2. Consider the following graph of a quadratic function.
Part A: Define the domain.
Part B: Define the range.
Part C: Where is the graph increasing?
Part D: Where is the graph decreasing
Part E: Identify any relative maximums.
Part F: Identify any relative minimums

Answers

Answer 1

Answer:

......

Step-by-step explanation:


Related Questions

graph the cosine function on the interval [-2π,0]​

Answers

Answer:

Credit to Desmos :D (Great online graphing program)

Step-by-step explanation:

graph the cosine function on the interval [-2,0]

E U F {2,4,6,8,} true or false

Answers

tbh i think its true not 100%

5 tenths + 8 hundreths

Answers

Answer:

50,800

Step-by-step explanation:

More help if you can! I desperately need to pass this one class

More help if you can! I desperately need to pass this one class

Answers

Answer:

volume of cuboid = lbh = 8.2 ft x 9.4 ft x 10.7 ft

= 824.8 ft^3

Find and simplify the following for f(x) = x(19-x), assuming h+0 in (C).
(A) f(x + h)
(B) f(x + h) – f(x)
f(x +h)-f(x)
(C)
h
(A) f(x + h) =
(Simplify your answer.)
B and c solve

Answers

Answer:  see below

Step-by-step explanation:

f(x) = x(19 - x)

     = 19x - x²

A) f(x+h) = (x + h)[19 - (x + h)]

             = (x + h)(19 - x - h)

             = 19x - x² - 2xh + 19h - h²

B) f(x+h) - f(x) = (19x - x² - 2xh + 19h - h²) - (19x - x²)

                     = - 2xh + 19h - h²

                     = h(-2x + 19 - h)

C) [f(x+h) - f(x)]/h = [h(-2x + 19 - h)]/h

                           = -2x + 19 - h

As h → 0:           = -2x + 19

The function will be equal to -2x + 19.

What is a function?

A function is defined as the expression that set up the relationship between the dependent variable and independent variable.

f(x) = x(19 - x)

    = 19x - x²

f(x+h) = (x + h)[19 - (x + h)]

               = (x + h)(19 - x - h)        

               = 19x - x² - 2xh + 19h - h²

f(x+h) - f(x) = (19x - x² - 2xh + 19h - h²) - (19x - x²)

                    = - 2xh + 19h - h²

                    = h(-2x + 19 - h)

[f(x+h) - f(x)]/h = [h(-2x + 19 - h)]/h

                          = -2x + 19 - h

As h → 0:            = -2x + 19

Therefore, the function will be equal to -2x + 19.

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If p:q=3/4:2 and p:r=1/3:1/2 find p:q:r

Answers

Answer:

3/8

Step-by-step explanation:

\( \frac{p}{q} = \frac{ \frac{3}{4} }{ \frac{2}{1} } \\ \frac{p}{q} = \frac{3}{8} \)

\( \frac{p}{r} = \frac{ \frac{1}{3} }{ \frac{1}{2} } \\ \frac{p}{r} = \frac{2}{3} \)

\( \frac{ \frac{p}{q} }{r} = \frac{ \frac{3}{8} }{ \frac{2}{3} } \\ \frac{ \frac{p}{q} }{r} = \frac{9}{16} = \frac{3}{8} \)

I think this is just combining ratios soo..
P:q
3/4:2

P : Q : R
3/4 : 2. :
1/3. : : 1/2
————————-
1/3. : 4.5 : 1/2

3/4X 1/3= 4/12=1/3
3/4 / 1/3= 9/4= 2.25
2 X 2.25= 4.5

The ratio is

1/3 : 4.5 : 1/2

Find an equation of a line with slope -7 and y-intercept 2. y=

Answers

Answer:

y = -7x + 2

Step-by-step explanation:

Use the slope-intercept form y = mx + b.

Substitute -7 for m, 0 for x and 2 for y.  Then

2 = (-7)(0) + b, so b must be 2.

The desired equation is y = -7x + 2.

Calculate 19.25 tons equal how many pounds

Answers

Answer:

38,500 pounds

Step-by-step explanation:

1 ton = 2000 pounds

Suppose that a scarf company estimates that its monthly cost is
C(a)=500x2 + 300 and its monthly revenue is
R(x) = -0.523 +6002-200+300, where x is in thousands of
scarves sold. The profit is the difference between the revenue and the cost.
What is the profit function, P(x)?

Answers

The profit function is P(x) = -500.523x^2 + 600x - 200.

