The value of B in the equation (2x + 5)(x - 3) = AX + Bx + C is -1.
To find the value of B, we need to expand the equation (2x + 5)(x - 3) and compare it with the given form AX + Bx + C.
Expanding (2x + 5)(x - 3) using the distributive property, we get:
(2x)(x) + (2x)(-3) + (5)(x) + (5)(-3)
= 2x^2 - 6x + 5x - 15
= 2x^2 - x - 15
Comparing this with the given equation AX + Bx + C, we can equate the corresponding coefficients:
B = -1
Therefore, the value of B is -1.
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Pls help I’m getting confused even though should be pretty easy.
Answer:
V = 108
Step-by-step explanation:
B = 9 x 4 = 36 Height of Triangular prism is 3 so 36 x 3 = 108
the lengths of two sides of a triangle are 11 cm and 19 cm. identify the range of possible lengths for the third side.
The third side of the triangle whose two sides are 11 cm and 19 cm can be between 9 and 29.
What is a triangle?A triangle is a geometric figure with three edges, three angles and three vertices. It is a basic figure in geometry.
The sum of the angles of a triangle is always 180°
Given that,
The sides of triangles are 11 cm and 19 cm,
Let the third side of the triangle is x,
Since, a side of a triangle is greater than the difference of two sides and less than the sum of two sides,
implies that,
19-11<x<19+11
8 < x < 30
The possible range of third side is (9,29).
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Answer:
8cm < x < 30cm
Step-by-step explanation:
To find the range of lengths for the third side of a triangle when two side lengths are known, first, assign a variable for the length of the third side.
Let x be the length of the unknown side.
Use the Triangle Inequality Theorem to write the three inequalities.
x + 11x > 19
x + 19 > 11
11 + 19 > x
Solve each inequality.
x > 8
x > -8
30 > x
Now find the range of values that satisfies all three inequalities.
The range between 8 and 30 satisfies all 3 inequalities. Therefore, this triangle's third side lengths range is 8cm < x < 30cm.
Find the length of side x I simplest radical form
Answer:
Option A
Step-by-step explanation:
By applying Pythagoras theorem in ΔABC,
(Hypotenuse)² = (Leg 1)² + (Leg 2)²
AC² = AB² + BC²
AC² = 6² + 5²
AC = \(\sqrt{61}\)
Similarly, by applying Pythagoras theorem in ΔACD,
AD² = AC² + CD²
(10)² = \((\sqrt{61})^2\) + x²
x² = 100- 61
x² = 39
x = √(39)
Option A will be the answer.
The answer of the question
Answer:
123cm
Step-by-step explanation:
becuse
Can you guys help me do today.
Answer:
Down Below
Step-by-step explanation:
b=0.5
g=0.8
1. 3b + 5g = ?
3×0.5+5×0.8=?
1.5+4= 5.5 cm
2. 6(3b+5g) = ?
18b + 30g
18×0.5+30×0.8
9+24= 33 cm
3. 2b + 3g
2×0.5+3×0.8
1+2.4=3.4 cm
4. 7(2b+3g)
14b + 21g
14×0.5+21×0.8
7+16.8= 23.8 cm
5. Add number 2 and 4 together
14b+21g+18b+30g= 32b+ 51g
Take numbers and add them from problems 2 and 4
23.8+33=56.8 cm
-6x>18 use a table to solve the inequality
Answer:36
Step-by-step explanation:multiply divide and subctract
Why is 4 + (-3) equal to 1?
Answer:
[See Below]
Step-by-step explanation:
\(Hey~There!\)
________________________
➜ Solve:
\(4+(-3)=1\)So with this problem technically your subtracting because of the \(-3\).________________________
So based on our work above we can conclude that the equation is equal because when solve it equals \(1\), making \(1=1\).
________________________
\(Hope~this~helps~Mate!\\-Your~Friendly~Answerer,~Shane\) ヅ
if a television screen with a length-to-height ratio of 16:9 has an area of 576 square inches, what is its perimeter?
