(1 point) Test the series for convergence or divergence. Σ8(-) 3(-e)** 1 - Part 1: Divergence Test Identify the corresponding positive terms: by Evaluate the limit: lim bn n00 Since lim bn is Select , the Divergence Test tells us Select n-00 Dort 2. Alternating Series Test

The residence time of seawater with respect to river inflow is generally longer than the residence time of sodium in seawater with respect to river inflow.

Seawater is constantly being replenished by river inflow, which brings in freshwater and other dissolved substances. This constant influx of river water ensures that the residence time of seawater, or the amount of time it takes for seawater to completely replace itself with new water, is relatively long. This process helps maintain the balance of the seawater composition.
On the other hand, sodium is a major component of seawater and is not easily removed from it. While some sodium may be lost due to sedimentation or other processes, the residence time of sodium in seawater is generally shorter compared to the residence time of seawater itself.
It's important to note that the specific residence times can vary depending on various factors such as location, ocean circulation patterns, and river characteristics. In general, the residence time of seawater with respect to river inflow is longer than the residence time of sodium in seawater with respect to river inflow. In conclusion, while the specific values may vary, the residence time of seawater with respect to river inflow is generally longer than the residence time of sodium in seawater with respect to river inflow.

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The points on the curve where the tangent is vertical are (-2,-2) and (2,-4).

The equation of the curve is

x=t³ - 3t and y=t³ - 3t².

Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to check your work.

Let's first find dy/dx.

So, we differentiate y with respect to x as follow:

dy/dx = (dy/dt)/(dx/dt)

Let's find dy/dt and dx/dt individually.

x = t³ - 3tdx/dt

= 3t² - 3y

= t³ - 3t²dy/dt

= 3t² - 6t

Now,

dy/dx = (dy/dt)/(dx/dt)

= (3t² - 6t)/(3t² - 3)

To find the horizontal tangent, we need to make the numerator equal to 0.

(3t² - 6t) = 0

t² - 2t = 0

t( t - 2) = 0

t = 0, t = 2

We have 2 values of t, t=0 and t=2.

Put t=0 in the equation of the curve:

x=0³ - 3*0

=0

y=0³ - 3*0²

=0

So, the point is (0,0).

Put t=2 in the equation of the curve:

x=2³ - 3*2

=2

y=2³ - 3*2²

=-4

So, the point is (2,-4).To find the vertical tangent, we need to make the denominator equal to 0.

3t² - 3 = 0

3(t² - 1) = 0

t = ±1

We have 2 values of t, t=1 and t=-1.

Put t=1 in the equation of the curve:

x=1³ - 3*1

=-2

y=1³ - 3*1²

=-2

So, the point is (-2,-2).

Put t=-1 in the equation of curve:

x=-1³ - 3*(-1)

=2

y=-1³ - 3*(-1)²

=-4

So, the point is (2,-4).

Thus, the points on the curve where the tangent is horizontal are (0,0) and (2,-4).

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Answer: Choice C \(f(x) = \frac{1}{x(x+4)}\)

========================================================

Explanation:

The vertical asymptotes are the red dashed lines. They are x = -4 and x = 0. Think of them as electric fences that the graph cannot touch or cross. The curve can only get closer and closer.

The vertical asymptote is due to a division by zero error.

When x = 0, the denominator x(x+4) turns into 0 since

x(x+4) = 0(0+4) = 0*4 = 0

Similarly, when x = -4, the denominator is also zero

x(x+4) = -4(-4+4) = -4*0 = 0

So if x = -4 or x = 0, then we have a division by zero error and that's what produces the vertical asymptotes at those locations shown on the graph.

This is why the answer is choice C. \(f(x) = \frac{1}{x(x+4)}\)

Complete question is;

An online store receives customer satisfaction ratings between 0 and 100, inclusive. In the first 10 ratings the store received, the average (arithmetic mean) of the ratings was 75. What is the least value the store can receive for the 11th rating and still be able to have an average of at least 85 for the first 20 ratings?

Answer:

50

Step-by-step explanation:

We are told that In the first 10 ratings the store received arithmetic mean of the ratings = 75.

Thus;

Sum of the first 10 ratings = 75 × 10 = 750

Now, for the mean of the first 20 ratings to be at least 85, it means that the sum of the first 20 ratings would be; 85 × 20 = 1700

Thus, the sum of the next 10 ratings would be; 1700 − 750 = 950.

If maximum rating = 100, then the maximum possible value of the sum of the 12th to 20th ratings is given by;

9 × 100 = 900.

Now, in order to make the store have an average of at least 85 for the first 20 ratings, the least value for the 11th rating is;

950 − 900 = 50

Answer: H = 35

Step-by-step explanation:

You do 20.00+5*h

Answer:

B

Step-by-step explanation:

Let me know how you did

Answer: 105

Step-by-step explanation:

Answer:

x = 28

y = 157/8

Step-by-step explanation:

you didn't give me access so I can't edit or solve the problem  and if this is extra credit to bring your grade up, shouldn't you be doing it?