To find the profit function, P(x), we need to subtract the cost function, C(a), from the revenue function, R(x).

Given:

Cost function: C(a) = 500x^2 + 300

Revenue function: R(x) = -0.523x^2 + 600x - 200 + 300

Profit function, P(x), is obtained by subtracting the cost function from the revenue function:

P(x) = R(x) - C(a)

P(x) = (-0.523x^2 + 600x - 200 + 300) - (500x^2 + 300)

Simplifying the expression:

P(x) = -0.523x^2 + 600x - 200 + 300 - 500x^2 - 300

P(x) = -500x^2 - 0.523x^2 + 600x + 300 - 200 - 300

P(x) = -500x^2 - 0.523x^2 + 600x - 200

Combining like terms:

P(x) = (-500 - 0.523)x^2 + 600x - 200

Simplifying further:

P(x) = -500.523x^2 + 600x - 200

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perimiter question asap answer

perimiter question asap answer

Answers

The perimeter of the figure is 58 m.

To find the perimeter of the given figure we can divide the figure in three rectangles.

Rectangle 1:

Perimeter= 2 (l + w)

= 2(5 + 2)

= 2 x 7

= 14 m

Rectangle 2:

Perimeter= 2 (l + w)

= 2(5 + 1)

= 2 x 6

= 12 m

Rectangle 3:

Perimeter= 2 (l + w)

= 2(14 + 2)

= 2 x 16

= 32 m

So, the perimeter of the figure is

= 14 + 12 + 32

= 58 m

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True or false are all structures made by humans and why

Answers

Answer:

mostly. trees and most plants arent

Megan scored 117 points by collecting 3 coins. After collecting a total of 12 coins, how many points will Megan have scored in all? Assume the relationship is directly proportional.

Answers

EXPLANATION

As Megan scored 117 points by collecting 3 coins, we need to divide the points by the number of coins and apply the unitary method in order to get the number of points that Megan will get.

\(\text{?points =}\frac{117\text{ points}}{3\text{ coins}}\cdot12\text{ coins=468 points}\)

In conclusion, Megan will score 468 points.

The circle graph represents the different kinds of plants the Martin family planted in their garden. Use the graph for Parts A-C.
Part A

If there are 200 plants in the garden, how many of them are green beans?

Part B

If there are 200 plants in the garden, which of the following represents the number of plants that are either pumpkin or tomato?

Part C

If there are 200 plants in the garden, which of the following represents how many more corn plants than cucumber plants there are?​

The circle graph represents the different kinds of plants the Martin family planted in their garden.

Answers

Part A: There are 28 green beans in the garden. Part B: There are 80 plants that are either pumpkin or tomato. Part C: There are 52 more corn plants than cucumber plants.

What is a circle graph?

A circle graph, often called a pie chart, is a circular graph with sectors on it, each representing a particular category or set of data. Each sector's area or angle is proportionate to the amount it stands for. In data visualisation, circle graphs are frequently used to show the relative sizes or proportions of several categories or groups within a dataset. They can instantly convey the distribution of data without the need for laborious numerical calculations, which makes them effective for presenting data that is divided into discrete groups. However, if the data is not presented in a clear and simple manner or if the sectors are not precisely drawn to scale, circle graphs may be deceiving.

Part A: The percentage of green beans in the circle graph is 14%.

14% of 200 = 0.14 x 200 = 28

Part B: The circle graph shows:

pumpkin plants and tomato plants is 20% + 20% = 40%.

40% of 200 = 0.40 x 200 = 80

Part C: The corn plants is 36% and the percentage of cucumber plants is 10%.

36% of 200 - 10% of 200 = (0.36 x 200) - (0.10 x 200) = 72 - 20 = 52

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giving 90 points! NEED IN TWO MINS

giving 90 points! NEED IN TWO MINS

Answers

Answer:

300

Step-by-step explanation:

A=wl=10·30=300

multiply the length of the rectangle by the width of the rectangle.

The area is measurement of the surface of a shape. To find the area of a rectangle or a square you need to multiply the length and the width of a rectangle or a square. Area, A, is x times y.

Answer:

Area = 378.5 ft²

Step-by-step explanation:

The figure is having two semi circles and one rectangle.

