1. How many valence electrons are in a molecule of Acetate?

a 2
b 6
c 5
d 1

2. If Acetate is part of an ionic bond, what will it's charge be?

a neutral
b negative
c positive

3. Will Acetate gain, lose, or share electrons in an ionic bond?

a share
b lose
c gain
4. In an ionic bond, how would Acetate be catagorized?

a anion
b cation

5 Is Acetatea metal, nonmetal, or polyatomic ion?

a metal
b nonmetal
c polyatomic ion

The mass of one unit copper cell is: A. 4.22 x \(10^{-22}\).

To determine the mass of one unit cell of copper, which crystallizes in a face-centered cubic lattice, follow these steps:

Then, the mass of one unit cell of copper in a face-centered cubic lattice is 4.22 x 10^-22 g. Therefore, he correct answer is A.

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Answer:

b

Explanation:

I think not for sure tho

Answer:

At its most basic level, heat is just

B energy

Explanation:

Answer: The concentration of hydrogen ions is \(10^{-11}M\) and the concentration of hydroxide ions is \(10^{-3}M\). Thus the concentration of hydroxide ions is more than the concentration of hydrogen ions.

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.  

\(pH=-\log [H^+]\)

\(pOH=-\log[OH^-]\)

Putting in the values:

\(11=-\log[H^+]\)

\([H^+]=10^{-11}M\)

\(pH+pOH=14\)

\(pOH=14-11=3\)

\(3=-log[OH^-]\)

\([OH^-]=10^{-3}M\)

Thus the concentration of hydroxide ions is more than the concentration of hydrogen ions.

The number of sulfate ions : 2.2 x 10²³

Reaction

Al₂(SO₄)₃⇒2Al³⁺+3SO₄²⁻

mol Al₂(SO₄)₃(MW=342,15 g/mol) :

\(\tt \dfrac{41.65}{342.15}=0.122\)

mol of sulfate ions (SO₄²⁻)

\(\tt 3\times 0.122=0.366\)

1 mol = 6.02 x 10²³ particles (ions, molecules, atoms), so for 0.366 mol :

\(\tt 0.366\times 6.02\times 10^{23}=2.20\times 10^{23}\)

Answer:

Carbon, hydrogen, nitrogen, oxygen, phosphorus,or potassium as nutrients for plants.

Explanation:

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Carbohydrates or starch serve as nutrients for plants.

Answer:

Explanations:

The formula for calculating the pH of the solution is given as:

Given that the pH is 2, then;

Hence the concentration of the hydronium ion is 0.01M

Since the pH of the solution is less than 7, hence the solution is acidic

Answer:

Explanations:

Given the operation below:

Grouping the operation into standard and exponential values will give:

Simplify the result

Write the resulting product in standard form:

Hence the coefficient (green) is 4.3615 and the exponent (yellow) is -1.

Answer:

, CaCO3, contains one atom of calcium, one of carbon and three of oxygen. so there are 5 atoms in CaCO3

Mg(OH)2, There is  one magnesium, two oxygen, and two hydrogen atoms. so there are 5 atoms  Mg(OH)2

a molecule of acetic acid  contains two carbon atoms, four hydrogen atoms, and two oxygen atoms. so there are 8 atoms in acetic acid

There are 3 atoms in CaCl2

H2SO4 is a chemical compound made up of two hydrogen atom, one sulfer atom, and four oxygen atoms. So there are 7 atoms in H2SO4

There are 8 atoms in sodium phosphate

Explanation:

I'm assuming that C is carbon.

\(4.590 \: mol \: c \times \frac{12.01 \:g \: c}{1 \: mol \: c} \)

55.1259 g of C

The mass number is 11. Hence, option C is correct.

An atom consists of a central nucleus that is usually surrounded by one or more electrons.

Mass Number(A) = Number of Protons + Number of Neutrons

The nucleus of an atom has 5 protons and 6 neutrons than the mass no. will be 6+5 = 11.

Hence, option C is correct.

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The hospital's experimentation with peroral endoscopic myotomy (POEM) filling is part of the tertiary care position.

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Taking into account the reaction stoichiometry, 17.61 moles of O₂ is required to react with 155 grams of C₃H₈.

In first place, the balanced reaction is:

C₃H₈ + 5 O₂  → 3 CO₂ + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 44 grams of C₃H₈ react with 5 moles of O₂, 155 grams of C₃H₈ react with how many moles of O₂?

\(moles of O_{2} =\frac{155 grams of C_{3} H_{8}x5 moles of O_{2} }{44 grams of C_{3} H_{8}}\)

moles of O₂= 17.61 moles

Finally, 17.61 moles of O₂ is required to react with 155 grams of C₃H₈.

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The equation that represents a single replacement reaction given the various options is 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)

A single replacement reaction, also known as single displacement reaction is a reaction in which elements higher in the electro-chemical series displace or replace elements lower in the electro-chemical series displace from a solution.

