Both times, the monomers go through a process called polymerization in which the double bonds separate and create new single bonds, resulting in the formation of lengthy chains known as polymers.
5) Saran Wrap is made from a polymer called polyvinylidene chloride (PVDC). The alkene monomer used to make PVDC is vinylidene chloride, which has the chemical formula \(CH_2=CCl_2\). It has a double bond between the two carbon atoms (C=C) and two chlorine atoms attached to one of the carbons.
6) Synthetic rubber is made from various polymers, but one common type is styrene-butadiene rubber (SBR). The monomers used to make SBR are styrene and butadiene. Styrene has the chemical formula \(C_6H_5CH=CH_2\), with a benzene ring connected to a vinyl group. Butadiene has the chemical formula\(CH_2=CH-CH=CH_2\), which has two double bonds in a four-carbon chain.
In both cases, the monomers undergo polymerization, where the double bonds break and form new single bonds, creating long chains called polymers. These polymers form the basis of the respective products (Saran Wrap and synthetic rubber).
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Explain how the size and shapes of the continents and oceans on earth have changed over million of year?
Helppppp……
A given reaction has an activation energy of 24.52 kJ/mol. At 25°C, the half-life is 4 minutes. At what temperature will the half-life be reduced to 20 seconds? Group of answer choices 150°C 115°C 100°C 125°C
The correct answer to the given question is 125°C.
We can use the Arrhenius equation to solve this problem:
k = A * e^(-Ea/RT)
where:
k is the rate constant
A is the pre-exponential factor
Ea is the activation energy
R is the gas constant (8.314 J/mol*K)
T is the temperature in Kelvin
Since we are looking for the temperature at which the half-life is reduced to 20 seconds, we can use the following relationship:
t1/2 = ln(2) / k
where t1/2 is the half-life.
We can combine these equations to eliminate the rate constant:
ln(2) / k1 = Ea / R * (1/T1 - 1/T2)
where T1 is the initial temperature (25°C = 298 K), T2 is the final temperature (unknown), and k1 is the rate constant at T1.
We can solve for T2:
T2 = Ea / R * (1/k1 * ln(2) + 1/T1)
First, we need to find k1. We know that the half-life at T1 is 4 minutes, or 240 seconds. So:
ln(2) / k1 = 240
k1 = ln(2) / 240 = 0.00289 s^-1
Now we can plug in the values:
T2 = (24.52 * 10^3 J/mol) / (8.314 J/mol*K) * (1/0.00289 s^-1 * ln(2) + 1/298 K)
T2 = 393 K = 120°C
Therefore, the temperature at which the half-life is reduced to 20 seconds is approximately 120°C. The closest option given is 125°C.
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Plants such as the venus flytrap produce chemical compounds that break down insects into substances that are usable by the plant. The enzymes, that break down the insects are most likely what kind of molecule?.
The enzymes, that break down the insects are most likely what kind of biological catalyst.
Biological catalysts are called enzymes. There is, for instance, an enzyme in our saliva which converts starch to a simple sugar, which is used by the cell to produce energy, and another enzyme which degrades the excess lactic acid produced when we overexert ourselves. Enzymes are proteins that catalyze a chemical reaction in our body. They function as a catalyst that speeds up the reaction by lowering the activation energy.
The enzyme accelerates a chemical reaction without changing its equilibrium, so it is called as a biocatalyst.
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In the reaction how many moles of ammonia will be produced from 1.30 mol of hydrogen and excess nitrogen?
In the reaction 0.867 moles of ammonia will be produced from 1.30 mol of hydrogen and excess nitrogen, because,
Hydrogen gas is oxidized by hydrogenase and electrons are carried to the anode. In the other, electrons come off the cathode and are combined with nitrogen, via nitrogenase, to create ammonia.
3H2(g) + N2(g) ⇄ 2NH3(g)
Assuming N2 is in excess, multiply the given moles H2 by the mole ratio between H2 and NH3 in the balanced equation so that moles H2 cancel, leaving moles NH3.
1.30 mol H2 × (2 mol NH3/3 mol H2) = 0.867 mol NH3.
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Nitrogen (N) has one more proton than Carbon (C) where did the proton come from in this reaction?
What type of reaction is depicted in the equation above?
Answer:
I'm sorry, but I don't see an equation in your question to provide a specific answer. However, I can answer your general question.
