6. In AC Welding Power Sources, the drooping external characteristics are normally provided by means of the movable iron core installed in the welding transformer. The welding current adjustment is made by taking in or taking out the movable iron core. Explain this principle, showing sketches of the welding transformer and its external characteristics 7. In MAG welding, the arc-length is maintained stably by the self-regulation of DC power source. Explain briefly by means of a sketch the mechanism of self-regulation.

Answer:C car

Explanation:

The chemical element in period 6 and group 12 is mercury (Hg).

A periodic table can be defined as an organized tabular array of all the chemical elements that are typically arranged in order of increasing atomic number (number of protons), in rows.

In Chemistry, some example of chemical elements that are found in group 12 of the periodic table include the following:

In this context, we can reasonably infer and logically deduce that mercury (Hg) is a chemical element that is found in period 6 and group 12 of the periodic table.

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Given,

u = 0.5 m/s

a=0.05 m/s²

and v=0

Now, v = u − at

=> 0 = 0.5−(0.05×t)

=> t = 10 s

after 10s it will stop

velocity after 5s is

v = 0.5-(0.05×5) = 0.25 m/s

Answer:

0.25 meter per second

Explanation:

I hope this helps and study well

One rope makes an angle of 25 29 with the horizontal and has a tension of 95.6 lb on it. the rope is horizontal. The weight of the crate is 46.16 lb and the tension in the horizontal rope is 82.24 lb.

To find the weight of the crate and the tension in the horizontal rope, we can use the concepts of vector components and equilibrium. Since the crate is in equilibrium, the sum of forces in both the horizontal and vertical directions must be zero.
Let T1 be the tension in the rope with an angle of 29 degrees and T2 be the tension in the horizontal rope.
1. For the horizontal direction:

\(T2=T1cos(29)\)

T2 = T1 × cos(29)
T2 = 95.6 lb × cos(29)
T2 ≈ 82.24 lb
2. For the vertical direction:
W = T1 × sin(29)
W = 95.6 lb × sin(29)
W ≈ 46.16 lb
So, the weight of the crate is approximately 46.16 lb, and the tension in the horizontal rope is approximately 82.24 lb.

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Dilute the unknown until its absorbance is inside the standard curve. The full strength concentration can be calculated after identifying the diluted quantity if the dilution process is documented.

A chemical that is present in large quantities relative to the volume is said to have a high concentration in a solution. For example, the Great Salt Lake contains very few fish due to the high concentration of salt.

You can determine how much solute has been dissolved in the solvent by looking at the concentration of the solution. For instance, the concentration may be stated as 1 teaspoon of salt per 2 cups of water if you add 1 teaspoon to 2 cups of water.

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The fewer the number of substitutes for a good, the less elastic the demand.

The concept of elasticity measures the responsiveness of demand or supply to changes in price. When there are fewer substitutes available for a particular good, consumers have limited alternatives to switch to if the price of that good increases. As a result, the demand for the good becomes less elastic, meaning that the quantity demanded is less responsive to changes in price.

In this scenario, option (a.) is correct. When there are fewer substitutes for a good, consumers have a more limited range of choices, making them less likely to respond strongly to changes in price. On the other hand, if there are many substitutes available, consumers have more flexibility to switch to alternative goods if the price of one particular good increases, resulting in a more elastic demand.

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the complete question is

The fewer the number of substitutes for a good: (a.) the less elastic the demand. b. the more elastic the demand.easenoni vtitnsu c. the more elastic the supply. sesetoeb yliinau d. the less elastic the supply

Given:

The initial height of the ball, h=1.6 m

The initial speed of the ball, u=14 m/s

To find:

a) The time of flight of the ball.

b) The range of the ball.

Explanation:

As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.

Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.

The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.

a)

From the equation of motion,

Where g is the acceleration due to gravity and t is the time of flight of the ball.

On substituting the known values,

b)

The range of the ball is given by,

On substituting the known values,

Final answer:

a) The time of flight of the ball is 0.57 s

b) The range of the ball is 7.98 m

The energy would be obtained if 44 g of carbon were irradiated is  5.8863 x 10^5 J.

