1. Air shows the property of
a) N
b) 02
c) Both a) and b)
d) None of these

Answer:

An aqueous solution of NaNO2 is obtained from the solution containing the salt of a strong base and weak acid. The pH of this solution will be greater than 7. Hence, NaNO2 the solution will be basic or alkaline. Therefore, an aqueous solution of NaNO2 will be basic.

When \(\rm NaNO_2\) is dissolved in water, it becomes slightly basic. However, the degree of basicity is rather low when compared to strong bases such as alkali metal hydroxides.

The salt sodium nitrite (\(\rm NaNO_2\)) is made up of the sodium cation (\(\rm Na^+\)) and the nitrite anion (\(\rm NO_2^-\)). A compound's acidity or basicity is determined by its behaviour in water and the presence of any acidic or basic characteristics. In the instance of NaNO2, hydrolysis occurs when it is dissolved in water. \(\rm NO_2^- + H_2O \rightarrow HNO_2 + OH^-\)

The nitrite ion has a basic nature since it can take a proton. As a result, when dissolved in water, \(\rm NaNO_2\) is slightly basic. However, the degree of basicity is rather low when compared to strong bases such as alkali metal hydroxides.

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Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

Answer:

I really don't know if this is right but i did the math and there would have to be one cent leftover , but you would have to buy 8 sodas and 5 bag of chips .

Explanation:

Answer:   3 mol oxygen.

Explanation:       Because by definition you have 1 mol of potassium nitrate. Potassium nitrate in this quantity comprises 1 mol K, 1 mol N,

Answer:

frequency of the wave f=4 Hz

The specific heat of the metal can be calculated using calorimetric equation. The specific heat of the metal here is 0.61 J/g °C.

The specific heat capacity of  substance is the heat energy required to raise its temperature by one degree Celsius per one gram  of the substance.

The calorimetric equation connecting the heat energy q, mass m, specific heat c and temperature difference ΔT is:

q = m c  ΔT

Here, the heat released from the metal is equal to the heat absorbed by water.

Therefore,

q metal = q water. Let c  be the specific heat of the metal.

25 g  × ( 99 - 20.15°C) ×c = 50 g  × ( 20.15°C- 14.33) × 4.18 J/g °C

                                         = 1217.5 J

Then c = 1217.5 J/25 g  × ( 99 - 20.15°C)  = 0.61 J/g °C.

Therefore, the specific heat of the metal is 0.61 J/g °C.

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Answer:

The Hawaiian Islands are a very small section of a huge chain of volcanic islands that crosses the northern half of the Pacific Ocean, called the Hawaiian-Emperor Volcanic Island Chain, which is over 6,000 kilometres long. The chain is linear, with a large bend in the middle: the southern half is called the Hawaiian Ridge and the northern half is called the Imperial Seamount.

Explanation:

In \(\rm 4\;NH_3\), the 4 has been the coefficient of the compound and represents the number of molecules of ammonia.

\(\rm NH_3\) has been a compound of nitrogen and hydrogen. The compound has been a covalent compound, formed by the sharing of electrons in between nitrogen and hydrogen.

The compound has been consisted of 1 nitrogen atom and 3 hydrogen atoms. The hydrogen atoms bonding results in the completion of the octet of the nitrogen and provides stability to the compound.

While writing the chemical equation, the coefficient of the compound has been describing the number of molecules present in the reaction. In \(\rm 4\;NH_3\), the 4 has been the coefficient of the compound and represents the number of molecules of ammonia.

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To calculate the atoms of an element in a given molecule, we need to multiply stoichiometry by the number that is written on the foot of that element. Therefore, the correct option is option D.

Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, displacement reaction.

The other characteristic of balanced reaction is that physical state should be written with each compound or molecule on reactant and product side. Physical state should be written in brackets. s means solid, l means liquid, g means gas.

The balanced equation for V\(_2\)O\(_5\) + CaS → CaO + V\(_2\)S\(_5\) is

V\(_2\)O\(_5\) + 5CaS → 5CaO + V\(_2\)S\(_5\)

Therefore, the correct option is option D.