Nitrogen has one more proton than Carbon because it has one more positively charged particle (proton) in its nucleus. This difference in the number of protons determines the atomic number and identity of the element.
Protons can only come from the nucleus of another atom, through a nuclear reaction. In nature, nitrogen is usually created by nuclear fusion in stars, where lighter elements combine under high pressure and temperature to form heavier elements.
Regarding the second part of your question, without the specific equation you are referring to, I cannot determine the type of reaction depicted. There are many types of chemical reactions, including synthesis, decomposition, combustion, acid-base, and redox reactions, among others.
What clues indicate that a chemical reaction has occurred?
Choose all correct answers.
the formation of a new liquid
a color change
a temperature change
the formation of bubbles
Answer:
its probably all of the above, if not then it should be the formation of a new liquid, and a color change
Explanation:
What mass (g) of NaN3 is required to provide 40.0 L of N2 at 25.0°C and 763 torr?
The needed mass of NaN3 is 71.175 grammes.
How much NaN3 must be produced in grammes?As seen above, for every 2 moles of sodium azide that break down, 3 moles of nitrogen gas are created. This mole ratio will be helpful in figuring out how much NaN3 N a N 3 is required to make 10.0 cubic feet of N2 gas. Hence, to generate 10.0 cubic feet of N2 gas, 547 grammes of NaN3 are required.
What gas makes up the majority of an air bag that has been inflated by the NaN3 reaction?The sodium azide, or NaN3, chemical would hold the key to the solution. Nitrogen gas, which may instantly inflate an airbag, is released when this chemical is ignited by a spark.
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consider 4-methylcyclohexanone. would you expect the ring of the compound to be more or less likely to ring flip compared to 4-tert-butylcyclohexanone?
The ring of 4-methylcyclohexanone is more likely to ring flip compared to 4-tert-butylcyclohexanone due to the smaller size of the methyl group.
In cyclohexane, chair conformations can interconvert by a ring flip. In the axial position of a cyclohexane ring, bulkier substituents experience more steric strain than in the equatorial position. Therefore, the stability of a cyclohexane ring is dependent on the position of the substituents.
In 4-tert-butylcyclohexanone, the bulky tert-butyl group is located at the axial position of the cyclohexane ring, resulting in a destabilized conformation. In contrast, in 4-methylcyclohexanone, the smaller methyl group is located at the axial position, which results in a lower degree of destabilization.
Therefore, due to the smaller size of the methyl group in 4-methylcyclohexanone, the ring is more likely to flip compared to 4-tert-butylcyclohexanone, which has a more hindered axial position due to the larger tert-butyl group.
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when intumescent coatings are exposed to heat, what reaction makes them an effective insulating material to protect steel
Intumescent coatings are designed to provide fire protection for steel structures by forming a protective insulating layer when exposed to heat.
The effectiveness of intumescent coatings as an insulating material is primarily due to a combination of chemical reactions that occur during exposure to high temperatures. When intumescent coatings are subjected to heat, they undergo a complex reaction process involving different components within the coating.
The reaction process can be summarized as follows:
Dehydration: As the temperature rises, the coating starts to evaporate, losing water or other volatile substances.
Acid decomposition: When heated, the coating's acid source breaks down, producing gases that are acidic. In the presence of heat, these acid gases combine with the carbon source to create a carbonaceous char.
Carbonization and foaming: When acid gases combine with a carbon source to form carbonaceous char, the char expands and foams, forming a structure resembling froth.
Insulation: During the foaming process, a thermally insulating layer is created that serves as a barrier between the heat source and the steel structure it is protecting.
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what is an atom plz answer to get 10 points +brainliest
If the mass is 3.8g and the volume is 3 ml/cm. What is the DENSITY?
Answer:
1.26666.....
Explanation:
Density is = to mass/volume
Answer: 19/15 in decimal form 1.267
Explanation:
when solving for density you divide mass by volume, when solving vor volume divide density and mass, finding mass multiply density and volume
Valence electrons are important to...
A- calculating mass
B-bonding
Answer:
I think it would be Bonding
Explanation:
Valence electrons indicate an element's bonding behavior, stability, and reactivity.
12. Interpret Data The table below shows the value of the equilibrium constant for a reaction at three different temperatures. At which temperature is the concentration of the products the greatest? Explain your answer.