Assume each carbon atom emits one photon. For each photon.

E=hc/lambda

Where h = Plank's constant

C = speed of light

E = (6.625×10^-34)×(3×10^8)/(7.45×10^-7)

E = 2.66819x10^-19 J

So the total energy emitted is

E = E1xn

E = (2.66819x10^-19)×(6.022x10^23)/ 1 mol of carbon atom

E = 5.8863 x 10^5 J

Black body radiation is a type of radiation in which a body is in thermodynamic equilibrium, emitted by a black body. It has a specific, continuous spectrum of wavelength. Photons are energy stored in bundles.

In above question,

Wavlength (lambda)=745nm = 7.45x10^-7m.

Mass of carbon = 44 gram

Assume each carbon atom emits one photon. For each photon.

E=hc/lambda

Where h = Plank's constant

C = speed of light

E = (6.625×10^-34)×(3×10^8)/(7.45×10^-7)

E = 2.66819x10^-19 J

So the total energy emitted is

E = E1xn

E = (2.66819x10^-19)×(6.022x10^23)/ 1 mol of carbon atom

E = 5.8863 x 10^5 J

Therefore, The energy would be obtained if 44 g of carbon were irradiated is  5.8863 x 10^5 J.

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Answer:

This leads to backwardness and lagging in the development of the the society. Social problems such as sickness, poverty , social injustices , corruption , nepotism, tribalism are slowing down the process of development .

Answer:

Look below :) Hope this helped. Please provide Brainliest, as reporters took all I had away. Thanks!

Explanation:

Kepler's family was Lutheran and he adhered to the Augsburg Confession a defining document for Lutheranism. However, he did not adhere to the Lutheran position on the real presence and refused to sign the Formula of Concord. Because of his refusal he was excluded from the sacrament in the Lutheran church. This and his refusal to convert to Catholicism left him alienated by both the Lutherans and the Catholics. Thus he had no refuge during the Thirty-Years War.

The Holy Roman Empire of German Nationality at the Time of Kepler

The Holy Roman Empire of German Nationality at the Time of Kepler.

In 1612 Lutherans were forced out of Prague, so Kepler moved on to Linz. His wife and two sons had recently died. He remarried happily, but had many personal and financial troubles. Two infant daughters died and Kepler had to return to Württemburg where he successfully defended his mother against charges of witchcraft. In 1619 he published Harmonices Mundi, in which he describes his "third law."

In spite of more forced relocations, Kepler published the Epitome Astronomiae in 1621. This was his most influential work and discussed all of heliocentric astronomy in a systematic way. He then went on to produce the Rudolphine Tables that Tycho had envisioned long ago. These included calculations using logarithms, which he developed, and provided perpetual tables for calculating planetary positions for any past or future date. Kepler used the tables to predict a pair of transits by Mercury and Venus of the Sun, although he did not live to witness the events.  

Johannes Kepler died in Regensburg in 1630, while on a journey from his home in Sagan to collect a debt. His grave was demolished within two years because of the Thirty Years War. Frail of body, but robust in mind and spirit, Kepler was scrupulously honest to the data.

Short Biography -|- Kepler's Firsts -|- Kepler's Laws -|- People and Events in Kepler's Time -|- Articles

Biographies and books -|- Web Sites -|- IYA Kepler

A List of Kepler's Firsts

First to correctly explain planetary motion, thereby, becoming founder of celestial mechanics and the first "natural laws" in the modern sense; being universal, verifiable, precise.

In his book Astronomia Pars Optica, for which he earned the title of founder of modern optics he was the:

First to investigate the formation of pictures with a pin hole camera;

First to explain the process of vision by refraction within the eye;

First to formulate eyeglass designing for nearsightedness and farsightedness;

First to explain the use of both eyes for depth perception.

Answer:

It often happens in a circuit which was conducting,and a switch is opened. Any inductance in the circuit will help the voltage increase due to back emf,and this can cause breakdown of the air insulation and an arc can form.