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Explanation:

Sodium and oxygen react to produce sodium oxide. The balanced equation of the reaction is:

4 Na + O₂ ----> 2 Na₂O

First we can convert the 45.35 g of Na₂O into moles using its molar mass.

molar mass of Na = 22.99 g/mol

molar mass of O = 16.00 g/mol

molar mass of Na₂O = 2 * 22.99 g/mol + 1 * 16.00 g/mol

molar mass of Na₂O = 61.98 g/mol

moles of Na₂O = 45.35 g * 1 mol/(61.98 g)

moles of Na₂O = 0.7317 moles

4 Na + O₂ ----> 2 Na₂O

According to the coefficients of the reaction, 4 moles of Na will react with 1 mol of O₂ to produce 2 moles of Na₂O. Then the molar ratio between O₂ and Na₂O is 1 to 2. We can use that relationship to find the answer to our problem.

1 mol of O₂ : 2 moles of Na₂O

moles of O₂ = 0.7317 moles of Na₂O * 1 mol of O₂/(2 moles of Na₂O)

moles of O₂ = 0.3659 mol

Answer: 0.3659 moles of oxygen are needed to produce 45.35 g of sodium oxide.

Answer: Their main aim was to provide goods, specifically furs and sugar exportation.

Explanation:

The equilibrium pressure of the nitrogen oxide is given as 4 atm.

Kp is the equilibrium constant for a chemical reaction in terms of partial pressures. It is defined as the ratio of the product of the partial pressures of the products raised to their stoichiometric coefficients to the product of the partial pressures of the reactants raised to their stoichiometric coefficients

We know that;

Kp = \(pNO_{2} ^2/pN_{2} ^2 . pO_{2}\)

\(3.2 * 10^-28 = (2x)^2/(3.21 - 2x) (6.21 - x)\\3.2 * 10^-28 = 4x^2/19.9 - 3.21x - 12.42x + 2x^2\\3.2 * 10^-28(19.9 - 15.63x + 2x^2) = 4x^2\\6.4 * 10^-27 - 5 * 10^-27 x + 6.4 * 10^-28x^2 = 4x^2\\x = 4 atm\)

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The equation that relates A and W, considering the desired 15% acetic acid concentration, is 3W = 2.55M.

The equation A = (3/17)W represents the relationship between the mass of acetic acid (A) and the mass of water (W) in the mixture. It states that the mass of acetic acid is equal to three seventeenths (3/17) of the mass of water.

Since the company wants the acetic acid to be 15% of the total mass of the mixture, we can set up another equation to represent this requirement. Let M be the total mass of the mixture. The mass of acetic acid (A) is 15% of the total mass, so we have A = 0.15M.

Now we can substitute A in terms of W from the first equation into the second equation: (3/17)W = 0.15M. We can simplify this equation by multiplying both sides by 17 to get 3W = 2.55M.

This equation allows the company to calculate the mass of water (W) required for a given mass of acetic acid (A) to maintain the desired concentration in the mixture.

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Answer:

Explanation:

From the information given:

\(CaF_2 \to Ca^{2+} + 2F^-\)

\(Ksp = 3.2 \times 10^{-11}\)

no of moles of \(Ca^{2+}\) = 0.01 L × 0.0010 mol/L

no of moles of \(Ca^{2+}\) = \(1 \times 10^{-5} \ mol\)

no of moles of \(F^-\) = 0.01 L × 0.00010 mol/L

no of moles of \(F^-\) = \(1 \times 10^{-6}\ mol\)

Total volume = 0.02 L

\([Ca^{2+}}] = \dfrac{1\times10^{-5} \ mol}{0.02 \ L} \\ \\ \\ \[[Ca^{2+}}] = 0.0005 \ mol/L\)

\([F^{-}] = \dfrac{(1\times 10^{-6} \ mol)}{0.02 \ L}\)

\([F^{-}] = 5 \times 10^{-5} \ mol/L\)

\(Q = [Ca^{2+}][F^-]^2 \\ \\ Q = 0.0005 \times (5\times 10^{-5})^2 \\ \\ Q = 1.25 \times 10^{-12}\)

Since Q<ksp, then there will no be any precipitation of CaF2

The correct option is (a) Cool air descends to the ground there is a  high-pressure zone.