Answer:

The measure is 145

Step-by-step explanation:

Answer:

145

Step-by-step explanation:

The total sum of angles around a point is 360 degrees.

Answer:

x=9.3

Step-by-step explanation:

use SohCahToa

in this case u use cos

cos(41°)=7/x

x=7/cos(41)

x=9.275090953

x=9.3

Answer:

(2,7), (6,-2),

Step-by-step explanation:

After finding the points you plug them in to the distance formula:

d=√((x2-x1)²+(y2-y1)²)

d=√[(6-2)²+(-2-7)²]

Step-by-step explanation:

\( \dashrightarrow \quad \rm {a = \dfrac{v -u}{t} } \\ \)

\( \dashrightarrow \quad \rm {a = \dfrac{9 -7}{2} \; m \: s^{-2}} \\ \)

\( \dashrightarrow \quad \rm {a = \dfrac{2}{2} \; m \: s^{-2}} \\ \)

\( \dashrightarrow \quad \underline{\boxed{\bf {a = 1 \; m \: s^{-2}}}} \\ \) (Answer)

The value of y is 80°

Two lines are said to be parallel if their slopes are equal and they do not intersect each other at any point.

Given that, are two parallel lines, crossed by a transversal, we need to find the value of y,

Here y = 80° by alternate exterior angles theorem.

Hence the value of y is 80°

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The volume of the cross-section perpendicular to the solid is the amount of space in the cross-section

The question is incomplete;

So, I will give a general explanation on how to set up a definite integral for volume of a solid

Assume the solid is a cone;

Using the disk method, the integral of the volume is:

\(V = \int\limits^a_b {\pi r(x)^2} \, dx\)

Using the washer method, the integral of the volume is:

\(V = \int\limits^a_b {\pi [R(x)^2 -r(x)^2 ]} \, dx\)

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The probability of randomly selecting a red, then a free marble from a bag of 5 red, 8 green, and 3 marbles

a)  0.1563

b) 0.1667

Since we are  given with bag of  5 red, 8 green, and 3 marbles. so, r=5, g=8 and b=  3. For the first  case, we replace the first  marble before drawing the second,  the total number of marble =  5 + 8 + 3 = 16. So, the probability of drawing a red marble at the 1st attempt is: 5/16. Then, the first marble is replaced back into the bag before making the second draw. Probability of drawing green marbles at the second draw is: 8/16= 1/2, Therefore the probability of selecting a red, then a green marble is: 5/16 * 1/2 = 5/32 =0.1563

For the second case , we do not replace the first marble, the probability of drawing a red marble at the 1st draw is:5/16 . Since we don't replace the balls  so the number of marbles remaining in the bag is: 16-1 =15 ,the probability of drawing green marbles at the second draw is: 8/15, therefore the combined probability of selecting a red, then a green marble is: 5/16 * 8/15  =0.1667

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The length of the microorganism that measure 5μm is equivalent to 0.005 mm

It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.

To solve this problem the we have to convert the units with the given information.

1mm is equal to 1000 μm

5μm * (1 mm/1000μm) = (5*1) / 1000 = 5/1000 = 0.005 mm = 5x10^-3 mm

The length of the microorganism that measure 5μm is equivalent to 0.005 mm

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To determine the optimal order quantity for Rocky Mountain Tire Center, you must consider ordering costs, storage costs, and the purchase price of the tires. The order quantity should minimize the total cost including both ordering cost and storage cost.

The EOQ formula is given by: EOQ = √((2DS) / H)

Where: D = Annual demand (7,000 go-cart tires)

S = Ordering cost per order ($40) H = Holding cost - percentage of the purchase price (40% of the purchase price)

we need to determine the purchase price per tire based on the quantity ordered.

EOQ = √((2 * 7,000 * 40) / (0.4 * 15))

=118 tires

they should order approximately 118 tires.

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Answer:

The sign is negative

Step-by-step explanation:

Given

\(Expression = 3xy\)

\(x > 0\)

\(y<0\)

Required

Determine the sign

The expression can be split into 3 factors

\((3) (x) (y)\)

If x > 0 then x is positive and If y < 0 then y is negative

So, the expression becomes:

\((+3) (+x) (-y)\)

Leave only signs

\((+) (+) (-)\)

\(+ * + = -\)

So, we have:

\((+*+) (-)\)

\((+) (-)\)

\(+ * - = -\)

So, we have:

\((+) (-) = -\)

Hence, the sign of the expression is negative

Take for instance;

\(x = 2\)

\(y = -4\)

The expression would be:

\(3 *2 * - 4 =-24\) -- negative

Answer

16

Step-by-step explanation:

slope go up 16 every time

The maximum value of the objective function is 4 at the vertex (4, 0), and the minimum value is -8 at the vertex (0, -4). The optimal solutions for the given LP problem are Maximum: p = 4 at x = 4 and y = 0 and Minimum: p = -8 at x = 0 and y = -4.