The perimeter of television is = 100 inches
What is mensuration ?The study of measuring geometric shapes and their qualities such as length, volume, shape, surface area, lateral surface area, and so on is known as mensuration. Mensuration will be covered in fundamental mathematics.
Calculationlet the length be 16x and width be 9x
area given = 576 sq. inches
16x * 9 x = 576
144 \(x^{2}\) = 576
x = 24/12
x = 2
length = 32
width = 18
perimeter = (32 + 18)*2 =100 inches
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Find the first and second derivatives of the function. (Factor your answer completely.)
g(u) = u(2u − 3)^3
g ' (u) = g'' (u) =
The first derivative of the function `g(u) = u(2u - 3)^3` is `g'(u) = 6u(2u - 3)^2 + (2u - 3)^3`. The second derivative of the function is `g''(u) = 12(u - 1)(2u - 3)^2`.
Given function: `g(u)
= u(2u - 3)^3`
To find the first derivative of the given function, we use the product rule of differentiation.`g(u)
= u(2u - 3)^3`
Differentiating both sides with respect to u, we get:
`g'(u)
= u * d/dx[(2u - 3)^3] + (2u - 3)^3 * d/dx[u]`
Using the chain rule of differentiation, we have:
`g'(u)
= u * 3(2u - 3)^2 * 2 + (2u - 3)^3 * 1`
Simplifying:
`g'(u)
= 6u(2u - 3)^2 + (2u - 3)^3`
To find the second derivative, we differentiate the obtained expression for
`g'(u)`:`g'(u)
= 6u(2u - 3)^2 + (2u - 3)^3`
Differentiating both sides with respect to u, we get:
`g''(u)
= d/dx[6u(2u - 3)^2] + d/dx[(2u - 3)^3]`
Using the product rule and chain rule of differentiation, we have:
`g''(u)
= 6[(2u - 3)^2] + 12u(2u - 3)(2) + 3[(2u - 3)^2]`
Simplifying:
`g''(u)
= 12(u - 1)(2u - 3)^2`.
The first derivative of the function `g(u)
= u(2u - 3)^3` is `g'(u)
= 6u(2u - 3)^2 + (2u - 3)^3`. The second derivative of the function is `g''(u)
= 12(u - 1)(2u - 3)^2`.
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The first derivative of g(u) is g'(u) = (2u - 3)³ + 6u(2u - 3)², and the second derivative is g''(u) = 12(2u - 3)² + 12u(2u - 3).
Using the product and chain ruleFirst, let's find the first derivative:
g'(u) = (2u - 3)³ * d(u)/du + u * d/dx[(2u - 3)³]
Using the chain rule, we can differentiate (2u - 3)³ and u as follows:
d(u)/du = 1
d/dx[(2u - 3)³] = 3(2u - 3)² * d(2u - 3)/du
= 3(2u - 3)² * 2
Plugging these values back into the equation for g'(u), we have:
g'(u) = (2u - 3)² + u * 3(2u - 3)² * 2
= (2u - 3)³ + 6u(2u - 3)²
Simplifying the expression, we have:
g'(u) = (2u - 3)³ + 6u(2u - 3)²
Now, let's find the second derivative:
g''(u) = d/dx[(2u - 3)³ + 6u(2u - 3)²]
Using the chain rule and product rule, we can differentiate each term:
d/dx[(2u - 3)³] = 3(2u - 3)² * d(2u - 3)/du
= 3(2u - 3)² * 2
d/dx[6u(2u - 3)²] = 6(2u - 3)² + 6u * d/dx[(2u - 3)²]
= 6(2u - 3)² + 6u * 2(2u - 3)
The Second derivativePlugging these values back into the equation for g''(u), we have:
g''(u) = 3(2u - 3)² * 2 + 6(2u - 3)² + 6u * 2(2u - 3)
= 6(2u - 3)² + 6(2u - 3)² + 12u(2u - 3)
= 12(2u - 3)² + 12u(2u - 3)
Simplifying the expression further, we have:
g''(u) = 12(2u - 3)² + 12u(2u - 3)
Therefore, the first derivative of g(u) is g'(u) = (2u - 3)³ + 6u(2u - 3)², and the second derivative is g''(u) = 12(2u - 3)² + 12u(2u - 3).
