2. (a) Explain the difference between welding and casting processes in general. (b) Looking at the engineering side and economic side, how do you think for a selection process of joining on steel plat

Answer:

Explanation:

Work, U, is equal to the force times the distance:

U = F · r

Force needed to lift the weight, is equal to the weight: F = W = m · g

so:

U = m · g · r

   = 20.4kg · 9.81 \(\frac{N}{kg}\) · 1.50m

   = 35.316 \(\frac{N}{m}\)

   = 35.316 W

Answer:

Sorry whats the question

Explanation:

2.56% benzene, 53.8% toluene, and 43.6% xylene make up the molar composition of the bottom stream from the second column.

The first step in resolving this issue is to determine the moles of benzene, toluene, and xylene in the top stream from the first column, followed by determining the moles of toluene and xylene in the top stream from the second column.

Benzene moles in the first column's top stream are equal to 0.225 moles (0.75 * 0.30).

0.35 * 0.30 = 0.105 moles of toluene in the top stream of the first column.

Moles of xylene in the first column's top stream are calculated as follows: 0.30 - 0.225 - 0.105 = 0.07 moles.

Then, in the bottom stream, we will locate the moles of benzene, toluene, and xylene.

Benzene moles in the first column's bottom stream: 0.30 - 0.225 = 0.075 moles.

Moles of toluene in the first column's bottom stream equal 0.35 moles.

Moles of xylene in the first column's bottom stream are equal to 0.225 moles (0.30 + 0.35 + 0.075).

By converting these mole fractions to percentages, we can finally:

Toluene is 0.538 times 100 and xylene is 0.436 times 100, giving a total of 2.56% for benzene and 0.538 for toluene.

As a result, 2.56% benzene, 53.8% toluene, and 43.6% xylene make up the bottom stream from the second column's molar composition.

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The flow rate through the bend may be calculated using these equations to be 7.01 ft3/s, and the y-direction anchoring force needed to keep the bend in place is 674 pounds.

General solutions to the issue.

Step 1: Calculate the flow rate through the bend using Bernoulli's equation.

Step 2: Calculate the y-direction anchoring force necessary to hold the bend in place using the momentum equation.

Step 3: Hold the bend in place using the x-direction and y-direction anchoring forces.

The common equations that can be applied are:

Bernoulli's equation: P1 + 0.5 rhov 1 + rhogh 1 = P2 + 0.5 rhov 2 + rhogh 2 where P1 = pressure at inlet, v1 = velocity at inlet, h1 = height at inlet, P2 = pressure at outlet, v2 = velocity at outlet, h2 = height at outlet, rho = fluid density, and g = gas constant.

the speeding up caused by gravity.

FAY is the y-direction anchoring force, Q is the flow rate, v1 is the velocity at the inlet, and v2 is the velocity at the outlet. The momentum equation is FAY = rhoQ(v2 - v1).

It should be noted that the flow rate through the bend is calculated independently of the x-direction anchoring force.

The flow rate through the bend may be calculated using these equations to be 7.01 ft3/s, and the y-direction anchoring force needed to keep the bend in place is 674 pounds.

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The flow rate through the bend is 7.01 ft^3/s, and the y-direction anchoring force, FAY required to hold the bend in place is 674 lbs. in.

To solve this problem, we can use the Bernoulli equation to relate the pressure and velocity of the water at different points along the bend. We can then use the conservation of mass equation to find the flow rate through the bend.

Using the given pressure gauge reading of 10 psi, we can determine the velocity of the water at point A using the Bernoulli equation. Solving for the velocity yields 34.77 ft/s. Using this velocity and the given geometry of the bend, we can determine the area of the flow at point A as 0.2019 ft^2.

Using the conservation of mass equation, we can relate the flow rate at point A to the flow rate at point B. Solving for the flow rate at point B yields 7.01 ft^3/s.

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Folds are an example of ductile deformation. Ductile deformation is a type of solid-state deformation that occurs when a material undergoes plastic deformation. It occurs at high temperatures and pressures. Folds are an example of ductile deformation because they result from the plastic deformation of rocks in response to compressional forces.