\({ \sf{area = area \: of \: semicircles + area \: of \: rectangle}} \\ \\ { \sf{area = 2( \frac{1}{2} \pi {r}^{2}) + (l \times w) }} \\ \\ { \sf{area = \pi {r}^{2} + (l \times w) }} \\ \\ { \sf{area = 3.14 \times {5}^{2} + (30 \times 10)}} \\ \\ { \sf{area = 378.5 \: {ft}^{2} }}\)

The number 100 is multiplied either by 2 or by 3, then the result is increased either by 1 or by 2, and then the new result is divided either by 3 or by 4. If the final result is a natural number, what is this final result?​

Answers

Answer:

67

Step-by-step explanation:

This is the right answer

Jennifer Aniston bought a property for $2,000,000. One year later, she sold it for $2,200,000. Jennifer invested only $1,000,000 of her own money and borrowed the rest interest-free from her friend, Brad Pitt. What was her return on this investment?

Answers

This means that she made a 20% return on the money she invested in the property. For every dollar she invested, she earned 20 cents in profit.

To calculate Jennifer Aniston's return on investment (ROI), we can use the formula:

ROI = (Net Profit / Initial Investment) * 100

First, let's calculate the net profit. The net profit is the selling price minus the initial investment:

Net Profit = Selling Price - Initial Investment

Net Profit = $2,200,000 - $2,000,000

Net Profit = $200,000

Next, we calculate the ROI:

ROI = (Net Profit / Initial Investment) * 100

ROI = ($200,000 / $1,000,000) * 100

ROI = 0.2 * 100

ROI = 20%

Jennifer Aniston's return on investment for this property is 20%.

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The word isometric can be broken into two parts. The prefix "iso-” means "of the same,” and "-metric” means "measure.” How does the meaning of the word isometric relate to determining if an isometric transformation occurred? Include the defining characteristics of angle measure and line segments in your response.

Answers

The term "isometric" has the Greek roots "isos," which means "same," and "metron," which means "measure." The definition of an isometric transformation is one in which the original figure and its transformed equivalent have the same shape, size, and orientation.

When we speak about geometric figures, the concept of shape, size, and orientation come into play.The defining characteristics of angle measure and line segments play a critical role in determining whether an isometric transformation has occurred. In geometry, angle measures are the measurements of angles in a geometric figure. An angle is formed by two line segments that share a common endpoint. It is a unit used to calculate the measure of a plane figure's interior or exterior, such as a polygon. In other words, the size of the angle doesn't change during an isometric transformation.Line segments are the building blocks of geometric figures. They are used to construct geometric figures such as polygons, triangles, and rectangles, among others. In an isometric transformation, the length of the line segments remains constant because the shape and size of the original figure and its transformed equivalent remain the same.In conclusion, the word "isometric" implies that the transformation has the same measurements of the original figure. It is a transformation that retains the original geometric figures' shape, size, and orientation. The defining characteristics of angle measure and line segments remain unchanged during the isometric transformation. This means that if an isometric transformation occurs, the original and transformed figures have the same measurements of angles and line segments.

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Can I get help on 1 and 2

Can I get help on 1 and 2

Answers

Answer:

1.the slope is 1/2 and the y int is -4

2.the slope is -3 and the y int is 6

Enter a positive value for d that makes this statement true: 34×d is less than 34 but greater than zero HELP PLSS FASTT

Answers

Answer:

0.5 (any number between 0 and 1)

Step-by-step explanation:

34 * 0.5 = 17

34 > 17 > 0

Tickets for the community fair cost $12 for adults and $5 dollars for children. On the first day of the fair, 322 tickets were sold for a total of $2,254. How many adult tickets and how many child tickets were sold?

Answers

92 adult tickets were sold

230 child tickets were sold

Explanation

Step 1

set the equations

let x represents the number of adult tickets sold

let y represents the number of child tickets sold

cost of adult ticket: 12

cost for child ticket : 5

so

a)On the first day of the fair, 322 tickets were sold

so

\(x+y=322\rightarrow equation(1)\)

b)total of $2,254

\(12x+5y=2254\rightarrow equation(2)\)

Step 2

Solve the equations:

\(\begin{gathered} x+y=322\rightarrow equation(1) \\ 12x+5y=2254\rightarrow equation(2) \end{gathered}\)

a) isolate x in equation (1) and then replace in eqaution(2)

\(\begin{gathered} x+y=322\rightarrow equation(1) \\ x=322-y \end{gathered}\)

replace in equation (2)

\(\begin{gathered} 12x+5y=2254\rightarrow equation(2) \\ 12(322-y)+5y=2254 \\ 3864-12y+5y=2254 \\ \text{add like terms} \\ 3864-7y=2254 \\ 3864-2254=7y \\ 1610=7y \\ \text{divide both sides by 7} \\ \frac{1610}{7}=\frac{7y}{t} \\ 230=y \end{gathered}\)

b) now, replace the y value in equation (1) and solve for x

\(\begin{gathered} x+y=322\rightarrow equation(1) \\ x+230=322\rightarrow equation(1) \\ x=322-230 \\ x=92 \end{gathered}\)

therefore

92 adult tickets were sold

230 child tickets were sold

I hope this helps you

Katye received 15 gifts and a total of $100 in cash for her birthday. She buys one book that costs $23, and she wants to donate $10 to each of several local charities. How much money will Katye have left over if she donates to as many charities as possible?Describe steps you would use to solve the problem. You do not need to find the answer.