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Statements about averages often present an incomplete picture, lacking information about the dispersion. T/F
True. Statements about averages often present an incomplete picture because they do not provide information about the dispersion or variability of the data.
The statement is true because averages, such as the mean or median, only give a measure of central tendency and do not convey information about the spread or distribution of the data points. Dispersion measures, such as standard deviation or range, are necessary to understand the variability or consistency within the dataset.
Without considering dispersion, it is possible to have datasets with the same average but different levels of variability. Therefore, to gain a comprehensive understanding of a dataset, it is important to consider both the average and the dispersion measures together.
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The data set represents the number of pages in the last book read by each of 20 students over the summer. 163, 170, 171, 173, 175, 205, 220, 220, 220, 253, 267, 281, 305, 305, 305, 355, 371, 388, 402, 431 Create a histogram to represent the distribution of the data.
The required histogram is attached as a picture.
Given the information on how many pages each of the 20 pupils read throughout the summer.
163, 170, 171, 173, 175, 205, 220, 220, 220, 253, 267, 281, 305, 305, 305, 355, 371, 388, 402, 431
With frequency on the y axis and class on the x axis.
we observe the histogram and make out that:
class 160 - 220 has the highest frequency of 6 students whereas
400 - 460 has the least with 2 students.
The classes between them range as follows:
220 - 280 has 5 students
280 - 340 has 4 students
340 - 400 has 3 students.
Hence the required histogram is created .
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1. Find the surface area of the pyramid. SHOW YOUR WORK.
5 cm
9cm...
5 cm
5 cm
9 cm
a. Find the area of all 4 triangles. SHOW YOUR WORK including formula and final units.
b. Find the area of the square. SHOW YOUR WORK hhxgincluding formula and final units.
c. Find the total surface area of the pyramid. SHOW YOUR WORK and include the units.
Plss I need the answer fast grades go in !!!!
The surface area of the square pyramid is 115 square meters
Finding the surface area of the prismFrom the question, we have the following parameters that can be used in our computation:
The square based pyramid
The formula for the surface area of a square pyramid is:
S = a² + 2al
where a is the length of one side of the square base and l is the slant height.
Area of 4 triangles
This is calculated as
A = 1/2 * 5 * 9 * 4 = 90
Area of the square
This is calculated as
A = 5 * 5 = 25
So, we have
Area = 90 + 25
Area = 115
Hence, the surface area of the square pyramid is 115 square meters.
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I need answers for this question
Answer & Step-by-step explanation:
The sweet Shoppe Bakery ordered 15 dozen eggs for their upcoming project. When the bill came, they were charged 33.75 for the eggs. What is a numerical expression that will find the cost of one dozen eggs?
Step-by-step explanation:
The numerical expression for the cost of 1 dozen eggs is 33.75/15.
What is the answer to (-18) - 14 =
Answer:
-32
Step-by-step explanation:
Negative plus negative = Negative
Just add those 2 together,
(-)18 + (-) 14
Which is -32
(-) 32 = -32
Find the value of x degrees.