They form in areas where rocks are subjected to compressional stresses over a long period of time, causing them to bend and fold.The process of folding involves the bending of rocks into a series of curves or undulations. This occurs as a result of the plastic deformation of the rocks, which allows them to deform without breaking. Folds are classified based on their shape, size, and orientation. They can be symmetrical, asymmetrical, or overturned, and they can occur on a small or large scale.

Folds are an important geological feature because they provide clues about the history of the rocks and the tectonic forces that have acted on them. By studying the orientation and shape of folds, geologists can learn about the direction and intensity of the forces that caused them to form. This information can be used to reconstruct the geologic history of an area and to predict the behavior of rocks under different stress conditions.

In conclusion, folds are an example of ductile deformation, which is a type of solid-state deformation that occurs when a material undergoes plastic deformation. Folds form in response to compressional forces and are an important geological feature that provides clues about the history of the rocks and the tectonic forces that have acted on them.

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Answer:

a. True

Explanation:

Apply the principle of conservation of mass.

and also the expression for the steady flow energy equation.

kinetic and potential energy effects can be neglected.

The given statement by the inventor who is claiming the development of a device that requires no work or heat transfer input yet is able to produce hot and cold air streams at a steady state is definitely false.

Heat transfer may be characterized as a type of process which involves the migration of heat from one object or component to another by numerous mechanisms like conduction, convection, and/or radiation.

The process of heat transfer may occur where there is a temperature difference between two objects exist. It significantly utilizes the mechanism of exchanging thermal energy between two or more physical systems.

According to the concept of physics, no object or thing has the ability to perform its function without the utilization of any source of heat or energy. Then, how it is possible for that device to produce hot and cold air streams at a steady state.

Therefore, the given statement by the inventor is absolutely false.

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Answer:

A = 5h (B + b); solve for B.

2

Answer:

116,090 Btus

Explanation:

The largest torque that can be applied at point A without exceeding the allowable shear stress for either rod is T=44.99 k-in.

The largest torque that can be applied at point A can be determined by using the equation for shear stress of a shaft:
τ=T/J
where τ is the shear stress, T is the applied torque, and J is the polar second moment of inertia.

For the 1.5-in.-diameter steel rod AB:
J=(π/32)D4
where D is the diameter of the rod, so for a 1.5-in. rod, J=(π/32)(1.5)4=3.704 in4.

So, the largest torque that can be applied at point A while maintaining a shear stress of 15 ksi is T=(15 ksi)(3.704 in4)=55.56 k-in.

For the 1.8-in.-diameter brass rod BC:
J=(π/32)D4
where D is the diameter of the rod, so for a 1.8-in. rod, J=(π/32)(1.8)4=5.848 in4.

So, the largest torque that can be applied at point A while maintaining a shear stress of 7.7 ksi is T=(7.7 ksi)(5.848 in4)=44.99 k-in.

Therefore, the answer is T=44.99 k-in.

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Explanation:

dnndndndndndndndndnndmfnfnf

Answer:

The plan is to make your design on AutoCAD and then make technical drawings. Print those technical drawings out with a scale of 1:1 and use those to trace over wood or metal.

Explanation:

Answer:

Make your design, make technical drawings, 3D print or trace

Explanation:

Answer:

1218.75

Explanation: If he makes a 25% profit, he needs to sell it for 125% of the computer price. 1.25*975 is 1218.75

Note that in this case, as far as the water pump and the gaskets are concerned, Neither technician A nor B is correct. (Option D)

A gasket is a mechanical seal that fills the gap between two or more mating surfaces, preventing leakage from or into the connected items while they are compressed.

Water pump gaskets are placed between the water pump and the engine block NOT between the water pump and the oil pan.

Technician B is mistaken when he says the oil pan gasket keeps water out of the cylinder. The oil pan gasket is in charge of keeping oil inside the oil pan and avoiding leaks. It serves no purpose in keeping water out of the cylinder.

Hence, the correct answer is Option D.

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Full Question:

Technician A states that water pump gaskets are located between the water pump and the oil pan. Technician B states that the oil pan gasket keeps oil in the cylinder and water out of the cylinder. Which technician is correct?

A) Technician A
B) Technician B
C) Technicians A and B
D) Neither Technician A or B

The heat transfer rate with insulation is significantly higher than the heat transfer rate without insulation, as can be shown by comparing the two heat transfer rates.

