1. Create a for…next loop that creates the following output in a label named lblBakingTemps, where the number displayed is the counter variable in the loop:
450
425
400
375
350
2. Create a function that calculates the value of the number passed to it to be the square of the value of the original number multiplied by 3.14159. For example, if a variable named decRadius contained the number 7 before your function is invoked, the function should return the value of 153.93791.
3. Create an independent sub procedure that performs the following tasks:
• has two string parameters passed to it, a name and a part number
• updates lblMessage with something that incorporates the name and the part number with some verbiage of your choosing ("Part ABC123 is a one inch sprocket flange")
4. Create an array of nine last names named strBattingLineup. Use whatever scope you want for your array.
In a separate instruction, set the name of the player in the very first position to Fowler. Set the name of the player in the very last position to Hendricks. Then set the name of the baseball player batting fourth to be Rizzo.
5. What the value of decLoopVariable after the third time through this loop?
Dim decLoopVariable As Integer = 1
Do While decLoopVariable < 99999
decLoopVariable = 1.5 * decLoopVariable * decLoopVariable + 3
Loop
Answers
1. Here is the for...next loop code to create the desired output in the lblBakingTemps label:
```
For intCounter As Integer = 450 To 350 Step -25
lblBakingTemps.Text &= intCounter.ToString() & vbCrLf
Next
```
This loop initializes a counter variable intCounter to 450 and then decrements it by 25 each time through the loop until it reaches 350. The code then appends the current value of intCounter to the lblBakingTemps label text, followed by a line break (vbCrLf).
2. Here is the function code that calculates the square of the value of the number passed to it, multiplied by pi:
```
Function CalcArea(ByVal decRadius As Decimal) As Decimal
Const decPi As Decimal = 3.14159
Return decRadius * decRadius * decPi
End Function
```
This function takes a decimal value decRadius as its input and multiplies it by itself and by pi to calculate the area of a circle with the specified radius. The result is returned as a decimal value.
3. Here is the independent sub procedure code that updates the lblMessage label with a custom message:
```
Sub UpdateMessage(ByVal strName As String, ByVal strPartNumber As String)
lblMessage.Text = "Part " & strPartNumber & " is a " & strName & vbCrLf
End Sub
```
This sub procedure takes two string parameters strName and strPartNumber, which represent the name and part number of a product. It then updates the lblMessage label with a custom message that includes these values.
4. Here is the code to create an array of nine last names named strBattingLineup and set the names of the first, last, and fourth players:
```
Dim strBattingLineup(8) As String
strBattingLineup(0) = "Fowler"
strBattingLineup(3) = "Rizzo"
strBattingLineup(8) = "Hendricks"
```
This code creates an array of nine strings named strBattingLineup and initializes each element to an empty string. It then sets the value of the first element to "Fowler", the fourth element to "Rizzo", and the last element to "Hendricks".
5. The value of decLoopVariable after the third time through the loop is approximately 133,415.
The given code uses a for...next loop to iterate from 450 to 350 in steps of -25. It appends each value of the counter variable, intCounter, to the lblBakingTemps label's text. The vbCrLf adds a line break after each value. The resulting output in lblBakingTemps will be a list of values from 450 to 350 in descending order, each value on a new line.
The provided function, CalcArea, calculates the area of a circle using the formula: radius squared multiplied by pi. It takes a decimal value, decRadius, as input and returns the calculated area as a decimal.
The independent sub procedure, UpdateMessage, updates the lblMessage label with a custom message. It takes two string parameters, strName and strPartNumber, and concatenates them with a predefined message. The resulting message includes the part number and name, separated by a space and followed by a line break.
The code creates an array named strBattingLineup with nine elements. It sets the first element to "Fowler", the fourth element to "Rizzo", and the last element to "Hendricks". The other elements are left empty or uninitialized.
The statement about decLoopVariable cannot be evaluated based on the given information. It refers to a variable not mentioned before, and no loop is described in the context.
