8. a metal has a yield strength of 30.5 kpsi at its elastic limit and the strain at that point is 0.00000177. what is the modulus of elasticity? assume that the test specimen is 0.505-in dia and has a 2-in gage length. what is the strain energy at the elastic limit? can you define the type of metal based on the given data?

It is important for drivers to be familiar with these colors and what they indicate. In Florida, a yellow curb indicates an area where parking is prohibited.

Parking rules and regulations are important to know. The laws regarding parking, however, are not always the same from state to state. For example, in Florida, parking on a yellow curb is generally prohibited. In contrast, parking on a red curb may be allowed in some states. Blue and green curbs, on the other hand, typically denote parking restrictions for a specific purpose or group of individuals. In California, for example, a blue curb indicates that parking is reserved for individuals with disabilities who have a disabled placard or plate displayed on their vehicle.

Similarly, green curbs often indicate short-term parking for loading and unloading, or parking spots reserved for electric vehicles that require charging.

The use of different colors to denote parking restrictions helps to ensure that drivers are aware of the rules and regulations regarding parking in a particular area.

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Z≤ -4.852 ft, Maximum efficiency is η≅ 0.88 ≅ 88% is the maximum discharge possible

Solution

Given Data:-

D = 14.62in, N = 2134 rc/min, T=20°C. At T= 20°C ɣ=ρg= 62.35 lb/ft³, vapor pressure. Pv = 49.2 lb/ft².

The efficienies at each flow rate is computal by using formula

η = ρgθH / (550) (bhp)

→ As we can See the maximum efficiency point is at θ = 6ft³/s (close to 6ft³/s)

Maximum efficiency is η≅ 0.88 ≅ 88%

b) Given NPSHR = 16 ft,hg=22ft. Zactual. = 9ft  (below the sea surface)

To avoid cavitation NPSH < Pa - Pv/ρg - Z - hf

Z < Pa - Pv/ρg - hf

Z < 2116 - 49.2/62.35 - 16 - 22 [1 atm = 2116 lb/ft2]

Z≤ -4.852 ft

-> Keeping the pump 9 ft below the surface gives 4.148 ft of marign against cavitation.

Hence it is Sufficient to avoid cavitation.

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You need to configure a DNS A record for the intranet site's hostname to map it to the correct IP address.

What is DNS?
DNS, or Domain Name System, is an internet protocol used to translate domain names, such as www.example.com, into IP addresses, such as 192.168.2.1, that computers can understand and use to communicate with each other. DNS acts as a directory service, providing a link between domain names and their associated IP addresses, which are stored and managed in a distributed database system. DNS is essential for the functioning of the internet, allowing users to access websites and services without having to remember their numerical IP addresses. DNS works by querying a distributed network of DNS servers, which maintain a database of IP addresses and their corresponding domain names. When a DNS query is made, the DNS server looks up the requested IP address in its database and returns it to the user. DNS is an important part of the internet infrastructure and is used by many different types of services, such as email, web hosting, and streaming services.

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Answer:

a) x = 5.7791 m ( this a turbulent flow )

b) x = 0.04 m ( this is a Laminar flow )

Explanation:

For Air, take

p = 1.2 kg/m³ and u = 1.8×10⁻⁵ kg/m³

So for A , x = 10 cm

Guess turbulent flow;

(Sturb / x) = (0.16 / (p∪x / u)^1/7)

we substitute

(0.1/x = 0.16) / ( 1.2 × 15 × x / 1.8×10⁻⁵)^1/7

x = 5.7791 m

CHECK

Re = (1.2 × 15 × 5.7791) / 1.8×10⁻⁵ = 5.779×10⁶

Therefore this a turbulent flow

for B, x = 1mm

Guess Laminar flow

(S-laminar / x) = ( 5 / (Reₓ)^1/2)

x = (Stutb)²p∪ / 23u

x = ((0.001)² × 1.2 × 15) / (25 × 1.8×10⁻⁵)

x = 0.04 m

CHECK

Re = (1.2 × 15 × 0.04) / (1.8×10⁻⁵)

= 40000

Therefore  this is a Laminar flow

Answer:

First we determine the tensile strength using the equation;

Tₓ (MPa) = 3.45 × HB

{ Tₓ is tensile strength, HB is Brinell hardness = 225 }

therefore

Tₓ = 3.45 × 225

Tₓ = 775 Mpa

From Conclusions, It is stated that in order to achieve a tensile strength of 775 MPa for a steel, the percentage of the cold work should be 10

When the percentage of cold work for steel is up to 10,the ductility is 16% EL.