We know that temperature at which there would be the highest concentration of the products is 373 K
Relationship between Keq and temperature?
Temperature variations can affect the reaction's equilibrium position and, as a result, change the equilibrium constant (Keq) value. Whether a reaction is exothermic or endothermic affects the precise outcome.
We know that the higher the Keq would mean that the products would be more and this is going to happen when the Keq is 373 K as we can see from the table that has been shown in the question here displayed.
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What volume will a gas occupy at 325 K if it occupies 5.8 L at 376 K? Assume the moles and pressure of gas are held constant
A) 2.89 L
B) 3.76 L
C) 5.01 L
D) 6.73 L
Answer:
5.01 L
Explanation:
my guy i just took the test, it was this one
Question 2 of 11 What will happen to the particles of a substance that is cooled to OK? A. They will stop moving. B. They will speed up. C. They will form a liquid. D. They will gain thermal energy.
plsssss help fast plss
Provide the coefficients needed to balance the redox reaction given. Fe(s) + Cl2(g) -> Fe3+(aq) + Cl-(aq)
The coefficients needed to balance the redox reaction are: 2Fe(s) + 3Cl2(g) + 6H+(aq) -> 2Fe3+(aq) + 6Cl-(aq) + 3H2O(l)
The balanced redox reaction requires two molecules of chlorine gas to react with one atom of iron, producing one Fe3+ ion and two chloride ions. We need to balance both the mass and charge on each side of the equation.
Step 1: Balance the atoms other than oxygen and hydrogen.
Fe(s) + Cl2(g) -> Fe3+(aq) + 2Cl-(aq)
Step 2: Balance the oxygen atoms by adding water (H2O) molecules.
Fe(s) + Cl2(g) -> Fe3+(aq) + 2Cl-(aq) + H2O(l)
Step 3: Balance the hydrogen atoms by adding hydrogen ions (H+).
Fe(s) + Cl2(g) + 6H+(aq) -> Fe3+(aq) + 2Cl-(aq) + H2O(l)
Step 4: Balance the charges by adding electrons (e-).
Fe(s) + Cl2(g) + 6H+(aq) -> Fe3+(aq) + 2Cl-(aq) + H2O(l) + 6e-
The balanced equation for the redox reaction is:
2Fe(s) + 3Cl2(g) + 6H+(aq) -> 2Fe3+(aq) + 6Cl-(aq) + 3H2O(l)
The balanced redox reaction is 2 Fe(s) + 3 Cl2(g) -> 2 Fe3+(aq) + 6 Cl-(aq) with coefficients 2, 3, 2, and 6 respectively.
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calculate the mass of 0.8 moles of Fe(NO3)3 (H2O)9
Answer:
Molar mass of (Fe(NO3)3)(H2O)9 is 403.9972 g/mole
Explanation:
the formula to find the mass of moles
Worked Example: molar mass = mass ÷ moles (M=m/n) Calculate the molar mass of a pure substance if 1.75 moles of the substance has a mass of 29.79 g.
i think it help you
Explain why the bohr model cannot predict spectra for multielectron atoms.
The Bohr model cannot predict spectra for multi electron atoms because Bohr model does not consider forces due to interelectronic attraction between electrons .
The primary problem with Bohr's model is that it performs admirably for atoms with just one electron, such as H or \(He ^{+}\), but appallingly poorly for atoms with multiple electrons.
We can predict the energies of each line in the hydrogen atom emission spectrum . The Bohr's model estimate the energy difference between each energy level. These atoms are all made up of two electrons in an outer s-shell in addition to an electron core.
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Select the statement that is TRUE about inorganic salts. A). All salts are neutral in pH. B). Flame test is a quantitative analysis method. C). All inorganic salts are strong electrolytes. D). Some ionic compounds are insoluble in aqueous solution. F). Flame test alone can determine the identify of the unknown salt.
The correct answer is D). Some ionic compounds are insoluble in aqueous solution.