Explanation:

The acceleration of the car can be calculated using the formula a = (v_f - v_i) / t, where a is acceleration, v_f is final velocity, v_i is initial velocity, and t is time. Plugging in the values given, we get a = (21 m/s - 14 m/s) / 6.0 s = 1.17 m/s^2.

To calculate the distance traveled by the car, we can use the formula d = v_i*t + 1/2*a*t^2. Plugging in the values, we get d = 14 m/s * 6.0 s + 1/2*1.17 m/s^2 * (6.0 s)^2 = 78.6 m. Therefore, the car traveled a distance of 78.6 meters in this time.

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For a 45 g ice cube can slide up and down a frictionless 30∘ slope. at the bottom, a spring with spring constant 30 n/m is compressed 10 cm and used to launch the ice cube up the slope. The ice cube goes approximately 0.34 meters above its starting point.

To determine how high the ice cube goes above its starting point, we need to consider the conservation of mechanical energy.

Initially, the ice cube has gravitational potential energy and potential energy stored in the compressed spring. At the highest point of its motion, all of the potential energy will be converted into gravitational potential energy.

The gravitational potential energy (PE) is given by the formula:

PE = m * g * h

where m is the mass,

g is the acceleration due to gravity,

and h is the height above the starting point.

Given:

m = 45 g

   = 0.045 kg

g = 9.8 m/s²

To find the height (h), we need to determine the potential energy at the bottom and the potential energy at the highest point.

At the bottom, the potential energy is stored in the compressed spring. The potential energy of a spring is given by:

PE_spring = (1/2) * k * x²

where k is the spring constant and x is the displacement from the equilibrium position.

Given:

k = 30 N/m

x = 10 cm = 0.1 m

PE_spring = (1/2) * (30 N/m) * (0.1 m)²

PE_spring = 0.15 J

At the highest point, all of the potential energy will be converted into gravitational potential energy:

PE_gravity = m * g * h

Since the mechanical energy is conserved:

PE_spring = PE_gravity

0.15 J = (0.045 kg) * (9.8 m/s²) * h

Solving for h:

h = 0.15 J / (0.045 kg * 9.8 m/s²)

h ≈ 0.34 m

Therefore, the ice cube goes approximately 0.34 meters above its starting point.

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To find the rate of change of temperature in the direction from (1, 1) to (2, -4), we need to calculate the gradient of the temperature function T(x, y) and then evaluate it at the starting point (1, 1).
Given:
T(x, y) = x^2 * e^(-(2x^2 + 3y^2))
The gradient of T(x, y) is given by:
∇T(x, y) = (∂T/∂x) * i + (∂T/∂y) * j
Taking the partial derivatives:
∂T/∂x = 2xe^(-(2x^2 + 3y^2)) - 4x^3e^(-(2x^2 + 3y^2))
∂T/∂y = -6xye^(-(2x^2 + 3y^2))
Now we can evaluate the gradient at the point (1, 1):
∇T(1, 1) = (2e^(-5) - 4e^(-5)) * i + (-6e^(-5)) * j
The rate of change of temperature in the direction from (1, 1) to (2, -4) is equal to the dot product of the gradient at (1, 1) and the unit vector pointing from (1, 1) to (2, -4). Let's calculate this:
Magnitude of the direction vector:
||(2, -4) - (1, 1)|| = ||(1, -5)|| = sqrt(1^2 + (-5)^2) = sqrt(1 + 25) = sqrt(26)
Unit vector in the direction from (1, 1) to (2, -4)
u = (1/sqrt(26)) * (2-1, -4-1) = (1/sqrt(26)) * (1, -5) = (1/sqrt(26), -5/sqrt(26))
Dot product of the gradient and the unit vector
∇T(1, 1) · u = [(2e^(-5) - 4e^(-5)) * (1/sqrt(26))] + [(-6e^(-5)) * (-5/sqrt(26))]
Calculating the value:
∇T(1, 1) · u = [(2e^(-5) - 4e^(-5)) / sqrt(26)] + [(6e^(-5)) / sqrt(26