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Related Questions
the string of a helium balloon slips from your hand and rises up into the air. when this happens
Answers
When the string of a helium balloon slips from your hand and rises into the air, the balloon rises until it reaches an altitude where its weight equals that of the same volume of air.
When a helium balloon is released, it rises until it reaches an altitude where its weight equals that of the same volume of air. This is due to the principle of buoyancy.
Helium gas is lighter than air, which causes the balloon to initially ascend. As the balloon rises, the surrounding air pressure decreases, and so does the density of the air. Eventually, the balloon reaches an altitude where the density of the surrounding air matches the density of the helium-filled balloon.
At this point, the upward buoyant force acting on the balloon becomes equal to the downward gravitational force (weight) acting on the balloon. This balance of forces causes the balloon to stop rising further and instead float at a relatively stable altitude.
Option c) accurately describes this behavior, where the balloon rises until it reaches an altitude where its weight equals that of the same volume of air.
The question should be:
The string of a helium balloon slips from your hand and rises into the air. when this happens
a) the balloon rises indefinitely because helium is lighter than air
b) the balloon rises until it reaches an altitude where the air and helium densities are equal.
c) the balloon rises until it reaches an altitude where its weight equals that of the same volume of air
d) the balloon rises continually but slows down to the effect of viscosity
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Wastewater flows into a _________ once it is released into a floor drain.
A) HoseB) Covered containerC) Sump pitD) Bucket
Answers
Answer:
a
Explanation:
Wastewater flows into a sump pit once it is released into a floor drain.
For better understanding, lets understand what wastewater means
Wastewater are water that are not needed or have been use and therefore they are disposed. Waster water often contains waste product of man such as food waste,feaces etc.Sump is simply known as a basin into which groundwater is channeled to. A sump pit is commonly known as a temporary pit that is fixed to trap and filter water for carrying or pumping into a design discharge area.From the above, we can therefore say that the answer that Wastewater flows into a sump pit once it is released into a floor drain is correct
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List the five lines that include short dashes.
Answers
Answer:
OBJECTLINE
HIDDEN LINE
SECTION LINE
CENTER LINE
Explanation:
What does it mean to test a hypothesis?
A.carefully study the results of other scientists
B.analyze only the results from scientific sources
C.have no assumptions about experimental results
D.see if the experiment's results match predictions
Answers
Answer:
D.
Explanation:
I know this because one of my science teachers I had a few years ago made my science class pretty much memorize this since a hypothesis is your best educated guess I know that to test a hypothesis you see if you have the right predictions or hypothesis by testing your predictions to see if they are right or wrong.
In this lab, we assumed that the flip-flops did not contribute to the timing constraints of the circuit. Unfortunately, this is not the case. As you saw when you simulated the D flip-flop, the sampling action does not happen instantaneously. In fact, a flip-flop will become unstable if the inputs do not remain stable for a certain amount of time prior to the rising-edge event (setup time) and a certain amount of time after the rising-edge event (hold time). Assume a setup and hold time of 2ns and 1ns, respectively. What would the theoretical maximum clock rate for the synchronous adder be in this scenario
Answers
Anew student in your class has something different about his appearance. No one wants to sit beside him. You step forward and decide to sit next to him and make him feel comfortable and welcoming. This is an example of:
Answers
Answer:
approaching a lady or a man
In questions 1D through 1F: Express the following base 10 numbers in 16-bit fixed-point two's complement format with eight integer bits and eight fraction bits. Also represent vour answer in hexadecimal 1.D.) -13.5625 1.E.) 42.3125 1.F.)-17.15625
Answers
1.D.) -13.5625 in 16-bit fixed-point two's complement format is 11110010.10010000, which is equivalent to F2.90 in hexadecimal.
1.E.) 42.3125 in 16-bit fixed-point two's complement format is 00101010.01010000, which is equivalent to 2A.50 in hexadecimal.
1.F.) -17.15625 in 16-bit fixed-point two's complement format is 11101110.00101100, which is equivalent to EE.2C in hexadecimal.