Maximize and minimize p = x + 2y

subject to:

x + y ≥ 4

x + y ≤ 10

x - y ≤ 4

x - y ≥ -4

First, let's graph the feasible region defined by the given constraints:

Plotting the lines:

x + y = 4 (solid line)

x + y = 10 (solid line)

x - y = 4 (solid line)

x - y = -4 (solid line)

The feasible region is the area that satisfies all the constraints and is bounded by the lines on the graph.

Upon examining the feasible region, we can observe that it is a bounded region.

To find the optimal solution, we need to evaluate the objective function p = x + 2y at the vertices (corner points) of the feasible region.

Now, let's find the vertices of the feasible region by solving the intersection points of the lines:

1. Intersection of x + y = 4 and x + y = 10:

Subtracting the equations, we get 0 = 6, which is not possible. No intersection point exists for these lines.

2. Intersection of x + y = 4 and x - y = 4:

Adding the equations, we get 2x = 8, x = 4. Substituting x = 4 into x + y = 4, we get 4 + y = 4, y = 0. The first vertex is (4, 0).

3. Intersection of x - y = 4 and x - y = -4:

Adding the equations, we get 2x = 0, x = 0. Substituting x = 0 into x - y = 4, we get -y = 4, y = -4. The second vertex is (0, -4).

Now, we evaluate the objective function at each vertex:

p(4, 0) = 4 + 2(0) = 4

p(0, -4) = 0 + 2(-4) = -8

The maximum value of the objective function is 4 at the vertex (4, 0), and the minimum value is -8 at the vertex (0, -4).

Therefore, the optimal solutions for the given LP problem are Maximum: p = 4 at x = 4 and y = 0 and Minimum: p = -8 at x = 0 and y = -4.

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Answer:

f

Step-by-step explanation:

f

Answer:

\(\boxed{AB = 9}\)

Step-by-step explanation:

AB = 2(AC) {Because a line segment drawn from a center of a circle bisect the chord opposite to it}

So,

AB = 2(4.5)

AB = 9

The speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

A star moving away from the observer (say on Earth) will have its emitted light red-shifted (move to lower frequency), i.e., the spectrum moving to left if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving towards the observer (say on Earth) will have its emitted light blue-shifted (move to higher frequency), i.e., the spectrum moving to the right if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving perpendicular to the observer (say on Earth) will have its emitted light will no change with respect to the spectrum of the stationary star.

These are due to the Doppler effect, the equation of frequency detected by the observer as

\(f_o = f_s\sqrt{\frac{1-\beta }{1+\beta } }\) where \(\beta = \frac{v}{c}\), v the relative velocity of the moving source (the star here), f^s is the frequency of light emitted by the source.

Hence the answer is the speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

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The given rock is a diamond because its density ranges among 3.5 and 3.54 g/cm³.

Density is the mass of a specific material per unit volume. Density is commonly measured in grams per cubic centimetre. Water, for example, has a density of 1 gram per cubic centimetre, whereas Earth has a density of 5.51 grams per cubic centimetre.

The formula for density is;

D = M/V,

where,

D is density,

M is mass ( = 1.17 g)

V is volume (0.33 cm³)

Substituting the values in the density formula;

Density = 1.17/0.33

Density = 3.54 g/cm³

As, diamond has a density that ranges between 3.5 & 3.54 g/cm3. As a result, the above rock is indeed a diamond.

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The correct question is-

If a rock sample has a mass of 1.17 g and a volume of 0.33 cm3, what type of rock is it?

Answer:

Step-by-step explanation:

diamond, common glass, cubic zirconia

Answer: ΔTAU ≈ ΔUAV ≈ ΔTUV

Step-by-step explanation:

I'm not really sure what "work" you really need; this is a problem that can be solved easily by simply looking at the triangles and seeing which sides have the same ratio of distances for each side.

Best of luck with your assignment. :) Feel free to give me Brainliest if you feel this helped. Have a good day.

Answer:

Step-by-step explanation:

let the number be x

=7+x

=3(7+x)

=3(7+x)-2

13=3(7+x)-2

solving for  x we have

13=21+3x-2

21+3x-2-13=0

collect like terms we have

21-2-13+3x=0

6+3x=0

6=-3x

x=6/-3

x=-2

The answer is B

B. -2

Answer:

Angles are 174 and 6

Step-by-step explanation:

The value stored in the variable x after the execution of the following code snippet will be b) 2.

The right-click context menu option or a combination of hotkeys can be used to add code snippets, which are compact chunks of reusable code, to a code file. Although try-finally and if-else blocks, for example, are frequently used code blocks found in code snippets, you can also use them to add whole classes or methods.

Learn more about using the templates tool to create reusable emails. Applications and web pages use snippets. Snippets are made to be reusable and to add functionality, like connecting various parts of a program.

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