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Answer:

The amount of energy wasted by light bulb 2 = 70 J

Explanation:

Sankey diagrams are used to graphically indicate the proportional flow rate of a quantity

The labelled Sankey diagrams, here, indicate the energy transfers in two light bulbs, light bulb 1 and light bulb 2

From the labelled Sankey diagrams, we have;

For light bulb 1, the input energy = 80 J

The useful energy = 40 J

The wasted energy = 80 - 40 = 40 J

For  light bulb 2, the input energy = 80 J

The useful energy = 10 J

Therefore, the wasted energy = 80 - 10 = 70 J

The amount of energy wasted by light bulb 2 = 70 J.

70 Joules of energy is wasted by light bulb 2 whereas bulb 1 wasted 40 joules of energy.

Bulb 1 uses 40 joules of energy out of 80 joules of energy and 40 joules of energy are wasted out of 80 joules of energy while on the other hand, bulb 2 uses 10 joules of energy as useful energy and 70 joules of energy are wasted out of 80 joules of energy.

According to the image, bulb 2 wasted more energy than bulb 1 so we can conclude that 70 joules of energy is wasted by bulb 2 out of 80 joules of energy.

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Answer:

i don't know but have a good day

The work done is 320 J and the distance covered is 2.5 m.

To calculate the work done in physics, you can use the formula:

Work (W) = Force (F) × Distance (d) × cosθ

However, since the question doesn't provide information about the force or the angle, we'll assume that the force is applied in the direction of motion, which means θ = 0° and cosθ = 1.

Given:

W = 320 J (work done)

d = 2.5 m (distance covered)

θ = 0° (angle between force and displacement)

Using the formula, we have:

320 J = F × 2.5 m × cos0°

Since cos0° = 1, the equation simplifies to:

320 J = F × 2.5 m

To find the force (F), we rearrange the equation:

F = 320 J / 2.5 m

F = 128 N

Therefore, the force applied is 128 N.

It's important to note that this calculation assumes that the force is constant over the entire distance and that there are no other factors influencing the work done.

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Answer:

The answer to this question is given below in this explanation section.

Explanation:

If you place a row of several steel balls on a track and let ball strike it and one end of the row,then the last ball at the other end will fly off,corresponding to the income impulse.All the other balls will remain at rest.This experiment is well known from the newton cradle toy,However you world be you surprise if the last ball in the row shot away like a bullet,even through the first ball.only seemed to have a very moderate velocity.This would not seem consistent with the law of the conservation of energy.

The effect is so surprising that one guesses it might be a trick and you would be right: one or more of the similar looking balls are in fact magnetic.

The first strike approaching from the left hand is from a non magnetic steel ball which will be strongly accelerated through the magnetic balls and thrust with a relatively high velocity on the row of resting balls.

Answer:true

Explanation:

red light is better able to pass completely through Earth's atmosphere and reach the moon

The working with electric charges, the symbol used in an equation to represent the electric field of an object is E. Thus, the correct option is B.

An electric field is defined as the physical field that surrounds the charges or electrically charged particles. The electric field is exerted the force on all the other charged particles and the force is either an attractive or repulsive force.

The electric field around the charges is denoted by the lines called electric field lines. The field lines are radially outwards if the charge is positive and the field lines are radially inwards if the charge is negative. For two charges, the field lines are starts from the positive charge and end with the negative charge.

The electric field equals force per unit test charge. The force is Coulomb's law between two charges. The electric field is also obtained as electric potential per unit displacement.

The electric field is denoted by the letter, E. E = F / q or -V/r, the negative sign indicates that the electric field moves opposite to the potential gradient. The unit of the electric field is Newton per coulomb or volt per meter.

Thus, the correct option is option B.

