1. When the equation:
_C₂H₂6+
O2 → __CO2 + _H20
is correctly balanced using the smallest whole number coefficient, the coefficient of O, is

According to the electronic configuration as the atomic size increases down the group, the melting point decreases .

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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Answer:

mutualism, commensalism, and parasitism.

Question:

Three type of symbiosis

Answer:

Mutualism: both partners benefit. ...

Commensalism: only one species benefits while the other is neither helped nor harmed. ...

Parasitism: One organism (the parasite) gains, while the other (the host) suffers

Little Info.

Symbiosis is a close relationship between two species in which at least one species benefits. For the other species, the relationship may be positive, negative, or neutral. There are three basic types of symbiosis: mutualism, commensalism, and parasitism

The stoichiometric table and the rate law for the given elementary liquid phase reaction have been constructed. The rate constant and activation energy have been calculated, and the type of reaction energy has been specified as endothermic.

Stoichiometric table in terms of concentrations:

The stoichiometric table for the given reaction can be constructed as follows:

A + 2B → products

                             A                                B                                products

Feed         0.3*Cf                        0.7*Cf                                       0

Exit              (0.3-0.3X)*C             (0.7-0.7X)*C                                0

Change         -0.3XC                      -0.7XC                                     0

Where:

Cf = Total feed concentration

C = Concentration inside reactor

X = Conversion of A

Rate of reaction of A:

The rate of the reaction can be expressed as:

rA = -1/2 * dCA/dt = k*C^2

where, CA is the concentration of A and k is the rate constant.

Since the reaction is elementary, the rate law is proportional to the concentrations of the reactants raised to their stoichiometric coefficients.

The rate of disappearance of A = rate of appearance of B

rB = -dCB/dt = 2*rA

Therefore, the rate of reaction of A can be expressed as:

rA = (0.7Cf - 0.7C)/V = k*C^2

Substituting values, we get:

rA = (0.710 - 0.70.7X)/5 = k(0.3 - 0.3*X)^2

Calculation of k and E:

The rate constant k can be calculated using the Arrhenius equation:

k = A * exp(-Ea/RT)

where A is the frequency factor, Ea is the activation energy, R is the gas constant and T is the temperature in Kelvin.

Assuming the activation energy is 50 kJ/mol, we can calculate the rate constant at the given temperature of 333 K:

k = 0.00717 * exp(-50000/(8.314*333)) = 0.0001504

The reaction energy can be determined by calculating the activation energy using the rate constant at two different temperatures. Assuming the rate constant at 323 K is 0.000098, we can solve for Ea:

ln(k2/k1) = Ea/R * (1/T1 - 1/T2)

ln(0.000098/0.0001504) = Ea/8.314 * (1/323 - 1/333)

Ea = 43775 J/mol

The positive value of the activation energy indicates that the reaction is endothermic.

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Answer:UIHIU

A small amount of chemical splashes in Frank’s eye. What should Frank do immediately?

Explanation:A small amount of chemical splashes in Frank’s eye. What should Frank do immediately?

Cost-effective definition: producing good results without costing a lot of money. E.g: that machine is very cost effective, it made 200 shirts with only a dollar.

Time effective definition: how well time was used. E.g that machine is very time-effective, it made 200 pants in one hour!

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The statement that is false is that a catalyst cannot affect the overall energy change for the reaction.

While catalysts are present before and after a reaction, they can affect the energy change since they can provide a different reaction pathway with a lower activation energy.

Catalysts can provide a different reaction pathway with a lower activation energy, which can affect the energy change of the reaction. This means that while a catalyst is present before and after a reaction, it can still affect the energy change of the reaction.

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Suppose you have a material in it's liquid phase. As you give energy to that liquid, the temperature of the liquid will increase gradually, and the relation between the increase of temperature and the given energy is the specific heat.

Now, there is a point, a critical point, where the temperature stops to increase, which means that we are near a change of phase. So from this point on, the energy is not used to increase the kinetic energy of the particles (which would increase the temperature), the energy is used to break the bonds and allow a change of phase, for example, from liquid to gas.

