3rd of the day C: dis for u friend

Answer: the pic is the answer and

Step-by-step explanation:I explaned on the pic HOPE THIS HELPS WITH UR QUESTION

Answer:

Options (B), (C) and (F) are correct.

Step-by-step explanation:

Properties of a rhombus,

1). All sides of a rhombus are equal in measure.

2). Both the diagonals of a rhombus are the perpendicular.

3). Diagonals bisect the vertex angles.

By these properties of a rhombus,

Option (B): PR is perpendicular to QS.

Option (C): ∠QPR ≅ ∠SPR

Option (F): PQ ≅ QR

Therefore, options (B), (C) and (F) are correct.

Answer:

B, C, F, and E are all correct.

Step-by-step explanation:

Answer:

148cm^2

Hope this helps :))

Answer:

LOOK AT YOUR ANSWER IN PICTURE

The smallest value of n that works is 11.

We can expand the given equation using the binomial theorem:

(x^2 + 1.2)^n = ∑(k=0 to n) [n choose k] x^(2(n-k)) (1.2)^k

The coefficient of x^6 in the expansion will be given by the term where k = n - 3, i.e.,

[n choose n-3] x^(2(3)) (1.2)^(n-3) = (n(n-1)(n-2)/(3!)) x^6 (1.2)^(n-3)

We want this coefficient to be larger than 200000, so we have:

(n(n-1)(n-2)/(3!)) (1.2)^(n-3) > 200000/16

Simplifying and taking the logarithm of both sides:

(n-1)log(1.2) + log(n(n-1)(n-2)) - log(3!) > log(12500)

Using the fact that log(n) < n for all n > 0, we can approximate log(n(n-1)(n-2)) by n log(n) and simplify further:

(n-1)log(1.2) + 3log(n) - log(3) > log(12500)

Now, we can use trial and error to find the smallest value of n that satisfies this inequality. We can start with n = 10 and increase it until we get a value that works:

For n = 10: (9)log(1.2) + 3log(10) - log(3) ≈ 2.413, which is not greater than log(12500) ≈ 4.819.

For n = 11: (10)log(1.2) + 3log(11) - log(3) ≈ 4.299, which is greater than log(12500).

Therefore, the smallest value of n that works is 11.

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Answer:

x = -⁷/9

Step-by-step explanation:

\( \frac{9x - 8}{3} = \frac{9x - 3}{2} \)

Multiply both sides by 3

\( \frac{9x - 8}{3}*3 = \frac{9x - 3}{2}*3 \)

\( 9x - 8 = \frac{3(9x - 3)}{2} \)

Multiply both sides by 2

\( 2(9x - 8) = \frac{3(9x - 3)}{2}*2 \)

\( 2(9x - 8) = 3(9x - 3) \)

\( 18x - 16 = 27x - 9 \)

Subtract 27 from each side

18x - 16 - 27x = 27x - 9 - 27x

-9x - 16 = -9

Add 16 to both sides

-9x - 16 + 16 = -9 + 16

-9x = 7

Divide both sides by -9

-9x/-9 = 7/-9

x = -⁷/9

The net force acting on the box is <10, 50> Newtons. Rounded to 2 decimal places, the magnitude of the net force is approximately 50.99

To find the net force acting on the box, we need to sum up the individual forces exerted by the ropes. We can do this by adding the corresponding components of the forces.

Given:

F₁ = <20, 30> Newtons

F₂ = <-10, 20> Newtons

To find the net force, we can add the corresponding components of the forces:

Net force = F₁ + F₂

= <20, 30> + <-10, 20>

= <20 + (-10), 30 + 20>

= <10, 50>

Therefore, the net force acting on the box is <10, 50> Newtons.

To calculate the magnitude of the net force, we can use the Pythagorean theorem:

Magnitude of the net force = √(10² + 50²)

= √(100 + 2500)

= √2600

≈ 50.99

Rounded to 2 decimal places, the magnitude of the net force is approximately 50.99 (without the unit).

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Answer: 17.

Step-by-step explanation: 429 divided by 25 = 17.16 so rounding that would just be 17.