Inorganic salts are compounds composed of ions held together by ionic bonds. They can be soluble or insoluble in aqueous (water) solution depending on the specific ions present and their solubility properties.
a. All salts are neutral in pH: This statement is not true. The pH of a salt solution depends on the nature of the ions present. Some salts can produce acidic or basic solutions when dissolved in water, depending on the acidic or basic nature of the ions involved.
b. Flame test is a quantitative analysis method: This statement is not true. The flame test is a qualitative analysis method used to identify certain elements based on the characteristic colors they produce in a flame. It does not provide quantitative data or measurements.
c. All inorganic salts are strong electrolytes: This statement is not true. Inorganic salts can be classified as strong electrolytes or weak electrolytes, depending on their ability to dissociate into ions in water. Strong electrolytes fully dissociate into ions and conduct electricity effectively, while weak electrolytes only partially dissociate.
d. Some ionic compounds are insoluble in aqueous solution: This statement is true. Not all ionic compounds dissolve readily in water. Some compounds have limited solubility and form precipitates or insoluble solids when mixed with water. These compounds are considered insoluble salts.
e. Flame test alone can determine the identity of the unknown salt: This statement is not true. While flame tests can provide valuable information about the presence of certain elements, they are not sufficient to determine the complete identity of an unknown salt. Additional tests and analyses are typically needed for a conclusive identification.
In conclusion, the true statement about inorganic salts is that some ionic compounds are insoluble in aqueous solution.
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WILL MARK BRAINLIEST!
Which of the following is not a catalyst?
A. Phosphorus
B. Platinum
C. Enzymes
D. Nickel
Answer: platinum
Explanation:
i think
Where does the heat that is needed to warm the surface of the ocean come from? A. the Sun B. the Earth's interior C. animals D. the Earth's surface
Answer:
A. The Sun
Explanation:
Answer:
A
Explanation:
Most of our heat source on Earth comes from the Sun.
The data below show the concentration of AB versus time for the following reaction: AB(g)→A(g)+B(g) Time (s) [AB] (M)
0 0.950
50 0.459
100 0.302
150 0.225
200 0.180
250 0.149
300 0.128
350 0.112
400 0.0994
450 0.0894
500 0.0812
Determine the value of the rate constant.Predict the concentration of AB at 21 s .
The concentration of AB at 21 s is 0.526 M.
The data below show the concentration of AB versus time for the following reaction:
AB(g)→A(g)+B(g)Time (s) [AB] (M)0 0.95050 0.459100 0.302150 0.225200 0.180250 0.149300 0.128350 0.112400 0.0994450 0.0894500 0.0812
Determine the value of the rate constant:
The reaction is a first-order reaction. The concentration of AB changes as follows:
[AB]t = [AB]0e^-ktln
([AB]t/[AB]0) = -ktln
(0.459/0.950) = -k(
0.693)k = 1.88 × 10^-3 s^-1
The rate constant value is 1.88 × 10^-3 s^-1.
Predict the concentration of AB at 21 s.
The formula for a first-order reaction is given by ln
([A]t/[A]0) = -ktln([AB]t
[AB]0) = -kt[AB]t = [AB]0 e^-kt
[AB]t = (0.950) e^-(1.88 × 10^-3)(21)[AB]t = 0.526 M.
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A technique that is sometimes used to destratify the water in a lake or to prevent stratification is?
The technique commonly used to destratify water in a lake or prevent stratification is lake mixing or artificial circulation.
One technique commonly used to destratify water in a lake or prevent stratification is called lake mixing or artificial circulation. Stratification occurs when water layers of different temperatures and densities form in a lake, leading to distinct layers with minimal mixing between them. This can have negative impacts on water quality and aquatic life.
To destratify the water, lake mixing involves the use of mechanical devices or aeration systems to promote vertical mixing and break up the stratified layers. One common method is the use of surface aerators or diffusers, which introduce large amounts of air into the water column. This process creates turbulence and promotes mixing between the layers, allowing for the exchange of oxygen and nutrients.
Another technique is the installation of submersible mixers or circulation pumps at various depths in the lake. These devices create water movement, stirring up the layers and mixing them together. By breaking up the stratification, this technique enhances oxygen distribution and nutrient circulation throughout the water column.
In some cases, lake mixing can also involve the use of thermal destratification systems. These systems utilize pumps to withdraw water from the bottom of the lake and redistribute it near the surface, where it mixes with the upper layers. This process helps equalize the temperature and nutrient distribution within the lake, reducing stratification.
It's worth noting that the choice of destratification technique depends on various factors, including lake size, depth, and specific objectives. Environmental considerations and potential impacts on the lake ecosystem should also be taken into account when implementing destratification measures. Consulting with lake management professionals or experts in the field is essential to determine the most suitable technique for a particular lake.
