6. Figure 6 shows the top view of a child of mass m with initial
speed v0 and stepping onto end B of the plank. The plank has length
L and mass M that is perpendicular to the child’s path as shown.

Answers

Answer 1

A plank of mass M and length L is situated parallel to the ground. It is set up to pivot about one end A and is supported by a rope from the other end B. A child of mass m and initial speed v0 is shown in Figure 6, stepping onto the plank at point B. After a short time, the child and the plank come to rest relative to the ground.


As we can observe from that a child of mass m with initial speed v0 stepping onto end B of the plank. The plank has length L and mass M that is perpendicular to the child’s path as shown. It is set up to pivot about one end A and is supported by a rope from the other end B. After a short time, the child and the plank come to rest relative to the ground. To solve this problem, we have to apply the law of conservation of momentum for the system and law of conservation of energy.

The velocity of the child can be calculated by law of conservation of momentum for the system of child and plank before and after the collision. Let the velocity of child and plank after collision be v1. So, according to law of conservation of momentum:Total momentum before collision = Total momentum after collisionmv0 = (M + m) v1....(1)The velocity of child and plank relative to the ground can be calculated by law of conservation of energy.

Total energy before collision = Total energy after collision

The initial kinetic energy of the child is mv0²/2As the plank is at rest, its initial kinetic energy is zero.The final potential energy of the system is (M+m)gL

The final kinetic energy of the system is (M+m)v1²/2Thus, we can write,mv0²/2 = (M+m)gL + (M+m)v1²/2....(2)From equation (1), v1 = mv0/(M+m)

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Related Questions

a force of 5 kg compresses the springs in series 10cm. what will be the total distance that the springs in parallel are compressed?

Answers

The total distance that the springs in parallel are compressed is 5 cm.

Given information,

mass, m = 5kg,

The total distance that springs compressed, x = 10 cm

where x = x₁ + x₂,

the force exerted by the spring is given as

F = -k.x

The force exerted  by spring at series is,

Fs = - Ks(x₁ + x₂)

and,

F₁ = -K₁x₁

F₂ = -K₂x₂

Fs = F₁ = F₂,

equating values,

- Ks(x₁ + x₂) = -K₁x₁

since, x₁ = x₂ and K₁ = K₂,

Ks = K₁/2

Ks = 0.5K₁

Fs = - 0.5×K(x₁ + x₂)

The force exerted  by spring at parallel is,

Fp = F₁ +  F₂

Fp = -K₁x₁ + (-K₂x₂)

Fp  = -2K₁x₁

Equating,

Fs = Fp

- 0.5×K₁×10 = -2K₁x₁

x₁ = 2.5 cm

The total distance is,

2.5 + 2.5 = 5 cm

Hence, The springs in parallel are compressed by a total distance of 5 cm.

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A doctor is using a treadmill to assess the
strength of a patient's heart. He sets the
1,75 m long treadmill to an incline of 17 degrees.
How high is the end of the treadmill raised?
a 0.71 m
0.46 m
0.54 m
0.62 m

Answers

The answer is 0.47 m, which is closest to the option (A) 0.71 m.

How to solve this problem

First we can use trigonometry. The height of the end of the treadmill raised is the opposite side of the right triangle, and the length of the treadmill is the hypotenuse.

The angle of inclination is the angle between the height and the hypotenuse, so we can use the sine function to find the height:

sin(17°) = opposite/hypotenuse

The length of the treadmill is 1.75 m, so:

opposite = sin(17°) x 1.75 m

opposite = 0.472 m

Therefore, the height of the end of the treadmill raised is approximately 0.47 m.

So the answer is 0.47 m, which is closest to the option (a) 0.71 m.

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HELPP
Viewed from Earth, it seems as if the Sun moves across the sky each day. This is because:
A. the sun isn't moving; observations made from Earth are rotating with the Earth
B. the Earth goes around the Sun over the course of a year
C. the Sun revolves around the Earth
D. the Earth isn't moving

Answers

Either A or B. I think maybe A

I need help with this ASAP.. I have to get it done right now
. It is pass due

I need help with this ASAP.. I have to get it done right now. It is pass due

Answers

The map of the world temperature zones gives;

23. Zone A = The North Frigid zone

Zone B = The North Temperate zone

Zone C = The Torrid

Zone D = The South Temperate zone

Zone E = The South Frigid zone

24. Zone C, the Torrid zone

25. Zone C, the Torrid zone

26. The Torrid zone

What are the temperature zones?