According to climatology, air that has been lifted at the equator causes high pressure to develop at the horse latitudes,

                           also known as the torrid zone, between the latitudes of 20 and 40 degrees from the equator.

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Answer:

NH4NO2.

Explanation:

Hello!

In this case, since the by-mass percent of any element (in this case nitrogen) is computed by:

\(\%N=\frac{n_N*m_N}{M}*100\%\)

Whereas n is the number of N in the compound, m the atomic mass of nitrogen (14.01 g/mol) and M the molar mass of the compound. Thus, down below we can find the molar mass of each compound and the by-mass percent of nitrogen:

NH4NH2CO2  = 78.07 g/mol

\(\%N=\frac{2*14.01}{78.07}*100\%=35.9\%\)

NH4NO2  = 64.06 g/mol

\(\%N=\frac{2*14.01}{64.06}*100\%=43.7\%\)

N2O3  = 76.01 g/mol

\(\%N=\frac{2*14.01}{76.01}*100\%=36.9\%\)

NH4Cl  = 53.49 g/mol

\(\%N=\frac{1*14.01}{53.49}*100\%=26.2\%\)

NH2OH = 33.03 g/mol

\(\%N=\frac{1*14.01}{33.03}*100\%=42.4\%\)

In such a way, the compound with the highest percentage of nitrogen by mass is NH4NO2.

Best regards!

Answer:

NH4NO2

Explanation:

The answer is the 2ndone

NH4NO2

Answer:

Empirical formula of a compound means that it provides simplest ratio of whole number.

Explanation:

Mass of boron and chlorine is 9.224% and 90.74%

Answer:

No. of moles, n = 7.52 moles

Explanation:

Given that,

Mass, m = 563.9 grams

Molar mass of arsenic = 74.92 g/mol

We need to find the number of moles in 563.9 grams of arsenic. Let it is denoted by n. It is equal to given mass divided by total molar mass.

\(n=\dfrac{563.9 }{74.92}\\\\=7.52\ \text{moles}\)

So, there are 7.52 moles in 563.9 grams of arsenic.

Answer:

\(\huge\boxed{\sf M = 0.06\ M}\)

Explanation:

No. of moles = n = 0.03 mol

Volume = v = 500 ml = 0.5 L

Molarity = M = ?

M = n / v

Put the given data in the above formula.

M = 0.03 / 0.5

\(\rule[225]{225}{2}\)

To prepare a 0.12 M solution of FeCl₃, the amount of solid FeCl₃ to be dissolved in a given volume of solvent will be 9.72 grams.

Given,

Molarity of FeCl₃ (M)= 0.12 M

The molecular weight (m) of FeCl₃ is  = 162 gm

The volume of the solution (V) to be prepared is =500 ml

The amount of FeCl₃ to be dissolved to make a 0.12 M solution is= x

So,

MV= x ÷ m × 1000

0.12× 500 = x ÷ 162 × 1000

x = 60 × 162 ÷ 1000

x= 9.72 gm

So 9.72 grams of FeCl₃ is dissolved to make 500 ml of 0.12 M solution.

For preparing 0.4 M HCl from 4M HCL:

If we need to make 500 ml of solution with 0.4M of HCL, then we use the formula:

M₁V₁= M₂V₂

0.4 × 500= 4 × x

x= 50 ml

So 50 ml of 4M HCL is taken to make 0.4 M HCL.

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Writing and balancing complex half-reactions in acidic solutions involves a systematic approach. Here are the general steps to follow:

Identify the oxidation and reduction half-reactions: Determine which species is being oxidized (losing electrons) and which is being reduced (gaining electrons).

Balance the atoms: Begin by balancing all atoms except hydrogen and oxygen in each half-reaction.

Balance the charges: Add electrons (e-) to one side of each half-reaction to balance the charges.

Balance the oxygen atoms: Add water (H2O) to the side of the equation that lacks oxygen atoms.

Balance the hydrogen atoms: Add hydrogen ions (H+) to the side of the equation that lacks hydrogen atoms. Keep in mind that the solution is acidic.

