13. write the balanced net ionic equations for the following reactions in acidic solution. a. mg(s) + vo4 3- (aq) → mg2+(aq) + v2+(aq) b. i - (aq) + io3 - (aq) → i3 - (aq)

Answer: The water will taste sour.

Explanation:

Answer: D. The water will taste sour (Edmentum)

Explanation:

Answer:

Asexual reproduction is faster than sexual reproduction

Answer:

Asexual reproduction is faster than sexual reproduction which is d

Explanation:

Answer a

acid-base

Answer b

oxidation-reduction: Na is oxidized, H+ is reduced

Answer c

oxidation-reduction: Mg is oxidized, Cl2 is reduced

Answer d

acid-base

Answer e

oxidation-reduction: P3− is oxidized, O2 is reduced

Answer f

acid-base

Yes, it affects the body’s ability to grow and repair cells.

As insulin is a hormone that turns glucose into energy for cellular functions through the process of cellular respiration, the blood glucose level rises when insulin is not produced in sufficient amounts or cells are unable to use the insulin.

The increased blood glucose levels impede the healing of wounds or prevent them from healing or repairing. In such a diabetic case, a small foot wound can grow into a foot ulcer very quickly. When blood sugar levels are high, blood vessels stiffen or constrict, slowing the flow of oxygen through the body in diabetics.

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Answer:

29.27M

Explanation:

Molar concentration can be calculated using the formula;

Molar concentration (molarity) = number of moles ÷ volume

Mole = mass ÷ molar mass

Where;

Molar Mass of glucose (C6H12O6) = 180.156g/mol

Mass = 433g

Mole = 433/180.156

Mole = 2.40moles

Volume = 82mL

Since 1L = 1000mL

82mL = 82/1000

= 0.082L

Molar conc. = 2.40mol/0.082L

Molar conc. = 29.27M

Salt, sugar, baking soda, etc. Some also consider honey, tap water, and vegetable oil as pure substances.

The classification of alcohols that can undergo oxidation to yield a ketone is only primary alcohols.

Primary alcohols undergo oxidation to yield aldehydes, which further oxidize to ketones. The oxidation process involves the removal of two hydrogen atoms and the addition of an oxygen atom.

In contrast, secondary and tertiary alcohols do not undergo oxidation to form ketones because they lack the hydrogen atom on the carbon atom directly attached to the hydroxyl group (-OH).

The hydrogen atom on primary alcohols makes them more susceptible to oxidation, allowing them to undergo the oxidation process to form ketones. This reaction is commonly used in organic chemistry to synthesize ketones.

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Answer:4

Explanation: I got it right

According to ideal gas law and kinetic molecular theory,the statement which describes  the characteristic of an ideal gas system is that  straight-line motion of the gas molecules is constant and random.

The ideal gas law is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.

The ideal gas law was proposed by Benoit Paul Emile Clapeyron in the year 1834.He was a physicist and an engineer.It is often written in empirical form.It is called as an ideal gas  equation which is a good approximation of behavior of many gases.It has several limitations.

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Chemicals such as sodium hydroxide and sulfuric acid should be labeled as corrosive, as they can cause severe damage to materials, living tissues, or skin upon contact.

Chemicals such as sodium hydroxide and sulfuric acid should be labeled as corrosive and possibly also as poisonous, depending on their specific properties. These labels are important for ensuring that individuals handling the chemicals are aware of the potential hazards and take appropriate safety measures. Labels may also include information about proper storage and disposal procedures, as well as first aid measures in case of accidental exposure. It is important to always follow label instructions and handle these chemicals with care to avoid injury or damage. They are typically not labeled as explosive unless they have additional properties that make them highly reactive.
 

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Chemicals such as sodium hydroxide and sulfuric acid should be labeled. Yes, chemicals like sodium hydroxide and sulfuric acid should be labeled to ensure proper identification, handling, and storage. Here's a step-by-step explanation:

1. Obtain appropriate labels: Use chemical-resistant labels that are durable and can withstand various environmental conditions.

