Products are the substance that is produced after completion of a chemical reaction
What is product and equation?Products are the substance that is produced after completion of a chemical reaction while on the other hand, reactants are the substances that reacts with each other in a chemical reaction.
The chemical equation is the symbolic representation of a chemical reaction in the form of symbols and formulae in which reactants are present at left side and products are present at the right side.
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A typical barometric pressure at the top of Mount Everest (altitude of 8848 meters) is 33.6 kPa. What is the pressure at the peak in units of atmospheres
The pressure at the peak of Mount Everest in units of atmospheres is 0.331 atm.
Mount Everest is Earth's highest mountain above sea level, located in the Mahalangur Himal sub-range of the Himalayas.
We can use the following conversion factor to convert kPa to atm:
1 kPa = 0.00987 atm
So, to convert 33.6 kPa to atm, we can use the following calculation:
33.6 kPa x 0.00987 atm/kPa = 0.331 atm
Therefore, the pressure at the peak of Mount Everest in units of atmospheres is 0.331 atm.
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2. A chef fills a 100 ml container with a 83.5 g of cooking oil.
What is the density of the oil?
Density (ρ) = 835 kilogram/cubic meter
Steps:
ρ =
m
V
=
83.5 gram
100 milliliter
= 0.835 gram/milliliter
= 835 kilogram/cubic meter
How many grams of H₂SO4 are needed to produce 27.00 g of water?
The mass of the acid that would be required in the reaction would be obtained as 7.35 g
What is the stoichiometry?Stoichiometry is a branch of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction.
We know that;
The reaction is;
H2SO4 + 2NaOH ----->2H2O + Na2SO4
Number of moles of water = 27 g/18 g/mol
= 1.5 moles
If 1 mole of H2SO4 produces 2 moles of H2O
x moles of H2SO4 will produce 1.5 moles of H2O
x = 0.75 moles
Mass = 0.75 moles * 98 g/mol
= 7.35 g
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Triangle ABC has been dilated about point A by a scale factor of One-third. Triangle A B C. Side A C has a length of 39, side A B is 30, side C B is 48. Triangle A prime B prime C prime. What are the lengths, in units, of the three sides of Triangle A prime B prime C prime? 10, 12, 13 10, 16, 13 90, 124, 97 90, 144, 117
Answer:
10, 16, 13
Explanation: I just took the test and it was correct :)
how many moles of magnesium (mg) are there in 69.3 g of mg?
Answer: 2.85 moles
Explanation: Use molar mass:
(69.3 g of Mg)*(1 mole of Mg/ 24.31g of Mg) = 2.84 moles
There are 2.85 moles of magnesium in 69.3 g of magnesium. 1 mole of magnesium is equal to 24.31 g of magnesium.
A mole is a unit of measurement used in chemistry to express the amount of a substance. One mol of a substance is defined as the amount of that substance that contains the same number of constituent particles. To find the number of moles in a given mass of a substance, we can use the formula: moles = mass / molar mass. The molar mass of magnesium (Mg) is 24.31 g/mol. So, we can plug in the given mass and molar mass into the formula:
moles = 69.3 g / 24.31 g/mol
moles = 2.85 mol
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The Sun is a constant supply of energy to Earth.
A. True
B. False
What is the difference between the sum of the measures of the interior angles in an octagon and the sum of the measures of the interior angles in a hexagon?.
The difference between the sum of the measures of the interior angles in an octagon and the sum of the measures of the interior angles in a hexagon is 360°.
Interior angle refers to the angle inside a polygon that is formed by two of its adjacent sides. The sum of the measures of the interior angles of a polygon is given by the equation:
180°(n - 2)
where n is the number of sides
An octagon is a polygon that has 8 vertices and 8 sides. The sum of the measures of the interior angles of an octagon is:
180°(8 - 2) = 180°(6) = 1080°
On the other hand, a hexagon is a polygon that has 6 vertices and 6 sides. The sum of the measures of the interior angles of an octagon is:
180°(6 - 2) = 180°(4) = 720°
Subtracting the sum of the interior angles of the two polygons,
1080° - 720° = 360°
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If 5.7 mol Cl2 reacts with Na , how many grams of NaCl could be formed? The
molar mass of NaCl is 58.44 g/mol
Answer:
666.22grams
Explanation:
The balanced chemical equation of this reaction is given as follows:
2Na + Cl2 → 2NaCl
Based on the above equation, 1 mole of Chlorine gas (Cl2) is needed to produce 2 moles of sodium chloride (NaCl).