23. The five temperature zones of the world based on the annual temperatures are;

The north frigid zone

The north temperate zone

The torrid zone (tropics)

The south temperate zone

The south frigid zone

Each of the five zones shown on the map are;

Zone A = The North Frigid zone

Zone B = The North Temperate zone

Zone C = The Torrid zone Tropics

Zone D = The South Temperate zone

Zone E = The South Frigid zone

24. The name of the temperature zone that includes the equator is; Zone C, the Torrid zone (The tropics).

The Equator is located around the horizontal line that runs around the center of the Earth at 0 ° latitude.

25. The zone that has the greatest amount of human habitable land mass is; Zone C, the Torrid zone, which covers 40% of the geographic surface of the Earth.

26. The zone that has the highest temperature all year round is the zone farthest from the north and south Frigid zone which is the Torrid zone

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Answer:

the answer is A.

Explanation:

A linebacker strikes a fullback with full force in a football game.The reaction force to the force of the linebacker striking the fullback is ____.
a. the fullback falls backwards to the ground
b. the force of the fullback colliding with the ground
c. the fullback fumbles
d. the fullback applies a force to the linebacker
e. the linebacker applies a force to himself.
f. the fullback applies a force to himself
g. the sound of the pads colliding
h. there is a 3-yard loss and the linebacker is applauded

Answers

a. the back falls backwards to the ground

how much force is needed to accelerate a 75 kg trick rider and his 225 kg pink flaming motorcycle to 5 m/s^2?

Answers

The force needed to accelerate the trick rider and the pink flaming motorcycle is 1500 N.

What is force?

Force is the product of mass and acceleration.

To calculate the force needed to accelerate the trick rider and the pink flaming motorcycle, we use the formula below

Formula:

F = a(m+M)................................. Equation 1

Where:

F = Forcea = Accelerationm = Mass of the trick riderM = Mass of the pink flaming motorcycle

From the question,

Given:

m = 75 kgM = 225 kga = 5 m/s²

Substitute these values into equation 1

F = 5(75+225)F = 5×300F = 1500 N

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The output of a solar panel powers a small pump. The pump operates a garden water fountain. The output of the solar panel is 10 V and the current supplied to the pump is 0.25 A. Calculate the electrical power generated by the solar panel.

The output of a solar panel powers a small pump. The pump operates a garden water fountain. The output

Answers

That’s tuff ima get in give me a min

The power generated by solar panel will be "2.7 W".

According to the question,

The values are:

Output of solar panel,

10 V

Current,

0.25 A

The electrical power generated will be:

→ \(P = VI\)

By substituting the given values is the above formula, we get

→     \(= 10\times 0.27\)

→     \(=2.7 \ W\)

Thus the above answer is right.

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I am having a bit of difficulty with this lab question:
_________________________________________
The passage of an occluded front may be accompanied by widespread precipitation and little temperature change at ground level. This is because occluded fronts are a combination of (1). [one / two / three] cold/cool air mass(es), which shifts a (2). [cold / warm / hot] air mass (3). [aloft / sideways / downwards].
_________________________________________
Currently, I have my answers as follows:
1. two cool/cold air masses
2. warm
3. downwards
Could someone help me out and let me know if I am correct? Thanks!

Answers

This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

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I have a project of how a steam engine works
pls tell me what i should research on or give ideas

Answers

In the metal junction box, insert the dowel rod and skewer so that the skewer is pointing up within the copper pipe.

How is the steam engine operated?

A steam engine is a heat engine that uses steam as its working fluid to carry out mechanical work. The steam engine moves a piston back and forth inside a cylinder using the force created by the pressure of the steam. A connecting rod and crank can convert this pushing force into a rotational force for work.

How are steam engines employed in modern times?

Technological devices have changed how people live. Nowadays, steam is used to propel ships and turn massive turbines that produce electricity for billions of people worldwide.