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Which number represents a basic pH, 4 or 9? (2 points)
Answer:
9
Explanation:
7 is neutral anything higher than 7 is a base anything lower than 7 is an acid.
Why can't scientists simply use carbon-12 (12C) do determine
the age of dead carbon-based life forms?
Answer:
carbon-12 is not radioactive
Explanation:
The measurement of the age of dead carbon based life forms requires the use of a radioactive isotope hence it is often referred to as radiocarbon dating.
Carbon-12 and Carbon-14 occur together in living things.The half life of Carbon-14 is about 5670 years.
Hence, since Carbon-12 is not radioactive, it can not be used to measure the age of dead carbon based materials.
what is true of hybridization and hybrid orbitals? select all that apply. a. non-hybrid orbitals could not form the bond angles predicted in vsepr b. sp2 hybrid orbitals are formed from the mixing of one s and two p orbitals c. hybrid orbitals retain the same shapes as the original orbitals d. pi bonds do not involve hybrid orbitals e. an sp orbital is degenerate with the two remaining p orbitals
A true statement about hybridization and hybrid orbitals is that sp2 hybrid orbitals are formed from the mixing of one s and two p orbitals. Thus, the correct option is B.
The hybridization of orbitals is favored since hybridized orbitals are more directional which leads to more prominent cover when shaping bonds, in this manner the bonds shaped are more grounded.
The crossover orbitals can be characterized as the combination of standard nuclear orbitals coming about within the arrangement of modern nuclear orbitals.
Redistribution of the vitality of orbitals of person molecules to provide orbitals of equivalent vitality happens when two nuclear orbitals combine to create a crossbreed orbital in a particle.
This preparation is called hybridization.
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You are given two beakers, one containing 0.5 gm of HCl (mat-1)
and another containing 0.5 M 250 ml HCl (sol-1). Calculate the pOH
of a solution having 800 ml of water, mat-1, and 200 ml of sol-1.
Given data: A beaker containing 0.5 gm of HCl (mat-1) of a solution having 800 ml of water, mat-1, and 200 ml of sol-1.To explain the given data, first, we need to understand the meaning of the terms used in the question:Beaker: A container used for holding, mixing, and heating liquids.Containing:'
It means that a substance is present inside the beaker.Water: A colorless, odorless, tasteless liquid that is essential for most forms of life.On the basis of given data, we can conclude that:Volume of water = 800 mlVolume of solution = 200 mlMass of HCl = 0.5 gmConcentration of HCl = mat-1From the given data, it is clear that we have two beakers. One of them contains 800 ml of water and the other one contains 200 ml of the solution. The solution contains 0.5 gm of HCl (mat-1).This solution is added to water to make a solution having a mat-1 concentration of HCl.
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Is this synthesis or decomposition or combination or double replacement
This is a single replamecement reaction, also called single displacemente reaction, since we have the Fe taking the place of H2 and forming a compound with sulfate ion (SO4^-2)
Please Help Quick ASAP Hurry Chemistry Unit 4 Review Sheet
N2(g) + 3H2(g) → 2NH3(g)
b. How many grams of NH3 result from this reaction?
Work:____________
Ans:_________
Please Help ASAP please
N2(g) + 3H2-> 2NH3(g) This is the balanced equation
Note the mole ratio between N2, H2 and NH3. It is 1 : 3 : 2 This will be important.
moles N2 present = 28.0 g N2 x 1 mole N2/28 g = 1 mole N2 present
moles H2 present = 25.0 g H2 x 1 mole H2/2 g = 12.5 moles H2 present
Based on mole ratio, N2 is limiting in this situation because there is more than enough H2 but not enough N2.
moles NH3 that can be produced = 1 mole N2 x 2 moles NH3/mole N2 = 2 moles NH3 can be produced
grams of NH3 that can be produced = 2 moles NH3 x 17 g/mole = 34 grams of NH3 can be produced
sorry if this isn't the right answer
7.
Which of the following gases is an important greenhouse gas?
a. Hydrogen
b. Nitrogen
C. Carbon dioxide
d. Oxygen
Answer:
C
Explanation:
I guess
Answer:
c. carbon dioxide
Explanation:
its the highest percentage of gas produced compared to hydrogen, nitrogen and oxygen.