Answers

Answer:

To solve this problem, we need to subtract the cost of the book and the total amount donated to charities from the total amount of cash Katye received for her birthday. Here are the steps:

Add up the value of the gifts Katye received:

Total value of gifts = (value of gift 1) + (value of gift 2) + ... + (value of gift 15)

Add up the value of the cash Katye received:

Total cash = $100

Subtract the cost of the book from the total cash:

Cash remaining after buying the book = $100 - $23

Determine the maximum number of $10 donations that Katye can make:

Maximum number of $10 donations = (cash remaining after buying the book) / $10

Multiply the maximum number of donations by $10 to get the total amount donated:

Total amount donated = (maximum number of $10 donations) x $10

Subtract the cost of the book and the total amount donated from the total cash:

Cash remaining = $100 - $23 - (total amount donated)

The final answer will be the cash remaining after these calculations

what is the perpendicular and parallel lines of y= -2 -4x

Answers

y=1/4x-2 is a perpendicular line and y=-4x+3 is a parallel line.

The equation y= -2 -4x in the form of slope intercept form y=mx+b is y=-4x-2.

Where m represents the slope and y intercept is -2.

The slope of a line perpendicular to another line is the negative reciprocal of the slope of the given line.

The negative reciprocal of -4 is 1/4.

Therefore, the slope of the perpendicular line is 1/4.

The perpendicular line is y=1/4x-2.

We know that the parallel lines have same slope.

y=-4x+3

Hence, y=1/4x-2 is a perpendicular line and y=-4x+3 is a parallel line.

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2. Which pair of angles is not congruent? F. ∠1 and ∠7 G. ∠3 and ∠5 H. ∠4 and ∠6 I. ∠2 and ∠5

2. Which pair of angles is not congruent? F. 1 and 7 G. 3 and 5 H. 4 and 6 I. 2 and 5

Answers

Answer:

I) ∠2 and ∠5

Step-by-step explanation:

first principle derivative of √cosecx​

Answers

Answer:

• from first principles rule:

\({ \boxed{ \bf{ \frac{ \delta y}{ \delta x} = {}^{lim _{x} } _{h \dashrightarrow0} \: \frac{f(x + h) - f(x)}{h} }}}\)

• f(x) → (csc x)^½

• f(x + h) → {csc (x + h)}^½

\({ \rm{ \frac{ \delta y}{ \delta x} = {}^{lim _{x} } _{h \dashrightarrow0} \: \frac{ \{\csc(x + h) \} {}^{ \frac{1}{2} } - (\csc x ) {}^{ \frac{1}{2} } }{h} }} \\ \\ \hookrightarrow \: { \tt{rationalise : }} \\ \\ = { \rm{{}^{lim _{x} } _{h \dashrightarrow0} \: \frac{ \csc(x + h) - \csc x }{h \{ \{\csc(x + h) \} {}^{ \frac{1}{2} } + ( \csc x) {}^{ \frac{1}{2} } \} } }} \\ \\ = { \rm{{}^{lim _{x} } _{h \dashrightarrow0} \: \frac{1 - (\sin (x + h))( \csc x)}{h \{ \sin(x + h) \} \{ \csc(x + h) \} {}^{ \frac{1}{2} } \{ \csc x \} {}^{ \frac{1}{2} } }}} \\ \\ = { \rm{ = { \rm{{}^{lim _{x} } _{h \dashrightarrow0} \: \frac{1 - ( \sin(x) \cos(h) + \cos(x) \sin(h)) \csc x }{h \{ \sin(x + h) \} \{ \csc(x + h) \} {}^{ \frac{1}{2} } \{ \csc x \} {}^{ \frac{1}{2} } }}} }} \\ \\ = { \rm{ = { \rm{{}^{lim _{x} } _{h \dashrightarrow0} \: \frac{1 - \cos(h) + \cot(x) \sin(h) }{h \{ \sin(x + h) \} \{ \csc(x + h) \} {}^{ \frac{1}{2} } \{ \csc x \} {}^{ \frac{1}{2} } }}} }} \\ \\ { \tt{but : \sin(h) \approx h}} \\ { \tt{ : \cos(h) \approx 1 }} \\ \\ = { \rm{{{}^{lim _{x} } _{h \dashrightarrow0 \: } \: \frac{h \cot(x) }{h \{ \sin(x + h) \} \{ \csc(x + h) \} {}^{ \frac{1}{2} } \{ \csc x \} {}^{ \frac{1}{2} } } }}} \\ \\ { \tt{h \: tends \: to \: 0}} \\ \\ { \boxed{ \rm{ \frac{dy}{dx} = - \frac{1}{2 \sqrt{ \cot(x) \csc(x) } } }}}\)