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a vertical spring of spring constant 115 n/m supports a mass of 75 g. the mass oscillates in a tube of liquid. if the mass is initially given an amplitude of 5.0 cm, the mass is observed to have an amplitude of 2.0 cm after 3.5 s. by neglecting the buoyant force, estimate the damping constant b.

Answers

By neglecting the buoyant force and using the given information, we estimate the damping constant (b) for this mass-spring system to be approximately 0.066 kg/s.

To estimate the damping constant (b) for a mass-spring system, we can use the following steps:

1. Calculate the angular frequency (ω) of the system using the spring constant (k) and mass (m):
ω = sqrt(k/m)

2. Determine the decay constant (α) using the initial amplitude (A0) and final amplitude (A) after time (t):
α = (1/t) * ln(A0/A)

3. Calculate the damping constant (b) using the angular frequency (ω) and decay constant (α):
b = 2 * m * α

Let's apply these steps to your problem:

1. Convert mass to kg: m = 75 g = 0.075 kg
ω = sqrt(115 N/m / 0.075 kg) ≈ 39.1 rad/s

2. Calculate decay constant (α):
α = (1/3.5 s) * ln(5.0 cm / 2.0 cm) ≈ 0.44 s^(-1)

3. Estimate the damping constant (b):
b = 2 * 0.075 kg * 0.44 s^(-1) ≈ 0.066 kg/s

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An engineer is troubleshooting trying to figure out the value of a capacitor. She knows that the charge value is 480 coulombs and the power supply feeds 110 V. What's the capacitor value?Question 19 options:A) 128B) 4.36C) 0.88D) 5,400

Answers

We can use the formula of the capacitance

\(C=\frac{Q}{V}\)

where C is the capacitance, Q is the charge and V is the voltage.

In our case

Q=480 C

V= 110 V

\(C=\frac{480}{110}=4.36\text{ F}\)

The value of the capacitor is 4.36 F

ANSWER B) 4.36F

acceleration is a derived unit ​

Answers

Acceleration is a derived unit because it is derived from two quantities : Velocity and time.

We know, acceleration = Change in velocity/Time

With friction turned on, let the skater do one back-and-forth on the half pipe. Use
the grid. Does he reach the same height as when he started?

Answers

The skater does indeed reach the same height on either side of the track With friction turned on.

The only thing that will change is how long it takes for the skater to come to a rest during the scenario. Only the skater's initial height when placed onto the track affects the overall energy, which remains constant.Potential energy is transformed into kinetic energy as the skateboarder descends the ramp. Some of the system's energy is changed into heat energy by friction. The energy cannot be returned to the system's potential or kinetic energy once the kinetic energy has been transformed into heat.

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If mass of an empty 7.0 mL pycnometer is 10.2g and the mass of the same pycnometer with an unknown liquid is 21.8g. Determine the density of the unknown liquid to ONE DECIMAL PLACE in g/mL.

Answers

The formula for calculating density is expressed as

Density = mass/volume

From the information given,

mass of empty pycnometer = 10.2

mass of the same pycnometer with an unknown liquid is 21.8.

Mass of unkown liquid = 21.8 - 10.2 = 11.6

volume of unknown liquid = 7

Thus,

Density = 11.6/7

Density = 1.7 g/ml

F 2000. kg of ice cover your driveway, how many kilojoules of heat would be required to melt it? the heat of fusion of water is 334 j/g .

Answers

Answer:

668 000 kJ

Explanation:

2000 kg = 2000 000 gm

2000000 gm * 334 J/g  = 668 000 000 J   = 668 000 kJ

As the
also increase.
_applied to a circuit increases, the power and the current

Answers

As the voltage applied to a crcuit increases, the power dissipated by the circuit, and the current flowing through the circuit, both also increase.

Answer:

voltage

Explanation:

state newtons second law

Answers

Answer:

A force applied to an object is equal to its mass times acceleration (F=ma)

Explanation:

Answer: The force can be calculated by simply multiplying mass by acceleration

Explanation:

This created the equation F=MA

What determines gravitational pull

What determines gravitational pull

Answers

Answer

Remember that the net force on you determines how your motion changes.  The strength of the gravitational force between two objects depends on two factors, mass and distance. The Mass of the Objects The more mass two objects have, the greater. the force of gravity the masses exert on each other.