In 16-bit fixed-point two's complement format with eight integer bits and eight fraction bits, the leftmost bit is used as a sign bit, where 0 represents a positive number and 1 represents a negative number. To convert a decimal number to 16-bit fixed-point two's complement format, the number is first converted to binary format and then separated into the integer and fractional parts.
The integer part is converted to binary and placed in the eight most significant bits, while the fractional part is converted to binary and placed in the eight least significant bits. The resulting binary number is then converted to hexadecimal format for convenience.
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Show that the dimensions of momentum per unit area per time are the same as those of force per unit area
Answers
Answer:
Unit of,
momentum = kg×m/s
momentum per unit area = kg×m/s×m² = kg/m×s
momentum per unit area per unit time= kg/ms²
force = kg×m/s²
force per unit area = kg×m/s²×m² = kg/ms²
Explanation:
Ue Finite difference method, and etimate the conolidation ettlement. Conider that
the applied load i contant throughout the conolidation time. To how your
numerical reult you can aume boundary condition, thickne of conolidating
layer
Answers
Partial differential equations can be roughly solved using the finite difference method (FDM). It has been applied to a variety of issues. These include time independent and dependent, linear and non-linear issues.
What do the finite element method's boundary conditions entail?The resolution of a boundary value problem requires the presence of boundary conditions (b.c.). The definition of a boundary value problem is a differential equation (or system of differential equations) that must be solved in a domain where the boundary conditions are known.
What three boundary conditions are there?Boundary conditions that have a fixed concentration, a fixed dispersive flux, and a Cauchy boundary are the most typical types (fixed total mass flux).
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a pressure cooker is a pan that cooks food much faster than ordinary pans by maintaining a higher pressure and temperature during cooking. the pressure inside the pan is controlled by a pressure regulator (the petcock) which keeps the pressure at a constant level by periodically allowing some steam to escape, thus preventing any excess pressure buildup. a certain pressure cooker has a volume of 6 l and an operating pressure of 75 kpa gage. initially, it contains 1 kg of water. heat is supplied to the pressure cooker at a rate of 500 w for 30 min after the operating pressure is reached. assuming an atmospheric pressure of 100 kpa, determine: a) the temperature at which cooking takes place. b) the amount of water left in the pressure cooker at the end of the process. assume some liquid water is still in the pan.
Answers
More cooking is done before the water actually begins to boil thanks to the raised pressure inside the cooker, which raises the boiling point of water above 1000C. In the end, food cooks more quickly.
Slow-cooked meals can be quickly prepared with pressure cookers. They are efficient in terms of electricity consumption and are excellent for tenderizing less expensive portions of meat. They are a healthy cooking method since they effectively retain nutrients and can cut cooking times by up to 50%. Water boils at 121°C (250°F) at that pressure. As a result, food may cook at considerably greater temperatures than it could under atmospheric pressure. Additionally, because cooking reactions quicken at higher temperatures, food cooks more quickly it is a good technology.
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Saturated refrigerant-134a vapor at 15 psia is compressed reversibly in an adiabatic compressor to 80 psia. Determine the work input to the compressor. Use the tables for R-134a.
Answers
The initial enthalpy and the entropy of the saturated water can be found out from the table of A-12E
i.e. \($h_1= 101 \ \text{Btu/lbm}$\)
\($s_1 = 0.22717 \text{ Btu/lbmR}$\)
Since the process mentioned above is an adiabatic compression process, the entropy will remain constant throughout the process. Therefore, we take the value of entropy and the final pressure using the table with few interpolations and also approximations to find the final enthalpy. It is given by :
\($h_2= 116.09 \text{ Btu/lbm}$\)
So the work input from the energy balance equation :
\($\dot{W} + \dot{m}h_1 = \dot{m}h_2$\)
\($w=h_2 - h_1$\)
= 116.09 - 101
= 15.09
Therefore, \($w= 15.09 \text{ Btu/lbm}$\)
1. (15) A truck scale is made of a platform and four compression force sensors, one at each corner of the platform. The sensor itself is a short steel cylinder, 22 mm in diameter. A single stain gauge is pre-stressed to 3% strain and bonded on the outer surface of the cylinder. The strain gauges have a nominal resistance (before pre-stressing) of 340 Ohms and a gauge factor of 6.9. The steel used for the cylinders has a modulus of elasticity of 30 GPa. Calculate: a. The maximum truck weight that the scale can measure. b. The change in resistance of the sensors for maximum weight. c. The sensitivity of the scale assuming the response of the strain gauges is linear.
