. Additionally, the direction of an object's motion is not relevant to its kinetic energy, as long as it is moving. Kinetic energy is a scalar quantity, meaning that it has only magnitude and no direction. It is also a form of mechanical energy, which is energy that is associated with the motion or position of an object. Other forms of mechanical energy include potential energy, which is energy that an object possesses due to its position or configuration, and thermal energy, which is the energy associated with the motion of particles within a substance.

Here,

Thermal energy is a form of energy associated with the motion of particles in a substance. Specifically, thermal energy is the sum of the kinetic energies of the particles in a substance. So, as the temperature of a substance increases, the average kinetic energy of its particles also increases. This means that the particles move faster and have greater kinetic energy. Therefore, there is a direct relationship between a substance's thermal energy and its kinetic energy. If the substance's thermal energy increases, its particles will have more kinetic energy and will move faster. Conversely, if the substance's thermal energy decreases, its particles will have less kinetic energy and will move more slowly.

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Answers:

Question 1: As the substance’s thermal energy increases, the kinetic energy of its particles increases, and vice versa.

Question 2: Its molecules move around more quickly, so there is more space between them, making it less dense than the air above it.

Question 3: Warmer sauce at the bottom of the pot is less dense, so it rises, forcing cooler sauce down, where it is warmed.

Question 4: Hot soup warms the bowl where it sits.

Question 5: transfer of thermal energy through infrared waves

Explanation:

i just did the quick check

I could make a poem for you if you actually gave the words...... what 10 words do i need to incorporate???☹︎

Answer:

By definition the acceleration due to gravity at the surface is g:

The altitude above the surface is zero for an acceleration of g.

Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

Considering the information from bubble 1 and bubble 2, the magnitude of F1-2 compares to F2-1 because the two forces have the same magnitude. Option B is correct.

This concept can be explained by physics through Coulomb's Law, which states that the electrostatic interaction between two particles occurs the greater the magnitude of the charges and the smaller the distance between the particles, the greater the force of attraction or repulsion between the charges.

Therefore, through Coulomb's Law we can understand the interaction between charged particles and the forces exerted by them that will be equal in magnitude and opposite in direction, making the magnitude of F1-2 equal to the force F2-1.

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Answer:The ampere is unique in that it uses the base unit of time (t) in its definition (second). All other electrical and magnetic units (such as voltage, power, and magnetic flux) use various combinations of base units in their definitions and are called derived units.

Explanation:

6.6 J/K

1.4 J/K

190 J/K

100 J/K

6.2 J/k

i think this is a answer

ANSWER:

1573.5 g

STEP-BY-STEP EXPLANATION:

Given:

Volume (V) = 150 cm³

We have that the density of silver is 10.49 g/cm³, therefore, we calculate its mass, as follows:

The mass of silver is 1573.5 grams

Answer:O2 & C6H12O6

Explanation:

C6H12O6 + 6O2-> 6CO2 + 6H2O

O2 and C6H12O6 molecules' chemical connections are disrupted.

         C6H12O6 + 6O2-> 6CO2 + 6H2O

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Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.

In a mixed economy, economic decisions are made by both the government and consumers.

The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.

In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.

The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.

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