Explanation:

try to look it up on google

I know. I know everything

The closest Venus comes to Earth is 0.28 AU. The closest Mars comes to Earth is 0.37 AU. In
kilometers, how much closer does Venus come to Earth than Mars does?

Answers

One astronomical unit (AU) is defined as the average distance between the Earth and the Sun, which is approximately 149.6 million kilometers. Therefore, to convert AU to kilometers, we can multiply the distance by 149.6 million.

The closest Venus comes to Earth is 0.28 AU, which is equal to 0.28 x 149.6 million = 41.888 million kilometers.

The closest Mars comes to Earth is 0.37 AU, which is equal to 0.37 x 149.6 million = 55.352 million kilometers.

Therefore, Venus comes about 13.464 million kilometers closer to Earth than Mars does.

Vector A has a magnitude of 63 units and points west, while vector B has the same magnitude and points due south. Find the magnitude and direction of a) A + B and b) A - B. Specify the directions relative due west.​

Answers

Given :

Vector A has a magnitude of 63 units and points west, while vector B has the same magnitude and points due south.

To Find :

The magnitude and direction of

a) A + B .

b) A - B.

Solution :

Let , direction in north is given by +j and east is given by +i .

So , \(A=-63i\) and \(B=63j\)

Now , A + B is given by :

\(A+B=-63i+63j\)

\(| A+B | = 63\sqrt{2}\)

Direction of A+B is 45° north of west .

Also , for A-B :

\(A-B=-63i-63j\)

\(|A-B|=63\sqrt{2}\)

Direction of A-B is 45° south of west .

( When two vector of same magnitude which are perpendicular to each other are added or subtracted the resultant is always 45° from each of them)

Hence , this is the required solution .

Which of the following statements about density is true.

Answers

there is nothing there

Va A rail wagon of mass
5000 kg moving at a velocity
of 1.6 ms-1 collides with a
stationary wagon of mass
3000 kg (see Figure 4). After
the collision, the 3000 kg wagon
moves away at a velocity of
1.5 ms-1. Calculate the speed
and direction of the 5000 kg
wagon after the collision.

Answers

Answer:

0.7m/s

Explanation:

According to the conservation of linear momentum, the moment before a collision is equal to the moment after the collision. The equation is written as follows: \(m_{a}u_{a} + m_{b}u_{b} = m_{a}v_{a} + m_{b}v_{b}\), where \(m\) is the mass of the object, \(u\) is the initial velocity, and \(v\) is the final velocity.

Let's say the object \(a\) is our moving wagon and the object \(b\) is our stationary wagon. \(m_{a} = 500kg, u_{a} = 1.6ms^{-1}\),  \(m_{b} = 3000kg, u_{b} = 0\), since the wagon is stationary, it doesn't have any initial velocity. After collision, the mass remains the same, but the velocity changes: \(v_{a} = ?, v_{b} = 1.5ms^{-1}\)

We can observe that \(v_{a}\) is what we're looking for according to the question. Now let's substitute our values.

\((5000 * 1.6) + (0) = 5000v_{a} + (3000 * 1.5)\)

\(v_{a} = \frac{(5000 * 1.6) - (3000*1.5)}{5000}\) = 0.7m/s

"Why do we refer to light as a wave?" Give at least THREE evidence statements that
indicate light is a wave.
Pls help

Answers

Waves transfer energy from one place to another. Light does transfer energy.

Waves can be reflected. Light can be reflected.

Waves can show diffraction and interference. Light shows diffraction and interference.

Wanda is taking photos using a lens that sees and records a very narrow view with a focal length longer than 60mm. When her friend asks what type of lens she is using for their photography outing, how does Wanda reply

Answers

Wanda can reply to her friend by saying that she is using a telephoto lens for their photography outing.

A telephoto lens is a type of camera lens that is designed to capture distant subjects by using a longer focal length than a standard lens. Telephoto lenses typically have a focal length of 60mm or longer, which allows them to see and record a very narrow view. This makes them ideal for capturing subjects that are far away, such as wildlife, sports events, and landscapes. Telephoto lenses are also popular for portrait photography because they can create a shallow depth of field, which helps to isolate the subject from the background.

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an nmos transistor having vt = 1v is operated in the triode region with vds small. with vgs = 1.5v, it is found to have a resistance rds of 1kω. what value of vgs is required to obtain rds = 200ω?