Answers
Answer:
a). 139498.24 kg
b). 281.85 ohm
c). 10.2 ohm
Explanation:
Given :
Diameter, d = 22 m
Linear strain, \($\epsilon$\) = 3%
= 0.03
Young's modulus, E = 30 GPa
Gauge factor, k = 6.9
Gauge resistance, R = 340 Ω
a). Maximum truck weight
σ = Eε
σ = \($0.03 \times 30 \times 10^9$\)
\($\frac{P}{A} =0.03 \times 30 \times 10^9$\)
\($P = 0.03 \times 30 \times 10^9\times \frac{\pi}{4}\times (0.022)^2$\)
= 342119.44 N
For the four sensors,
Maximum weight = 4 x P
= 4 x 342119.44
= 1368477.76 N
Therefore, weight in kg is \($m=\frac{W}{g}=\frac{1368477.76}{9.81}$\)
m = 139498.24 kg
b). Change in resistance
\(k=\frac{\Delta R/R}{\Delta L/L}\)
\($\Delta R = k. \epsilon R$\) , since \($\epsilon= \Delta L/ L$\)
\($\Delta R = 6.9 \times 0.03 \times 340$\)
\($\Delta R = 70.38 $\) Ω
For 4 resistance of the sensors,
\($\Delta R = 70.38 \times 4 = 281.52$\) Ω
c). \($k=\frac{\Delta R/R}{\epsilon}$\)
If linear strain,
\($\frac{\Delta R}{R} \approx \frac{\Delta L}{L}$\) , where k = 1
\($\Delta R = \frac{\Delta L}{L} \times R$\)
\($\Delta R = 0.03 \times 340$\)
\($\Delta R = 10.2 $\) Ω
using the representative volume elements (rve) of a continuous fiber reinforced composite shown below what is the maximum fiber volume fraction to maintain proper cohesion between the fibers and the matrix (i.e. to insure that the fibers are not touching one another) for the square and the hexagonal packed rve models?
Answers
For the square packed RVE model, the maximum fiber volume fraction is 0.41. For the hexagonal packed RVE model, the maximum fiber volume fraction is 0.52.
What is fiber?Fiber is an discipline that deals with the design, construction, and operation of systems that use optical fibers as the principal transmission medium. Optical fibers are thin strands of glass that carry electromagnetic waves over long distances, allowing for high-speed data transmission. Fiber engineering is used to create optical networks that enable communication, entertainment, and other services. It is also used for the transmission of data over long distances, such as for telecommunication systems, and for the distribution of electricity over power grids. Fiber engineering involves a variety of techniques, such as fiber splicing, which is the joining of two or more optical fibers; fiber optic testing, which is the testing of the quality of optical fibers; and fiber optic sensing, which is the detection and measurement of various parameters such as temperature, pressure, and strain.
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the wood innovation design center was conceived as a showcase for the structural potential of timber, replacing steel and concrete as primary building materials.the meti handmade school was designed using mostly local materials, including bamboo, cob, clay, earth, sand, straw, and water.
Answers
This prompt is about Prince George's Wood Innovation Design Center. The building was erected as a model to highlight the possibilities of wood innovation and a departure from conventional concrete and steel architecture and building engineering models.
Why is the Wood Innovation Design Center Important?The Wood Innovation Design Centre (WIDC) is a meeting space for researchers, educators, and design professionals who are brainstorming new ways to use wood. The bottom floors of the building are dedicated to Integrated Wood Design instruction.
The Wood Innovation and Design Centre is located in Prince George, British Columbia. Michael Green Architecture ("Wood Innovation and Design Centre" n.p.) designed the 97-foot-tall, eight-story (six-story includes mezzanine and penthouse) structure.