Therefore, 5.7moles of Cl2 will react to produce (5.7 × 2) = 11.4moles of NaCl.
Note that, the mass of NaCl was asked in this question. We find the mass of NaCl from the mole by using the formula;
moles = mass/molar mass
Molar mass of NaCl = 58.44 g/mol
11.4 = mass/58.44
mass = 58.44 × 11.4
mass = 666.22grams.
hhhhhheeeeelpppppp willl give brainliest
Answer:
w = d x f
Explanation:
hope it helps u
draw the mechanism of vanillin reaction with hbr to form the major product as determined by your experiment.
The overall reaction can be represented as follows:
Vanillin + HBr → 4-bromo-3-methoxybenzaldehyde + H2O
The mechanism begins with the protonation of the oxygen atom in vanillin, creating a highly electrophilic carbon atom. This electrophilic carbon then attacks the bromide ion, forming a bromonium ion intermediate.
The bromide ion attacks the other side of the bromonium ion, leading to the formation of a cyclic bromohydrin intermediate. Finally, water acts as a nucleophile and attacks the bromine atom, resulting in the formation of the major product, which is 4-bromo-3-methoxybenzaldehyde.
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a molecule of trna includes a sequence of three nitrogenous bases called an anticodon. what is the role of the anticodon in the process of translation?
The role of the anticodon in the process of translation is to bind to a codon on mRNA
An anticodon is a trinucleotide sequence of RNA that is complementary to a codon in messenger RNA (mRNA). It is located on a transfer RNA (tRNA) molecule and is responsible for recognizing and binding to specific codons during protein synthesis.
The anticodon pairs with the codon through base-pairing interactions, which ensure the proper transfer of the correct amino acid from the tRNA to the growing polypeptide chain.
During protein synthesis, the ribosome moves along the mRNA and reads the codons, which determine the sequence of amino acids in the resulting protein. The ribosome then selects the appropriate tRNA molecule based on the anticodon sequence, which is complementary to the codon on the mRNA.
The tRNA carries the appropriate amino acid that corresponds to the codon and transfers it to the growing polypeptide chain. This process continues until a termination codon is reached and the protein is complete.
Therefore, The role of the anticodon in the process of translation is to bind to a codon on mRNA
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if the ratio of acid to base in a buffer increases by a factor of 100, the ph of the buffer
a. decreases by 2.
b. increases by 10.
c. remains unchanged.
d. increases by 2.
e. decreases by 100.
If the ratio of acid to base in a buffer increases by a factor of 100, the pH of the buffer remains unchanged (c).
The pH of a buffer solution is determined by the ratio of acid to base components and their respective dissociation constants. In a buffer, the acid and its conjugate base exist in equilibrium, and this equilibrium determines the pH of the solution.
When the ratio of acid to base in a buffer increases by a factor of 100, it means that the concentration of the acid component becomes 100 times greater compared to the base component. This change in concentration, however, does not affect the dissociation constants of the acid and its conjugate base.
The pH of a solution is a measure of its acidity or alkalinity and is defined as the negative logarithm of the hydrogen ion concentration ([H+]). In a buffer solution, the pH is determined by the equilibrium between the acid and base components. Increasing the concentration of the acid while keeping the base concentration constant does not alter the equilibrium and, therefore, does not change the pH of the buffer solution.
Hence, when the ratio of acid to base in a buffer increases by a factor of 100, the pH of the buffer remains unchanged.
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Use the periodic table to determine the electron configuration for Cl and Y in noble-gas notation.
Cl:
A. ) [He]2s22p63s23p5
B. ) [Ne]3s23p4
C. )[Ar]3s23p5
D. )[Ne]3s23p5
The correct electron configuration for Cl in noble-gas notation is option D, [Ne]₃s²³p⁵.
This notation indicates that the electron configuration of Cl is the same as that of the noble gas neon ([He]₂s²²p⁶), except for the three additional electrons in the 3rd shell, occupying the 3s and 3p orbitals.
The electron configuration for Y in noble-gas notation can be determined by finding the noble gas that precedes Y in the periodic table, which is Kr. The electron configuration for Kr is [Ar]₃d¹⁰⁴s²⁴p⁶
Yttrium (Y) has an atomic number of 39, which means it has 39 electrons. The electron configuration for Y in noble-gas notation is therefore:
[Kr]₅s²⁴d¹
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The amount of energy required to turn a liquid into a gas is termed.
The amount of energy required to turn a liquid into a gas is termed latent heat.