And 16% EL is greater than 12% EL

Therefore, it is possible to cold work steel to a given minimum Brinell hardness of 225 and at the same time a ductility of at least 12% EL

The estimated nominal thrust for the jet engine is approximately 6,754 lbf.

To calculate the nominal thrust, we'll follow the steps outlined in the explanation.

Calculate the mass flow rate (m_dot):

Using the equation m_dot = rho * A_i * V_i, we can find the mass flow rate of air passing through the engine.

Given:

Intake cross-sectional area (A_i) = 10 ft^2

Intake air velocity (V_i) = 700 ft/s

First, we need to determine the density of the intake air (rho). We can use the ideal gas law:

PV = nRT

Where:

P is the pressure (11.4 psia)

V is the volume (unknown)

n is the number of moles of gas (unknown)

R is the gas constant (assuming air, R = 1545 ft·lbf/lbm·R)

T is the temperature (480 deg R)

Solving for n/V and substituting known values:

n/V = P / (RT)

Now, we can calculate n/V by plugging in the values:

n/V = (11.4 psia) / (1545 ft·lbf/lbm·R * 480 deg R)

Once we have n/V, we can calculate the density (rho) using the molar mass of air (28.97 lbm/lbmol):

rho = n/V * molar mass of air

= (n/V) * (28.97 lbm/lbmol)

Now that we have the density, we can calculate the mass flow rate:

m_dot = rho * A_i * V_i

Calculate the thrust:

Using the equation Thrust = (m_dot * V_e) - (m_dot * V_i), we can calculate the nominal thrust.

Given:

Exhaust gas velocity (V_e) = 1640 ft/s

Now, substitute the calculated value of m_dot, the intake air velocity (V_i), and the exhaust gas velocity (V_e) into the equation and solve for the thrust.

The estimated nominal thrust for the specific jet engine under the given conditions is approximately 6,754 lbf.

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Answer:

True

Explanation:

Those are the exact uses of a resistor

If a vehicle is coming from the opposite direction in your lane, it means that the vehicle is traveling in the wrong direction and is headed toward you.

This is a dangerous situation that requires quick action to avoid a collision. It is important to remain calm and take evasive action, such as slowing down or moving to the side of the road if possible.

It is also important to signal to the other driver with your horn or headlights to alert them of their mistake and to prevent an accident. Remember to always be alert and aware of your surroundings while driving to avoid situations like this.

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It is because an isometric sketch is more useful for functional drawings that are used to explain how something works, while one-point perspective drawings are typically used to give a more sensory idea of an object or space.

Isometric Sketch or isometric drawing can be described as a pictorial representation of an object in which all three dimensions are drawn at full scale. It looks like an isometric projection. Isometric sketch is kind of 3D drawing, which is set out using 30-degree angles. It is kind of axonometric drawing so the same scale is used for every axis, resulting in a non-distorted image.

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The quartiles divide a set of observations into four portions, each representing 25% of the observations, together with the minimum and maximum values of the data set. The interquartile range, a measurement of variation around the median, is calculated using quartiles.

Statistical file: {2, -6, 5}

Quartile Q1: -6

Quartile Q2: 2

Quartile Q3: 5.

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The corresponding minimum and maximum velocities that the rocket experiences are 23.195m/s and 37.249m/s.

The minimum value will be:

V(t) = 3t³ + (-24)t² + 54t

V(3.721) = 3(3.721)³ - 24(3.721)² + 54(3.721)

= 23.195m/s.

The maximum value will be:

V(.1613) = 3(1.613)³ - 24(1.613)² + 54(1.613)

= 37.249m/s

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Magnitude of average acceleration  \(a_{avg}\)=2.75 units

Average acceleration \(a_{avg}=\) \(2.265 i- 1.58j\)

We're given that \(s=\frac{t^2}{4}\)

And partice is at A at t=2 s and at B at t= 2.2s

Instantaneous velocity \(\frac{ds}{dt} =\frac{t}{2}\)

Velocity at A  (\(V_{a}\)) at 2s = \(\frac{t}{2}\) or  \(\frac{t}{2}Cos \frac{\pi}{3} i+ \frac{t}{2}Sin \frac{\pi}{3}j=\frac{i+\sqrt{3} j}{2}\)

Velocity at B  (\(V_{b}\)) at 2.2s =\(\frac{t}{2}\) or \(\frac{t}{2}Cos \frac{\pi}{6} i+ \frac{t}{2}Sin \frac{\pi}{6}j=\frac{\sqrt{3}i+j }{2}\)

Average acceleration = \(\frac{V_{b}-V{a}}{t}\) =\(2.265 i- 1.58j\)

magnitude = \(\sqrt{(2.265)^2- (1.58)^2}\) = \(2.75\)

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Answer:false

Explanation:

Bc

The estimated cost for a 500-MW fossil-fuel plant is $592.5 million using the cost-capacity factor. The suitable cost estimating method is indexing.