Answer:
X=25°
Step-by-step explanation:
\(x = \frac{1}{2} (t2 - 22) \)
\( = \frac{1}{2} (50)\)
\( = 25\)
\(x = 25\)
hope it helps u
Simplify by adding like terms: mp^2+ mpm + + mpm + 2a^b^2 + mp + abab
Given the following expression:
The similar terms must have the same variable with the same exponents
So, note the following:
\(\begin{gathered} \text{mpm}=m^2p \\ \text{abab}=a^2b^2 \end{gathered}\)So, the given expression will be:
\(\begin{gathered} mp^2+\text{mpm}+2a^2b^2+mp+\text{abab} \\ =mp^2+m^2p+mp+2a^2b^2+a^2b^2 \\ \\ =mp^2+m^2p+mp+3a^2b^2 \end{gathered}\)HELLO IS ANYONE GOOD AT MATH IF SO PLEASE ANSWER THIS IS DUE TONIGHT
Draw where the dots go on the graph please
yo anwser this as well
Answer:
3^8
Step-by-step explanation:
please mark me as brainlest to all questions please
Determine the intercepts of the line.
Do not round your answers.
y=6x+13y=6x+13
Answer: X= -2.1667 Y= 13
Solve the inequality below for g.
-10g + 4 < 9 - 159
A. IS
B. 5 > 1
C. g <1
D. § 2 - 3
Reset
Submit
Answer:
the answer to the inequality is C. g<1
aj sold 200 candy bars to raise money for their community softball league. Milk chocolate candy bars sold for $3 each, and dark chocolate candy bars sold for $4 each. Aj sold $675 worth of candy bars. The system of equations below represents the sales of candy bars.
m+d=200
3m+4d=675
How many dark chocolate candy bars did AJ sell?
Enter your answer in the box.
The number of dark chocolate AJ sold is 75
What is Simultaneous equation?Simultaneous equations are two or more algebraic equations that share variables e.g. m and d . They are called simultaneous equations because the equations are solved at the same time.
If the number of Milk chocolate candy is m and the number of dark chocolate candy is d, then
m+d= 200 equation 1
3m+4d= 675 equation 2
to eliminate m we multiply both equations by 3
3m+3d= 600 equation 3
3m+ 4d=675 equation 4
subtract equation 3 from 4
d = 675-600
d= 75
Therefore the number of dark chocolate candy AJ sold is 75.
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Which of the following rules describes the function graphed below? On a coordinate plane, points are at (negative 1, 1), (1, 2), (3, 3), (5, 4). a. Output = Input c. Output = (0.5)(Input) + 1.5 b. Output = (2)(Input) – 3 d. Output = (1.5)(Input) + 3
The rule that describes the function is (c) Output = (0.5)(Input) + 1.5
How to determine the rule?The points on the coordinate plane are given as
(negative 1, 1), (1, 2), (3, 3), (5, 4)
Express as numbers
So, we have
(-1, 1), (1, 2), (3, 3), (5, 4)
Divide the input values by 2
So, we have
0.5(Input) => (-1/2, 1), (1/2, 2), (3/2, 3), (5/2, 4)
Add 1.5 to the input values
So, we have
0.5(Input) + 1.5 => (1, 1), (2, 2), (3, 3), (4, 4)
So, we have
Output = 0.5(Input) + 1.5
Hence, the equation is (c)Output = 0.5(Input) + 1.5
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An isosceles triangle in which the two equal sides, labeled a, are longer than the base, labeled b.
This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the triangle is 15.7 centimeters. The equation can be used to find the side lengths.
If one of the longer sides is 6.3 centimeters, what is the length of the base?
cm
If one of the longer sides of the Isosceles triangle is 6.3 centimeters, the length of the base is 3.1 centimeters.
Let's solve the problem step by step:
1. Identify the given information:
- The triangle is isosceles, meaning it has two equal sides.
- The two equal sides, labeled "a," are longer than the base, labeled "b."
- The perimeter of the triangle is 15.7 centimeters.
- One of the longer sides is 6.3 centimeters.
2. Set up the equation based on the given information:
Since the triangle is isosceles, the sum of the lengths of the two equal sides is twice the length of the base. Therefore, we can write the equation:
2a + b = 15.7
3. Substitute the known value into the equation:
One of the longer sides is given as 6.3 centimeters, so we can substitute it into the equation:
2(6.3) + b = 15.7
4. Simplify and solve the equation:
12.6 + b = 15.7
Subtract 12.6 from both sides:
b = 15.7 - 12.6
b = 3.1
5. Interpret the result:
The length of the base, labeled "b," is found to be 3.1 centimeters.