What is Latent Heat?Latent heat, also known as the heat of vaporization or latent heat of vaporization is the magnitude of heat energy necessary to change the phase of a liquid substance to gas.
The change of phase, in this case, is not accompanied by a change in the temperature or the pressure of the liquid. In other words, latent heat is the amount of heat energy required to change a liquid to a gas at constant temperature and pressure.
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PLEASE HELP Will give brainliest and 50 points!! Please give honest answers
A second concern was discovered when a chemical dosing machine in the bottling line had a minor release during a change out of the chemical dimethyl dicarbonate (DMDC). The employees were evacuated without injury.
These two incidents led the winery to determine the level of risk and potential solutions. A risk assessment team was formed, and an assessment was performed. The team determined that the SO2 and DMDC exposure risks both presented multiple fatality – level risk and required immediate risk treatment.
Management sets the expectations, context, and objectives of the assessment. The risk assessment team was established that included the consultant as facilitator, the winemaker, assistant winemaker, cellar manager, operations manager, bottling
department manager, maintenance manager, and Health and Safety Executive (HSE) manager.
Data were collected regarding the SO2 and DMDC operations, equipment and instruments used, instructions, chemicals, and their SDSs, operator training, procedures, and available incident information. A search for similar events involving SO2 and DMDC were also conducted. Employees were interviewed to learn from their experiences, concerns, and suggestions.
The two procedures were observed to document and understand the sequence of tasks and potential risks associated with tasks. Photographs, tank quantities, room dimensions and configurations, distances to exits, means of egress, and other physical attributes were collected.
After reviewing the information, the potential concerns of fatalities or serious incidents were discussed. Workplace exposures such as pure SO2 releases and DMDC releases which present a potential for fatalities or serious incidents must be given the highest priority and controlled to an acceptable level. As a side note, the consultant explained that unlike like less-serious workplace incident rates, fatality, and serious incident/injury rates have not declined and do require serious attention. FSI exposures that can result in environmental releases, explosions, and disasters have been found to involve some of the following factors (14):
• Unusual and nonroutine work
• Nonproduction tasks
• Facility modification or construction activities
• Shutdowns and startups for repair and maintenance tasks
• Exposure to high-energy sources (e.g. electrical, steam, pneumatic, chemical) • Upsets (situations going from normal to abnormal).
The risk assessment team, consisting of various members from different departments within the winery, conducted a comprehensive assessment of the potential risks associated with sulfur dioxide (SO2) and dimethyl dicarbonate (DMDC) operations.
Data was collected regarding the equipment, chemicals, procedures, training, incident history, and physical attributes of the workplace. The team also interviewed employees to gather their experiences, concerns, and suggestions.
After reviewing the collected information, the team identified the potential risks of fatalities or serious incidents related to workplace exposures of SO2 and DMDC. These risks were considered of utmost priority and required immediate control to ensure an acceptable level of safety. The consultant highlighted the importance of addressing these serious risks, as fatality and serious incident rates have not shown a decline and demand serious attention.
Factors contributing to the potential for environmental releases, explosions, and disasters were identified, including unusual and nonroutine work, nonproduction tasks, facility modification or construction activities, shutdowns and startups for repair and maintenance tasks, exposure to high-energy sources (such as electrical, steam, pneumatic, chemical), and situations transitioning from normal to abnormal (upsets).
Based on the assessment and the identified risks, it is crucial for the winery to implement effective control measures to minimize the potential for fatalities, serious incidents, and environmental disasters. These measures may include improving procedures, enhancing operator training, implementing stricter safety protocols, and ensuring proper handling and storage of chemicals.
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Arrange the following elements in order from lowest to highest first ionization energy : , Ar , Cs, Na *
Answer:
Lowest Cs, Na, highest is At
Explanation:
Reaction of hypochlorous acid and ammonia is product-favored system at equilibrium. Answer A: Reaction of hypochlorous acid and ammonia is product-favored system at equilibrium. A Reaction of hypochlorous acid and ammonia is reactant-favored system at equilibrium. Answer B: Reaction of hypochlorous acid and ammonia is reactant-favored system at equilibrium. B Reaction of hypochlorous acid and ammonia yields pH 7.00. Answer C: Reaction of hypochlorous acid and ammonia yields pH 7.00. C No reaction occurs between hypochlorous acid and ammonia. Answer D: No reaction occurs between hypochlorous acid and ammonia. D Further data are needed to draw a conclusion about a prospective reaction.