So, we know that if you have a mol of water at 100°C, then you need to add 40.7 kJ of energy to change the phase of the water from liquid to gas phase.

This means that if you have a mol of water and you give that exact energy, the temperature will not change, instead, you now will have a mol of water at the temperature of 100°C.

Similarly with the case at 25°C (which happens for a particular pressure only)

So the heat of vaporization can not really be related to increases in temperature as you thought.

For changes in temperature, you need to use the specific heat.

We know that for water it is:

c = 4.184 J/g*°C = 76.15 J/mol*°C

So, if you want to increase the temperature from 25° to 100°

This means an increase of 75°C of one mol of water.

We just need to multiply the above number by:

1mol*(75°C)

Energy needed = (76.15 J/mol*°C)*1mol*(75°C) = 5,711.25 J

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Answer:2

Explanation: Acids do indeed conduct electricity (Love the one peice pfp btw)

Answer:

[He]2\(s^{2}\)3\(p^{1}\)

Explanation:

The electron configuration for Boron is 1\(s^{2}\)2\(s^{2}\)3\(p^{1}\), but you can also write it as the noble gas configuration, which is [He]2\(s^{2}\)3\(p^{1}\)

Note that helium has the configuration of 1\(s^{2}\), so we instead of writing it, we write [He]. This can be useful when writing the configurations of elements from the later periods as it saves space.

B has a stronger intermolecular interaction than A.

The term intermolecular forces refers to the forces that holds the molecules of a substance together. We know that there forces are responsible for the state of matter in which a particular material occurs.

Now, looking at that image of the concept map, we can see that the molecules in A are polar molecules that do not contain hydrogen bonds. Since the presence of polarity makes the molecules to attract each other much better, it the follows that B has a stronger intermolecular interaction than A.

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carbon is an elements ,The compounds of carbon are called an organic compounds.

Carbon have tendency to catenation. catenation means forming bond with another carbon atom and form a long chain of carbon. This is the reason for the presence variety of number of organic compounds. The atomic size of carbon is small and have the valency of four, forms covalent bond. Carbon is strong and stable. Generally carbon containing compound are organic compounds. Generally all the Organic compounds contain carbon and hydrogen  called as hydrocarbon.

Thus, carbon is an elements ,The compounds of carbon are called an organic compounds.

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Answer:

From the given balanced equation, the valid mole ratio is four moles of Fe over 3 moles of moles of c02..

Explanation:

Mole ratio can be defined as the ratio of mole compound with the another.

The partial pressure of O₂ is 0.954 atm

The moles O₂ that formed is 0.000859 moles

The mass of NaNO₃ that reacted is 0.146 g.

The balanced chemical equation for the reaction is given below:

Mole ratio of NaNO₃ to O₂ is 2 : 1

From Dalton's Law of partial pressures:

The partial pressure of O₂ = Total pressure - Partial pressure of water vapor

The partial pressure of O₂ = (0.98 - 0.026) atm

The partial pressure of O₂ is 0.954 atm

b. From the ideal gas law:

PV = nRT

where;

Solving for n

n = PV/RT

n = (0.954 * 0.0230)/(0.0821 * 295.15)

n = 0.000859 moles

Moles of O₂ formed = 0.000859 moles

c. The mass of NaNO₃ that reacted is calculated using the formula below:

molar mass NaNO = 84.99 g/mol

moles of NaNO₃ = 0.000859 moles * 2

moles of NaNO₃ = 0.001718 moles

Solving for the mass NaNO₃ that reacted;

mass NaNO₃ that reacted = 0.001718 * 84.99

mass NaNO₃ that reacted = 0.146 g

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Answer:

Because during the observation, 2 moles of gold were present, while 4 moles were added to silver.

Explanation:

In the chart, the amount of moles of silver was more than the moles of gold.....therefore it takes more heat to melt all 4 moles of silver versus only 2 moles of gold.