2. Include the chemical name: Write the full chemical name, such as sodium hydroxide or sulfuric acid, on the label.

3. Indicate the chemical formula: Include the chemical formula (e.g., NaOH for sodium hydroxide, H2SO4 for sulfuric acid) to provide additional information for users.

4. Provide hazard information: Indicate the hazards associated with the chemical, such as corrosive or toxic, using standardized hazard symbols.

5. Include handling and storage information: Provide any specific instructions for handling and storing the chemicals safely.

6. Apply the label: Affix the label to the container in a visible location, ensuring it is secure and cannot be easily removed.

By following these steps, you will ensure that sodium hydroxide and sulfuric acid, as well as other chemicals, are labeled appropriately to promote safe handling and storage.

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Answer:

Explanation:

Mide 2mL de etanol, añadelo a un matraz aforado, pon agua hasta llegar a 100mL

The question requires us to choose the best option to explain why bubbles rise faster from a warm can of soda than a cold can, based on the solubility of gases in liquids.

Adding heat to a solution composed of a liquid and a gas (i.e., increasing its temperature) provides thermal energy to the gas that makes it possible to overcome the forces that maintain molecules of solvent (liquid) and solute (gas) together. In this way, the molecules of solvent and solute tend to separate, therefore decreasing the solubility of the gas. Based on this, we can say that the solubility of gases in liquids increase with increasing temperature.

Therefore, the best option to answer the question is the first one, "gases become less soluble in liquids at higher temperatures".

The formation of 3-chloro-2,2-dimethyl-1-butene, alcohol, ethyl acetylene, ester, and 2-methyl-2-cyclohexene-1-one are the products of the following reactions respectively.

The products and starting materials of the following reactions are,

1. SOCI₂ Stereochemistry: Nucleophilic substitution reaction would occur, in which the nucleophile would be chloride.

2. LiAlH(O⁺Bu) Stereochemistry: The reaction will occur with the reduction of an ester, in which the hydrogen of the hydride reagent would add to the carbonyl group of the ester.

3. NaOEt, EtOH Stereochemistry: A base-catalyzed reaction that would occur with the deprotonation of the acid present.

4. NaOH, H₂O Stereochemistry: A base-catalyzed reaction that would occur with the deprotonation of the acid present.

5. H⁺, heat Stereochemistry: The elimination reaction would occur in which the hydrogen of the alpha-carbon would be eliminated from the ring by forming a double bond.

The products of reactions:

1. The formation of 3-chloro-2,2-dimethyl-1-butene will occur.

2. The reduction of an ester would occur with the formation of

3. The formation of ethyl acetylene would occur.

4. The formation of an ester would occur.

5. The formation of 2-methyl-2-cyclohexene-1-one would occur.

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The correct answer is: a) The reaction could occur at low temperatures but not at higher temperatures.

When a reaction is unfavorable with respect to entropy but favorable with respect to enthalpy, it means that the reaction has a negative change in entropy (ΔS) but a negative change in enthalpy (ΔH). In such cases, temperature plays a crucial role in determining the spontaneity of the reaction.

At low temperatures, the unfavorable entropy change can be overcome by the favorable enthalpy change, resulting in a negative Gibbs free energy change (ΔG = ΔH - TΔS). Since ΔG determines the spontaneity of a reaction, the reaction can occur at low temperatures where the enthalpy change dominates over the entropy change.

However, as the temperature increases, the entropy term (TΔS) in the Gibbs free energy equation becomes more significant. If the entropy change is strongly unfavorable, the positive entropy term can outweigh the negative enthalpy term, resulting in a positive ΔG and making the reaction non-spontaneous at higher temperatures.

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Based on the available resources and profit per unit, producing 266 units of Product 1 would result in the highest total profit of BD 585.20.

To determine the maximum number of units of each product that can be produced given the available resources, we need to compare the resource requirements of the products with the available resources.