The following example illustrates single replacement reaction:

A + BC -> AC + B

From the above reaction, we can see that A has replace/displace B to from AC.

With the above information, we can determine the equation that represents single replacement reaction. Details below:

Equation from the questions:

From the above, we can see that only 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) conform to single replacement reaction.

Thus, the correct answer to the question is: 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)

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Formaldehyde is a substance made up of Carbon, Nitrogen, and Oxygen different types of atoms that are chemically combined in a fixed ratio of 1: 2:1. It is classified as an aldehyde.

This refers to a naturally occurring organic compound with the formula CH2O and structure H−CHO. It is also called methanal. The pure compound is a pungent, colorless gas such that it polymerizes spontaneously into paraformaldehyde. It can be stored as an aqueous solution that is formalin. This is also used to store animal specimens.

Formaldehyde is an organic compound. It contains a carbon atom present in its chemical formula. It is also classified as an aldehyde. Formaldehyde(RC=OH) contains a formyl group  and an R group, which is a group that contains carbon and/or hydrogen.

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Answer:

i think its a liquid..... im not that sure

Answer:

A). Trial 1, because the average rate of the reaction is lower.

Explanation:

The first sentence elaborates that 'trial 1 had a lower level of concentration of the reactant that eventually led the reaction's average rate to fall.'

A trial having a higher level of concentration of a specific reactant will cause the concentration's average rate to rise. As per the graph provided, trial 2's average reaction rate is higher which shows that its concentration is greater and more reactive. However, the opposite happens in trial 1 where the amount of reactant is lesser in the concentration that leads the concentration to possess a lower rate of reaction. Thus, option A is the correct answer.

The ratio between the energy and oxygen is 21.36 kJ/g of oxygen.

According to the given balanced equation:C_{2}H_{5}OH + 2O_{2} → 2CO_{2} + 3H_{2}O + 1367 kJ. The balanced equation tells us that one molecule of C_{2}H_{5}OH reacts with two molecules of O2 to form two molecules of CO2, three molecules of H_{2}O, and 1367 kJ of energy. Therefore, to determine the ratio between energy and oxygen, we need to first find the energy released per mole of O2 reacted. To do this, we need to use the energy released by the combustion of 1 mole of C_{2}H_{5}OH, which is given as 1367 kJ. So, 1 mole of C_{2}H_{5}OH releases 1367 kJ of energy. To balance the equation, 2 moles of O2 are required for every mole of C_{2}H_{5}OH reacted. So, 2 moles of O2 is equivalent to 1367 kJ of energy. Therefore, the energy released per mole of O2 is 1367/2 = 683.5 kJ/mol. Oxygen has a molar mass of 32 g/mol and therefore the mass of one mole of oxygen is 32 g/mol. Using the molar mass of oxygen and the energy released per mole of O2, we can calculate the energy released per gram of oxygen as follows: Energy released per gram of O2 = Energy released per mole of O2 / Molar mass of O2= 683.5 / 32 = 21.36 kJ/g. Therefore, the ratio between the energy and oxygen is 21.36 kJ/g of oxygen.

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complete question: C_{2}H_{5}OH + 2O_{2} → 2CO_{2} + 3H_{2}O + 1367 kJ

What is the ratio between the energy and oxygen based on the equation?

-[?] kJ

[?]mol O2

Answer:

Chloroform has a boiling point of 61.15 degrees Celsius and a vapor pressure of 9.5 kPa at 20 degrees Celsius. Glycerol, on the other hand, has a boiling point of 290 degrees Celsius and a vapor pressure of 0.0002 kPa at 20 degrees Celsius. Therefore, chloroform has a much lower boiling point and a much higher vapor pressure than glycerol. This means that chloroform is more volatile and evaporates more easily than glycerol.

Explanation:

Chloroform has a boiling point of 61.15 degrees Celsius and a vapor pressure of 9.5 kPa at 20 degrees Celsius. Glycerol, on the other hand, has a boiling point of 290 degrees Celsius and a vapor pressure of 0.0002 kPa at 20 degrees Celsius. Therefore, chloroform has a much lower boiling point and a much higher vapor pressure than glycerol. This means that chloroform is more volatile and evaporates more easily than glycerol.

Answer:

40

Explanation:

The total mass of calcium in the products is 40

The mass number (represented by the letter A) is defined as the total number of protons and neutrons in an atom. Consider the table below, which shows data from the first six elements of the periodic table. Consider the element helium. Its atomic number is 2, so it has two protons in its nucleus.

Together, the number of protons and the number of neutrons determine an element's mass number: mass number = protons + neutrons. If you want to calculate how many neutrons an atom has, you can simply subtract the number of protons, or atomic number, from the mass number.

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Bromine exists naturally as a mixture of bromine-79 and bromine-81 isotopes. An atom of bromine-81 contains: 81 protons, 81 electrons, and 81 neutrons.

Bromine is a chemical element with the symbol Br and atomic number 35.

It is the third-lightest halogen and is a fuming red-brown liquid at room temperature that evaporates readily to form a similarly coloured gas.