The molar fusion of gold is 12.6, and the molar fusion of silver is 11.3. When adding the moles as seen in the chart, we simply multiply both elements by their according moles:

12.6 kJ/mol x 2–> 25.2 kJ/mol of gold.

11.3 kJ/mol x 4–>45.2 kJ/mol of silver.

Silver has a lower molar heat of fusion compared to that of gold. The silver sample required the most added heat to melt because it has a higher melting point.

The molar heat of fusion is the amount of heat required to melt one mole of a substance. A lower molar heat of fusion means that less heat is required to melt a mole of the substance. However, the melting point of a substance is the temperature at which it melts, and silver has a higher melting point than gold. This means that even though silver has a lower molar heat of fusion, it requires more heat to melt because it has a higher melting point.

To illustrate this, let's say we have a sample of silver and a sample of gold, both with a mass of 1 mole. The silver sample has a molar heat of fusion of 11.3 kJ/mol, while the gold sample has a molar heat of fusion of 12.6 kJ/mol. The silver sample also has a melting point of 961°C, while the gold sample has a melting point of 1064°C.

To melt the silver sample, we would need to add 11.3 kJ of heat. To melt the gold sample, we would need to add 12.6 kJ of heat. Even though the silver sample has a lower molar heat of fusion, it requires more heat to melt because it has a higher melting point.

Therefore, the silver sample required the most added heat to melt because it has a higher melting point, even though it has a lower molar heat of fusion.

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There are approximately 6.022 × 10^23 atoms in 12 grams of Carbon-12 (12C).

The number of atoms in a given amount of a substance can be calculated using Avogadro's number, which represents the number of atoms or molecules in one mole of a substance. Avogadro's number is approximately 6.022 × 10^23.

Carbon-12 is a specific isotope of carbon, with an atomic mass of 12 atomic mass units (amu). One mole of Carbon-12 has a mass of 12 grams. Since one mole of any substance contains Avogadro's number of particles, in the case of Carbon-12, it contains 6.022 × 10^23 atoms.

Therefore, if we have 12 grams of Carbon-12, which is equal to one mole, we can conclude that there are approximately 6.022 × 10^23 atoms in this amount of Carbon-12.

In summary, 12 grams of Carbon-12 contains approximately 6.022 × 10^23 atoms. Avogadro's number allows us to relate the mass of a substance to the number of atoms or molecules it contains, providing a fundamental concept in chemistry and enabling us to quantify and understand the microscopic world of atoms and molecules.

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Answer:

B. Litmus paper

Explanation:

The test for chlorine can use either type of litmus paper, but blue litmus paper is used most commonly. The litmus paper must be damp - the water dissolves some of the chlorine so that it can react with the indicator on the litmus paper. This test shows that chlorine is a powerful bleach.

Answer:

D.) ±0.01 cm?​

Explanation:

Since 32.23 cm has two decimal places, the uncertainty is taken as one-half the last decimal pace.

The last decimal place is 0.03. Half of this is 0.03 cm/2 = 0.015 cm.

Since we cannot go below two decimal places, we ignore the 5 in 0.015 cm.

So, we have our uncertainty as 0.01 cm.

So, the best expression of the uncertainty in the measurement 32.23 cm is ± 0.01 cm.

So, the answer is D. which is ± 0.01 cm.

Answer:

no correct answer please mention other answers.

wavelength=30000000/frequency

Answer:

Explanation:

aluminum

Answer: The aluminum ion

Explanation:

With 25 grams of sodium chloride, 1.2 liters of a 0.35 M solution of sodium chloride may be created.

The quantity of solute dissolved in one liter of solution is known as molarity (M).

Molarity (M) is defined as the number of moles of a solute divided by the volume of the solution in litres.

M = n / v where

M stands for molarity, n for moles, and V for volume of solution.

NaCl's molar mass is 23 g/mol plus 35.5 g/mol.

= 58.5 g/mol

Now,

Given mass/molar mass equals the number of moles (n).

= 0.427

We must now determine the solution's volume.