The table shows that solids (s) generally conduct heat at rates that are significantly higher than those of liquids (l) and gases (g).

The following equation can be used to determine the heat transfer rate without insulation under the conditions of steady-state heat transmission and little heat generation in the wire:

A = pidL A = pi0.0831 = 0.26 square inches. Q = hA(T wire - T inf).

Q = 2.50.26(90 - 50) = 26 Btu/h without insulation R = 0.02 / (0.075×0.26) = 0.98 hrft2°F/Btu

Copper, which is frequently used for electrical cables, has a thermal conductivity of roughly 223 Btu/hft°F. Inputting the values provided yields:

R total = 1 / (2230.26pi×0.0832 / 4) = 0.14 hours/feet/degrees Fahrenheit/Btu

We obtain the following by substituting the above values: q with insulation = (90 - 50) / 0.14 = 286 Btu/h

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Answer:

they probably have more sidewalks and traffic lights.

Explanation:

a lot of people live in urban areas.

Explanation:

Remember, to say a product is incorporated with aesthetic design implies that its overall appearance is designed to look beautiful to the eyes of the user/buyer. For example, a clothing company whose target market is mainly focused on women's clothing would need to take into consideration that certain colors like pink, blue, etc are attractive to women more than men. So they'll have to ensure the colors of their clothing are suitable to the needs of their target market.

The Universal Design process involves building products that can be used by a wide range of users at ease. For example, you may ask yourself: Is my product/service easily accesible to those with disabilities?

Other processes include;

Answer:

Option 1

Explanation:

As the team has already submitted the plans for the part drawing, the best way to proceed would be how it was given in the plans. Hence, the option to be selected :

Answer:

The first option

Explanation:

Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.

Answer:

\(Length =3\)   \(Height = 2\)   and  \(Width = \frac{3}{2}\)

Explanation:

Given

\(Volume = 9m^3\)

Represent the height as h, the length as l and the width as w.

From the question:

\(Length = 2 * Width\)

\(l = 2w\)

Volume of a box is calculated as:

\(V = l*w*h\)

This gives:

\(V = 2w *w*h\)

\(V = 2w^2h\)

Substitute 9 for V

\(9 = 2w^2h\)

Make h the subject:

\(h = \frac{9}{2w^2}\)

The surface area is calculated as:

\(A = 2(lw + lh + hw)\)

Recall that: \(l = 2w\)

\(A = 2(2w*w + 2w*h + hw)\)

\(A = 2(2w^2 + 2wh + hw)\)

\(A = 2(2w^2 + 3wh)\)

\(A = 4w^2 + 6wh\)

Recall that: \(h = \frac{9}{2w^2}\)

So:

\(A = 4w^2 + 6w * \frac{9}{2w^2}\)

\(A = 4w^2 + 6* \frac{9}{2w}\)

\(A = 4w^2 + \frac{6* 9}{2w}\)

\(A = 4w^2 + \frac{3* 9}{w}\)

\(A = 4w^2 + \frac{27}{w}\)

To minimize the surface area, we have to differentiate with respect to w

\(A' = 8w - 27w^{-2}\)

Set A' to 0

\(0 = 8w - 27w^{-2}\)

Add \(27w^{-2}\) to both sides

\(27w^{-2} = 8w\)

Multiply both sides by \(w^2\)

\(27w^{-2}*w^2 = 8w*w^2\)

\(27 = 8w^3\)

Make \(w^3\) the subject

\(w^3 = \frac{27}{8}\)

Solve for w

\(w = \sqrt[3]{\frac{27}{8}}\)

\(w = \frac{3}{2}\)

Recall that : \(h = \frac{9}{2w^2}\)   and \(l = 2w\)

\(h = \frac{9}{2 * \frac{3}{2}^2}\)

\(h = \frac{9}{2 * \frac{9}{4}}\)

\(h = \frac{9}{\frac{9}{2}}\)

\(h = 9/\frac{9}{2}\)

\(h = 9*\frac{2}{9}\)

\(h= 2\)

\(l = 2w\)

\(l = 2 * \frac{3}{2}\)

\(l = 3\)

Hence, the dimension that minimizes the surface area is:

\(Length =3\)   \(Height = 2\)   and  \(Width = \frac{3}{2}\)

The temperature of R-134a at the exit of the compressor cannot be determined without additional information such as the specific enthalpy-temperature relationship or properties table for R-134a.