To estimate the cost for building a 500-MW fossil-fuel plant, we can use the cost-capacity factor and the known cost of a 200-MW plant. Here's a step-by-step explanation:

1. Understand the cost-capacity factor: The cost-capacity factor is a parameter used to estimate the relationship between the capacity of a power plant and its cost. It represents the cost increase per unit of capacity.

2. Calculate the cost-capacity factor: The cost-capacity factor for the fossil-fuel power plant is given as 0.79. This means that for every additional unit of capacity, the cost increases by 0.79 times.

3. Determine the cost of a 200-MW plant: It is stated that the cost of a 200-MW plant is $300 million. This serves as our baseline cost.

4. Calculate the cost for a 500-MW plant: To estimate the cost for a 500-MW plant, we need to apply the cost-capacity factor. Since the cost-capacity factor is 0.79, the cost for a 500-MW plant can be calculated as follows:

  Cost for a 500-MW plant = Cost of a 200-MW plant * (Capacity of 500-MW plant / Capacity of 200-MW plant) * Cost-capacity factor

  Plugging in the values:

  Cost for a 500-MW plant = $300 million * (500 MW / 200 MW) * 0.79

  Simplifying the calculation:

  Cost for a 500-MW plant = $300 million * 2.5 * 0.79 = $592.5 million

Therefore, the estimated cost for building a 500-MW fossil-fuel plant is $592.5 million.

5. Determine the appropriate cost estimating method: Based on the given information, the most suitable cost estimating method for this scenario is indexing. Indexing involves adjusting historical costs using a cost index to account for changes in inflation, labor rates, and material costs over time.

In summary, the estimated cost for building a 500-MW fossil-fuel plant is $592.5 million using the cost-capacity factor. The appropriate cost estimating method for this estimation is indexing.

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Incorrect result: (C) ?- bachelor(Who). Who = henry; Who = joe; false. The Option C.

The query bachelor(Who) is expected to find all individuals who are male and not married, providing their names as solutions. However, the incorrect result is obtained in this case.

The correct part of the result, Who = henry, is consistent with the knowledge base, as Henry is declared as a male and is not married. However, the incorrect part of the result, Who = joe, is unexpected. There is no mention of Joe in the knowledge base, so the query should not yield him as a solution.

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Answer:

lubrication

Explanation:

MARK ME BRAINLEIST

Answer:

Magic

Explanation:

magic is the answer to everything unexplainable

Answer:

YES

Explanation:

NO

;-;

First, we need to calculate the actual power consumption of the 40 HP motor with a load factor of 75% and an efficiency of 89.3%.

Actual power consumption = Rated power x Load factor / Efficiency

= 40 HP x 0.75 / 0.893

= 33.6 kW

Next, we need to calculate the actual power consumption of the 30 HP motor with a load factor of 100% and an efficiency of 93.6%.

Actual power consumption = Rated power x Load factor / Efficiency

= 30 HP x 1 / 0.936

= 31.9 kW

The power savings from this project can be calculated as the difference between the actual power consumption of the 40 HP motor and the actual power consumption of the 30 HP motor.

Power savings = Actual power consumption of 40 HP motor - Actual power consumption of 30 HP motor

= 33.6 kW - 31.9 kW

= 1.7 kW

Therefore, the project will result in a power savings of 1.7 kW.

Answer:

say in English plz I don't understand

''Class A'' fire extinguishers are used for ordinary combustibles.

Since, Class A fire extinguishers are typically used for ordinary combustibles such as wood, paper, and cloth.

Class A fire extinguishers are designed to extinguish fires that involve ordinary combustibles that leave an ash or residue, and work by cooling the fuel source and removing oxygen from the fire, thereby suffocating it.

It's important to note that using the wrong type of fire extinguisher on a fire can actually make the fire worse, so it's important to know which type of fire extinguisher is appropriate for the specific type of fire.

Thus, ''Class A'' fire extinguishers are used for ordinary combustibles.

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Platinum filament.

Thomas Edison went through a series of different experiments while developing bulb until and unless the electricity passed through the Platinum filament, and it finally worked.

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Answer:

The percentage of recycling in high socioeconomic localities is 11.02%.