Answer:
A. True
B. False
Explanation:
Reaction between hypochlorous acid and ammonia does not yields a Ph value of 7.00 , this value is defined to water and no other reaction can yield exactly this Ph value. The acid reaction will give a Ph value below 7 while a base reaction will give Ph value of above 7.
the sears tower in chicago is 1454 ft tall. how high is this in meters
Answer: It is 443.1792 high in Meters.
Explanation:
the bohr model was based on the helium atom and rings around the nucleus are called orbits. true or false
The statement "the Bohr model was based on the helium atom and rings around the nucleus are called orbits" is partially true and partially false.
The Bohr model was actually based on the hydrogen atom, not the helium atom. However, it is true that the rings around the nucleus are called orbits. So, the correct answer would be that the statement is both true and false due to the inaccuracy regarding the atom the model was based on.
The statement mentioned in the question is not entirely accurate. The Bohr model was based on the hydrogen atom, not the helium atom. The Bohr model was developed to explain the hydrogen atom's atomic structure, which is simpler than the helium atom's atomic structure. The hydrogen atom has one electron and one proton, whereas the helium atom has two electrons and two protons.
On the other hand, the second part of the statement is accurate. The rings around the nucleus in the Bohr model are called orbits. These orbits are specific, quantized energy levels that electrons can occupy in an atom. When an electron transitions between these energy levels, it emits or absorbs a photon of specific energy, which gives rise to the spectral lines observed in atomic spectra.
Therefore, the statement "the Bohr model was based on the helium atom and rings around the nucleus are called orbits" is partially true and partially false. The first part of the statement is incorrect because the Bohr model was based on the hydrogen atom, not the helium atom. The second part of the statement is accurate because the rings around the nucleus in the Bohr model are called orbits.
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In the box below, draw the open-chain structure (as a Fischer projection) of 2-deoxy-D-glucose. You may draw your Fischer projection without using wedged or hashed bonds. Align the Fischer projection vertically, e.g. Show explicitly the bonds to any hydrogens attached to chiral carbons. Do not show bonds to other hydrogens. A start structure for you modify is provided in the sketcher.
Below is an example of the open-chain structure (as a Fischer projection) of 2-deoxy-D-glucose.
The Fischer projection should be aligned vertically, with the carbon atoms at the top and bottom and the oxygen atoms on the left and right. The chiral carbon atoms should be labeled and any hydrogens attached to them should be explicitly shown. Note that bonds to other hydrogens should not be shown.
O O | /| | / | | H | H | H | | H | | H | | H | H | H | | H | |H | C--C--C--C--C
The diagram provided is a Fischer projection of 2-deoxy-D-glucose. The vertical alignment of the carbon atoms at the top and bottom, and the oxygen atoms on the left and right is correct. The chiral carbon atoms should be labeled and any hydrogens attached to them should be explicitly shown. Note that bonds to other hydrogens should not be shown.
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In the above equation how many moles of N2 can be made when 91 moles of CuO are
consumed?
Please help
Ammonium sulphate,(NH4)2SO4,is a fertilizer used to supply both nitrogen and sulphate.How many molecules of ammonium sulphate are in 35.8moles of (NH4)2SO4.
Number of (NH4)2SO4 molecules = 2.16 × 10^25 molecules / 2 = 1.08 × 10^25 (NH4)2SO4 molecules. There are approximately 1.08 × 10^25 molecules of ammonium sulfate in 35.8 moles of (NH4)2SO4.
To determine the number of molecules in 35.8 moles of ammonium sulfate ((NH4)2SO4), we need to use Avogadro's number, which states that there are 6.022 × 10^23 particles (atoms, molecules, or ions) in one mole of any substance.
The molecular formula of ammonium sulfate indicates that there are two ammonium ions (NH4+) and one sulfate ion (SO4^2-) in each molecule.
To calculate the number of molecules in 35.8 moles of (NH4)2SO4, we can follow these steps:
Determine the number of moles of (NH4)2SO4 by multiplying the given value by Avogadro's number:
Number of moles = 35.8 moles × (6.022 × 10^23 molecules/mole) = 2.16 × 10^25 molecules
Since each molecule of (NH4)2SO4 contains one ammonium ion and one sulfate ion, the number of molecules can be divided by two to obtain the number of (NH4)2SO4 molecules:
Number of (NH4)2SO4 molecules = 2.16 × 10^25 molecules / 2 = 1.08 × 10^25 (NH4)2SO4 molecules
Therefore, there are approximately 1.08 × 10^25 molecules of ammonium sulfate in 35.8 moles of (NH4)2SO4.