Therefore, if one of the longer sides of the isosceles triangle is 6.3 centimeters, the length of the base is 3.1 centimeters.
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Find the surface area of the polyhedra
pls!! show how you got the surface area
Answer:
384m^2
Step-by-step explanation:
surface area of cube = area of 1 side x 6
area of 1 side = 64m^2
so, surface area = 64 x 6 = 384m^2
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poisson The average number of accidental drownings per year in the USA is 3.0 per 100,000. What is the probability that in a city with a population of 200,000 there will be exactly 2 accidental drownings per year
2.23% is the probability of a city with a population of 200,000, and there will be exactly 2 accidental drownings per year.
The Poisson distribution, is useful for modeling the number of events (in this case, accidental drownings) in a fixed interval (here, a year). Given the average rate of 3.0 drownings per 100,000 people per year, we first need to find the expected number of drownings in a city with a population of 200,000.
Expected drownings per year = (3.0 drownings / 100,000 people) * 200,000 people = 6 drownings
Now, we can use the Poisson probability formula to calculate the probability of exactly 2 accidental drownings per year in this city:
P(X = k) = (λ^k * e^(-λ)) / k!
Here, X represents the number of drownings, k is the desired number of drownings (2 in this case), λ (lambda) is the expected number of drownings per year (6), e is the base of the natural logarithm (approximately 2.718), and k! is the factorial of k.
P(X = 2) = (6^2 * e^(-6)) / 2! = (36 * e^(-6)) / 2 = (36 * 0.002478) / 2 = 0.04461 / 2 = 0.022305
Therefore, the probability that in a city with a population of 200,000, there will be exactly 2 accidental drownings per year is approximately 0.0223 or 2.23%.
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On a bicycle trail, the city is painting arrows like the one shown below:
Upper pointing arrow with height of 15 and length of 13. Rectangular base of arrow has length of 11 and height of 12. All units are in centimeters.
Calculate the area of the arrow by decomposing it into rectangles and triangles. (4 points)
195 square centimeters
171 square centimeters
151.5 square centimeters
148.5 square centimeters
The Area of the composite figure = area of the rectangle + area of the triangle = 148.5 cm².
What is the Area of a Composite Figure?The figure formed by the arrow can be decomposed into a rectangle and a triangle.
The area of the composite figure = area of the rectangle + area of the triangle.
Find the area of the rectangle:
Length = 12 cm
Width = 11 cm
Area of the rectangle = (length)(width) = (12)(11)
Area of the rectangle = 132 cm²
Find the area of the triangle
Base = 11 cm
Height = 15 - 12 = 3 cm
Area of the triangle = 1/2(b)(h) = 1/2(11)(3)
Area of the triangle = 16.5 cm²
Area of the composite figure = area of the rectangle + area of the triangle = 132 + 16.5 = 148.5 cm².
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Simplify 2/4/8 what the awnser
Answer:
2 1/2
Step-by-step explanation:
Is this relation a function? {(1,4), (-5,2), (4,1), (1,6)}
Answer:
no
Step-by-step explanation:
No, it is not since 2 points have the same x-coordinate and different y-coordinates.
What is the answer to this question?
Answer:
≈ 3.9 miles
Step-by-step explanation:
The third angle in the triangle is
180° - (53 + 78)° = 180° - 131° = 49°
Using the Sine rule in the triangle with distance from 2 being x, then
\(\frac{3}{sin49}\) = \(\frac{x}{sin78}\) ( cross- multiply )
x × sin49° = 3 × sin78° ( divide both sides by sin49° )
x = \(\frac{3sin78}{sin49}\) ≈ 3.9 ( to the nearest tenth )