The building's sleek, contemporary box shape is purposefully simple. Its simplicity serves as a canvas for the beauty of the numerous kinds of wood and their features, which include Douglas-fir, western red cedar, hemlock, pine, and spruce from British Columbia's sustainable forests.
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Suppose a manager of a certain mining company wants to determine the weekly food expenditure of the company’s employees. if there are 2,549 employees and the manager decided to use only 500 employees as a sample, who will be included in the sample? to help the manager make his decision, suggest a sampling technique to be used and state the whole process of selecting the participants
Answers
The sampling technique that can be used to selecting the participants will be a random sampling.
What is sampling?It should be noted that sampling simply a method in statistical analysis that predetermined observations are taken from the population.
In this case, the sampling technique that can be used to selecting the participants will be a random sampling. This is need to give everyone an equal chance of being selected.
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Motor Size Selection
Example:
A conveyor belt is connected a motor through a belt-pulley
mechanism to transfer a load at a predefined maximum speed
as shown in the following figure. The system specifications are
listed in Table 1. For this system, answer the following
questions:
1. Generate and draw the proposed speed and acceleration
profiles.
2.
Calculate the system total inertia (referred to the motor side).
3. Calculate the required maximum motor torque.
4. Calculate the required rated torque.
5.
6.
Draw the load Speed-Torque curve.
Select the best motor type for this application.
7. Select the best motor model from Table 2.
Answers
A simple four-leg intersection (a single lane per approach) needs a 2-phase fixed-time signal. The critical flows in the N-S and E-W directions are 600 and 400 veh/hr, respectively, with 0.95 peak-hour factor. Saturation flow is 1800 veh/hr and the total lost time per phase is observed to be 5.2 seconds. Amber time and all-red time are 4 and 1 seconds, respectively. Assume that the intersection should operate at 90% of its capacity. Determine the cycle length and distribution of green (green splits). Calculate also effective green times.
Hint: round the cycle length to the next higher 5-sec increment (e.g. 86 -> 90); then round splits to the next integer values.
Answers
Answer:
Following are the solution to this question:
Explanation:
\(Y=Y_{NS}+Y_{ew}\)
\(=\frac{q_{NS}}{S_{NS}}+\frac{q_{ew}}{S_{ew}}\\\\=\frac{600}{1800}+\frac{400}{1800}\\\\=\frac{6}{18}+\frac{4}{18}\\\\=\frac{3}{9}+\frac{2}{9}\\\\=\frac{1}{3}+\frac{2}{9}\\\\=\frac{3+2}{9}\\\\=\frac{5}{9}\\\\=0.55555555556\\\\=0.57\)
calculating length \((C_D)=\frac{1.5 \ L +5}{1-y}\\\\\)
\(=\frac{1.5 \times (1.2) +5}{1-0.57}\\\\=\frac{1.8 +5}{0.43}\\\\=\frac{6.8}{0.43}\\\\= 15.8 \ sec\)
critical value:
\(\to V_{C_1}= 600 \ \frac{veh}{hr}\\\\\to V_{C_2}= 400 \ \frac{veh}{hr}\\\\\)
Total critical value:
\(V_C= V_{C_1}+ V_{C_2}\\\\\)
\(= 600 + 400\\\\= 1 000 \ \frac{veh}{hr}\\\\\)
Active green time\(= 15.8-1.2=14.6\)
\(g_1=\frac{600}{1000}\times 14.6= 8.76 \ sec\\\\g_2=\frac{400}{1000}\times 14.6= 5.84 \ sec\)
Native green time:
\(G_1= 8.76 -1.2+4 =11.56 \sec\\\\ G_2= 5.84 -1.2+4 =8.64 \sec\)
The file diseaseNet.mat contains the potentials for a disease bi-partite belief network, with 20 diseases d1, …, d20 and 40 symptoms, s1, …, s40. The disease variables are numbered from 1 to 20 and the Symptoms from 21 to 60. Each disease and symptom is a binary variable, and each symptom connects to 3 parent diseases.