Answers

The value of Vgs required to obtain Rds = 200Ω in an NMOS transistor operated in the triode region with small Vds is approximately 0.9V.

To calculate the required Vgs, we can use the equation that relates Rds to the transistor parameters. In this case, we assume the electron mobility (μn), oxide capacitance per unit area (Cox), and the width-to-length ratio (W/L) of the transistor to be constant.

By rearranging the equation and substituting the given values, we find that Vgs - Vt is inversely proportional to Rds. Since we know the initial value of Vgs (1.5V) and Rds (1kΩ), we can calculate the new value of Vgs using the proportionality.

By solving the equation, we find that Vgs ≈ 0.9V is required to achieve Rds = 200Ω in the given NMOS transistor.

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The magnetic field produced by the solenoid in a magnetic resonance imaging (MRI) system designed for measurements on whole human bodies has a field strength of 9.0 T, and the current in the solenoid is 2.5 102 A. What is the number of turns per meter of length of the solenoid

Answers

To find the number of turns per meter of length of the solenoid, we can use the formula for the magnetic field inside a solenoid

Formula of magnetic field inside a solenoid B = μ₀ * n * I

where B is the magnetic field strength, μ₀ is the permeability of free space (4π × 10^-7 T·m/A), n is the number of turns per unit length, and I is the current.

Rearranging the formula, we have:

n = B / (μ₀ * I)

Plugging in the given values, we get:

n = 9.0 T / (4π × 10^-7 T·m/A * 2.5 × 10^2 A)

n = 9.0 T / (1.26 × 10^-4 T·m/A)

n ≈ 7.14 × 10^4 turns/m

Therefore, the number of turns per meter of length of the solenoid is approximately 7.14 × 10^4 turns/m.

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Three blocks of masses 1.7, 2.43, and 3.04 kilograms are connected by massless strings, one of which passes over a frictionless pulley of negligible mass. while the 1.7 and 2.43 masses are attached to one side of the string, the mass 3.04 is on the other side. calculate the acceleration of the 3.04 kg block

Answers

The acceleration of the 3.04 kg block is approximately 1.825 m/s².

To calculate the acceleration of the 3.04 kg block, we need to apply Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

Given:

Mass of the 3.04 kg block (m3) = 3.04 kg

Mass of the 1.7 kg block (m1) = 1.7 kg

Mass of the 2.43 kg block (m2) = 2.43 kg

Let's assume that the 1.7 kg block is hanging vertically and the 2.43 kg block is on the other side connected to the 3.04 kg block.

The net force acting on the system is the difference between the weight of the 3.04 kg block and the weight of the 1.7 kg block. The weight of an object is given by the formula: weight = mass × gravitational acceleration (g).

Net force = (m3 × g) - (m1 × g)

Net force = (3.04 kg × 9.8 m/s²) - (1.7 kg × 9.8 m/s²)

Net force = 29.792 N - 16.686 N

Net force = 13.106 N

Now, we can calculate the acceleration using the formula: acceleration = net force / total mass.

Total mass = m1 + m2 + m3 = 1.7 kg + 2.43 kg + 3.04 kg = 7.17 kg

Acceleration = 13.106 N / 7.17 kg

Acceleration ≈ 1.825 m/s²

Therefore, the acceleration of the 3.04 kg block is approximately 1.825 m/s².

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When is it safer to drive a heavier car over a lighter car?

a. When you crash into a wall
b. When you crash into a tree
c. When you crash into another car
d. It is never safe in a hevaier car

Answers

Answer:

I think it would be c, crashing into another car

D I believe it’s the awnswer

how do we use sounds in ways other than just listening?

Answers

Answer:

talking and we can make our own sound

Explanation:

How do we use sounds in ways other than just listening?

Sound could be an element for detecting people or entities, This is very useful for blind people. Sounds could also heal your chakra or make you feel like dancing.

Hope I helped. :)

- Valenteer

A student walks to school at a speed of 2.0 m/s. If the students mass is 50 kg, what is the kinetic energy from the students forward movement?

Answers

Answer:

100 J

Explanation:

\(kinetic \: energy \: = \frac{1}{2} \times 50 \times {2}^{2} \)

= 100 joules

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