Answer:

Hence the expression \($$(6p+5)(p+1)=6p^2+11p+5$$\)

Step-by-step explanation:

Explanation

\($$\frac{\begin{matrix}{} & {} & 6p & + & 5 \\ \times & {} & p & + & 1 \\ \end{matrix}}\)

_____________

\({\frac{\begin{matrix}{} & {} & 6p & + & 5 \\ 6{{p}^2} & + & 5p & {} & {} \\ \end{matrix}}{\begin{matrix}6{{p}^2} & + & 11p & + & 5 \\ \end{matrix}}}$$\)

If we are interested in a larger class size Riverside School is a better choice because its mean and median class sizes are both larger than those of Sky View School.

The measures of center need to find the mean and median for each school.

For Sky View School:

Mean = (210 + 112 + 913 + 114) / 15 = 10.2

Median = (5+5)/2 = 5

For Riverside School:

Mean = (220 + 321 + 522 + 723 + 624 + 425 + 226 + 027 + 028 + 129) / 30 = 23

Median = (6+7)/2 = 6.5

The mean class size at Sky View School is 10.2 and at Riverside School is 23.

The median class size at Sky View School is 5 and at Riverside School is 6.5.

The measures of variability need to find the range interquartile range (IQR) and standard deviation for each school.

For Sky View School:

Range = 13-5 = 8

Q1 = 10, Q3 = 12

IQR = Q3 - Q1 = 2

Standard deviation = 2.37

For Riverside School:

Range = 29-20 = 9

Q1 = 22, Q3 = 25

IQR = Q3 - Q1 = 3

Standard deviation = 3.32

The range of class sizes at Sky View School is 8 and at Riverside School is 9.

The IQR of class sizes at Sky View School is 2 and at Riverside School is 3.

The standard deviation of class sizes at Sky View School is 2.37 and at Riverside School is 3.32.

Riverside School has a larger maximum class size (29) compared to Sky View School (13).

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Step-by-step explanation:

nevermind di ko maintindihan yung sinasabi mo hotdog ng sayo hotdog mobile legend caravans marunong ka mag mobile legends na totoo

Answer:

Step-by-step explanation:

Common ratios are found by either multiplying the same number in to get to the next number in the sequence, or by dividing out the same number in to go the next number in the sequence. Multiply or divide, NOT add or subtract! Be careful! Obiviously, our numbers are going down, so we are dividing out a specific number as opposed to multiplying one in. To get from 18 to 6, we have to divide by 3; however, the 6 is negative, so we have to divide by -3. To determine if we are correct, divide -6 by -3 and see if that result is the next one in line. -6 divided by -3 is 2. So we are correct, and the common ratio is -3.

A flashlight has six batteries, two of which are defective. if two are selected at random without replacement, then the probability that both selected batteries are defective is 1/15.

To find the probability that both selected batteries are defective, we need to calculate the probability of selecting a defective battery on the first draw, and then the probability of selecting another defective battery on the second draw.

There are a total of 6 batteries, and 2 of them are defective. So, the probability of selecting a defective battery on the first draw is 2/6.

After the first draw, there will be 5 batteries remaining, and 1 defective battery remaining. So, the probability of selecting another defective battery on the second draw, without replacement, is 1/5.

To find the probability of both events occurring, we multiply the probabilities:

P(both defective) = P(defective on first draw) * P(defective on second draw)

= (2/6) * (1/5)

= 1/15

Therefore, the probability that both selected batteries are defective is 1/15.

The question should be:

A flashlight has six batteries, two of which are defective. If two are selected at random without replacement, find the probability that both are defective.

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Answer:

The linear equation is y = 450 - 30 x, where y is the number of pages

Lourdes has left to read after x days

Step-by-step explanation:

Each day, Lourdes reads 30 pages of a 450-page book

- We need to write a linear equation to represent the number of pages

 Lourdes has left to read after x days

∵ Lourdes reads 30 pages each day

∵ Lourdes will read for x days

∴ The number of pages Lourdes will read in x day = 30 x

- The left pages will be the difference between the total pages of the

 book and the pages Lourdes read

∵ The book has 450 pages

∵ Loured will read 30 x in x days

∴ The number of pages left = 450 - 30 x

- Assume that y represents the number of pages Lourdes has left

 to read after x days

∴ y = 450 - 30 x

The linear equation is y = 450 - 30 x, where y is the number of

pages Lourdes has left to read after x days

The required formula to calculate exterior angle and an interior angle are  360°/n and (n-2) * 180°/n.