Tasha used the pattern in the table to find the value of 4 Superscript negative 4.

Powers of 4
Value
4 squared
16
4 Superscript 1
4
4 Superscript 0
1
4 Superscript negative 1
One-fourth
4 Superscript negative 2
StartFraction 1 Over 16 EndFraction

She used these steps.

Step 1 Find a pattern in the table.
The pattern is to divide the previous value by 4 when the exponent decreases by 1.
Step 2 Find the value of 4 Superscript negative 3.
4 Superscript negative 3 = StartFraction 1 Over 16 EndFraction divided by 4 = StartFraction 1 Over 16 EndFraction times one-fourth = StartFraction 1 Over 64 EndFraction
Step 3 Find the value of 4 Superscript negative 4.
4 Superscript negative 4 = StartFraction 1 Over 64 EndFraction divided by 4 = StartFraction 1 Over 64 EndFraction times one-fourth = StartFraction 1 Over 256 EndFraction
Step 4 Rewrite the value for 4 Superscript negative 4.
StartFraction 1 Over 256 EndFraction = negative StartFraction 1 Over 4 Superscript negative 4 EndFraction

Answers

The value of 4 Superscript negative 4 is negative StartFraction 1 Over 4 Superscript negative 4 EndFraction.

In the given table, Tasha observed a pattern in the powers of 4. When the exponent decreases by 1, the previous value is divided by 4. Using this pattern, she determined the values for 4 squared, 4 Superscript 1, 4 Superscript 0, 4 Superscript negative 1, and 4 Superscript negative 2.

To find the value of 4 Superscript negative 3, she divided the previous value (StartFraction 1 Over 16 EndFraction) by 4, resulting in StartFraction 1 Over 64 EndFraction.

Similarly, for 4 Superscript negative 4, she divided the previous value (StartFraction 1 Over 64 EndFraction) by 4, yielding StartFraction 1 Over 256 EndFraction.

Finally, to rewrite the value for 4 Superscript negative 4, she expressed it as negative StartFraction 1 Over 4 Superscript negative 4 EndFraction.

Therefore, the value of 4 Superscript negative 4 is negative StartFraction 1 Over 4 Superscript negative 4 EndFraction, which simplifies to StartFraction 1 Over 256 EndFraction

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Find the volume of the solid generated by revolving the region bounded by the lines and curves about the x-axis. y = x, y =1, x = 0

Answers

Answer:

The volume is: \(V = \frac{\pi}{3}\) cubic units

Step-by-step explanation:

Volume of a solid:

The volume of a solid, given by the function f(x), over an interval between a and b, is given by:

\(V = \pi \int_{a}^{b} (f(x))^2 dx\)

y = x, y =1, x = 0

This means that the upper function is y = 1, and the lower function is y = x. So

\(f(x) = (1 - x)\)

The lower limit of integration is x = 0.

The upper limit is y = x when y = 1, so x = 1.

Then

\(V = \pi \int_{a}^{b} (f(x))^2 dx\)

\(V = \pi \int_{0}^{1} (1-x)^2 dx\)

\(V = \pi \int_{0}^{1} (1-2x+x^2) dx\)

\(V = \pi (x-x^2+\frac{x^3}{3})|_{0}^{1} dx\)

\(V = \pi(1 - (1^2) + \frac{1^3}{3})\)

\(V = \frac{\pi}{3}\)

Christina is buying a $170,000 home with a 30-year mortgage. She makes a $20,000 down payment.
Use the table to find her monthly PMI payment.
A. $51.25
B. $37.50
C. $23.75
D. $42.50

Christina is buying a $170,000 home with a 30-year mortgage. She makes a $20,000 down payment.Use the

Answers

The monthly PMI Payment for Christina's loan is $37.50.The correct answer is option B.