M = 0.35 = 0.427 / v

V is 1.2 liters

Thus, 25 grams of sodium chloride might be used to create 1.2 liters of sodium chloride solution at 0.35M.

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Answer: The molar mass of menthol is 156.15 g/mol

Explanation:

Depression in freezing point is given by:

\(\Delta T_f=K_f\times m\)

\(\Delta T_f=T_f^0-T_f=2.84^0C\) = Depression in freezing point

\(K_f\) = freezing point constant = \(20.8^0C/m\)

m= molality

\(\Delta T_f=K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}\)

Weight of solvent (cyclohexane)= 25.0 g = 0.025 kg  

Molar mass of solute (menthol) = ?

Mass of solute (menthol) = 0.533 g

\(2.84^0C=20.8\times \frac{0.533}{xg/mol\times 0.025}\)

\(x=156.15g/mol\)

The molar mass of menthol is 156.15 g/mol

Answer:

a

Explanation:

Answer:

The redox reaction in the question is missing. The reaction is :

Cl 2(g) + Mn 2 +(aq) + 2 H-On â 2 Cl-(aq) + MnO2(s) + 4 H + (aq)

2.59V

Explanation:

A redox reaction is also known as oxidation - reduction reaction. In redox reaction, there is a transfer of electrons between the species. In one species there is oxidation and in the other species there is reduction process.

Cathode half reaction equation:

\($ Cl_2(aq) + 2e \rightarrow 2Cl^- (aq)$\)

Anode half reaction equation:

\($ Mn^2 (aq) + 2H_2O (l) \rightarrow MnO_2 (s) +2e +4H\)

E°cathode= 1.36V

E°anode= -1.23V

E°cell= E°cathode - E°anode

E°cell= 1.36 - (-1.23)

E°cell= 2.59V

The concentration of CO2 in club soda is approximately 1.1964 g/L.

To find the concentration of CO2 in club soda, we need to use the stoichiometry of the reaction and the volume and concentration of the NaOH solution used.

The balanced equation for the reaction is:

CO2(aq) + 2NaOH(aq) → Na2CO3(aq)

From the stoichiometry of the equation, we can see that 1 mole of CO2 reacts with 2 moles of NaOH. Therefore, the moles of CO2 can be calculated using the volume and concentration of NaOH solution used.

Given that 32.14 mL of 0.04202 M NaOH solution was used, we can calculate the moles of NaOH:

moles of NaOH = volume (L) × concentration (M)

moles of NaOH = 32.14 mL × 0.04202 mol/L

moles of NaOH = 0.001351 mol

According to the stoichiometry of the equation, 1 mole of CO2 reacts with 2 moles of NaOH. Therefore, the moles of CO2 can be calculated as:

moles of CO2 = (moles of NaOH) / 2

moles of CO2 = 0.001351 mol / 2

moles of CO2 = 0.0006755 mol

Now, we need to convert the moles of CO2 to grams. The molar mass of CO2 is approximately 44.01 g/mol.

mass of CO2 = moles of CO2 × molar mass of CO2

mass of CO2 = 0.0006755 mol × 44.01 g/mol

mass of CO2 = 0.02979 g

Finally, we need to express the concentration of CO2 in club soda in g/L. We are given that the sample of club soda used is 25.00 mL.

concentration of CO2 = (mass of CO2) / (volume of club soda in L)

concentration of CO2 = 0.02979 g / (25.00 mL × 0.001 L/mL)

concentration of CO2 = 1.1964 g/L

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Answer:

arrow down is gravity

Explanation:

Answer: The person above me is right

Explanation:

Have a Great day!

dolphin and whales use echolocation

The volume of 1.5 moles of gas at STP  is 33.6 L.

The volume of the gas at STP is calculated as follows;

I mole of gas at STP = 22.4 L

1.5 moles of the gas at STP = ?

= 1.5 moles  x 22.4 L/mole

= 33.6 L

Thus, the volume of 1.5 moles of gas at STP  is 33.6 L.

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