To determine the temperature of R-134a at the exit of the compressor, we need to use the given data and the properties of the refrigerant.

First, we convert the flow rate from m³/min to m³s:

Next, we can use the compressor power and the flow rate to calculate the specific work done on the refrigerant:

Given that the power supplied to the refrigerant during compression is 2.4 kW, we have:

Now, we can use the pressure and specific volume of the refrigerant at the exit of the compressor to determine the temperature.

Using the pressure and specific volume values at the exit:

We can calculate the specific enthalpy at the exit using the refrigerant properties table or equations specific to R-134a.

Finally, using the specific enthalpy and pressure at the exit, we can determine the temperature of R-134a at the exit of the compressor.

Please note that the specific enthalpy-temperature relationship for R-134a can vary depending on the specific formulation and properties data used, so it is essential to refer to reliable sources or tables specific to R-134a to obtain accurate values.

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The statement "The ASTM system is one set of pipe and fittings that carries away wastewater and solid waste" is FALSE.

What is the ASTM system?ASTM stands for the American Society for Testing and Materials. It is a globally recognized organization that develops and publishes technical standards for various materials, including pipes and fittings for drainage and wastewater systems. The ASTM standards establish product specifications, test methods, and performance criteria, as well as best practices for installation, operation, and maintenance.ASTM standards are commonly used in the construction industry to ensure the quality, safety, and reliability of building materials and systems. They cover a broad range of applications, including concrete, steel, timber, plastics, and more.In the case of pipes and fittings for drainage and wastewater systems, ASTM has established several standards, such as ASTM D2729, ASTM D3034, ASTM F679, and ASTM F758, among others. These standards define the material properties, dimensions, joint types, and performance requirements for pipes and fittings used in gravity-flow systems to transport wastewater, stormwater, and solids from buildings and infrastructure to treatment plants or disposal areas.

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The given statement "The ASTM system is one set of pipe and fittings that carries away wastewater and solid waste" is true.

ASTM is the abbreviated form of the American Society for Testing and Materials. It is a global leader in the development of voluntary consensus standards for products, services, systems, and materials. These standards are used to define and measure quality in everything from construction materials to medical devices, to ensure that products are safe and reliable.

The ASTM system is a single set of pipes and fittings that is utilized for conveying wastewater and solid waste from one location to another. The ASTM system includes fittings that can be joined together without the need for special tools or welding. This system is used in industrial, commercial, and residential settings.

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The signal-to-noise ratio (S/N) would be approximately 15.5 if ensemble averaging of 256 spectra is performed.

When taking a single scan of an NMR spectrum and calculating the signal-to-noise ratio (S/N) to be 1.2, it indicates that the signal amplitude is 1.2 times greater than the noise level. However, by performing ensemble averaging of 256 spectra, we can significantly improve the S/N ratio.

Ensemble averaging involves taking multiple spectra and adding them together, effectively increasing the signal while keeping the noise level relatively constant. When averaging a large number of spectra, the signal amplitudes accumulate, resulting in a higher overall signal. On the other hand, the random noise contributions tend to average out due to their statistical nature.

By averaging 256 spectra, the signal will be enhanced by a factor of 256, while the noise will only increase by a factor equal to the square root of 256, which is 16. Therefore, the resulting S/N ratio would be approximately 256/16, or 15.5.

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Technician A says that a scan tool is commonly used to pinpoint electronically controlled transmission noise issues. Technician B says that the PCM/TCM controls gear selection on an electronically controlled transmission. Both technicians are correct.

A technician is a person that is expert of technical instruments. He has the knowledge to repair technical issues.

Both Technicians are correct because the one is talking about scan tool which is correct and PCM/TCM are used in gears related to vehicles.

Thus, Technician A and Technician B are correct.

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You need to configure a DNS A record for the intranet site's hostname to map it to the correct IP address.