Balance the charges: Adjust the number of electrons (e-) on each side of the equation to ensure that the charges are balanced.

Multiply the half-reactions: Multiply each half-reaction by an appropriate factor so that the number of electrons gained and lost are equal.

Combine the half-reactions: Add the two balanced half-reactions together and cancel out common terms on both sides of the equation.

By following these steps, you can effectively write and balance complex half-reactions in acidic solutions, ensuring that the overall reaction is balanced in terms of both atoms and charges.

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Answer:

amino acids

Hope this helps:)

Answer:

C: Amino Acids on edge

Explanation:

Answer:

About 7.0 × 10³ J or 7.0 kJ

Explanation:

We want to determine the amount of energy needed to raise the temperature of 67 grams of water from 20°C to 45°C.

We can use the heat equation:

\(\displaystyle q = mC\Delta T\)

Where C is the specific heat of water.

Substitute and evaluate:

\(\displaystyle \begin{aligned} q & = (67\text{ g})\left(\frac{4.2\text{ J}}{\text{g-$^\circ$C}}\right)\left(45^\circ \text{ C}- 20.^\circ\text{ C}\right) \\ \\ & = (67\text{ g})\left(\frac{4.2\text{ J}}{\text{g-$^\circ$C}}\right)(25^\circ \text{ C}) \\ \\ & = 7.0\times 10^3 \text{ J}\end{aligned}\)

Recall that there are 1000 J in a kJ. Hence:

\(\displaystyle \begin{aligned} q & = 7.0\times 10^3 \text{ J} \cdot \frac{1\text{ kJ}}{1000\text{ J}} \\ \\ & = 7.0 \text{ kJ}\end{aligned}\)

In conclusion, it will take about 7.0 × 10³ J or 7.0 kJ of energy to raise the temperature of 67 grams of water from 20 °C to 45 °C.

Hello, this is Bing. I can help you with your question. Based on the information I found on the web, **H2** can be broken down into its two atoms of hydrogen (H) by supplying enough energy to overcome the bond that holds them together⁴. This process is called **dissociation** and requires an energy equal to or greater than the **dissociation energy** of H2, which is about 436 kJ/mol⁴.

One way to break down H2 is by using **electricity** to split water (H2O) into hydrogen (H2) and oxygen (O2) through a process called **electrolysis**¹. In this process, water is decomposed into its elements by passing an electric current through it. The electric current is provided by a battery or another source of electricity and the water needs to have an **electrolyte**, such as salt or acid, added to it to make it conductive¹. Two electrodes, usually made of metal or other conductive material, are inserted into the water and connected to the battery. The electrode connected to the positive terminal of the battery is called the **anode** and the one connected to the negative terminal is called the **cathode**¹. When the electric current flows through the water, hydrogen gas bubbles form at the cathode and oxygen gas bubbles form at the anode¹. The overall chemical reaction for electrolysis of water is:

2 H2O → 2 H2 + O2

Another way to break down H2 is by using **heat** to cause a reaction between hydrogen and oxygen that produces water and releases a large amount of energy. This reaction is called **combustion** or **oxidation** and can be ignited by a spark or a flame³. The reaction is very fast and explosive and can be dangerous if not controlled. The overall chemical reaction for combustion of hydrogen is:

2 H2 + O2 → 2 H2O

I hope this helps you understand how H2 can be broken down and what methods are used to do so.

Answer:

The answer to this reaction would be C-C-OH + H2.

Answer:neutral

Explanation:ionic compounds is between a cation and anion so they cancel eachother out

Answer:

R=k[D]^2

Explanation:

Given that it is a decomposition reaction;

D--->product

Hence;

The rate law is;

R= k[D]^x ----(1)

When we triple the concentration of D we have;

[D]' = [3D]^x

Therefore;

R'= 3R

R'= k[D]'----(2)

Hence dividing (1) by (2);

R/R' = k[D]^x/k[D]'

R/9R = k[D]^x/k[3D]^x

1/9 = 1/3^x (take inverse of both sides)

9 = 3^x

3^2 = 3^x

x= 2

Hence the rate law;

R=k[D]^2