Let's calculate the resource requirements for each product:

Product 1:

- Metal sheet: 0.250 m2 per unit

- Glass sheet: 0.120 m2 per unit

- Electrical components: 3 units per unit

Product 2:

- Metal sheet: 0.150 m2 per unit

- Glass sheet: 0.050 m2 per unit

- Electrical components: 2 units per unit

Now let's compare the resource requirements with the available resources:

Metal sheets:

- Product 1 requires 0.250 m2 per unit, so the maximum number of units that can be produced using available metal sheets is 90 m2 / 0.250 m2 = 360 units.

- Product 2 requires 0.150 m2 per unit, so the maximum number of units that can be produced using available metal sheets is 90 m2 / 0.150 m2 = 600 units.

Glass sheets:

- Product 1 requires 0.120 m2 per unit, so the maximum number of units that can be produced using available glass sheets is 30 m2 / 0.120 m2 = 250 units.

- Product 2 requires 0.050 m2 per unit, so the maximum number of units that can be produced using available glass sheets is 30 m2 / 0.050 m2 = 600 units.

Electrical components:

- Product 1 requires 3 units per unit, so the maximum number of units that can be produced using available electrical components is 800 units / 3 units = 266 units.

- Product 2 requires 2 units per unit, so the maximum number of units that can be produced using available electrical components is 800 units / 2 units = 400 units.

Now let's determine the maximum number of units that can be produced for each product based on the limiting resource:

Metal sheets: The maximum number of units that can be produced is 360 units (for Product 1) since it requires a larger area of metal sheets.

Glass sheets: The maximum number of units that can be produced is 250 units (for Product 1) since it requires a larger area of glass sheets.

Electrical components: The maximum number of units that can be produced is 266 units (for Product 1) since it requires a larger number of electrical components.

Since the limiting resource for all three resources is reached with Product 1, the maximum number of units that can be produced for Product 1 is 266 units. As for Product 2, it can be produced up to a maximum of 250 units.

Now let's calculate the profit for each product:

Profit per unit for Product 1: BD 2.200

Profit per unit for Product 2: BD 1.400

Total profit for Product 1: 266 units × BD 2.200 = BD 585.20

Total profit for Product 2: 250 units × BD 1.400 = BD 350.00

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Answer:

.0316

Explanation:

The formula is...

H+ = 10^-pH

- Hope that helps! Please let me know if you need further explanation.

The products in the overall equation for aerobic respiration are ATP (adenosine triphosphate) and CO2 (carbon dioxide).

What is aerobic respiration?

Aerobic respiration is a metabolic process that uses oxygen to convert glucose into energy. During aerobic respiration, glucose (sugar) is broken down in the presence of oxygen (O2) to produce energy in the form of ATP (adenosine triphosphate). This process also produces carbon dioxide (CO2) and water (H2O). The energy produced by aerobic respiration is used to fuel cellular processes such as protein synthesis and muscle contractions. Aerobic respiration is the main form of respiration in humans and other animals.

The overall equation for aerobic respiration is C6H12O6 + 6O2 yields 6CO2 + 6H2O + energy (as ATP). ATP (adenosine triphosphate) and CO2 (carbon dioxide) are products in the overall equation for aerobic respiration. NaOH (natrium hydroxide) and CO (carbon monoxide) are not products in the equation.

Therefore, ATP (adenosine triphosphate) and CO2 (carbon dioxide) are the answers.

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Answer:

An impure substance

Explanation:

Substance means: hard surface example: salt,corals,coal.

The first plateau denotes the solvent's pure boiling point.

Boiling point elevation refers to the increase in a solvent's boiling point brought on by the presence of a solute. Similar to this, freezing point depression refers to a solvent's freezing point being lowered as a result of the addition of a solute. A solvent's freezing point actually drops as its boiling point rises.

The phenomenon known as boiling-point elevation states that the boiling point of a liquid will increase when another chemical is added, i.e., a solution has a higher boiling point than a pure solvent. When a non-volatile solute, like salt, is added to a pure solvent, like water, this occurs. The first plateau denotes the solvent's pure boiling point.

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Both the hydrogen and oxygen atoms in water have a partial positive and negative charge. Both hydrogen and carbon ions are both somewhat positive in ethanol, while oxygen is partially negative.

The c (C), oxygen (O), & hydrogen (H) atoms that make up alcohols are combined to form organic molecules. The alcohol is known as ethanol if it contains two carbons (also known as ethyl alcohol). In beverages like beer and wine, alcohol is present in the form of ethanol.

An constituent in alcoholic drinks including beer, wine, and brandy, ethanol is also known as alcohol, ethyl alcohol, and grain alcohol. It is a transparent liquid with no color. Ethylene can be hydrated to make ethanol, which is a naturally occurring result of plant fermentation.

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The Lewis dot structures for water (H2O) and ethanol (C2H5OH) are as follows:

Water (H2O):

H

/

H O

\ /

H

Ethanol (C2H5OH):

H H

\ /

C

/

H H

|

O

|

H

In both structures, the oxygen atom has a higher electronegativity than the hydrogen or carbon atoms, meaning it attracts electrons more strongly. As a result, the oxygen atom in both water and ethanol has a partial negative charge (denoted by the symbol δ-), while the hydrogen atoms have a partial positive charge (denoted by the symbol δ+). This polarity arises due to the unequal sharing of electrons between the oxygen and hydrogen atoms, with the oxygen atom attracting the electrons more strongly.

In water, the partial negative charge on the oxygen atom creates a hydrogen bond with the partial positive charge on a neighboring hydrogen atom of a nearby water molecule, resulting in the formation of a network of hydrogen bonds. These hydrogen bonds give water its unique properties, such as high surface tension and high boiling and melting points.

In ethanol, the partial negative charge on the oxygen atom is also responsible for the molecule's polarity. The carbon atom is partially positive due to the electron-withdrawing effect of the oxygen atom, which makes ethanol more soluble in polar solvents such as water. Ethanol can also form hydrogen bonds with water due to the presence of the hydroxyl (OH) group.

Answer:

Explanation:

Mass m1 = 44.8776

The chemical equation for the given word equation is Ca(OH)\(_2\)(S) + 2HCI(I) → CaCl\(_2\)(aq) + 2H\(_2\)0(1).   Therefore, the correct option is option D.

Chemical equations are symbols or chemical formulas that depict a chemical reaction symbolically. With a plus sign separating the entities in the reactants and products, the reactant objects are listed on the left as well as the result entities are listed on the right.

An arrow indicating the reaction's direction points in the path of the products. The chemical formulas could be mixed, symbolic, or structural. The critical values of a stoichiometric figures are shown as coefficients beside the symbols as well as formulas of the various entities. The chemical equation for the given word equation is Ca(OH)\(_2\)(S) + 2HCI(I) → CaCl\(_2\)(aq) + 2H\(_2\)0(1).  

Therefore, the correct option is option D.

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Answer:

Metals conduct electricity and heat very well because of their free-flowing electrons. As electrons enter one end of a piece of metal, an equal number of electrons flow outward from the other end. These electrons are free to move around within the metal, colliding with the metal atoms and transferring heat to them efficiently. This makes metals better conductors of heat than most other materials.

The fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

Fugacity is a measure of the escaping tendency of a component in a mixture, which is defined as the pressure that the component would have if it obeyed ideal gas laws. It is used as a correction factor in the calculation of equilibrium constants and thermodynamic properties such as chemical potential. Here we need to determine the fugacity in atm for pure ethane at 310 K and 20.4 atm and the change in the chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm. So, using the formula of fugacity: f = P.exp(Δu/RT) Where P is the pressure of the system, R is the gas constant, T is the temperature of the system, Δu is the change in chemical potential of the system.  Δu = RT ln (f / P)The chemical potential at the initial state can be calculated using the ideal gas equation as: PV = nRT    

=>  P

= nRT/V

=> 20.4 atm

= nRT/V

=> n/V

= 20.4/RT The chemical potential of the system at the initial state is:

Δu1 = RT ln (f/P)

= RT ln (f/20.4) Also, we know that for a pure substance,

Δu = Δg. So,

Δg1 = Δu1 The change in pressure is 24 atm – 20.4 atm

= 3.6 atm At the second state, the pressure is 24 atm.

Using the ideal gas equation, n/V = 24/RT The chemical potential of the system at the second state is: Δu2 = RT ln (f/24) = RT ln (f/24) The change in chemical potential is Δu2 – Δu1 The change in chemical potential is

Δu2 – Δu1 = RT ln (f/24) – RT ln (f/20.4)

= RT ln [(f/24)/(f/20.4)]

= RT ln (20.4/24)

= - 0.0911 RT Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is:

f = P.exp(Δu/RT)

=> f

= 20.4 exp (-Δu1/RT)

=> f

= 20.4 exp (-Δg1/RT) And, the change in the chemical potential between this state and a second state of ethane where the temperature is constant but pressure is 24 atm is -0.0911RT. Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

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2 M

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Unit 0

Aqueous Solutions

Step 1: Define

36.7 g CaF₂

300 mL H₂O

Step 2: Identify Conversions

Molar Mass of Ca - 40.08 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of CaF₂ - 40.08 + 2(19.00) = 78.08 g/mol

1000 mL = 1 L

Step 3: Convert

Solute

Solution

Step 4: Find Molarity

Step 5: Check

Follow sig fig rules and round. We are given 1 sig fig as our lowest.

1.56677 M ≈ 2 M

Answer:

Explanation:

Here, we want to spell out the names of the elements present in the compound

There are three elements in the given compound

We have Mg, O and H

The names can be obtained from the periodic table of element

We have;

Mg - Magnesium

O - Oxygen

H- Hydrogen

Answer:

In gases and liquids, heat is usually transferred by convection, in which the motion of the gas or liquid itself carries heat from one place to another. ... If you boil water in a kettle, the heat is transferred through convection from the fire to the pot.

The values of all sub-parts have been obtained.

(a) The 6.04 amol/vescile of epinephrine are in each vesicle.

(b) The 3637892 molecules of epinephrine are in each vesicle.

(c) The volume of a spherical vesicle is V = 3.34 × 10⁻¹⁷ L.

(d) The concentration of epinephrine = 0.30 M.

What is molar concentration.

A chemical species' concentration, specifically the amount of a solute per unit volume of solution, is measured by its molar concentration. The number of moles per litre, denoted by the unit sign mol/L or mol/dm3 in SI units, is the most often used molarity unit in chemistry.

(a) Evaluate that how many attomoles (amol) of epinephrine are in each vesicle?

As given,

1 fmol = 10⁻¹⁵ mol

1 amol = 10⁻¹⁸ mol

Number of attomoles epinephrine:

= 151 fmol × (10⁻¹⁵ mol)/ 1 fmol × 1amol/10⁻¹⁸ mol

= 151000 amol

Number of attomoles of epinephrine in each vescile:

= 151000 amol/2.5 × 10⁴ vescile

= 6.04 amol/vescile.

(b) Evaluate that how many molecules of epinephrine are in each vesicle?

Number of molecules present in 1 mol of epinephrine:

     = 6.04/vescile × [(10⁻¹⁵ mol)/ 1 fmol] × [6.023 × 10²³ molecules/1 mol]

     = 3637892

(c) Evaluate the volume of a spherical vesicle of radius 200 nm.

Radius of spherical vescile is 2.00 × 10⁻⁷ m

Volume of the spherical vescile is,

V = 4/3 πr³

Substitute value of r respectively,

V = 4/3 π(2.00 × 10⁻⁷ )³

V = 3.34 × 10⁻²⁰ m³

V = 3.34 × 10⁻¹⁷ L

(d) Evaluate the molar concentration of epinephrine in the vesicle if it contains 10 amol of epinephrine.

Number of moles epinephrine = 10 amol

= 1.00 × 10⁻¹⁷mol

Volume of the spherical vescile = 3.34 × 10⁻¹⁷ L

Concentration of epinephrine = (1.00 × 10⁻¹⁷mol)/(3.34 × 10⁻¹⁷ L)

Concentration of epinephrine = 0.30 M

Hence, the values of all sub-parts have been obtained.

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