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What is “the process in which electrons are rearranged without direct contact”???
Answer:
Induction
Explanation:
When a body is brought in contact with another, electrons are rearranged by contact.
When a body is rubbed against one another, charging by friction occurs.
The process whereby electrons are rearranged without direct contact with one another is called induction.
By induction electrons can get charged without them having to be in contact with one another.
When a charged body is brought to the vicinity of the electrons, either an attraction or repulsion force is set up. Similar charges causes repulsion If a negatively charged body is brought near the electrons, there would be heavy repulsion and the electrons would be forced to rearranged. This effect is product as a result of a force field.determine the volume of a 0.0246 m li3po4 solution that contains 11.8 grams of li3po4.
The volume of the 0.0246 M \(Li_{3}PO_{4}\) solution that contains 11.8 grams of \(Li_{3}PO_{4}\) is 4.14 liters.
To determine the volume of a 0.0246 M \(Li_{3}PO_{4}\) solution that contains 11.8 grams of \(Li_{3}PO_{4}\), we need to use the following formula: moles of solute = mass of solute / molar mass of solute
Using the molar mass of \(Li_{3}PO_{4}\) (115.79 g/mol), we can calculate the number of moles of Li3PO4 in the solution: moles of \(Li_{3}PO_{4}\) = 11.8 g / 115.79 g/mol = 0.1019 moles
Next, we can use the formula for molarity to calculate the volume of the solution: molarity = moles of solute / volume of solution, 0.0246 M = 0.1019 moles / volume of solution
Solving for volume of solution, we get: volume of solution = 0.1019 moles / 0.0246 M = 4.14 L
Therefore, the volume of the 0.0246 M \(Li_{3}PO_{4}\) solution that contains 11.8 grams of \(Li_{3}PO_{4}\) is 4.14 liters.
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a saline solution has a concentration ratio of 0.5 milligrams of salt in 75 millilitres of solution
how many milligrams of salt will be needed to produce 180 millilitres of saline soluyhaving this same concentration
To produce 180 millilitres of a saline solution of the same concentration, we need 1.2 milligrams of salt.
It is given that a ratio of 0.5 milligrams of salt is present in 75 millilitres of solution. Let us assign a variable x to the amount of salt present in 180 millilitres of saline solution.
To maintain the same concentration we can use the method of cross-multiplication:
The following equation can be used to determine the value of x:
0.5 mg / 75 ml = x mg / 180 ml
( 0.5 × 180) / 75 = x mg
x mg = 90 / 75
Hence x is approximately equal to 1.2 mg.
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2. Do you think you would have to exercise longer to use the energy that can be released
from three grams of carbohydrate, fat or protein? Why?
NHa is an
example of
O an element.
O a mixture.
O a compound
O an atom.
Answer:
what is the question
Explanation:
Answer:
COMPOUND
Explanation:
I THINK
What is the molarity of a solution that contains 0.702 mol KCl in 0.98 L solution?
a. 0.68 M
c. 0.72 M
b. 0.459 M
d. 1.40 M
Answer:
C. 0.72 M
Explanation:
To calculate the molarity use the following equation, C=n/V
You have the molar number n which is 0.702 and the volume 0.98 L
Replace those numbers in the formula C=0.702/0.98= 0.72 M
What is the half‑life of an isotope that decays to 6.25% of its original activity in 78.7 h?
The half-life of the isotope that decays to 6.25% of its original activity in 78.7 hours is 26.23 hours. Simplifying and reaction solving for t1/2, we get: t1/2 = 26.2 hours (rounded to one decimal place).
The half-life of an isotope is the amount of time it takes for half of the radioactive atoms in a sample to decay. In this problem, we are given that the isotope decays to 6.25% of its original activity in 78.7 hours. To find the half-life, we can use the formula: N = N0 * (1/2)^(t / t1/2)
where N is the final amount of activity (6.25% of the original activity), N0 is the initial amount of activity, t is the time elapsed (78.7 hours), and t1/2 is the half-life we are trying to find. Substituting in the given values, we get:
0.0625N0 = N0 * (1/2)^(78.7 / t1/2).
Where N is the final activity, N0 is the initial activity, t is the time, and T is the half-life. In this case, we know that the isotope decays to 6.25% of its original activity, so N = 0.0625 * N0, and the time is 78.7 hours. We can now rewrite the formula as: 0.0625 * N0 = N0 * (1/2)^(78.7 / T).
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