It occasionally exists as a diatomic molecule, Br2.

It has 35 electrons and 35 protons, which is 79Br.

When it comes to bromine-81, it has 81 protons and 81 electrons, which means that it is chemically indistinguishable from regular bromine.

However, it contains 81 neutrons in its nucleus, unlike the most common form of bromine, which contains only 46 neutrons in its nucleus.

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Answer:

4365.54 moles

Explanation:

Take the scientific notation and multiply it by the molar mass of 59.76.

Answer:

16.83°

Explanation:

The computation of temperature in degrees is shown below:

For this we need to applied the combination of the Clasius Clapyeron equation which is

\(ln(\frac{P_2}{P_1}) = \frac{-\Delta Hvap}{R} \times (\frac{1}{T_2}- \frac{1}{T_1})\)

Where

P_2 and P_1 represents the pressure of vapor at point 1 and 2

dH = Here we use J/mol

R = 8.314 J/mol K

T1 and T2 represent the temperature of Saturation temperature for point 1 and 2

Now

we have to change the negative signs

i.e

\(ln(\frac{P_2}{P_1}) = \frac{\Delta Hvap}{R} \times (\frac{1}{T_1}- \frac{1}{T_2})\)

As we know that

dHvap for water = 40.67 kJ/mol

T1 = 373 K,

T2 = x

P1 = 14.7 psi;

P2 = 11.2 + 14.7 = 25.9 psi

Now put the values to the above formula

So,

\(ln (\frac{25.9}{14.7}) = \frac{40670}{8.314} \times (\frac{1}{373}- \frac{1}{T_2})\\\\T_2 = - (ln (\frac{25.9}{14.7})\times \frac{8.314}{40670} - \frac{1}{373})^{-1}\)

After solving this

T_2 = 389.836K

T_2 = 389.836 - 273

T_2 = 116.836 °C

Therefore by 16.83°,  it becomes higher

Answer:

They vibrate about a fixed position

Answer:

3.97 x 10^-19 J

Explanation:

The energy E of a photon is given by:

       E = hf where h = Planck's constant = 4.14 × 10−15 eV · s and f = frequency

In this case, f = 6×10^14s−1, hence, the energy E of one photon of the light would be;

E = 4.14 × 10−15 eV · s x 6×10^14s−1

               =  2.484 eV

Note that:

1 eV = 1.60 × 10−19 J

Hence,

2.484 eV = 2.484 x 1.60 × 10−19 J

              = 3.97 x 10^-19 J

The steps involved in nucleophilic acyl substitution of a reactive carboxylic acid derivative by a strong nucleophile are: 1) nucleophilic attack by the nucleophile on the carbonyl carbon of the carboxylic acid derivative, 2) tetrahedral intermediate formation, 3) leaving group departure, and 4) proton transfer.

Nucleophilic acyl substitution is a reaction in which a nucleophile attacks a carbonyl carbon of a reactive carboxylic acid derivative, resulting in the substitution of the leaving group attached to the carbonyl carbon with the nucleophile. The steps involved in this reaction are:

Nucleophilic attack: The nucleophile attacks the carbonyl carbon of the carboxylic acid derivative, resulting in the formation of a tetrahedral intermediate.

Tetrahedral intermediate formation: The carbonyl carbon is now bonded to the nucleophile, and the leaving group is now in a position to leave.

Leaving group departure: The leaving group departs, resulting in the formation of the acylated nucleophile.

Proton transfer: If necessary, a proton transfer may occur to yield the final product.

The overall mechanism of the reaction depends on the nature of the carboxylic acid derivative and the nucleophile involved. For example, if the carboxylic acid derivative is an acid chloride, the mechanism will proceed via an acyl chloride intermediate. If the nucleophile is a primary amine, the mechanism will involve the formation of an amide. The specific reaction conditions and reagents used will also play a role in determining the mechanism and product of the reaction.

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Answer:

0.75M Fe²⁺

Explanation:

First, we need to balance the redox reaction in acidic medium. Then, we can obtain moles of KMnO4 and with the reaction moles and molarity of the Fe²⁺ solution:

Redox Balance:

Fe²⁺ → Fe³⁺ + 1e⁻

5e⁻ + 8H⁺ + MnO₄⁻ → Mn²⁺ + 4H₂O

___________________________

5Fe²⁺ + 5e⁻ + 8H⁺ + MnO₄⁻ → 5Fe³⁺ + 5e⁻ + Mn²⁺ + 4H₂O

Moles of KMnO₄:

70.0mL = 0.0700L * (0.150mol / L) = 0.0105 moles KMnO₄

Moles and molarity Fe²⁺:

0.0105 moles KMnO₄ * (5 moles Fe²⁺ / 1mol KMnO₄) = 0.0525 moles Fe²⁺

In 70.0mL = 0.0700L:

0.0525 moles Fe²⁺ / 0.0700L =

Water is called the universal solvent

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