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Answer:

The initial velocity of the pitch is approximately 36.5 m/s

Explanation:

The given parameters of the thrown fastball are;

The height at which the pitcher throws the fastball, h₁ = 2.65 m

The angle direction in which the ball is thrown, θ = 2.5° below the horizontal

The height above the ground the catcher catches the ball, h₂ = 1.02 m

The distance between the pitcher's mound and the home plate = 18.5 m

Let 'u' represent the initial velocity of the pitch

From h = \(u_y\)·t + 1/2·g·t², we have;

\(u_y\) = The vertical velocity = u·sin(θ) = u·sin(2.5°)

h = 2.65 m - 1.02 m = 1.63 m

uₓ·t = u·cos(θ) = u·cos(2.5°) × t = 18.5 m

∴ t = 18.5 m/(u·cos(2.5°))

∴ h = \(u_y\)·t + 1/2·g·t² =  (u·sin(2.5°))×(18.5/(u·cos(2.5°))) + 1/2·g·t²

1.63 = 8.5·tan(2.5°) + 1/2 × 9.8 × t²

t² = (1.63 - 8.5·tan(2.5°))/(1/2 × 9.8) = 0.25691469087

t = √(0.25691469087) ≈ 0.50686752763

t ≈ 0.50686752763 seconds

u = 18.5 m/(t·cos(2.5°)) = 18.5 m/(0.50686752763 s × cos(2.5°)) = 36.5334603 m/s ≈ 36.5 m/s

The initial velocity of the pitch = u ≈ 36.5 m/s.

Answer:

.....

Explanation:

3rd and 6th row in second table do not agrees with the equation ( Force = mass * acceleration ) , rest follows the equation

There is a relation between force , mass and acceleration of the body , in a such a way that it agrees with newton's third law which is  Force = mass * acceleration

All the given data in the table follows this relation except where

mass = 150 kg

a = 0.67 \(m/s^{2}\)

F (given ) = 100 N

calculated force = ma = 150 * 0.67 =  100.5 N

mass = 300 kg

force (given) = 100 N

a = 0.33 \(m/s^{2}\)

calculated force = ma = 300 * 0.33 = 99 N

rest of the data completely follow the equation F = ma

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Answer:

☆<《HOPE IT WILL HELP YOU 》>☆

Explanation:

The probability of getting 4 is 1

Answer:

1/6

Explanation:

There are 6 faces, and one of them is 4. Therefore the answer is 1/6.

Answer:

La presión que los patinadores ejercen sobre el hielo es 7,848,000 Pa

Explanation:

Los parámetros dados de los patinadores en la pala son;

La longitud de la hoja en el patín, l = 30 cm = 0.03 m

El espesor de la hoja, t = 5 mm = 0,005 m

El peso de las dos personas, m = 120 kg

Suponiendo que la sección transversal de la cuchilla sobre el hielo es rectangular, tenemos;

A = l × t

∴ A = 0,03 m × 0,005 m = 0,00015 m²

La fuerza de peso de los dos patinadores, W = m × g

Dónde;

g = La aceleración debida a la gravedad ≈ 9,81 m / s²

m = La masa de los dos patinadores = 120 kg

∴ W = 120 kg × 9,81 m / s² = 1,177,2 N

Presión, P = Fuerza, F/(Área, A)

∴ P = (1.177,2 N) / (0.00015 m²)= 7,848,000 Pascals

La presión que los patinadores ejercen sobre el hielo., P = 7,848,000 Pascals

Answer:

C

Explanation:

So, lets start off by thinking about what we know is in both cells, and rule out from there.

There are just some basic things you need in eukaryotic cells, those include the following:

Here are jsut a few examples of what can be found in both plant and animal cells, however we can already rule out all of the following except for:

C

Because remember, c talks about the chlorplast, which is not the chlorplasm found in both plant anf animal cells, its just the chloroplast found in plant cells.

Although I gave the asnwer to you. Here are some things that are in plant cells that arent in animal cells:

Animal cells on the other hand, have a few things that plant cells do not as well:

Hope this helps! ;)

The final speed of the ball when it accelerate uniformly at a rate of 3.52 m/s² for 23.3 m is 12.81 m/s.

Speed can be defined as the ratio of distance to time.

The S.I unit of speed is m/s.

To calculate the final speed of the ball, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the final speed of the ball is 12.81 m/s.

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