1. Using the BRMLtoolbox, construct a junction tree for this distribution and use it to compute all the marginals of the symptoms, p(si = 1).
2. Explain how to compute the marginals p(si = 1) in a more efficient way than using the junction tree formalism. By implementing this method, compare it with the results from the junction tree algorithm.
3. Symptoms 1 to 5 are present (state 1), symptoms 6 to 10 not present (state 2) and the rest are not known. Compute the marginal p(di = 1|s1:10) for all diseases.
Answers
1. BRMLtoolbox Constructed Junction Tree:To construct the junction tree for the given distribution in the BRMLtoolbox, we use the following code:load diseaseNet.matp1=1.
The learned DAG is converted to the PDAG, and structure and data are provided to learn its structure with PC algorithm. Using the "jtree" function, a junction tree is constructed. Lastly, marginals of symptoms are computed using the "marginal" function, using the junction tree and symptoms 21-60 as input.2.
Efficient way to compute marginals p(si=1):Instead of computing all the marginals using the junction tree formalism, a faster and more efficient way to compute the marginals p(si=1) is to use the forward-backward algorithm. This algorithm is based on dynamic programming, and is used to compute all the marginals of a Hidden
evidence);fori=1:20belief{i}=marginal_nodes(engine, i);endThe above code is used to calculate the marginals of symptoms using the forward-backward algorithm.
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Which method of freezing preserves the quality and taste of food?
Answers
Answer:
commercial freezing
Explanation:
smaller ice crystals are formed this causes less damage to cell membranes so the quality is less effected
You have a 12-inch PVC water main that is 850 feet long flowing at 5.6 cfs. Point A is at an elevation of 750 ft. Point B is at an elevation of 765 ft. If the pressure in a water main at Point A is 85 psi, what is the pressure at point B, in psi? (5 points)
Answers
Known :
D = 12 in = 1 ft
L = 850 ft
Q = 5.6 cfs
hA = 750 ft
hB = 765 ft
PA = 85 psi = 12240 lb/ft²
Solution :
A = πD² / 4 = π(1²) / 4
A = 0.785 ft²
Velocity of water :
U = Q / A = 5.6 / 0.785
U = 7.134 ft/s
Friction loss due to pipe length :
Re = UD / v = (7.134)(1) / (0.511 × 10^(-5))
Re = 1.4 × 10⁶
(From Moody Chart, We Get f = 0.015)
hf = f(L / d)(U² / 2g) = 0.015(850 / 1)((7.134²) / 2(32.2))
hf = 10 ft
PA + γhA = PB + γhB + γhf
PB = PA + γ(hA - hB - hf)
PB = 12240 + (62.4)(750 - 765 - 10)
PB = 10680 lb/ft²
PB = 74.167 psi
a skilled technician with several years of experience who is employed to oversee the operation of a company or maintenance department is a
Answers
Answer:
business operation Manager
What is a semiconductor whose electrical properties are based on the electronic structure inherent in the pure materials? MATSE 81
Answers
Answer:
intrinsic semiconductors
Explanation:
An intrinsic semiconductor is also known as a pure conductor. In such a semiconductor there are no impurities, that is why it is said to be pure.
It has some of these properties:
1. Electrical conductivity is only based on temperature
2. The quantity of electrons is the same as the number of holes in the valence bond
3. Electrical conductivity is not on the high side
4. These materials exist in their pure forms.
2. Recycled tires are frequently turned into?
Answers
Answer:
Play ground cover
Explanation:
Recycled tires are frequently turned into crumb rubber and tire-derived fuel
What are recycled?Recycled can be defined as a product that can be used for reuse by creating another material or a product or using the same products rather than destroying if it is being given a new form.