In a two-dimensional plane, a polygon is a closed object formed of line segments rather than curves. Polygon is a word that combines the words poly (which meaning numerous) and gon (means sides). To create a closed figure, a minimum of three line segments must be connected end to end.

The measure of an exterior angle of a regular polygon with n sides is given by 360°/n. The measure of an interior angle of a regular polygon with n sides is given by (n-2) * 180°/n.

So if you provide the number of sides of the polygon, I can give you the measures of the exterior and interior angles rounded to the nearest tenth if necessary.

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Answer:

56

Step-by-step explanation:

The easiest way to solve this is by cross multiplying. We can make an equation to find the answer of this by simply taking a side from each triangle and then the variable and equal side on the other triangle, shown below.

\(let \: \: ? = x\)

\( \frac{7}{49} = \frac{8}{x} \)

Now we solve with cross multiplication

\(7 x = 392 \\ x = 56\)

Now we know the mystery number is 56

Answer:

A. 12 for every 7 or 12:7

If the question had asked for ratio of peas in her hair to those in the bowl that would be 7 for every 12 or 7:12

Answer:

12:7

Step-by-step explanation:

A

The function f(x) = xlnx is decreasing on the open interval (0, e^-1).

To find the interval on which the function f(x) = xlnx is decreasing, we need to find the intervals where the first derivative f'(x) is negative.

Using the product rule of differentiation, we can find the first derivative of f(x) as

f'(x) = x × (1/x) + ln(x) × 1 = 1 + ln(x)

Now, we need to find the values of x where f'(x) < 0

1 + ln(x) < 0

ln(x) < -1

x < e^-1

Therefore, f(x) is decreasing on the interval (0, e^-1).

Note that we exclude x = 0 from the interval because the function is not defined for x ≤ 0.

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the claim aligns with the null hypothesis, as both assert the absence of an effect, difference, or relationship between variables.

The claim and the null hypothesis are the same when the claim being made is that there is no significant difference or relationship between variables or that there is no effect or impact of a particular factor. In other words, the claim asserts that the null hypothesis is true.

For example, if the null hypothesis (H₀) states that there is no difference between the means of two groups, the corresponding claim would be that the means are indeed equal. Similarly, if the null hypothesis states that there is no correlation between two variables, the claim would be that there is indeed no significant correlation.

In such cases, the claim aligns with the null hypothesis, as both assert the absence of an effect, difference, or relationship between variables.

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The maximum width of the border is 8 inches.

To find the maximum width of the border, use the formula:

area of garden = area of garden bed + area of borderThe area of the garden is 1,200 square feet (120 feet by 10 feet).The area of the garden bed is 1,000 square feet (100 feet by 10 feet).

Hence, the area of the border is 200 square feet.

To find the maximum width of the border, divide the area of the border (in square feet) by the length of the garden bed (in feet).

That is,Maximum width of border = Area of border / Length of garden bed= 200 / 10= 20 feet= 8 inches (converted to inches by multiplying by 12).

Therefore, the maximum width of the border is 8 inches.

We are given that a 20 square foot bag of mulch will cover an area of 20 square feet, which is equivalent to 2,880 square inches.

By using the completed table, we are required to find the maximum width of the border.

The area of the garden is 1,200 square feet (120 feet by 10 feet), and the area of the garden bed is 1,000 square feet (100 feet by 10 feet). So, the area of the border is 200 square feet.

To find the maximum width of the border, we divide the area of the border (in square feet) by the length of the garden bed (in feet).

Maximum width of border = Area of border / Length of garden bed= 200 / 10= 20 feet= 8 inches (converted to inches by multiplying by 12).Therefore, the maximum width of the border is 8 inches.

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The algebraic expression 6x(3y + 4z) can be simplified as 18xy + 24xz

the algebraic expression given in the question is a linear equation in three variables that are x , y and z and the simplification of this algebraic expression would also contain all the three variables

To solve this question we have to use the algebraic of  distributive property of addition over multiplication

so, using the above property and substituting the values given in the question we get

6x(3y +4z) = 6x(3y) + 6x(4z)

                  = 18 xy + 24 xz

Hence, The algebraic expression 6x(3y + 4z) can be simplified as 18xy + 24xz

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Answer:

y = 2/5x + 18.