Explanation:

Since in high socioeconomic localities, 10% of paper is recycled, 12% of plastic, 1.7% of fabrics, 1.2% of rubbers, 0.9% of metals, 3.5% of glass, 33% of food wastes, 35% soil and 1.9% miscellaneous, to determine the average recycling percentage the following calculation must be performed:

(10 + 12 + 1.7 + 1.2 + 0.9 + 3.5 + 33 + 35 + 1.9) / 9 = X

99.2 / 9 = X

11.02 = X

Therefore, the percentage of recycling in high socioeconomic localities is 11.02%.

Answer:

Hence, the steady state temperature distribution between concentric spheres with radii 1 and 4 is:

u = \(\frac{C1}{r }\) + C2

u = \(\frac{\frac{-320}{3} }{r}\) + \(\frac{320}{3}\)

Explanation:

Solution:

Note: This question is incomplete and lacks necessary data to solve this question. But I have found a similar question and will try to solve it.

This question has this following part missing:

"If the temperature of the outer sphere is maintained at 80 degrees and the inner sphere at 0 degrees.

Now, this question is complete.

Let's find out the steady state temperature distribution.

As, we know the spherical symmetric heat equation:

\(\frac{du}{dt}\) = \(\frac{k}{r^{2} }\) \(\frac{D}{Dr}\) (\(r^{2}\) \(\frac{Du}{Dr}\))

Where, small (d) represents the partial differentiation and Capital D represents simple derivative.

And the ordinary differential equation (ODE) for steady state temperature distribution is:

\(\frac{k}{r^{2} }\) \(\frac{D}{Dr}\)(\(r^{2}\) \(\frac{Du}{Dr}\)) = 0

So it can be said that:

\(r^{2}\) \(\frac{Du}{Dr}\)

Consequently,

\(\frac{Du}{Dr}\) = \(\frac{C1}{r^{2} }\)

Taking derivative of the above equation we get:

u = -\(\frac{C1}{r }\) + C2

Solution of the ordinary differential equation

u = \(\frac{C1}{r }\) + C2 (Consuming the negative sign into C1 constant)

As, it is given in our question that our boundary conditions are: 1 and 4

So,

Putting the boundary conditions into the variable (r) to find the constants we get:

u1 = \(\frac{C1}{1} }\) + C2 = 0 (degrees)

u1 = C1 + C2 = 0 (degrees)  equation (1)

Similarly,

u4 = \(\frac{C1}{4}\) + C2 = 80 (degrees)

u4 = \(\frac{C1}{4}\) + C2 = 80 (degrees)  equation (2)

Solving for C1, we get:

Equation 1 - Equation 2

(C1 - C2 = 0) - (\(\frac{C1}{4}\) + C2 = 80)

\(\frac{-3}{4}\)C1 = 80

Solving for C1

C1 = -\(\frac{320}{3}\)

With the help of value of C1, we get value of C2

Put the value of C1 in equation (1) to get value of C2

C1 + C2 = 0

-\(\frac{320}{3}\) + C2 = 0

Solving for C2

C2 = \(\frac{320}{3}\)

Hence, the steady state temperature distribution between concentric spheres with radii 1 and 4 is:

u = \(\frac{C1}{r }\) + C2

Plugging in the values of C1 and C2

u = \(\frac{\frac{-320}{3} }{r}\) + \(\frac{320}{3}\)

Answer:

778.4°C

Explanation:

I = 700

R = 6x10⁻⁴

we first calculate the rate of heat that is being transferred by the current

q = I²R

q = 700²(6x10⁻⁴)

= 490000x0.0006

= 294 W/M

we calculate the surface temperature

Ts = T∞ + \(\frac{q}{h\pi Di}\)

Ts = \(30+\frac{294}{25*\frac{22}{7}*\frac{5}{1000} }\)

\(Ts=30+\frac{294}{0.3928} \\\)

\(Ts =30+748.4\\Ts = 778.4\)

The surface temperature is therefore 778.4°C if the cable is bare

o have a monitored object owned by a unique pointer, you'll need to follow these steps:

1. Check if the weak pointer is valid.
2. Lock the weak pointer to obtain a shared pointer.
3. Create a new unique pointer from the shared pointer.


1. First, ensure the weak pointer is valid, meaning it's actually monitoring an object. If the weak pointer's `expired()` function returns `false`, it is valid.
2. If the weak pointer is valid, use the `lock()` function to create a shared pointer from the weak pointer. The shared pointer will share ownership of the monitored object.
3. Now, create a unique pointer from the shared pointer. You'll need to use `std::unique_ptr` with the object type, and pass the object managed by the shared pointer using `shared_ptr.get()`. Since unique pointers don't allow shared ownership, you must reset the shared pointer after creating the unique pointer to ensure the object is owned exclusively by the unique pointer.

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Answer:

what's the question?...........