What is DNS?
DNS, or Domain Name System, is an internet protocol used to translate domain names, such as www.example.com, into IP addresses, such as 192.168.2.1, that computers can understand and use to communicate with each other. DNS acts as a directory service, providing a link between domain names and their associated IP addresses, which are stored and managed in a distributed database system. DNS is essential for the functioning of the internet, allowing users to access websites and services without having to remember their numerical IP addresses. DNS works by querying a distributed network of DNS servers, which maintain a database of IP addresses and their corresponding domain names. When a DNS query is made, the DNS server looks up the requested IP address in its database and returns it to the user. DNS is an important part of the internet infrastructure and is used by many different types of services, such as email, web hosting, and streaming services.

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In terms of angular size, the Moon and the Sun are similar. Only when the Moon is new can there be a solar eclipse.

Around noon and midnight, the first quarter moon rises and sets. When the sun is setting and the moon is at its greatest point in the sky, this is the finest moment to view the first quarter moon. It can also be seen in the early afternoon, close to the horizon.

The Moon's first quarter is when we can see half of its illuminated surface and half of its shadow.

The day after a total lunar eclipse, one can observe the Moon in its first quarter phase. In terms of angular size, the Moon and the Sun are similar. Only when the Moon is new can there be a solar eclipse. Only when the Moon is new does a lunar eclipse take place.

Therefore, the statement is true.

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Answer:

no, the pure fission bomb is a hydrogen bomb

Answer: a pure fission bomb is not a nuclear

bomb

Explanation: fusion is the combining of hydrogen particles, whereas fission is the splitting of atoms.

In addition to a proper air void system and strength level, a concrete mixture must contain durable Aggregates in order to perform adequately in a freeze-thaw service environment. The correct option is A.

The inert components known as aggregates, which are combined with cement and water to create concrete, are essential to increasing the strength and resilience of the concrete to freeze-thaw cycles.

Aggregates give concrete structure and strength, but they also affect how well it holds up in challenging conditions. Concrete may become moistened in freeze-thaw circumstances, which will make it expand when it freezes. The concrete may crack and deteriorate as a result of this expansion.

Thus, the ideal selection is option A.

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Answer:

a) The ductility = -30.12%

the negative sign means reduction

Therefore, there is 30.12% reduction

b) the true stress at fracture is 658.26 Mpa

Explanation:

Given that;

Original diameter \(d_{o}\) = 12.8 mm

Final diameter \(d_{f}\) = 10.7

Engineering stress  \(\alpha _{E}\) = 460 Mpa

a) determine The ductility in terms of percent reduction in area;

Ai = π/4(\(d_{o}\) )²  ; Ag = π/4(\(d_{f}\) )²

% = π/4 [ ( (\(d_{f}\) )² - (\(d_{o}\) )²) / ( π/4  (\(d_{o}\) )²) ]

= ( (\(d_{f}\) )² - (\(d_{o}\) )²) / (\(d_{o}\) )² × 100

we substitute

= [( (10.7)² - (12.8)²) / (12.8)² ] × 100

= [(114.49 - 163.84) / 163.84 ] × 100

= - 0.3012 × 100

= -30.12%

the negative sign means reduction

Therefore, there is 30.12% reduction

b) The true stress at fracture;

True stress  \(\alpha _{T}\) = \(\alpha _{E}\) ( 1 +  \(E_{E}\) )

\(E_{E}\)  is engineering strain

\(E_{E}\)  = dL / Lo

= (do² - df²) / df² = (12.8² - 10.7²) / 10.7² = (163.84 - 114.49) / 114.49

= 49.35 / 114.49  

\(E_{E}\) = 0.431

so we substitute the value of \(E_{E}\)  into our initial equation;

True stress  \(\alpha _{T}\) = 460 ( 1 +  0.431)

True stress  \(\alpha _{T}\) = 460 (1.431)

True stress  \(\alpha _{T}\) = 658.26 Mpa

Therefore, the true stress at fracture is 658.26 Mpa

Answer:

8.24μm

Explanation:

The theory of brittle fracture was used to solve this problem.

And if you follow through with the attachment made a the subject of the formula

Such that,

a = 2x(69x10⁹)x0.3/pi(40x10⁶)²

= 4.14x10¹⁰/5.024x10¹⁵

= 8.24x10^-06

= 8.24μm

This is the the maximum length of the surface flaw

Tech b says that many oxygen sensors have a built-in heater to warm them up more quickly - correct

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