Step-by-step explanation:

The line will have the same slope of 2/5.

Using the point-slope form of a line:

y - 12 = 2/5(x - -15)

y - 12 = 2/5(x + 15)

y = 2/5x + 6 + 12

y = 2/5x + 18.

Answer:

y  = (2/5)*x + 18

Step-by-step explanation:

Because the line is parallel to the line y = 2/5 x + 17, the slope of the new line has to be the same as well. So far, we have y = (2/5)*x .

Now what we can do is plug in -15 for x and see what we get for y. Because we get -6, we need 18 more to make it 12. Because of that, the y-intercept is 18 to make the equation of the line y  = (2/5)*x + 18.

Answer:

10/51

Step-by-step explanation:

5

6

1

13

4

Answer:

it is -11 because use the cauculator lol

Answer:

-11

Step-by-step explanation:

use a calculator bruh

The line of best-fit is of:

\(y = 21.37x + 169.58\)

Using the line:

------------------------

The line of best fit, for the amount spent on football in x years after 2005 is given by:

\(y = mx + b\)

\(m = \frac{\sum_{i = 1}^{6} (x_i - \overline{x})(y_i - \overline{y})}{\sum_{i = 1}^{6} (x_i - \overline{x})^2}\)

The means are:

\(\overline{x} = \frac{0 + 1 + 2 + 3 + 4 + 5}{6} = 2.5\)

\(\overline{y} = \frac{177 + 192 + 207 + 227 + 243 + 292}{6} = 223\)

Finding the slope:

\(\sum_{i = 1}^{6} (x_i - \overline{x})(y_i - \overline{y}) = 374\)

\({\sum_{i = 1}^{6} (x_i - \overline{x})^2} = 17.5\)

\(m = \frac{\sum_{i = 1}^{6} (x_i - \overline{x})(y_i - \overline{y})}{\sum_{i = 1}^{6} (x_i - \overline{x})^2} = \frac{374}{17.5} = 21.37\)

Now finding b:

\(y = 21.37x + b\)

Replacing the means:

\(223 = 21.37(2.5) + b\)

\(b = 169.58\)

Thus, the line of best fit is:

\(y(x) = 21.37x + 169.58\)

2022 is 2022 - 2005 = 17 years after 2005, thus, the estimate for 2022 is of:

\(y(17) = 21.37(17) + 169.58 = 532.87\)

Following the same logic, the estimate for 2041 is of:

\(y(36) = 21.37(36) + 169.58 = 938.9\)

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Answer:

Below.

Step-by-step explanation:

f) (a + b)^3 - 4(a + b)^2  

The (a+ b)^2 can be taken out to give:

= (a + b)^2(a + b - 4)

= (a + b)(a + b)(a + b - 4).

g)  3x(x - y) - 6(-x + y)

=  3x( x - y) + 6(x - y)

= (3x + 6)(x - y)

= 3(x + 2)(x - y).

h) (6a - 5b)(c - d) + (3a + 4b)(d - c)

=  (6a - 5b)(c - d) + (-3a - 4b)(c - d)

= -(c - d)(6a - 5b)(3a + 4b).

i)  -3d(-9a - 2b) + 2c (9a + 2b)

= 3d(9a + 2b) + 2c (9a + 2b)

=  3d(9a + 2b) + 2c (9a + 2b).

= (3d + 2c)(9a + 2b).

j)  a^2b^3(2a + 1) - 6ab^2(-1 - 2a)

=  a^2b^3(2a + 1) + 6ab^2(2a + 1)

= (2a + 1)( a^2b^3 + 6ab^2)

The GCF of a^2b^3 and  6ab^2 is ab^2, so we have:

(2a + 1)ab^2(ab + 6)

= ab^2(ab + 6)(2a + 1).

Answer:

Step-by-step explanation:

side length of the square : ( z + 5 )

\( {z}^{2} + 10z + 25 \\ {z}^{2} + 5z + 5z + 25 \\ z(z + 5) + 5(z + 5) \\ (z + 5)(z + 5) \\ \)

perimeter of the square :

\((z + 5) \times 4 \\ 4z + 20 \\ \)

Answer:

z= -2

Step-by-step explanation:

5z-2= -12

5z= -10

z= -2