To determine Christina's monthly PMI (Private Mortgage Insurance) payment, we need to find the corresponding interest rate for her loan-to-value (LTV) ratio. The LTV ratio is calculated by dividing the loan amount by the property value.

The loan amount can be calculated by subtracting the down payment from the property value:

Loan amount = Property value - Down payment

           = $170,000 - $20,000

           = $150,000

Now we can calculate the LTV ratio:

LTV ratio = Loan amount / Property value * 100

         = $150,000 / $170,000 * 100

         = 88.24%

Since Christina is obtaining a 30-year mortgage, we need to look at the interest rates for LTV ratios between 85.01% and 90%. According to the table, the interest rate for this range is 0.30%.

To calculate the PMI payment, we multiply the loan amount by the PMI rate and divide it by 12 months:

PMI payment = (Loan amount * PMI rate) / 12

           = ($150,000 * 0.30%) / 12

           = $450 / 12

           = $37.50

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The Probable question may be:
Christina is buying a $170,000 home with a 30-year mortgage. She makes a $20,000 down payment.

Use the table to find her monthly PMI payment

Base to loan% = 95.01% to 97%,90.01% to 95%,85.01% to 90%,80.01% to 85%.

30-year fixed-rate loan = 0.55%,0.41%,0.30%,0.19%

15-year fixed-rate loan = 0.37%,0.28%,0.19%,0.17%.

A. $51.25

B. $37.50

C. $23.75

D. $42.50

For #81-84, fill in the missing dimensions from the given expression. Then rewrite the
expression as a product.
2x+24
(81.)
(82.)
2x
(83.)
84. Expression as a product
Choices for 81-84:
A) 2
E) 12
AE) 2x
CD) 4x(x+4)
24
B) 4
AB) 14
BC) 4x
CE) 2(2x+9)
C) 6
AC) 16
BD) 4(x+6)
DE) 2(x+12)
D) 9
AD)
x
BE) 2(2x+16)
ABC) 4x(x+14)

For #81-84, fill in the missing dimensions from the given expression. Then rewrite theexpression as a

Answers

The missing dimensions from the given expression should be completed with the following:

(81.) A) 2

(82.) AD) x

(83.) E) 12

The expression as a product should be written as: DE) 2(x + 12).

What is a factored form?

In Mathematics and Geometry, a factored form can be defined as a type of quadratic expression that is typically written as the product of two (2) linear factors and a constant.

In this scenario and exercise, we would complete the table above by showing the factored form and expanded form of each of the given expressions as follows;

        x           12

2      2x         24

Note: 2x/2 = x.

         24/2 = 12.

(2x + 24) = 2(x + 12).

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perform the indicated operation 5/17 • 3/8 I really need explanation on how to do the problem when I need to do it alone

Answers

To multiplicate two fractions, you have to multiply their numerator and denominator, like this:

\(\frac{5}{17}\times\frac{3}{8}=\frac{15}{136}\)

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times the inverse tangent of the quantity x squared divided by 4, plus C one fourth times the natural log of x to the 4th power plus 16, plus C one fourth times the inverse tangent of the quantity x squared divided by 4, plus C the product of negative one fourth and 1 over the quantity squared of x squared plus 16, plus C

Answers

Answer:

\(\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c\)

Step-by-step explanation:

Given

\(\int\limits {\frac{x}{x^4 + 16}} \, dx\)

Required

Solve

Let

\(u = \frac{x^2}{4}\)

Differentiate

\(du = 2 * \frac{x^{2-1}}{4}\ dx\)

\(du = 2 * \frac{x}{4}\ dx\)

\(du = \frac{x}{2}\ dx\)

Make dx the subject

\(dx = \frac{2}{x}\ du\)

The given integral becomes:

\(\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du\)

\(\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du\)

\(\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du\)

Recall that: \(u = \frac{x^2}{4}\)

Make \(x^2\) the subject

\(x^2= 4u\)

Square both sides

\(x^4= (4u)^2\)

\(x^4= 16u^2\)

Substitute \(16u^2\) for \(x^4\) in \(\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du\)

\(\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du\)

Simplify

\(\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du\)

\(\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du\)

\(\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du\)

In standard integration

\(\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)\)

So, the expression becomes:

\(\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du\)

\(\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)\)

Recall that: \(u = \frac{x^2}{4}\)

\(\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c\)

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