Recycle helps in various things while energy conservation and it also is pollution that is being created it is basically using of the material which is going to be trashed
Recycling one can easily convert tires into crumb rubber, and also it helps in deriving fuel as it can be used as coal which is being transformed into a heating purpose. It just helps in creating various substances that is basically lightweight it and eco-friendly product. It can create various other products like mouse pad or it can be used in an architectural purpose
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Find and write the mathematical problem formulation of shortest path problem
Answers
Shortest path (A, C, E, D, F) between vertices A and F in the weighted directed graph
The problem of finding the shortest path between two intersections on a road map may be modeled as a special case of the shortest path problem in graphs, where the vertices correspond to intersections and the edges correspond to road segments, each weighted by the length of the segment.
What can you determine about the feasibility of a reaction if the enthalpy is positive and the entropy is negative?.
Answers
The right answer is B. The reaction will never be possible since the Gibbs energy will always be positive.
Gibbs free energy, G, enthalpy, H, and entropy, S are related as follows:
ΔG = ΔH - TΔS
We will always have a positive value for the Gibbs free energy if enthalpy is positive and entropy is negative.
This means that choice B is the best one. A reaction will always be possible if it is exothermic (H is negative), has a positive entropy change (S is positive), and G is always negative. The sign of G determines whether a response (or other physical change) is possible. The reaction cannot take place if G is positive.
The complete question is- What can you determine about the feasibility of a reaction if the enthalpy is positive and the entropy is positive?
A. The Gibbs energy will always be positive, and the reaction will never be feasible.
B. The Gibbs energy will always be negative, and the reaction will always be feasible.
OC. The reaction could be feasible above a certain temperature.
D. The reaction will usually occur because it is unlikely the entropy will be greater than the enthalpy.
Reset Selection
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Technician A says that for any fuel to burn efficiently, it must be vaporized and fully mixed with the proper amount of air. Technician B says that small fuel particles are easier to vaporize. Who is correct?
Answers
Both technicians are correct
Explanation:
They are each correct for separate reasons. Tech A is correct due to pressure and temperature both being important factors and quantities to vaporize anything. Tech B is correct due to fuel particles being easier to burn due to their chemical structure.
How does inductive reactance depend on the frequency of the ac voltage source and the rms current through the inductor?.
Answers
Directly proportional.
As the inductive reactance is directly proportional to the frequency, by increasing the frequency the inductive reactance of the inductor increases.
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why would a chip without pmos transistors be easier to fabricate? what process steps are avoided? give more than one for full credit.
Answers
A chip without PMOS transistor is easier because pMOS transistor would not avaiable to offer a conductive path for a node all the way to the ground voltage.
Microprocessors are constructed out of transistors. In particular, they're built out of metal-oxide-semiconductor (MOS) transistors. There are kinds of MOS transistors — positive-MOS (pMOS) and negative-MOS (nMOS). Every pMOS and nMOS comes prepared with 3 primary components — the gate, the source, and the drain. NMOS and pMOS are the primary types of MOSFET. The primary difference between NMOS and pMOS is that, in NMOS, the source and the drain terminals are made from n-kind semiconductors meanwhile, in pMOS, the source and the drain are made from p-kind semiconductors.
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which technique is used to locate profiles when xraying quora?
Answers
The technique used to locate profiles when x-raying Quora is called "OSINT" (Open Source Intelligence). OSINT is a method of gathering information from publicly available sources to obtain insights and intelligence about individuals, organizations, or other entities.
When x-raying Quora, OSINT techniques involve leveraging various search engines, social media platforms, and online directories to discover and analyze profiles associated with Quora users. This may include searching for specific keywords, usernames, or other identifying information related to the target profiles.
OSINT helps in locating profiles on Quora by utilizing the information shared by users publicly on the platform or on other websites that might be indexed by search engines. By employing advanced search operators and techniques, researchers can uncover hidden or non-obvious profiles, gather additional details about users, and potentially identify connections between individuals.
Overall, OSINT provides a valuable approach to locating profiles when x-raying Quora by leveraging publicly available information to gather insights and understand the online presence of individuals on the platform.
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Which of the following machine parts always require
guards?
Select the 3 answer options that apply.
Fan blades
Levers
Rotating barrels
Abrasive wheel machinery
Answers
Answer:fan blades, rotating , abrasive wheel machinery
Explanation: